I don't know how to say this charitably, but your post indicates that you
**really need to go through an R tutorial or two.** Rather than give you
answers to these very basic matters, a couple of hints:
1. A and P are vectors with 3 elements, not matrices .
2. I presume things like c11 and c32 a
Hello,
I have two matrices: a<-matrix(c(100,350,100,240,150,210,60,120,200 ),3,3)
and c<-matrix(c(2,9,13,10,4,11,14,12,3),3,3).
I have also defined the following variables:
K=0
A[i,j]=colSums(a)
P[i,j]=rowSums(a)
F[i,j]=c[i,j]^(-2 )
Using these data I want to perform the calculation which must
On Fri, 20 Jul 2018, William Dunlap wrote:
To find the lines in the file, tfile, with bogus dates, try
readLines(tfile)[ is.na(dataFrame$DateTime) ]
Bill,
Thanks for another lesson.
Regards,
Rich
__
R-help@r-project.org mailing list -- To UN
On Fri, 20 Jul 2018, Rich Shepard wrote:
Thank you all. I found the typos which covered a single day toward the end
of the dataframe.
FWIW, all these data came from PDF reports and had to be manually
highlighted and pasted into a text file. Given 29 years of hourly (and
sometimes half-hourl
To find the lines in the file, tfile, with bogus dates, try
readLines(tfile)[ is.na(dataFrame$DateTime) ]
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Fri, Jul 20, 2018 at 1:30 PM, Rich Shepard
wrote:
> On Fri, 20 Jul 2018, David Winsemius wrote:
>
> I don't think you read Bill's message
On Fri, 20 Jul 2018, William Dunlap wrote:
You mean each line in the file, not row in data.frame, has the form
"year-month-day,hour:min,numericValue". Try the following, where tfile
names your file:
Bill,
Yes, I was looking at the data file in one emacs buffer and my R session
in another on
> And each dataframe row has this format:
>2015-10-01,00:00,90.6689
>2015-10-01,01:00,90.6506
>2015-10-01,02:00,90.6719
>2015-10-01,03:00,90.6506
You mean each line in the file, not row in data.frame, has the form
"year-month-day,hour:min,numericValue". Try the following, where tfile
names your
On Fri, 20 Jul 2018, David Winsemius wrote:
wy2016$dt_time <- with( wy2016, as.POSIXct( paste( date, time ) , format=
"%Y-%m-%d %H:%M") )
David/Bill/Eric:
Thank you all. I found the typos which covered a single day toward the end
of the dataframe.
Carpe weekend,
Rich
On Fri, 20 Jul 2018, Eric Berger wrote:
This may not be the most efficient but it will identify the offenders.
foo <- paste(wy2016$date, wy2016$time))
uu <- sapply(1:length(foo),
function(i) { a <- try(as.POSIXct(foo[i]),silent=TRUE)
"POSIXct" %in% class(a) })
which
On Fri, 20 Jul 2018, David Winsemius wrote:
I don't think you read Bill's message properly.
David,
Obviously not.
He was not saying that there were NA's; he was telling you to use a format
specification in your as.POSIXct call and the the result of that call
would have NA's.
wy2016$dt_ti
On Fri, 20 Jul 2018, William Dunlap wrote:
Which format did you use when you used is.na on the output of
as.POSIXlt(strings, format=someFormat)
and found none? Did the resulting dates look OK? Perhaps
all is well.
Bill,
All dates here are kept as -mm-dd.
And each dataframe row ha
> On Jul 20, 2018, at 11:58 AM, Rich Shepard wrote:
>
> On Fri, 20 Jul 2018, William Dunlap wrote:
>
>> The problem occurs because no commonly used format works on all your date
>> strings. If you give as.POSIXlt the format you want to use then items that
>> don't match the format will be trea
Which format did you use when you used is.na on the output of
as.POSIXlt(strings, format=someFormat)
and found none? Did the resulting dates look OK? Perhaps
all is well.
Note the the common American format month/day/year is not
one that is tested when you don't supply a format - xx/yy/
i
Hi Rich,
This may not be the most efficient but it will identify the offenders.
> foo <- paste(wy2016$date, wy2016$time))
> uu <- sapply(1:length(foo),
function(i) { a <- try(as.POSIXct(foo[i]),silent=TRUE)
"POSIXct" %in% class(a) })
> which(!uu)
HTH,
Eric
On Fri, J
On Fri, 20 Jul 2018, William Dunlap wrote:
The problem occurs because no commonly used format works on all your date
strings. If you give as.POSIXlt the format you want to use then items that
don't match the format will be treated as NA's. Use is.na() to find them.
Bill,
No NAs found using
The problem occurs because no commonly used format works on
all your date strings. If you give as.POSIXlt the format you want to
use then items that don't match the format will be treated as NA's.
Use is.na() to find them.
> d <- c("2017-12-25", "2018-01-01", "10/31/2018")
> as.POSIXlt(d)
Error i
The structure of the dataframe is
str(wy2016)
'data.frame': 8784 obs. of 4 variables:
$ date : chr "2015-10-01" "2015-10-01" "2015-10-01" "2015-10-01" ...
$ time : chr "00:00" "01:00" "02:00" "03:00" ...
$ elev : num 90.7 90.7 90.7 90.7 90.7 ...
$ myDate: Date, format: "2015-10-01"
On Fri, 20 Jul 2018, Duncan Mackay wrote:
If you have to make several plots you can subset your data
Duncan,
That's what I thought I should do.
xyplot(... data = subset(x, condition), ...)
or
XYn <- xyplot(... data = x[row1:row2, ], ...)
in a loop
have a look a ? print.trellis
if you wa
Hi
Values in conv_df are almost same for each Error level
> aggregate(conv_df$Intercept, list(conv_df$Error), mean)
Group.1 x
1 High CML error -3.226313
2 Low CML error -3.226536
3 Med CML error -3.226422
> aggregate(conv_df$Slope, list(conv_df$Error), mean)
Group.1
On 07/20/2018 02:01 PM, Micha Silver wrote:
On 07/20/2018 01:28 PM, Bert Gunter wrote:
Nothing attached. The mail server strips most attachments for security.
Here is a (slightly shorter) repex.
The fourth plot shows the problem. The first three are as expected.
library(ggplot2)
strat_d
On 07/20/2018 01:28 PM, Bert Gunter wrote:
Nothing attached. The mail server strips most attachments for security.
Here is my repex, inline:
library(ggplot2)
conv_df <- structure(list(Adjustment = structure(c(1L, 2L, 3L, 4L, 5L, 1L,
2L, 3L, 4L, 5L, 1
Nothing attached. The mail server strips most attachments for security.
See the posting guide below and ?dput for how to include data.
+ We need your faulty code also, of course.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking thing
Hello:
I have two data frames (subsetted from a larger one). I am plotting
scatterplots with ggplot2 and coloring by different variables. When
using one of the variables "Error" with one of the dataframes "conv_df"
only a single color is displayed. All the other variables show colors as
expec
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