Taking this question further.
If I use a complex number or a numeric as an operand in logical
operations, to me it APPEARS that these two types are first coerced to
LOGICAL internally and then THIS logical output is further used as the
operand.
For eg.
> x <- 4+5i; c(x & F, x & T, x | F, x | T)
[
Any answer?!
On Friday, May 19, 2017 6:33 AM, Elahe chalabi via R-help
wrote:
Hi all,
I'm running train function from caret package on my data set patientdata:
model=train(type~., data=patientdata, method="lvq", preProcess="scale",
trControl=control)
and I get this error:
Er
I tried using latest R-3-4.0. ./configure works but when I type make it does
not work.
From: William Dunlap [mailto:wdun...@tibco.com]
Sent: Friday, May 19, 2017 4:27 PM
To: Pramod Anugu
Cc: r-help@R-project.org
Subject: [EXTERNAL] Re: [R] had non-zero exit status
Try using a more recent versio
Try using a more recent version of R - 3.4.0 is the current version and
3.1.0 is considered pretty old now. 'R_DoubleColonSymbol' is in
RHOME/include/Rinternals.h in R-3.3.0 but not in R-2.15.0. I don't know
exactly when it was added.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Fri, May 19,
Hi , When installing a tidyr package. I get an error message to install rlang
package and I try to install rlang I get
"installation of package 'rlang' had non-zero exit status"
Please advise.
Ran
install.packages("tidyr", dependencies=TRUE)
getting below error message. Please advise. R version
This is a minor problem with the print method for "survdiff" objects. It
acts like it computes the p-value with
1 - pchisq( chisq, df)
instead of
pchisq( chisq, df, lower.tail = FALSE)
The former will give zero when the latter gives a number less than about
10^-16.
Most people would accept
Thanks Jeff. I will try elsewhere.
Patrick Casimir, PhD
Health Analytics, Data Science, Big Data Expert & Independent Consultant
C: 954.614.1178
From: Jeff Newmiller
Sent: Friday, May 19, 2017 11:04:22 AM
To: r-help@r-project.org; Patrick Casimir; r-help@r-proje
Thank's Thierry, but as i mentioned, it is not a constant depending only of
the data, since with the same observed trait:
the difference (between asreml and R packages) is equal to 29.40 in the model
with a fixed effect (Type)
and the difference is equal to 32.16 in the model with only mu.
Considering the deafening silence after three repeats, one explanation could be
that you are asking the wrong group of people. It is also possible that your
failure to follow the Posting Guide with regard to using plain text email and a
reproducible example [1][2] means that readers who are not
Dear Members & Experts,
Since the Dictionary () function is no longer available with the tm package.
How do I use other functions to do the same as below? I want to capture a list
of specific terms from a corpus. By example, if my corpus has 102 files. I want
to see a list with occurrences of
On 10/05/2017 6:46 AM, Keith Jewell wrote:
Thanks for confirming that I wasn't being stupid :-}
When using default=pathlong I get the _correct_ starting directory...
(M:\test\Averyveryveryveryverylongfoldername\Averyveryveryveryverylongfoldername\Averyveryveryveryverylongfoldername)
... both in
Hi all,
I'm running train function from caret package on my data set patientdata:
model=train(type~., data=patientdata, method="lvq", preProcess="scale",
trControl=control)
and I get this error:
Error in comp(expr, env = envir, options = list(suppressUndefined = TRUE))
:
could n
Hi,
Did somebody know why asreml does not provide the same REML loglikehood as
coxme, lme4 or lmne.
Here is a simple example showing the differences:
###
library(lme4)
library(coxme)
library(asreml)
library(nlme)
data(ergo
[I unadvertently sent my reply below to Jeremie, instead of R-help.
Also, I havve had an additional thought which may clarify things
for R users].
[Original reply]:
The point about this is that (as Rolf wrote) FALSE & (anything)
is FALSE, provided logical NA is either TRUE ot FALSE but,
because the
FALSE & FALSE -> FALSE
FALSE & TRUE -> FALSE
Why do you need to know what the second value is? It doesn't matter what it
is... the answer is FALSE.
--
Sent from my phone. Please excuse my brevity.
