> On Sep 19, 2017, at 6:18 PM, Sherief Ghozy via R-help
> wrote:
>
> Greetings. I hope my message finds you well.
>
> I know this question may be silly for some experts like you but it's a very
> important matter for me so, sorry for that.
>
> I was trying to make a network meta-analysis usi
Greetings. I hope my message finds you well.
I know this question may be silly for some experts like you but it's a very
important matter for me so, sorry for that.
I was trying to make a network meta-analysis using R for the attached data set
which shows the association between breast feeding
Run this code
tree<-graph_from_literal(1-+2:3,3-+5,1-+4);
graph.bfs(tree,root=1, neimode="out",father=TRUE,order=TRUE,unreachable =
FALSE)
I do not understand why the father values will give NA 1 1 3 1 rather than NA
1 1 1 3
The reason I am doing this is to obtain the values(by vertex names) or
Here are some more examples:
library(Ryacas)
x <- Sym("x")
yacas("x:=2")
Eval(x*x)
## [1] 4
# vignette has similar example
y <- Sym("y")
Eval(Subst(y*y, y, 3))
## [1] 9
# demo("Ryacas-Function") has similar example to this
f <- function(z) {}
body(f) <- yacas(expression(z*z))[[1]]
f(4)
## [1] 1
Thanks for the response. Yes, I did study the vignette but did not
understand it fully. Anyway, I have tried once again now. I am happy to say
that I have got what I wanted.
library(Ryacas)
x <- Sym("x");U <- Sym("U");x0 <- Sym("x0");C <- Sym("C")
my_func <- function(x,U,x0,C) {
return (U/(1+exp
Hi Bert;
I sincerely appreciate for this. When I follow your way I have got
dimnames(dm)
[[1]]
NULL
I think this is the reason why the matrix is being converted into a column
vector.
Regards,
Greg
On Tue, Sep 19, 2017 at 11:32 AM, Bert Gunter
wrote:
> Works fine for me. What do you object t
Your description was confusing. You do not have row names that are non-numeric:
> str(dta)
'data.frame': 5 obs. of 5 variables:
$ Sub_Pathways: Factor w/ 79 levels "Acetylated_Peptides",..: 3 3 3 3 3
$ BMI_beta: num 0.2382 -0.313 0.1238 0.3035 -0.00982
$ SAT_beta: num -0.0241 -1.97
Works fine for me. What do you object to in the following?
Calling the above df "d",
> dm <- as.matrix(d)
> dm
Sub_PathwaysBMI_beta SAT_beta VAT_beta
1 "Alanine_and_Aspartate" " 0.23820" "-0.02409" " 0.94180"
2 "Alanine_and_Aspartate" "-0.31300" "-1.97510" "-2.22040"
3 "Alanine_
Dear all;
Thanks. Here are the dput results as Duncan suggested.
Regards,
Greg
structure(list(Sub_Pathways = structure(c(3L, 3L, 3L, 3L, 3L), .Label =
c("Acetylated_Peptides",
"Advanced_Glycation_End-product", "Alanine_and_Aspartate", "Aminosugar",
"Ascorbate_and_Aldarate", "Carnitine", "Cerami
Your claims are false -- or at least confused.
> d <- data.frame(a = I(letters[1:3]), b = 1:3)
## the I() is to prevent automatic conversion to factor
> d
a b
1 a 1
2 b 2
3 c 3
> dm <- as.matrix(d)
> dm
a b
[1,] "a" "1"
[2,] "b" "2"
[3,] "c" "3"
> dimnames(dm)
[[1]]
NULL
[[2]]
[1] "a"
Greg, I think you should stop using noquote, because it is doing something that
will not be useful to you for preparing your data for analysis.
Please follow Duncan's advice and provide us with a sample of your data. Also,
please set your email program to send plain text rather than HTML format
Hi Duncan and Bert;
I do appreciate for your replies. I just figured out that after x1=
noquotes(x) commend my 733*22 matrix returns into n*1 vector. Is there way
to keep this as matrix with the dimension of 733*22?
Regards,
Greg
On Tue, Sep 19, 2017 at 10:04 AM, Duncan Murdoch
wrote:
> On 1
On 19/09/2017 9:47 AM, greg holly wrote:
Hi all;
I have data at 734*22 dimensions with rows and columns names are
non-numeric.When I convert this data into matrix then all values show up
with quotes. Then when I use
x1= noquotes(x) to remove the quotes from the matrix then non-numeric row
names
Have you studied the "Introduction to Ryacas" vignette that come with the
package?
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Tue, Sep 19, 2
Hi all;
I have data at 734*22 dimensions with rows and columns names are
non-numeric.When I convert this data into matrix then all values show up
with quotes. Then when I use
x1= noquotes(x) to remove the quotes from the matrix then non-numeric row
names remain all other values in matrix disappear
Hello,
I believe that the easiest way is
curve(1/x, -5, 5)
Also, you're missing a '-' in y < 1/x, it should be y <- 1/x
Hope this helps,
Rui Barradas
Citando AbouEl-Makarim Aboueissa :
Dear All: good morning
I am trying to graph the function y=f(x)=1/x over the interval (-5,5). But
I am
Hi all,
I am trying to implement the following matlab code with Ryacas :
syms U x x0 C
d1=diff(U/(1+exp(-(x-x0)/C)),x);
pretty(d1)
d2=diff(U/(1+exp(-(x-x0)/C)),x,2);
pretty(d2)
solx2 = solve(d2 == 0, x, 'Real', true)
pretty(solx2)
slope2=subs(d1,solx2)
I have tried the following :
librar
It's always good to start a new session when you don't understand what's
wrong, because sometimes your code is correct, but you use old data
without knowing it :)
Ivan
--
Dr. Ivan Calandra
TraCEr, Laboratory for Traceology and Controlled Experiments
MONREPOS Archaeological Research Centre and
Dear Zeileis:
Thank you very much
abou
On Tue, Sep 19, 2017 at 4:13 AM, Achim Zeileis
wrote:
>
>
> On Tue, 19 Sep 2017, AbouEl-Makarim Aboueissa wrote:
>
> Dear All: good morning
>>
>> I am trying to graph the function y=f(x)=1/x over the interval (-5,5). But
>> I am getting an error message.
On Tue, 19 Sep 2017, AbouEl-Makarim Aboueissa wrote:
Dear All: good morning
I am trying to graph the function y=f(x)=1/x over the interval (-5,5). But
I am getting an error message. Please see below.
I am getting the error message: *Error in xy.coords(x, y, xlabel, ylabel,
log) : *
* 'x' an
Dear All: good morning
I am trying to graph the function y=f(x)=1/x over the interval (-5,5). But
I am getting an error message. Please see below.
I am getting the error message: *Error in xy.coords(x, y, xlabel, ylabel,
log) : *
* 'x' and 'y' lengths differ*
x
x <- seq(-5, 5, 0.01)
y < 1/x
Dear ALL,
I was trying to extract the data only for european region from this file
https://www.dropbox.com/s/xpo7zklcmtm3g5r/gfdl_preci.nc?dl=0
using these points (-10.375, 35.125), (43.375, 35.125), (-10.375, 71.375),
(43.375, 71.375). However, I am not sure how I can proceed further.
I have start
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