Hi,
I need help to simulate data to model pump's failure. Below is thought
process to simulate the data:
- For each Pump readings are captured via sensors each minute for period of
3 months. There are 10 pumps in total.
- The failure rate or occurrences of event in 3 months for each Pump is
defined
Hi,
I need to generate correlated (positive as well as negative) bivariate
exponential distribution with rate of 1/5 or any rate
I need some guidance here. Please help.
Regards,
Sunny
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> On Jun 15, 2017, at 3:05 PM, oussama bouldjedri
> wrote:
>
> Hi every one I am working on shiny app using bnlearn for Bayesian networks
> and using r studio I get a fatal error and when I use R GUI I get this error
>
> ** caught segfault ***
>
> address 0xfffc0fcd6248, cause 'memory no
Hi every one I am working on shiny app using bnlearn for Bayesian networks and
using r studio I get a fatal error and when I use R GUI I get this error
** caught segfault ***
address 0xfffc0fcd6248, cause 'memory not mapped' Traceback: 1:
.Call("mappred", node = node, fitted = fitted, data =
Did you perhaps accidentally include your response as a predictor?
> On Jun 15, 2017, at 12:48 PM, lily li wrote:
>
> Thanks for your replies. I tried the regression, but then got a NA value
> for the slope. And here is the error message:
> Coefficients: (1 not defined because of singularities)
David,
thanks for the response. In your response the quantile function (if I see
correctly) runs on the columns versus I need to run it on the rows, which is
an easy fix, but that is not exactly what I had in mind... essentially we can
remove t() from my original code to make "res" look like t
> On Jun 15, 2017, at 12:37 PM, Andras Farkas via R-help
> wrote:
>
> Dear All,
>
> we have:
>
> t<-seq(0,24,1)
> a<-10*exp(-0.05*t)
> b<-10*exp(-0.07*t)
> c<-10*exp(-0.1*t)
> d<-10*exp(-0.03*t)
> z<-data.frame(a,b,c,d)
>
> res<-t(apply(z, 1, quantile, probs=c(0.3)))
>
>
>
> my goa
Hi Persian,
While this is not a forum for Excel:
Right click on the alphabetic label at the top of the column
Select "Format Cells"
Select the "Font" tab
Pick your font
I will leave it to others to deliver sermons about the moral dangers
of using Excel.
Jim
On Thu, Jun 15, 2017 at 10:33 PM, Per
> On Jun 15, 2017, at 9:53 AM, Alice Domalik wrote:
>
> Hi List,
>
> I'm having some trouble finding documentation for the package glmmTMB.
I had no trouble finding documentation with the search strategy copied from
your sentence: "documentation for the package glmmTMB."
Can you describe w
You really have to show what you did to get the result you showed. E.g.,
something like the following:
> d <- data.frame(x=1:7, y=c(7,4,2,3,6,8,7))
> fit <- lm( y~cos(x), data=d)
> coef(fit)
(Intercept) cos(x)
5.0791903.022805
> sfit <- summary(fit)
> sfit$r.squared
[1] 0.9915548
> wi
Rather than just posting your error message, it helps immensely to post the
code that produced the error--indeed with some small sample data that
reproduces the problem.
x <- rnorm(40)
y <- 0.6 * x + rnorm(40, sd = 0.3)
plot(y ~ x)
model <- lm(y ~ cos(x))
summary(model)
plot(y ~ cos(x))
abline(mod
Thanks for your replies. I tried the regression, but then got a NA value
for the slope. And here is the error message:
Coefficients: (1 not defined because of singularities)
On Thu, Jun 15, 2017 at 12:20 AM, PIKAL Petr wrote:
> Hi
>
> But X can be some function like - sin, cos, log, exp...
