Hi Peter,
I did the same but I received an error stating X11 is not available.
On Fri, Apr 24, 2015 at 8:11 PM, peter dalgaard wrote:
> Plot directly to the appropriate device, e.g.
>
> pdf(file="my.pdf")
> plot(rnorm(500))
> dev.off()
>
> This is often recommendable even if you do have an on-
Hi Antonio,
If you do create the map in R, you can use locator().
Jim
On Sat, Apr 25, 2015 at 8:37 AM, Antonio Serrano via R-help
wrote:
>
> Hello, all:
>
>I am new here, and have a challenge to present some graphical data to the
> user in a convenient way.
>
>The challenge is to pres
Reproducibility
http://adv-r.had.co.nz/Reproducibility.html
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
John Kane
Kingston ON Canada
> -Original Message-
> From: mikeh...@y7mail.com
> Sent: Wed, 22 Apr 2015 18:52:45 + (UTC)
> To: r-help@
Hello, all:
I am new here, and have a challenge to present some graphical data to the
user in a convenient way.
The challenge is to present a map to the user which is coloured with the
value of a variable. Say for example, temperature. This is a preexisting graph
that I can generate in
Hi everybody,
I am trying to replicate the formula shown in the attachment. I want to
estimate tau using a macroeconomic variable X at month t using k lags of the
variable X.
My code so far looks as follows:
psi <- fn(...)
k <- 1:K
ltau <- m + theta*sum(psi*X[t-k])
Unfortunately, if I run the c
Geospatial image maps or just exif tags?
Search for "r exif" for several leads.
Cheers, Mike
On Sat, Apr 25, 2015, 08:48 Alejo C.S. wrote:
> Hi all, I have several jpeg files with lat long information. I want to make
> a lat long table whit this info. Anyone knows how to do it? Can't find
> an
That's a pretty vague question, but you might be able to do it with
functions from the raster package.
Followup on this topic should be to R-sig-geo.
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 4/24/15, 3:46 PM, "Al
Hi all, I have several jpeg files with lat long information. I want to make
a lat long table whit this info. Anyone knows how to do it? Can't find
anything in google.
Thanks a lot in advance
A.
[[alternative HTML version deleted]]
__
R-help@r-
R 3.2.0
OS X
Colleagues
I have a script that has been unchanged for years but I just noticed a
difference in the output. A minimal example is:
jpeg(file="xxx.jpeg", width=4, height=2, unit="in", pointsize=12,
bg="white", res=150, quality=100)
plot(1)
graphics.off()
Bonjour,
We need more information. See Reproducibility
http://adv-r.had.co.nz/Reproducibility.html for some suggestions on how to ask
a question.
John Kane
Kingston ON Canada
> -Original Message-
> From: mamadouns...@gmail.com
> Sent: Fri, 24 Apr 2015 13:26:32 +0100
> To: r-help@r
Hi,
Thanks so much for the hints, I think I've cracked it! The key is to
create a dummy function, "continue_on_error" which gets run instead of
"stop" when an error occurs, then reference it
with options(error=continue_on_error). Here's an example:
==
continue_on_error
Hello,
Please, read and follow the posting guide and provide a minimal
reproducible example as you are encouraged to do. Moreover, write to the
list in english.
Just a quick test : have you looked at your object 'mat_tp' :
> str(mat_tp)
Bon courage,
François
Le 24/04/2015 14:26, Mamadou Ndia
You really really really need to work with a local statistical expert, as
your post indicates fundamental confusion. Furthermore, statistical issues
are off topic here.
Cheers,
Bert
On Friday, April 24, 2015, Praveen kr singh wrote:
> Hi,
>
> Currently i am working with the lm() function for so
Plot directly to the appropriate device, e.g.
pdf(file="my.pdf")
plot(rnorm(500))
dev.off()
This is often recommendable even if you do have an on-screen graphics device
because some subtleties can get lost in translation for one device to another.
(The prototypical example is that a legend box
try lm.ridge from MASS package.
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal,
Hi All,
I am wondering how to save plots in R at CentOS when X11 is not available,
any suggestion would be appreciated.
Warm Regards
Sudip
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This is very off-topic here. My suggestion would be to do as the Posting Guide
says and ask this on R-devel, or perhaps even a gdb forum. From what little I
know, valgrind might help also.
---
Jeff Newmiller
Jeff Newmiller dcn.davis.ca.us> writes:
>
> This seems like a recipe for garbage results to me, but there may be I
something you can set the error option
> to. See ?options.
