On 23.01.2016 01:21, Robert Sherry wrote:
In R, I run the following commands:
df = data.frame( x=runif(10), y=runif(10) )
df2 = df[order(x),]
You use another x from your workspace, you actually want to
df2 = df[order(df[,"x"]),]
Best,
Uwe Ligges
The first, as I would expect
In R, I run the following commands:
df = data.frame( x=runif(10), y=runif(10) )
df2 = df[order(x),]
The first, as I would expect, creates a data frame with two columns and
10 rows. I expect the second to sort the data based upon
the columns x and produce a new data frame, df2, with the s
Look at the choroplethr package.
On Fri, Jan 22, 2016 at 5:31 PM, Amoy Yang wrote:
> Let me just make this case simple and quick to address what I need.
>
> Giving a data-file that includes tow columns: zip5 and population. How do I
> put pop (colored with different segments) by zips (with bounda
Let me just make this case simple and quick to address what I need.
Giving a data-file that includes tow columns: zip5 and population. How do I put
pop (colored with different segments) by zips (with boundary) on the USA map
with R?
Amoy
On Friday, January 22, 2016 12:45 PM, David Winsemius
Using column names where you used column numbers would work:
example <- data.frame(
check.names = FALSE,
Nuclei = c(133L, 96L, 62L, 60L),
`Positive Nuclei` = c(96L, 70L, 52L, 50L),
Slide = factor(c("A1", "A1", "A2", "A2"), levels = c("A1", "A2")))
aggregate(example["Nuclei"], by=ex
Hello,
Maybe something like the following.
temp2 <- cbind(temp[[3]][, 1], temp[[3]][, 2])
str(temp2)
Hope this helps,
Rui Barradas
Citando Jun Shen :
> Dear list,
>
> Say I have some quantile operation like this
>
> data.frame(ID=rep(1:10,each=10),CONC=runif(100)) -> test
>
> lapply(c('mean
Dear list,
Say I have some quantile operation like this
data.frame(ID=rep(1:10,each=10),CONC=runif(100)) -> test
lapply(c('mean','sd','quantile'), function(x)
aggregate(test['CONC'],by=test['ID'],FUN=x)) -> temp
The output temp is a list of three elements. I would like to merge the
three elemen
I'd like to allow users to edit data in tcltk tables and to use vcmd to
validate data entry, e.g., not allowing non-numbers to be entered in
numeric cells and not allowing '\n' to be entered in text cells.
The problem is that I can't figure out how to "see" their data entry before
it is entered, a
So that's how that works! Thanks.
On Fri, Jan 22, 2016 at 1:32 PM, Joe Ceradini wrote:
> Does this do what you want?
>
> aggregate(Nuclei ~ Slide, example, sum)
>
> On Fri, Jan 22, 2016 at 12:20 PM, Ed Siefker wrote:
>>
>> Aggregate does the right thing with column names when passing it
>> nume
Good pointers, although R bindings document is not quite getting into the
really messy bits.
I think Daniel may be at a point where he needs to study the code snippets that
he has got to work and figure out why and how they work. The help(TclInterface)
page is the most definitive documentation
Thanks, Adrian...the discussions about R bindings to Tcl and Tk look very
helpful!
-Dan
On Fri, Jan 22, 2016 at 2:49 AM, Adrian Waddell
wrote:
> I have written some content about the R bindings to Tcl and Tk:
>
> http://waddella.github.io/loon/learn_R_tcltk.html
>
> And the pack geometry manag
Does this do what you want?
aggregate(Nuclei ~ Slide, example, sum)
On Fri, Jan 22, 2016 at 12:20 PM, Ed Siefker wrote:
> Aggregate does the right thing with column names when passing it
> numerical coordinates.
> Given a dataframe like this:
>
> Nuclei Positive Nuclei Slide
> 1133
On Fri, Jan 22, 2016 at 01:20:59PM -0600, Ed Siefker wrote:
> Aggregate does the right thing with column names when passing it
> numerical coordinates.
