Aha! I haven't thought about it. I really like the approach presented
by Bert Gunter in the previous post. It is a good lesson.
I made my previous code a little bit better by building a function that
pulls out only the desired component. At this time, the names of
sublists are changed as be
I am just using the first two components of your output.
> op
$bp
chr pos ci.low ci.high lod
c7.loc45 7 47.7 36.7156.7 6.11
c15.loc8 15 12.0 3.9622.8 5.29
$hr
chr pos ci.low ci.high lod
c2.loc542 59.8 14.887.8 4.19
D15MIT184 15 22.8 12.036.0
I believe what Karim is after is often referred to as a “ragged array”. For
disk storage, such structures have been added to netcdf4 for things like
subsurface profiles with a different number of depths.
This blog might be of interest:
http://www.r-bloggers.com/efficient-ragged-arrays-in-r-and
I guess that you may need 'panel.text()' to customize panel function.
Please run the following code and see the output. You will see
different value of R-squared in each panel.
xyplot(
y~x|name, data=df,
panel = function(x, y, ...) {
panel.xyplot(x, y, ...)
panel.abline(lm(y~x), co
I use plyr and am learning dplyr and magrittr, but those are just syntactic
sugar. What I have been having difficulty with in this thread is the idea that
it somehow makes sense to pad vectors with NA values... because I really don't
think it does. It seems more like a hammer looking for a nail
Hi,
On Jan 19, 2015, at 5:17 PM, Karim Mezhoud wrote:
> Thanks Ben.
> I need to learn more about apply. Have you a link or tutorial about apply. R
> documentation is very short.
>
> How can obtain:
> z <- list (Col1, Col2, Col3, Col4..)?
>
This may not be the most efficient way and there
I have any problems in R:
The downloaded binary packages are in
/var/folders/s9/kr21631n3nj30hb_4td3pv_8gn/T//RtmpDDAFmJ/downloaded_packages
Warning messages:
1: In download.file(url, destfile, method, mode = "wb", ...) :
downloaded length 2122881 != reported length 2235972
2: 'tar' returne
Hi,
I'm trying to use both the survey package and the anesrake package to
perform raking on my sample dataset, to get the proportions to match up
with population data from the census.
I'm trying the following, but the resulting weights are very large:
> svy.unweighted <- svydesign(ids=~1, dat
Subject: Regression Modeling Strategies 4-Day Short Course March 2015
*RMS Short Course 2015*
Frank E. Harrell, Jr., Ph.D., Professor and Chair
Department of Biostatistics, Vanderbilt University School of Medicine
*March 3, 4, 5 & 6, 2015* With Optional R Workshop March 2
9:00am - 4:00pm
Student
I do not think any one has replied to this.
Having 2 keys I think comes under the bit in the help under legend.
I have not got time at the moment but see
?xyplot
and have a look at
https://stat.ethz.ch/pipermail/r-help/2005-February/066264.html
and the following
Regards
Duncan
Duncan Mac
why not just use the tools in npudens? they can predict on a new set.
You can also you tools like fitdistr to fit a parametric multivariate
density, or you can use loess or lm with poly or splines to estimate the
surface (but this will not guarantee a volume of 1).
On Thu, Jan 15, 2015 at 2:19 A
Thanks Ben.
I need to learn more about apply. Have you a link or tutorial about apply.
R documentation is very short.
How can obtain:
z <- list (Col1, Col2, Col3, Col4..)?
Thanks
Ô__
c/ /'_;kmezhoud
(*) \(*) ⴽⴰⵔⵉⵎ ⵎⴻⵣⵀⵓⴷ
http://bioinformatics.tn/
On Mon, Jan 19, 2015 at 8:22 PM,
Dear All,
I'd like to add a list name into the list contents to make a new output. The
list is a list of data.frame derived from summary command in Rqtl. I want to
add this list name to the data frame with a given column name such as "trait"
and output this entire list as a table tab delimited a
Hi again,
On Jan 19, 2015, at 1:53 PM, Karim Mezhoud wrote:
> Yes Many thanks.
> That is my request using lapply.
>
> do.call(cbind,col1)
>
> converts col1 to matrix but does not fill empty value with NA.
>
> Even for
>
> matrix(unlist(col1), ncol=5,byrow = FALSE)
>
>
> How can get Matrix
Yes Many thanks.
That is my request using lapply.
do.call(cbind,col1)
converts col1 to matrix but does not fill empty value with NA.
Even for
matrix(unlist(col1), ncol=5,byrow = FALSE)
How can get Matrix class of col1? And fill empty values with NA?
