Dear Mr. Savicky,
I am currently working on a project where I want to test a random number
generator, which is supposed to create 10.000 continuously uniformly
distributed random numbers between 0 and 1. I am now wondering if I can use the
Chi-Squared-Test to solve this problem or if the Kolmog
stats::spectrum for starters.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Tue, Apr 10, 2018 at 5:49 AM, Danniel Lafeta Machado <
danniel.laf...@bcb.gov.br> wrote:
> Dear all,
> Is there any spectral analisys functionality available for R version 3.4.3?
> Series() functionality doesn't work i
Please provide a reproducible example of the problem, with sample data.
Notes:
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2) Technically, 3.4.3 is not
Hi
You could instead of selecting columns by name select them by number
Something like
your.data[,2:3] <- do.call(data.frame, lapply(your.data[,2:3], factor))
or you could construct a vector of column numbers
x <- c(2,3)
Cheers
Petr
-Original Message-
From: R-help [mailto:r-help-boun.
Dear all,
Is there any spectral analisys functionality available for R version 3.4.3?
Series() functionality doesn't work in this version.
Regards
Danniel
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> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Saif Tauheed
> After that I have the following error:
>
> cols<- c("GrMM", "RELG", "CASTE1", "SECTOR", "SECTOR4","AGE", "MARITAL",
> "JOBSTATUS", "ENG", "EDU", "PARENT_EDU", "MASSMEDIA_F",
> "MASSMEDIA_M", "HomeComputer", "HomeInter
Not sure whether this is the problem but calling your data frame
data.frame is not a good idea.
On 10/04/2018 11:48, Saif Tauheed wrote:
Thank you very much.
After that I have the following error:
cols<- c("GrMM", "RELG", "CASTE1", "SECTOR", "SECTOR4","AGE", "MARITAL", "JOBSTATUS", "ENG", "ED
Thanks.
S. Elison provided a similar but apparently more general solution (see other
post in thread).
- Original Message -
From: "David Winsemius"
To: "Sebastien Bihorel"
Cc: r-help@r-project.org
Sent: Monday, April 9, 2018 12:33:41 AM
Subject: Re: [R] Question about subset
Sent fro
Thanks.
That works great!
> df <- data.frame(x=c(1,1,NA,NA,2), y=c('a','a','a','b','b'),
> z=c(TRUE,FALSE,TRUE,FALSE,TRUE))
> cond1 <- 'x==1'
> cond2 <- 'x==1 & z'
> df
x y z
1 1 a TRUE
2 1 a FALSE
3 NA a TRUE
4 NA b FALSE
5 2 b TRUE
> subset(df, subset = ifelse(is.na(eval(parse(te
Thank you very much.
After that I have the following error:
cols<- c("GrMM", "RELG", "CASTE1", "SECTOR", "SECTOR4","AGE", "MARITAL",
"JOBSTATUS", "ENG", "EDU", "PARENT_EDU", "MASSMEDIA_F", "MASSMEDIA_M",
"HomeComputer", "HomeInternet")
> for (I in cols) {data.frame[,i]= as.factor(data.frame[,i
You are missing a comma between "MARITAL" and "JOBSTATUS".
On Tue, Apr 10, 2018 at 10:27 AM, Saif Tauheed
wrote:
> I run this command for converting the numerical variable into factor.
> However, I get the following error message.
>
> > cols<- c(“GrMM", "RELG", "CASTE1", "SECTOR", "SECTOR4","AGE
I run this command for converting the numerical variable into factor. However,
I get the following error message.
> cols<- c(“GrMM", "RELG", "CASTE1", "SECTOR", "SECTOR4","AGE", "MARITAL"
> "JOBSTATUS", "ENG", "EDU", "PARENT_EDU", "MASSMEDIA_F", "MASSMEDIA_M",
> "HomeComputer", "HomeInternet")
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