> On Oct 31, 2016, at 5:29 PM, Nordlund, Dan (DSHS/RDA)
> wrote:
>
> I don't know what version Linux or other OS you are using, but have you
> installed the bzip2 development package? It would be named something like
> libbz2-dev (that is what it is in Ubuntu, I believe).
This question has
Hello R Users:
I am using the survey package in R for modeling with complex survey data. I am
trying to reset the baseline level of certain predictor variables being used in
a logistic regression without success. The following is a reproducible example:
library(RCurl)
library(survey)
data <-
I don't know what version Linux or other OS you are using, but have you
installed the bzip2 development package? It would be named something like
libbz2-dev (that is what it is in Ubuntu, I believe).
Dan
Daniel Nordlund, PhD
Research and Data Analysis Division
Services & Enterprise Support Adm
Jeff,
Thanks for the response. You are right of course. I went back and reread the
help page. I guess I just glossed over the 'x is numeric' statement because
the default FUN was the mean, and seq_along doesn't care about type. I should
know better than to disregard what I read in the help p
I am not able to compile R 3.3,
configure halting with:
--
checking for BZ2_bzlibVersion in -lbz2... yes
checking bzlib.h usability... yes
checking bzlib.h presence... yes
checking for bzlib.h... yes
checking if bzip2 version >= 1.0.6... no
checking w
hi everyone,
how can I store result of meta analysis by Rstudio,I can not save the
result of metaseq and metaDE package,I want to use sink to store the output
in a file.
in metaseq package there are several objects to store:(I copy example of
this package)
> head(F$Upper)
1/2-SBSRNA4 A1BG A1BG-AS
The help page describes the first argument x as a numeric... it is not designed
to accept character, so the fact that you get anything even close to right is
just a bonus.
As the doctor says, "if it hurts, don't do that".
ave( rep( 1, length( v ), v, FUN=seq_along )
--
Sent from my phone. Plea
Given the following R statements
v <- c('a', 'a', 'a', 'b', 'b', 'b', 'c', 'c', 'c', 'c')
ave(v, list(v), FUN=seq_along)
[1] "1" "2" "3" "1" "2" "3" "1" "2" "3" "4"
I was expecting to get a numeric vector back. I apparently have missed
something in the documentation. If vector v is charact
You may get a reply here, but this post belongs on a statistics list
like stats.stackexchange.com, not r-help, which is concerned about R
programming issues rather than statistical methodology.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and s
Thank you. I understand that it's best to use the current versions of R
packages. Neither the current version of polycor nor the current version of
mvtnorm would install when I used the most recent version of R, 3.3.1:
> install.packages("polycor", repos="http://R-Forge.R-project.org";)
Warning
"any advice" is to use the latest R and packages. Unfortunately the number of
things that can go wrong trying to keep an old version of R working is too
extensive for this list to support (per Posting Guide).
If you wish to proceed without support then by all means download any older
versions o
Did you mean 'tolower' instead of 'to lower' in your example?
Or is there a similarly named function that converts the levels
of a factor to lower case instead of converting the factor to
a character vector and then lower-casing that?
> d %>% dplyr::mutate_if(is.factor, tolower)
NumF1 F2
1
Use tolower on the levels of the factor columns. E.g.,
> d <- data.frame(Num=1:3, F1=c("One","Two","Three"), F2=c("A","B","a"))
> str(d)
'data.frame': 3 obs. of 3 variables:
$ Num: int 1 2 3
$ F1 : Factor w/ 3 levels "One","Three",..: 1 3 2
$ F2 : Factor w/ 3 levels "a","A","B": 2 3 1
> fo
This looks like homework and r-help has a policy of not providing answers for
homework. But first you need to research what happens when you convert a data
frame to a matrix.
Also in your loop, i is a numeric value between 1 and the length of x:
What is x (what class)?
What is the length of an
I have been trying to install the R polycor package without any success. I want
to install version 0.7-8 because it is supposed to work with R version 3.1.0,
which I have to use to run an R plug-in for SPSS. But I get a message that
polycor is not available for R version 3.1.0:
> install.packa
Friends,
Matched pairs studies are well documented, but what happens if we were to alter
the manner in which events were paired to one another. Say we change the order
of our data and pair without replacement, so that event 1 may pair with event
23 in one instance, but also event 36 or 102 in
Hi everybody,
I’m new to R and i’m trying to learn fundamentals. I’m facing a small problem
for which i can’t find a solution online.
What i want to do: write a function to lower case for all the columns in my
data.frame if they respect a condition (class = factor)
This code works, but for all
Aye, Bill. I figured others wld include a `vapply()` example (didn't
want to "hog" the answer :-).
I went with bland `sapply()` as an alternative since I made an
assumption Thomas (like the large % of R users I've come in contact
with - albeit a biased sample) aren't really familiar with `vapply()
vapply(buylist, slot, "reqstock", FUN.VALUE=0.0)
is closer in spirit than sapply() to purrr::map_dbl() - FUN.VALUE
gives the expected type and size of f's output. vapply() is usually
quicker than sapply(), uses less memory, gives the right results
when given a vector of length 0, and gives an erro
But if all the OP want is a count, wouldn't
sum(sapply(buylist, slot, "reqstock") > 100)
suffice?
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Mon
which(purrr::map_dbl(buylist, slot, "reqstock") > 100)
or
which(sapply(buylist, slot, "reqstock") > 100)
ought to do the trick.
On Mon, Oct 31, 2016 at 10:09 AM, Thomas Chesney
wrote:
> I have the following object
>
> setClass("buyer",
> representation(
> reqstock="numeric",
> buyout="
I have the following object
setClass("buyer",
representation(
reqstock="numeric",
buyout="numeric"),
)
nBuy <- 5
#Set buyer parameters here
buylist <- list()
for (i in 1:nBuy){
buylist[[i]] <- new("buyer")
buylist[[i]]@reqstock <- sample(c(50:200),1)
}
and want to count the number of objects in
Hi
Another approach is to use function like following
fff<-function(x, ...) {
temp <- x[which(x[,"day"]==1),]
temp$day <- 361
x <- rbind(x, temp)
x[order(x$site, x$day),]
}
fff(dat)
Cheers
Petr
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of jim
>
try this:
> dat<-structure(list(site = c(1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2,
+ 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2), day = c(1, 31, 61, 91, 121,
+ 151, 181, 211, 241, 271, 301, 331, 1, 31, 61, 91, 121, 151, 181,
+ 211, 241, 271, 301, 331), temp = c(8.3, 10.3, 9.4, 6.1, 3, 1.3,
+ 1, 0.8, 1, 1.4, 2.7
The build system rolled up R-3.3.2.tar.gz (codename "Sincere Pumpkin Patch")
this morning.
The list below details the changes in this release.
You can get the source code from
http://cran.r-project.org/src/base/R-3/R-3.3.2.tar.gz
or wait for it to be mirrored at a CRAN site nearer to you.
Bin
Hi, everyone
I have a model like.
cpue=catch*1000/Hook
glmmodel=glm(log(cpue)~yy+qq+cc+pp, family=gaussian)
and I want to estimate yy, qq, cc, pp effect and CI
A senior scientist suggested to use
model <- cbind(yhat=predict.glm(glmmodel, se.fit=T), DATA
A) Please post in plain text so your code doesn't get mangled by HTML.
B) Please provide a reproducible example. [1] [2]
C) RStudio is probably not the problem, but if it is then this is the wrong
place to ask about that (see the RStudio website for help with that software).
Simply try your cod
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