Hi
Thanks for the code but where is Prop?
It is not a variable in germination data set so we do not know how you did the
computation.
My wild guess is, that your Prop do not follow logistic curve and therefore no
results from nlsList
Cheers
Petr
> -Original Message-
> From: R-help [
Hi
I did not see any response but what about
par(mfrow=c(2,2))
before plotting?
Cheers
Petr
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Elahe chalabi
> via R-help
> Sent: Monday, October 16, 2017 2:26 PM
> To: R-help Mailing List
> Subject: [
Answering my own question. It took a lot of trial and error, but the code
below will work. The trick is to do form the lis to plots, create the html
tag, and use renderUI() for that, and then in the UI.R part use htmlOutput()
to output the result.
-Roy
> library(shiny)
>
> # Define UI fo
Hi All:
This is really getting into the weeds, but I am hoping someone will have a
solution. I am trying to use dygrahs for R, within Shiny.
The situation arises when I am combining a number of dygraphs into one plot.
If I am just in an RNotebook, if you look at:
https://stackoverflow.com/q
Hi all,
I am trying to use nonlinear regression (nls) to analyze some seed germination
data, but am having problems with error codes.
The data that I have closely matches the germination dataset included in the
drc package.
Here is the head of the data
temp species start end germinated TotS
Dear R-help Listers,
The following two student competitions are of interests to the now many student
R package developers. I'd appreciate your help in spreading them.
#1. John M. Chambers Statistical Software Award 2018
The Statistical Computing Section of the American Statistical
Association
Dear David and Petr,
It worked and I think now I can modify the code little bit to fit my
requirement. Thank you so much for your help.
Thanks,
MW
On Wed, Oct 18, 2017 at 7:15 AM, David L Carlson wrote:
> Building on Petr's suggestion, you could modify his code to get all 10
> samples at once
I was able to reproduce the problem with this self-contained example. Maybe
it could be reproduced with an even smaller one ...
library(tidyquant) # Loads tidyverse, tidyquant, financial pkgs, xts/zoo
library(xts)
dtV <- as.Date("2017-01-01") + 1:100
locL <- list( foo=xts(rnorm(100), order.by=d
Building on Petr's suggestion, you could modify his code to get all 10 samples
at once in a compact format:
> Samples <- lapply(lll, function(x) replicate(10, sample(x, rep=TRUE)))
# Samples is a list containing 3 matrices, one for each group
# Each column gives the index (row) numbers for a part
Hi
maybe there is another more elegant solution but something like this
> idx <- 1:nrow(dat1)
> lll <- split(idx, dat1$group)
> dat1[unlist(lapply(lll, sample, rep=TRUE)),]
gives you selected rows.
You could use for cycle or save those data frames manually
Cheers
Petr
> -Original Message-
Hi R User,
I am new in R and trying to create tables with selecting rows randomly (but
with replacement) for each group but each group should have same number as
original. Is it possible to create it using the following example data set?
Your help is highly appreciated.
dat1<-structure(list(Regio
11 matches
Mail list logo