> Given a dataframe like this:
>
> Nuclei Positive Nuclei Slide
> 1133 96A1
> 2 96 70A1
> 3 62
Aggregate does the right thing with column names when passing it
numerical coordinates.
Given a dataframe like this:
Nuclei Positive Nuclei Slide
1133 96A1
2 96 70A1
3 62 52A2
4 60 50A2
I can call 'aggregate' li
There are ways, but most likely you will not be satisfied with such a monster.
Try the maptools package or the Analysis of Spatial Data Task View [1].
[1] https://cran.r-project.org/web/views/Spatial.html
--
Sent from my phone. Please excuse my brevity.
On January 22, 2016 1:18:45 AM PST, Alai
> On Jan 22, 2016, at 9:24 AM, Amoy Yang via R-help
> wrote:
>
> This is the results that addresses David's advice.
>> library(maptools)
>> library(maps)
>> state.map <- readShapeSpatial("maps/st24_d00.shp")
> Error in getinfo.shape(fn) : Error opening SHP file
>> # David question: What does li
I see. Thanks!
2016-01-22 10:57 GMT-05:00 Rmh :
> FAQ 7.31
>
> in this case subtract the two numbers and see that
> they differ by about 1e-16
>
> Sent from my iPhone
>
> > On Jan 22, 2016, at 10:46, li li wrote:
> >
> > Hi all,
> > I encountered the following strange phenomenon.
> > For some r
> On Jan 22, 2016, at 7:01 AM, mara.pfleide...@uni-ulm.de wrote:
>
> Hi all,
>
> I am dealing with a problem about my linear Poisson regression model (link
> function=identity).
>
> I am using the glm()-function which results in negative coefficients, but a
> negative influence of the regress
Try using the latest xts on GitHub:
https://github.com/joshuaulrich/xts
On Thu, Jan 14, 2016 at 9:05 AM, Olivier ETERRADOSSI
wrote:
> Hi list,
>
>
>
> I thought I knew how to use extended time series (package xts), but I was
> wrong J …
>
>
>
> While preparing a toy example for something else,
This is the results that addresses David's advice.
> library(maptools)
> library(maps)
> state.map <- readShapeSpatial("maps/st24_d00.shp")
Error in getinfo.shape(fn) : Error opening SHP file
> # David question: What does list.files('maps') return? Is there a
> 'st24_d00.shp' value in there?
> lis
Hi all,
I am dealing with a problem about my linear Poisson regression model
(link function=identity).
I am using the glm()-function which results in negative coefficients,
but a negative influence of the regressors wouldn't make sense.
(i) Is there a possibility to set constraints on the
Lorenzo
Berend's suggestion may be the simplest if you have univariate ts style
series. If you are writing code and you want it to work with
multivariate series and other time representations then you might want
to consider the splice() function in package tframe.
library(tfplot)
ts3 <- s
I think I got it:
set.seed(123)
x <- data.frame(a = 1:10, b = 2:11, c = 3:12, other = rnorm(10))
x
temp <- as.matrix(x[1:3])
temp[temp %in% 7] <- 4
temp[temp > 7] <- temp[temp > 7]-1
x[1:3] <- temp
x
It works only with matrices, right? Can't do x[x>7] when x is a data frame?
Thanks!
On Fri, Jan
Hello!
# I have a data frame x:
x <- data.frame(a = 1:10, b = 2:11, c = 3:12, other = rnorm(10))
# First, I need to change every value 7 in columns a:c to 4
# Then, I need to decrease by 1 all values in columns a:c that are >7
What would be the fastest way of doing it?
Thank you!
