On 24/09/2015 6:26 PM, Hermann Norpois wrote:
> Hello,
>
> I am looking for a possibility to define something like ylim for lines. I
> thought, there might be a possibility to define the range of lines by means
> of par ("usr") but I did not find the correct syntax. In my toy example I
> would lik
Hi all,
I´m trying to use quantmod and to display plot of Bollinger bands is
working properly.
¿How should I add for instance addWPR(n =300 ) below the main plot? Could
it would be plotted independently?
chartSeries(
IB,theme="white",TA = c(addBBands(200,2) )
Thanks in advance.
[[alte
Hello,
I am looking for a possibility to define something like ylim for lines. I
thought, there might be a possibility to define the range of lines by means
of par ("usr") but I did not find the correct syntax. In my toy example I
would like to stop the red line at y=0.3.
Thanks Hermann
toy examp
You seem to have sent the message in HTML and most of it did not arrive.
R-help is a plain text mailing list and strips out any HTML as a security
precaution.
Please have a look at
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-ex
ample and/or http://adv-r.had.c
Your professor should immediately recognize that the quoted code is standard
regression input/output and that the Urkund results in this case are without
merit.
> On Sep 22, 2015, at 7:27 AM, BARRETT, Oliver wrote:
>
>
> Dear 'R' community support,
>
>
> I am a student at Skema business sc
On Sep 24, 2015, at 1:54 PM, Lorenzo Isella wrote:
> On Thu, Sep 24, 2015 at 01:30:02PM -0700, David Winsemius wrote:
>>
>> On Sep 24, 2015, at 12:36 PM, Lorenzo Isella wrote:
>>
>>> Hi,
>>> And thanks for your reply.
>>> Essentially, your script gets the job done.
>>> For instance, if I run
>>
> -Original Message-
> From: pda...@gmail.com
> Sent: Thu, 24 Sep 2015 11:41:19 +0200
> To: murdoch.dun...@gmail.com
> Subject: Re: [R] 'R' Software Output Plagiarism
>
>
> On 23 Sep 2015, at 02:33 , Duncan Murdoch
> wrote:
>
>> I don't see why this puzzles you. A simple explanation i
Bogdan,
I would look into bioconductor for packages handling this type choromosomal
range data. cntools is one poped into my mind.
Tao
On Thursday, September 24, 2015 12:59 PM, Sarah Goslee
wrote:
merge() most likely, but: are these really lists in the R sense?
The correct answer depe
Dear Bert and Sarah, thank you for your suggestions. Yes, I came across
"dplyr" that has a few functions already implemented, thanks again !
On Thu, Sep 24, 2015 at 1:17 PM, Bert Gunter wrote:
> Also, in addition to what Sarah told you, have you checked on the
> Bioconductor site, as this sounds
On Thu, Sep 24, 2015 at 01:30:02PM -0700, David Winsemius wrote:
On Sep 24, 2015, at 12:36 PM, Lorenzo Isella wrote:
Hi,
And thanks for your reply.
Essentially, your script gets the job done.
For instance, if I run
mm <- cbind(5/(1:5), -2*sqrt(1:5))
dst <- dist(mm)
dst2 <- as.matrix(dst)
diag
On Sep 24, 2015, at 12:36 PM, Lorenzo Isella wrote:
> Hi,
> And thanks for your reply.
> Essentially, your script gets the job done.
> For instance, if I run
>
> mm <- cbind(5/(1:5), -2*sqrt(1:5))
> dst <- dist(mm)
> dst2 <- as.matrix(dst)
> diag(dst2) <- NA
> idx <- which(apply(dst2, 1, functio
Also, in addition to what Sarah told you, have you checked on the
Bioconductor site, as this sounds like the sort of thing that they may
well have something for already.
... and you've posted here often enough that you shouldn't still be
posting HTML and you should know about toy examples!
Cheers
merge() most likely, but: are these really lists in the R sense?
The correct answer depends on what the format actually is; you need to
use dput() or some other unambiguous way of providing sample data.
Without a reproducible example that includes some sample data provided
using dput() (fake is f
Dear all,
please could you advise on a computationally quick way to compare and merge
2 long lists in R;
the lists are of the following type, for example :
<> in list 1 :
chromosome, coordinateA, coordinateB, value1
chromosome, coordinateC, coordinateC, value2,
etc
<> in list 2 :
chromosome, c
Hi,
And thanks for your reply.
Essentially, your script gets the job done.
For instance, if I run
mm <- cbind(5/(1:5), -2*sqrt(1:5))
dst <- dist(mm)
dst2 <- as.matrix(dst)
diag(dst2) <- NA
idx <- which(apply(dst2, 1, function(x) all(na.omit(x)>.9)))
then it correctly detects the first two rows,
You can use quantile regression (in quantreg package) to compare
percentiles between two groups in a linear model formulation. If you are
really interested in "equivalence" testing and not just using the term
informally, you might check out Cade (2011. Estimating equivalence with
quantile regress
Mohamed,
You probably should seek the help of a local statistician, and should read
about Pearson's chi square test and Fisher's exact test.
John
John David Sorkin M.D., Ph.D.
