I think this does what you want.
z1<- -1
z2<- 2
oldp <- par(mgp=c(3, .5, 0))
curve(dnorm(x,0,1), xlim=c(-5, 5),main="Standard Normal",
xaxt="n", frame=F, xlab="")
jj<-seq(z1,z2,0.01)
cord.x<- jj
cord.y<- dnorm(jj)
polygon(c(-1, cord.x, 2), c(0, cord.y, 0), col="skyblue")
axis(1,at=c(-5,z1,0,z
David, Rui, and All:
Greetings.
1. I need a helping hand with the polygon statement below so that I can
have the area under the curve highlighted, between (z1,z2).
2. Is it possible to label the X-axis with in two scale, in the current
z-scale and another, say x = (z+5)*2?
Thank you.
z1<- -1
z2<
I post long time ago a post on my blog about this:
https://max2.ese.u-psud.fr/epc/conservation/Girondot/Publications/Blog_r/Entrees/2014/8/3_Install_RStudio_server_on_Marverick_MacOSX.html
You could try using this base.
Marc
Le 21/10/2018 à 05:12, Fuchs Ira a écrit :
Can I run Rstudio Server o
Hi,
I'm not entirely sure what you want to calculate.
If you want to integrate by u in the interval from 0 to 4 for every value
of x I would suggest something like this:
x <- rnorm(10,0,1)
f <- function(u,x){
exp((x-u))
}
sapply(x, function(i){
integrate(f,lower=1,upper=4, x=i)$value
})
hello
please you help me i have this functionx<-rnorm(10,0,1)f<-fuction(u,x)
{exp((x-u)}I want to calculate the integral of this function for each value of
x{for(i in 1:lenght(x)integrate(f,lower=1,upper=4)
thinks
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