On 5/12/17 4:55 PM, Ranjan Maitra wrote:
Hi,
Is it possible to display double dot (umlaut) over a character such as would be
possible using \ddot x in LaTeX? I can do this using tikzDevice but I wanted
something simpler to point to.
Here is an example of what I would like to do, but it is not
Hi,
Is it possible to display double dot (umlaut) over a character such as would be
possible using \ddot x in LaTeX? I can do this using tikzDevice but I wanted
something simpler to point to.
Here is an example of what I would like to do, but it is not quite there:
require(ggplot2)
data<-as.d
On 12/05/2017 4:21 PM, Elahe chalabi via R-help wrote:
Hi all,
I'm using Rstudio 64 bit version3.2.5 and I faced a problem installing caret
package,the error is :
Loading required package: lattice
Loading required package: ggplot2
Error : object ‘sigma’ is not exported by 'namespace:stats'
Err
> On May 12, 2017, at 1:21 PM, Elahe chalabi via R-help
> wrote:
>
> Hi all,
>
> I'm using Rstudio 64 bit version3.2.5
I'm guessing that means using R 3.2.5, at least if RStudio is keeping its
different os versions numering in sync. I'm on R studio 1.0.136 and I don't
think I'm that out of
Hi all,
I'm using Rstudio 64 bit version3.2.5 and I faced a problem installing caret
package,the error is :
Loading required package: lattice
Loading required package: ggplot2
Error : object ‘sigma’ is not exported by 'namespace:stats'
Error: package or namespace load failed for ‘caret’
how sho
> On 12 May 2017, at 16:40 , Tobias Christoph wrote:
>
> Hey guys,
>
> thanks a lot for your tips. The regression is finally running. As you
> said, I had to integrate the column "year" in the function "time" in R.
>
> So I used the following formula: *plm(log(revenue) ~ log(supply) +
> fact
> On May 12, 2017, at 7:40 AM, Tobias Christoph
> wrote:
>
> Hey guys,
>
> thanks a lot for your tips. The regression is finally running. As you
> said, I had to integrate the column "year" in the function "time" in R.
>
> So I used the following formula: *plm(log(revenue) ~ log(supply) +
>
Jim is generous enough that he might do this, but such assistance is not
sustainable. Fortunately, you can type a ? in front of the name of a function
and read about what goes in and what comes out. You can also type expressions
like x[2] or which(matches) right before you execute the line of co
On 05/12/2017 06:53 PM, David L Carlson wrote:
Actually, not using apply() would be faster and simpler
cor(t(compare_data), t(test_data))
Worked just as I wanted, thanks!
I first reshaped the data frames, then I didn't even need the t()
David C
-Original Message-
From: R-help [mail
Dear Jim..,
Many thanks for your answer.
As I'm a new R user, could you please provide a short explanation
about what each line of the following does ?
findMatches<-function(x,sep=",") {
matchval<-NA
x1bits<-unlist(strsplit(x[1],sep))
x2bits<-unlist(strsplit(x[2],sep))
matches<-x1bits %i
Well, you'll have to find the boundaries in some electronic GIS format such as
a shapefile (though there are other options).
I don't know where to find such a thing. Your chances of finding someone who
does know are greater on the R-sig-geo mailing list, so I'd suggest asking
there.
You may al
Hello,
I have never used plm but the standard way of adding a quadratic term is
I(time(year)^2)
Hope this helps,
Rui Barradas
Em 12-05-2017 15:40, Tobias Christoph escreveu:
Hey guys,
thanks a lot for your tips. The regression is finally running. As you
said, I had to integrate the column "
Hi again,
I am trying to draw a World map which is divided into 6 Economic
regions as available in below link
http://www.worldbank.org/en/about/annual-report/regions
I am aware of various R ways to draw World map based on Countries like
one available in
http://stackoverflow.com/questions/241368
Thanks for your reply. What I exactly have is a data frame with rows containing
words which have been used in each speech and columns containing frequency of
these words, I have an extra row showing the type of the speech whether it was
from a control group or Alzheimer group. Then I create a
Actually, not using apply() would be faster and simpler
cor(t(compare_data), t(test_data))
David C
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of David L Carlson
Sent: Friday, May 12, 2017 10:48 AM
To: Ismail SEZEN ; Micha Silver
Cc: R-help@r-project.
Actually, r is a vector, not an index value. You need
apply(compare_data, 1, function(r) cor(r, t(test_data)))
-
David L Carlson
Department of Anthropology
Texas A&M University
College Station, TX 77840-4352
-Original Message-
From: R-help [mailto:r-
> On 12 May 2017, at 17:57, Micha Silver wrote:
>
> I have two data.frames, one with a single row of 31 columns, and the second
> with 269 rows and the same 31 columns.
> > dim(compare_data)
> [1] 269 31
> > dim(test_data)
> [1] 1 31
>
> I want to apply cor() between the one row of 'test_dat
I have two data.frames, one with a single row of 31 columns, and the
second with 269 rows and the same 31 columns.
> dim(compare_data)
[1] 269 31
> dim(test_data)
[1] 1 31
I want to apply cor() between the one row of 'test_data', and each row
of the 'compare_data' .
I tried 'apply' but I get
Hey guys,
thanks a lot for your tips. The regression is finally running. As you
said, I had to integrate the column "year" in the function "time" in R.
So I used the following formula: *plm(log(revenue) ~ log(supply) +
factor(town)*time(year), data=R_Test_log_Neu)*
So I have now sucessfully ad
Thanks a lot Duncan, Jim and Marc!
2017-05-11 22:59 GMT-03:00 Marc Schwartz :
>
> Bingo.
>
> The 'inset' argument is what I was missing. That allows this to be done
> with one step, rather than the two that I had.
>
> Thanks Duncan.
>
> Mar
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_
> On 12 May 2017, at 15:30, Elahe chalabi wrote:
>
>
>
> Thanks for your reply. What I exactly have is a data frame with rows
> containing words which have been used in each speech and columns containing
> frequency of these words, I have an extra row showing the type of the speech
> whethe
Please take this thread elsewhere(e.g. Stats.stackexchange.com) as it is
largely about statistics and is therefore offtopic here (this list is about
R programming).
Cheers,
Bert
On May 12, 2017 1:21 AM, "Margot Neyret" wrote:
Hi Jim,
Sorry if my question was not clear. I will try to explain a
Hi Margot,
Very messy, like nature. One way is to do tests with dummy variables
that compare:
beans+anything vs anything without beans
maize+anything vs anything without maize
pumpkin+anything vs anything without pumpkin
Then if you find that the "beans" comparison has the strongest effect,
perha
Hi Jim,
Sorry if my question was not clear. I will try to explain again…
I have one response variable Y, let’s say vegetation cover. Then I have my
explanatory variable, let’s call it Crop. In my field I can have either Maize
(m), Bean (b), Pumpkin (p) or mixtures : m+b, m+p, b+p, m+b+p. I also
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