Professor of Medicine
Chief, Biostatistics and Informatics
University of Maryland School of Medicine Division of Geronto
Dear AllI Have the data for two samples drawn from two different populations
|
|
|
|
|
| Percentiles
|
|
| Mean
| STD
| Min
| Max
| 5th
| 25th
| 50th
| 75th
| 95th
|
| Sample 1
| 25
| 2
| 16
| 30
| 18
You're posting in HTML and your link didn't make it :-(
B.
On Sep 24, 2015, at 1:34 PM, amir via R-help wrote:
> I would greatly appreciate if anybody could help with the stack-overflow
> question : Updating and Forecasting times series with new data
> | |
> | | | | | | | |
I would greatly appreciate if anybody could help with the stack-overflow
question : Updating and Forecasting times series with new data
| |
| | | | | | | |
| Updating and Forecasting times series with new dataWe can fit a time series
and use the model to make forecasts, for example
Hi
I have some code which does (on a symmetric matrix 'x')
backsolve(chol(x), diag(nrow(x)))
and I am wondering what is the recommended way to accomplish this when x
is also sparse (from package:Matrix). I know that package:Matrix
provides a chol method for such matrices, but not a backsolve
I see that you have used
add = TRUE
in the boxplot call. Add only makes sense if there is already a plot to
which to add the boxplot. But your boxplot is first, so there isn't
anything to add it to.
Try doing the beeswarm plot first?
Will the two plots will have the same y axis ranges?
Minor
There is actually a fair amount of ERP literature using mixed-effects
modelling, though you may have to branch out from the traditional
psycholinguistics journals a bit (even just more "neurolinguistics" or
language studies published in "psychology" would get you more!). But
just in the traditional
On 24 Sep 2015, at 15:07 , Agustin Lobo wrote:
> I would like to make sure that I'm using friedman.test() correctly,
> because I have to reformat my data set to fulfil the requirement
> "exactly one observation in y for each combination of levels of groups
> and blocks" mentioned
> in the help p
Dear Rosa,
coefficents of a probit-regression do not have a odds-ratio
interpretation, you should use a logit link for that.
cheers.
Am 24.09.2015 um 09:51 schrieb Michael Dewey:
> Dear Rosa
>
> Please keep the list on the recipients as others may be able to help.
>
> See inline
>
> On 23/09/2
I would like to make sure that I'm using friedman.test() correctly,
because I have to reformat my data set to fulfil the requirement
"exactly one observation in y for each combination of levels of groups
and blocks" mentioned
in the help page of function friedman.test().
Assuming data from
http://
A better solution provide by Adriano Rivolli:
library(parallel)
models <- mclapply(1:10, function(i) {
model <- RWeka::J48(Species ~., iris[sample(nrow(iris))[1:100],])
rJava::.jcache(model$classifier)
model
});
2013-10-24 10:16 GMT-02:00 Luís Paulo F. Garcia :
> Dear, Patrick.
>
> I
and a somewhat convoluted solution, if A or K are always in the second
"position"
x <- c("LBAM 5|A|15C|3h", "LBAM 5|K|15C|2h")
unlist(lapply(strsplit(x,"\\|"),function(y)
paste(y[c(1,3,4)],collapse="|")))
Stephen C. Upton
SEED (Simulation Experiments & Efficient Designs) Center
Operations Rese
Dear Michael (and all :))
Thank you very much.
I fixed my problem, I think ;)
Best,
RO
Atenciosamente,
Rosa Oliveira
--
Rosa Celeste dos Santos Oliveira,
E-mail: rosit...@gmail.com
Tlm: +351 939355143
Linkedin:
On 24 Sep 2015, at 12:05 , Thierry Onkelinx wrote:
> gsub("[A|K]\\|", "", x)
That'll probably do it, but what was the point of the | in [A|K] ?? I don't
think it does what I think you think it does...
Somewhat safer, maybe:
gsub("\\|[AK]\\|","\\|", x)
(avoids surprises from, say, "LBAM 5|A|
gsub("[A|K]\\|", "", x)
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie & Kwaliteitszorg / team Biometrics & Quality Assurance
Kliniekstraat 25
1070 Anderlecht
Belgium
To call in the statistician after the experiment is done ma
I need to change a vector dd that looks like this:
c("LBAM 5|A|15C|3h", "LBAM 5|K|15C|2h")
into this:
c("LBAM 5|15C|3h", "LBAM 5|15C|2h")
It's not very imaginative, but I could use a complicated nesting of
gsub() as so:
gsub("-", "\\|", gsub("K-", "", gsub("A-", "", gsub("\\|", "-", dd
Or
On 23 Sep 2015, at 02:33 , Duncan Murdoch wrote:
> I don't see why this puzzles you. A simple explanation is that Urkund
> is incompetent.
That much I figured. What I was puzzled about was _how_ it was being
incompetent. Also how it could be so in a way that wouldn't be obvious to the
profes
Dear Rosa
Please keep the list on the recipients as others may be able to help.
See inline
On 23/09/2015 19:19, Rosa Oliveira wrote:
Dear Michael,
*New cleaned code :)(I think :))*
casedata <-read.spss("tas_05112008.sav")
tas.data<-data.frame(casedata)
#Delete patients that were not dis
Hi everybody,
I'm new and i need help very fast.
I will make a transparent boxplot overlap a beeswarm.
I don't want to use ggplot2, i will use ggplot.
Here is my own script but it doesn't worked.
Maybe you can help me.
Thanks in advance
Julia
require(beeswarm)#rohdaten boxplots
rm(list=ls())
setw
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