>
---
> Jeff NewmillerThe
On 04/24/2015 06:49 AM, Franckx Laurent wrote:
Dear all
I have bumped into the dreaded 'segfault' error type when running some C++
code using .Call().
segfaults often involve invalid memory access at the C level that are best
discovered via valgrind or similar rather than gctorture. A good wa
Hi,
Currently i am working with the lm() function for some regressions required
for my project.
suppose the formula parameter in that is given by "response ~ terms",after
some testing i found out that when the number of observations under terms
is less than the number of columns or features un
Bonjour, je suis un nouveau dans R. Je fais actuellement mon mémoire de
mastère et je voudrais appliquer le Package BCDating. Mail il se trouve que
je reçois toujours le message d'erreur suivant:
Erreur dans if (mat_tp[r, 1] < n) mat_tp <- rbind(mat_tp, c(n, 1 -
mat_tp[r, :
l'argument est de lon
Have just checked with R 3.2.0 and MASS 7.3-40 and there still appears to
be a problem/strangeness at around k=2.5
On 23 April 2015 at 14:09, Francis Bursa
wrote:
> Dear all,
>
> I believe I have found a bug in rlm in the MASS package. Specifically, the
> scale estimate can be wrong when there
Hello Erin,
I think you have explain your goal more detailed. Maybe I am completely
lost but as far as I understand now you only need the command cbind:
m1 <- cbind(dog, dat, tree)
dog cat tree
[1,] 1 25
[2,] 2 36
[3,] 3 47
But I can't imagine that is the solution yo
I wanted to increase the size of the font in R, but when I do, I get the error
message below. I've searched on Google, and the only thing I saw is about
changing the version of X11. I'm running the current version of X11, and
running OS X Yosemite 10.10.3. I'm using a Mac Desktop, 3.2 Ghz pro
Dear all
I have bumped into the dreaded 'segfault' error type when running some C++ code
using .Call().
I have already undertaken several attempts to debug the C++ code with gdb(),
but until now I have been unable to pinpoint the origin of the problem. There
are two elements that I think are p
You could do something tricky like
> do.call(cbind, lapply(big.char, as.name))
dog cat tree
[1,] 1 25
[2,] 2 36
[3,] 3 47
but you are usually better off creating these things as part of a list
and passing that to do.call(cbind, list).
There is a slight danger
On 24 April 2015 at 12:59, Achim Zeileis wrote:
>
>
> On Fri, 24 Apr 2015, Jue Lin-Ye wrote:
>
> Dear fellow R-help members,
>>
>> If my data is
>>
>> MM DD HH
>> 2015 04 24 01
>> 2015 04 24 02
>> 2015 04 24 06
>>
>> Where
>>
>> : year
>> MM:month
>> DD:day
>> HH: hour
>>
>> How could I
Hi Joachim,
This function allows the user to set some characters in a string to
superscript or subscript. If sup or sub are set to one or more numbers
corresponding to an index in the string, those letters will be placed
appropriately. I can't properly test this as there is some problem
with X11 fo
On Fri, 24 Apr 2015, Jue Lin-Ye wrote:
Dear fellow R-help members,
If my data is
MM DD HH
2015 04 24 01
2015 04 24 02
2015 04 24 06
Where
: year
MM:month
DD:day
HH: hour
How could I calculate the mean of the ISOdatetime(,MM,DD,HH,0,0) of
these?
With the mean() method? On my
Dear fellow R-help members,
If my data is
MM DD HH
2015 04 24 01
2015 04 24 02
2015 04 24 06
Where
: year
MM:month
DD:day
HH: hour
How could I calculate the mean of the ISOdatetime(,MM,DD,HH,0,0) of
these?
Note: I set minutes and seconds to 0, as I don't have data for them.
Tha
I am amazed at the number of rather obtuse misunderstandings of the
actual nature of Erin's question.
The suggestion that Erin should read the intro to R made me smile. Erin
is a long time and highly sophisticated user of R; she has no need to
read the intro. The person who made that sugge
> Steve Taylor
> on Thu, 23 Apr 2015 23:32:00 + writes:
> This works for me...
> get0 = function(x) get(x,pos=1)
> sapply(big.char, get0)
Note that get0() is a _ somewhat important for efficient code _
new function since R 3.2.0
so you'd rather call your functions di
G'day Erin,
On Thu, 23 Apr 2015 20:51:18 -0400
Erin Hodgess wrote:
> Here is the big picture. I have a character vector with all of the
> names of the variables in it.
>
> I want to "cbind" all of the variables to create a matrix.