On May 19, 2017 5:24:06 AM PDT, "Jérémie Juste" wrote:
>My apologies if I was not clear enough,
On 19/05/2017 8:48 AM, S Ellison wrote:
SQL, for example, generally takes the view that any
expression involving 'missing' is 'missing'.
Well, then SQL gets it wrong.
Well, that's a view. But paraphrasing an R Turner from a few lines away in the
same email:
One should be very, very circum
> On 19 May 2017, at 14:24 , Jérémie Juste wrote:
>
> My apologies if I was not clear enough,
>
> TRUE & NA could be either TRUE or FALSE and consequently is NA.
> why is FALSE & NA = FALSE? NA could be TRUE or FALSE, so FALSE & NA
> should be NA?
>
At the risk of flogging a dead horse:
F
> > SQL, for example, generally takes the view that any
> > expression involving 'missing' is 'missing'.
>
> Well, then SQL gets it wrong.
Well, that's a view. But paraphrasing an R Turner from a few lines away in the
same email:
> One should be very, very circumspect about presuming to know
My apologies if I was not clear enough,
TRUE & NA could be either TRUE or FALSE and consequently is NA.
why is FALSE & NA = FALSE? NA could be TRUE or FALSE, so FALSE & NA
should be NA?
On Fri, May 19, 2017 at 2:13 PM, Rolf Turner
wrote:
> On 20/05/17 00:01, Jérémie Juste wrote:
>
>> Hello,
On 20/05/17 00:01, Jérémie Juste wrote:
Hello,
Rolf said,
TRUE & FALSE is FALSE but TRUE & TRUE is TRUE, so TRUE & NA could be
either TRUE or FALSE and consequently is NA.
OTOH FALSE & (anything) is FALSE so FALSE & NA is FALSE.
According to this logic why is
FALSE & NA
[1] FALSE
Huh
On 19/05/17 23:38, S Ellison wrote:
TRUE & FALSE is FALSE but TRUE & TRUE is TRUE, so TRUE & NA could be
either TRUE or FALSE and consequently is NA.
OTOH FALSE & (anything) is FALSE so FALSE & NA is FALSE.
As I said *think* about it; don't just go with your immediate knee-jerk
(simplistic) rea
Hello,
Rolf said,
TRUE & FALSE is FALSE but TRUE & TRUE is TRUE, so TRUE & NA could be
either TRUE or FALSE and consequently is NA.
OTOH FALSE & (anything) is FALSE so FALSE & NA is FALSE.
According to this logic why is
> FALSE & NA
>
[1] FALSE
?
Best regards,
Jeremie
On Fri, May 19, 2017
> TRUE & FALSE is FALSE but TRUE & TRUE is TRUE, so TRUE & NA could be
> either TRUE or FALSE and consequently is NA.
>
> OTOH FALSE & (anything) is FALSE so FALSE & NA is FALSE.
>
> As I said *think* about it; don't just go with your immediate knee-jerk
> (simplistic) reaction.
Hmm... not sure t
On 19/05/17 21:48, Ramnik Bansal wrote:
Hi,
I need to understand the inconsistent behaviour of & and I operators when
used with NA.
The code below explains this inconsistency
TRUE & NA
[1] NA
FALSE & NA
[1] FALSE
TRUE & NA
[1] NA
FALSE | NA
[1] NA
TRUE | NA
[1] TRUE
TRUE == N
& -> AND -> results only TRUE if both inputs are TRUE. Hence: FALSE AND
unknown = FALSE, TRUE AND unknown = unknown
| -> OR -> results in TRUE as soon as one of the inputs is TRUE. Hence FASE
or unknown = unknown, TRUE or unknown = TRUE
TRUE == NA and FALSE == NA compares TRUE/FALSE against unknown
Hi,
I need to understand the inconsistent behaviour of & and I operators when
used with NA.
The code below explains this inconsistency
> TRUE & NA
[1] NA
> FALSE & NA
[1] FALSE
> TRUE & NA
[1] NA
> FALSE | NA
[1] NA
> TRUE | NA
[1] TRUE
> TRUE == NA
[1] NA
> FALSE == NA
[1] NA
[[a
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