This mailing list is not meant for homework help, you should ask your
instructor to clarify the assignment.
Best,
Ista
On Feb 14, 2016 9:24 PM, "HEATHER MICHEL via R-help"
wrote:
>
> As a follow-up to my request for help this morning, I have watched
tutorials on R all afternoon. Many topics come
As a follow-up to my request for help this morning, I have watched tutorials on
R all afternoon. Many topics come close to my problem, but none specifically
address my situation where "specdata" is not a text file but a list of small
files in a folder.I found a command that should be more right
Also ... it doesn't make sense to create a directory that already exists in the
first place. Are you perhaps thinking about setting the working directory to
"specdata"? That would be the setwd() command.
B.
On Feb 14, 2016, at 6:52 PM, Duncan Murdoch wrote:
> On 14/02/2016 2:40 PM, HEATHER M
dear all,
I have a set of data that can be defined as bimodal; would be possible
to define a cut-off to split it? my mathematical/statistical knowledge
is limited, my apologies, thus i am not sure what kind of area this
problem belongs to; at the moment I can fit -- thanks to previous help
from the
On 14/02/2016 2:40 PM, HEATHER MICHEL via R-help wrote:
I am trying to complete a homework assignment, but I know very little about R.The assignment says,
"For this programming assignment you will need to unzip this file and create the directory
'specdata".I unzipped the file on my desktop, and
Hi John and Peter,
Thanks for your reply. I found that fitdistcens, is a good approach. I did that
for lognormal, exp ,and other distributions. Values for lnorm from SAS and R
were close, but slightly different. At the moment, my main concern is finding
the estimated lambda value for poisson for
I am trying to complete a homework assignment, but I know very little about
R.The assignment says, "For this programming assignment you will need to unzip
this file and create the directory 'specdata".I unzipped the file on my
desktop, and my computer automatically created a new folder which I r
I want to run a hierarchical Bayes regression model using this runiregGibbs
function. My data is like the following:
y userid Proximity TimeKnowledge Test Purchase
Service1 8 1 422 132
7 1 222 2
No specific experience of the package you are using, but you have
> as.character(nwCorp1)
This does nothing to nwCorp1; it just returns a character version of it to the
console. If it was not the right kind of object you can expect later commands
to throw errors.
Perhaps you meant
nwCorp1 <- a
You can do things like
while ( !is.nan( r <- randomFunction(x) )) {}
# r will be a non-NaN value of randomFunction(x) now
or
for(i in seq_len(1000)) {
if (!is.nan( r <- randomFunction(x))) {
break
}
if (i == 1000) {
stop("no good values of randomFuncti
Hi all,
I'm trying to write 2 functions(as a part of a larger code) to evaluate a
certain equation. The function is :
X= c (0.3893094 2.0962311 2.6007558 3.0761810 3.3246947 3.3917976
4.1981546 6.8826140 12.3128013 15.5588470)
R=c (0 1 0 0 0 1 1 1 0 1)
alpha.update=function(X, R, alpha.c
Thank you, kind sir, you are correct but I was too rushed to write more as the
bread needed to be taken out of the oven.
John Kane
Kingston ON Canada
> -Original Message-
> From: pda...@gmail.com
> Sent: Sun, 14 Feb 2016 15:37:22 +0100
> To: jrkrid...@inbox.com
> Subject: Re: [R] Esti
Fortune candidate :-)
However, the more scientific approach would be to ask for evidence to be
scrutinized, acknowledging that R might be fallible, however unlikely that may
seem.
Also, there is always the possibility that there are two answers because the
question is not the same.
-pd
> On
> By the way, is there anything for lognormal?I think fitdistcens is not
> good for this purpose as it gives me different result compared to SAS
The general assumption is that if Excel or any other spreadsheet gives a result
that is different from R then R will be correct.
Generally with SAS it
14 matches
Mail list logo