>
> Doing 3 is straightforward, but many, not so much.
So I g
On 24/04/2015 01:22, billy am wrote:
Hi Everyone ,
Is there a place where I can download msi installer for latest version of
R?
I believe not: certainly not an official one. Consult the manual as to
how to build one if you really need one.
Thanks
Billy
[[alternative HTML version
Is this what you're looking for?
> dog <- 1:3
> bat <- 2:4
> tree <- 5:7
> big.char <- c("dog","bat","tree")
> do.call(cbind,lapply(big.char, get))
[,1] [,2] [,3]
[1,]125
[2,]236
[3,]347
>
On Thu, Apr 23, 2015 at 3:41 PM, Erin Hodgess wrote:
> Hello!
Hello,
I am not sure what you mean by a matrix. If you want to have a matrix, use the
function matrix, (matrix(c(dog,cat,tree),3))
but I have the feeling you really want a data frame as you are talking about
variables.
In that case simply use
mydataframe <- data.frame(dog,cat,tree)
If you are
Regex "[^a-zA-Z]" reads as "not a letter".
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Live Go...
Live: OO#.. D
This seems like a recipe for garbage results to me, but there may be I
something you can set the error option to. See ?options.
---
Jeff NewmillerThe . . Go Live...
DCN:Basics
On 24/04/15 10:41, Erin Hodgess wrote:
Hello!
I have a cbind type question, please: Suppose I have the following:
dog <- 1:3
cat <- 2:4
tree <- 5:7
and a character vector
big.char <- c("dog","cat","tree")
I want to end up with a matrix that is a "cbind" of dog, cat, and tree.
This is a toy e
Hi Everyone ,
Is there a place where I can download msi installer for latest version of
R?
Thanks
Billy
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What are you expecting?
dog <- 1:3
cat <- 2:4
tree <- 5:7
big.char <- c("dog","cat","tree")
xx <- cbind(dog, cat, tree, big.char)
gives me
xx1 <- structure(c("1", "2", "3", "2", "3", "4", "5", "6", "7", "dog",
"cat", "tree"), .Dim = 3:4, .Dimnames = list(NULL, c("dog", "cat",
"tree", "big.
On 23/04/15 13:41, Albin Blaschka wrote:
Hello
Am 23.04.2015 um 09:57 schrieb Berend Hasselman:
On 23-04-2015, at 08:45, Sun Shine wrote:
Hi list
Recently, when starting up RStudio, the following warning is being
displayed:
"Error in tools:::httpdPort <= 0L :
comparison (4) is possible
Here is the big picture. I have a character vector with all of the names
of the variables in it.
I want to "cbind" all of the variables to create a matrix.
Doing 3 is straightforward, but many, not so much.
Hence my question.
Thanks so much for your answers!
Sincerely,
Erin
On Thu, Apr 23,
On Apr 23, 2015, at 5:41 PM, Erin Hodgess wrote:
>
> Hello!
>
> I have a cbind type question, please: Suppose I have the following:
>
> dog <- 1:3
> cat <- 2:4
> tree <- 5:7
>
> and a character vector
> big.char <- c("dog","cat","tree")
>
> I want to end up with a matrix that is a "cbind" of
This works for me...
get0 = function(x) get(x,pos=1)
sapply(big.char, get0)
The extra step seems necessary because without it, get() gets base::cat()
instead of cat.
cheers,
Steve
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Erin Hodgess
Sent:
These are great! Thank you!
On Thu, Apr 23, 2015 at 7:14 PM, William Dunlap wrote:
> You could do something tricky like
> > do.call(cbind, lapply(big.char, as.name))
>dog cat tree
> [1,] 1 25
> [2,] 2 36
> [3,] 3 47
> but you are usually better off creat
Perhaps:
dog <- 1:3
cat <- 2:4
tree <- 5:7
big.char <- cbind(dog,cat,tree)
big.char
dog cat tree
[1,] 1 25
[2,] 2 36
[3,] 3 47
colnames(big.char)<-c("dog","cat","tree")
big.char
dog cat tree
[1,] 1 25
[2,] 2 36
[3,] 3 47
Clint Bowma
Hi Erin,
Well, if I do this:
dog <- 1:3
cat <- 2:4
tree <- 5:7
dct<-cbind(dog,cat,tree)
I get this:
dct
dog cat tree
[1,] 1 25
[2,] 2 36
[3,] 3 47
If I assume that you want to include the character vector as well:
rownames(dct)<-big.char
dct
Jim
On Fri, Apr 24, 2
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