>
>
Dear All,
we have:
t<-seq(0,24,1)
a<-10*exp(-0.05*t)
b<-10*exp(-0.07*t)
c<-10*exp(-0.1*t)
d<-10*exp(-0.03*t)
z<-data.frame(a,b,c,d)
res<-t(apply(z, 1, quantile, probs=c(0.3)))
my goal is to do a 'reverse" of the function here that produces "res" on a data
frame, ie: to get the answer
Hello,
I have a vector of values with significant autocorrelation, and I want to
calculate an unbiased standard deviation that adjusts for the autocorrelation.
The formula linked below purports to provide what I want:
https://en.wikipedia.org/wiki/Unbiased_estimation_of_standard_deviation#Effect
Hi List,
I'm having some trouble finding documentation for the package glmmTMB.
I would like to fit a zero-truncated poisson, what do I need to specify in
"family = " for this distribution?
Thanks! Alice
[[alternative HTML version deleted]]
_
I think look at the manual
Is.null(mylist[[1]])
Will work
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of ce
Sent: 15 June 2017 16:33
To: r-help@r-project.org
Subject: [R] is.null(mylist[1]) and is.null(mylist$a) returns different values
Hi
I have a l
Hello,
You have to be aware that mylist[1] and mylist[[1]] are different things.
class(mylist[1])
[1] "list"
class(mylist[[1]])
[1] "NULL"
Apparently you want/need the latter:
is.null(mylist[[1]])
[1] TRUE
Hope this helps,
Rui Barradas
Em 15-06-2017 16:33, ce escreveu:
Hi
I have a list
The suggestion to post on R-sig-ME was a good one.
The problem turned out to be a bug in lmer parsing, which is now fixed.
S Ellison writes:
> > Is there a difference between I(x*y) and I(y*x) ?
> > I have a call to lmer that results in this complaint:
> > Error in is.alpha2.subordinate * ~z
Hi all!
I need an example/reference to show me how to change the font of a
certain column in an existing .xlsx document. Thank you in advance
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> On Jun 15, 2017, at 1:35 AM, jean-philippe
> wrote:
>
> hi david
>
> Thank you very much for the hack of draw.circle that you proposed me.
> I don't understand some part of the code, why do you pass radius as a vector
> in the function (if I understand well the purpose of the for loop) ? Al
By the way, NULL is not a "null list", it has class (and type and mode)
"NULL" not "list". "NULL" is an odd class, in that it can have only one
instance and hence can never have any attributes. "list" objects, like
other vector objects, may have length zero, but such objects are not the
same as
Thank you all , very informative, never thought of doing a str( mylist[1] )
-Original Message-
From: "Jeff Newmiller" [jdnew...@dcn.davis.ca.us]
Date: 06/15/2017 11:56 AM
To: r-help@r-project.org, "Huzefa Khalil" , "ce"
Subject: Re: [R] is.null(mylist[1]) and is.null(mylist$a) returns
I find that the str function is more helpful for understanding the difference
between a null list and a list containing a null list than the implicit print
function call that the interpreter invokes when you enter an expression at the
console.
str( mylist[1] )
--
Sent from my phone. Please e
Hi,
Try
> is.null(mylist[[1]])
[1] TRUE
Notice the double square brackets.
From: ?`[`
"The most important distinction between [, [[ and $ is that the [ can
select more than one element whereas the other two select a single
element."
On Thu, Jun 15, 2017 at 11:33 AM, ce wrote:
> Hi
>
> I have
Hi
I have a list :
mylist <- list( a = NULL, b = 1, c = 2 )
> mylist[1]
$a
NULL
> is.null(mylist[1])
[1] FALSE
> is.null(mylist$a)
[1] TRUE
why? I need to use mylist[1]
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https://st
> Is there a difference between I(x*y) and I(y*x) ?
> I have a call to lmer that results in this complaint:
> Error in is.alpha2.subordinate * ~z.min.co.res :
A reproducible example would help ...
In the absence of that, check the classes of the two variables in I() and, if
you run the produc
hi david
Thank you very much for the hack of draw.circle that you proposed me.
I don't understand some part of the code, why do you pass radius as a
vector in the function (if I understand well the purpose of the for
loop) ? Also what is ymult?
If I set the radius to the value 0.85 as I wante
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