You misspelled panel.abline as panel.labline in your code you included
here. If that's the real code, that's why.
-- Bert
Bert Gunter
"Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom."
-- Clifford Stoll
On Sun, Sep 13, 2015 at 8:43 PM, Christin
If this mailing list accepted formatted submissions I would have used the
trèsModernSarcastic font for my first sentence. Failing the availability of
that mode of communication I am (top) posting through Nabble (perhaps) in
"Comic Sans".
On Sat, Sep 12, 2015 at 9:52 AM, David Winsemius
Also, you should bookmark this link.
http://www.r-bloggers.com/this-r-data-import-tutorial-is-everything-you-need/
On Wednesday, July 29, 2015 at 6:41:35 AM UTC-4, jpara3 wrote:
>
> data<-read.csv("
> https://raw.githubusercontent.com/sjkiss/Survey/master/mlogit.out.csv",header=T,sep=",";)
>
How about this?
library(XML)
library(RCurl)
url <-
"https://raw.githubusercontent.com/sjkiss/Survey/master/mlogit.out.csv";
urldata <- getURL(url)
data <- readHTMLTable(urldata, stringsAsFactors = FALSE)
On Wednesday, July 29, 2015 at 6:41:35 AM UTC-4, jpara3 wrote:
>
> data<-read.csv("
Dear all,
I want to draw a line at DI=1 across all four graphs in the xy plot, I have
used panel.abline, but I failed to do so, does any one has an idea of what has
went wrong?
structure(list(Date = structure(c(6L, 7L, 2L, 4L, 13L, 17L, 5L,
12L, 4L, 11L, 14L, 9L, 7L, 2L, 4L, 13L, 10L, 17L, 5L,
On 14/09/15 00:31, Mehmet Doğan wrote:
Dear All, I can NOT format and create an xts object of my data in
order to forecast Volatility. Moreover I can NOT plot the data.
basically i cant work with the data i have. I need to finish my
project till tomorrow. Could you please help me with those pro
Further to my posting re: extracting case values from ancova adjusted means, I
have solved the problem.
Regards,
Brian Jessop
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
library(xts)
library(zoo)
EURUSD<-read.csv("Data_Forecast/EURUSD.csv") # to load the data
EURUSD<-read.csv("Data_Forecast/EURUSD.csv",stringsAsFactors=F) # to load as
a factor
#??
EURUSD$Date<-as.Date(EURUSD$Date,format="%Y-%m-%d" , "h:m:s") # here the code
is not working to form
The function takes a two way table. Assuming your example involves two ordinal
vectors c(1,2,3,4,5) and c(3,4,1,2,5), you need:
> xy <- table(c(1,2,3,4,5),c(3,4,1,2,5))
> xy
1 2 3 4 5
1 0 0 1 0 0
2 0 0 0 1 0
3 1 0 0 0 0
4 0 1 0 0 0
5 0 0 0 0 1
> cd <- ConDisPairs(xy)
> cd
$pi.c
Hi Mehmet,
Did you send this in HTML? That's what it looks like.
It is currently almost unreadable.
You need to reformat it and send it as plain text.
You need to reduce the code to the key parts if possible. It looks like most of
the code is unneeded for the problem and is just a distraction.
You are in the right place but the question in not very clear. Have a look at
the links below for some suggestions on how to ask a question on R-help.
I think we need the data in dput() format. See ?dput or the discussion of
dput() in the links.
http://stackoverflow.com/questions/5963269/how-to
>>From it, I infer that, if i is logical and length(i) >= length(x), x[i] <-
>>value has >the same effect to x[which(i)] <- value, where which(i) takes
>>indices where i is >T.
The return value of which(i) gives only the indices of the TRUE values in i.
It does not return the length of i. Hence
Dear Zahra
Your email is completely unreadable because you posted in HTML. Please
reset your mailer and try again.
On 13/09/2015 06:12, Zahra Karimi via R-help wrote:
Hello,
I have a data like this:1 2331 3331 4551 3452 5432 4332 3442 4003 4443 1113
0003 432I want to change it to this new da
Dear All,
I can NOT format and create an xts object of my data in order to forecast
Volatility. Moreover I can NOT plot the data. basically i cant work with the
data i have. I need to finish my project till tomorrow. Could you please help
me with those problems?
I also attached my data. the prob
This is my first time posting here
library(BradleyTerry2)
library(xlsx)
data(flatlizards)
str(flatlizards)
a <- data.frame(x=rnorm(10), y=runif(10))
b <- data.frame(w=rnorm(20), z=runif(20))
ablist <- list(a, b)
write.xlsx(mydata, "c:/Test/mydata.xlsx")
On Tuesday, June 16, 2015 at
Thank you for looking.
If the last element of i is TRUE, the largest value of which(i) is length(i).
So, even if x[i] <- value were translated to x[which(i)] <- value, the result
would have length(x) == length(i).
Difference between x[i] <- value and x[which(i)] <- value in R would occur when
Hello,
I have a data like this:1 2331 3331 4551 3452 5432 4332 3442 4003 4443 1113
0003 432I want to change it to this new dataset:c1 c2 c3233 543 444333
433 111455 344 000345 400 432
How can I do this in R? Please if this not the correct place to ask my
queston.. then could you
... and this, of course, is a nice example of how statistics
contributes to the "irreproducibility crisis" now roiling Science.
Cheers,
Bert
(Quote from a long ago engineering colleague: "Whenever I see an
outlier, I never know whether to throw it away or patent it.")
Bert Gunter
"Data is not
Hi there,
I´m using random Forest package to create a random Forest:
model<-randomForest(A~.,data=mydata)
, and I use the varImpPlot(model) to see which are the most important
variables, so I obtain that C, D and F are the most important ones, but...
How can I see the model, in which levels I
19 matches
Mail list logo