--
Dimitri Li
We can duplicate the error by giving a path to a non-existent
shapefile, which is probably the original problem:
> require(maptools)
Loading required package: maptools
Loading required package: sp
Checking rgeos availability: TRUE
> foo=readShapeSpatial("fnord.shp")
Error in getinfo.shape(fn) :
FAQ 7.31
in this case subtract the two numbers and see that
they differ by about 1e-16
Sent from my iPhone
> On Jan 22, 2016, at 10:46, li li wrote:
>
> Hi all,
> I encountered the following strange phenomenon.
> For some reason, the obs_p[1] and res1$st_p[89] have
> the same value but when I
On 01/22/2016 10:46 AM, li li wrote:
Hi all,
I encountered the following strange phenomenon.
For some reason, the obs_p[1] and res1$st_p[89] have
the same value but when I run "==", it returns FALSE.
Can anyone help give some explanation on this?
Thanks very much!
Hanna
obs_p[1]
[1]
Hi,
This can get you started:
https://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-doesn_0027t-R-think-these-numbers-are-equal_003f
--Fabio
On Fri, Jan 22, 2016 at 1:46 PM, li li wrote:
> Hi all,
> I encountered the following strange phenomenon.
> For some reason, the obs_p[1] and res1$st_p[89
FAQ 7.31
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Fri, Jan 22, 2016 at 7:46 AM, li li wrote:
> Hi all,
> I encountered the following strange
Hi all,
I encountered the following strange phenomenon.
For some reason, the obs_p[1] and res1$st_p[89] have
the same value but when I run "==", it returns FALSE.
Can anyone help give some explanation on this?
Thanks very much!
Hanna
> obs_p[1]
[1] 0.002201438
> res1$st_p[89]
[1] 0.0022014
Dear
I try to use pgmm to estimate dynamic model for panel data. I got the message
below. It is appreciate that you could help on this.
data<-read.csv("G:/MMU/Research/Urbanlisation/paneldata.csv",sep=",",
header=TRUE) library(plm) library(Formula) urban<-pdata.frame(data,
index=c("id","year_b
Hi Tonja
Maybe I wasn't clear in my last post. This is the code:
library(gWidgetstcltk)
library(gWidgets)
options(guiToolkit="tcltk")
Population <- c("A","B","C","D","E","F")
w = gwindow("")
g1 = ggroup(horizontal = F, cont=w)
g2 = ggroup(horizontal = T, cont=g1)
glabel("Population:", cont=g2)
S
I have written some content about the R bindings to Tcl and Tk:
http://waddella.github.io/loon/learn_R_tcltk.html
And the pack geometry manager
http://adrian.waddell.ch/EssentialSoftware/Rtcltk_geometry.pdf
But if you have no experience with building graphical user interfaces then
you might wan
hi group
How 'functional complimentarity' of a bipartite network can be calculated
using the package 'bipartite'
--
Pushan Chakraborty
CSIR - SRF
Center for Pollination Studies, University of Calcutta
35, Ballyguanje Circular Road, Kolkata - 700019
&
Wildlife Institute of India
Chandra
Dear all,I would like to execute some php or javascripts I found on the web.
see at middle of this page towards bottom
http://www.howtocreate.co.uk/php/gridref.php#samples
Is there any way I can call the php function for example directly from R?
I would like to thank you in advance for your reply
On 22/01/2016 2:29 AM, TJUN KIAT TEO wrote:
I am trying to populate an array of lists in R . Here is my code
TunePar<-matrix(list(Null),2,2)
TunePar[1,1]=list(G=2)
But when I type TunePar[1,1,], all I get is 2. The G has disappeared. why?
If I do this
Test=list(G=2)
Test
$G
[1] 2
Matric
Hi,
Provide a list of a list in the second assignment:
--
TunePar <- matrix(list(NULL), 2, 2)
TunePar[2,1] <- list(list(G = 2))
TunePar[2,1]
TunePar[2,1][[1]]$G
TunePar[[2]]$G
---
The point is that "[" returns the list element of the same level as the
original object (TunePar in the present ex
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