Thanks
Karim
Ô__
c/ /'_;kmezhoud
many thanks for replying
the code
A is list of sets where each list element is a set
i<-1
A[i]<-3
#inside the loop
i<-i+1;
# for example new element in the list will be {7,9}, each added
separately inside the loop
A[i] <- union( A[[i]] ,new element)
many thanks for replyin
> On 19-01-2015, at 17:10, Ragia Ibrahim wrote:
>
> many thanks for replying
> the code
> A is list of sets where each list element is a set
> i<-1
> A[i]<-3
> #inside the loop
> i<-i+1;
> # for example new element in the list will be {7,9}, each added
> separately inside the loop
Hi,
On Jan 18, 2015, at 4:36 PM, Karim Mezhoud wrote:
> Dear All,
> I am trying to get correlation between Diseases (80) in columns and
> samples in rows (UNEQUAL) using gene expression (at less 1000,numeric). For
> this I can use CORREP package with cor.unbalanced function.
>
> But before to
Hi Jim,
that is exactly what I was looking for. Thanks a lot! I can even
choose how to label the countries e.g. Italy or just IT.
Have a nice day and thank you for helping me again
Claudia
Zitat von Jim Lemon :
Hi Claudia,
You're right, when the map is maximized the coordinates of the obj
Dear Team,
I have downloaded and uncompressed ORCH from
http://www.oracle.com/technetwork/database/database-technologies/bdc/big-data-connectors/downloads/index.html
Then I added Environmental Variables
export ORCH_HADOOP_HOME=/opt/cloudera/parcels/CDH/lib/hadoop
export ORCH_HDFS_HOME=/opt/cloud
many thanks for replying
the code
A is list of sets where each list element is a set
i<-1
A[i]<-3
#inside the loop
i<-i+1;
# for example new element in the list will be {7,9}, each added
separately inside the loop
A[i] <- union( A[[i]] ,new element)
many thanks for replyin
Hi
are you sure that you understand what union does?
AFAIK union(set_name ,element) takes vector set_name, add all non duplicated
values from element and returns concatenated vector.
x<-1:10
y<-5:15
union(x,y)
[1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
x<-NULL
union(x,y)
[1] 5 6 7
> On 19-01-2015, at 15:51, Ragia Ibrahim wrote:
>
> Hello,
> I started the program with an empty set then I add and element when needed.
> the problem how can I add the first element to the empty set
> union(set_name ,element)
> gives "subscript out of bounds “
>
Which program did you start?
Hello,
I started the program with an empty set then I add and element when needed.
the problem how can I add the first element to the empty set
union(set_name ,element)
gives "subscript out of bounds "
thanks in advance
R.
[[alternative HTML ver
1) Read the help file
?timezones
and note that the R project does not do any of the programming associated with
that functionality.
2) Keep in mind that it is you who are supplying an indeterminate value to be
interpreted. You need to know from context (another column of data? The trend
of va
On 19/01/2015 11:51, Vasantha Kumar Kesavan wrote:
Hi,
Let me know, how to set/unset "isdst" parameter in system/session level.
I could understand the possible values of isdst 0, 1 and -1.
Example:
Sys.setenv(TZ="PST8PDT");
as.POSIXct("2007-11-04 01:00:00");
when I was executed the above com
Dear all,
Given vectors "x" and "y", I would like to compute the proportion of
entries that are equal, that is, mean(x == y).
Now, suppose I have the following matrix:
n <- 1e2
m <- 1e4
X <- matrix(sample(0:2, m*n, replace = TRUE), ncol = m)
I am interested in calculating the above proportion f
Hi Davide,
You really shouldn't post on multiple forums. Please see my response on
SO,
http://stackoverflow.com/questions/27990932/r-deepnet-package-how-to-add-more-hidden-layers-to-my-neural-network,
where I tell you that you can add additional layers by simply adding to the
hidden vector.
Rega
Hi,
Let me know, how to set/unset "isdst" parameter in system/session level.
I could understand the possible values of isdst 0, 1 and -1.
Example:
Sys.setenv(TZ="PST8PDT");
as.POSIXct("2007-11-04 01:00:00");
when I was executed the above command,
LINUX.X64 -> it was treated as PST value.
[1]
Hi,
Here is a solution which is restricted to lists with identically shaped
"branches" (like your example). The idea is to transform the list to an
array and make use of the fact that unlist(x, use.names=FALSE) is much
much faster for large lists than unlist(x).
# function which transforms
Brian Diggs writes:
> On 1/16/15 9:34 AM, Bert Gunter wrote:
>> Chee Hee's approach is both simpler and almost surely more efficient,
>> but I wanted to show another that walks the tree (i.e. the list)
>> directly using recursion at the R level to pull out the desired
>> components. This is in ke
Bert Gunter writes:
> Chee Hee's approach is both simpler and almost surely more efficient,
I am not sure about the efficient - if the lists are large, they need to
be copied and "un-listed" which both require memory allocations and
processing time - so I would actually guess that your (and Bria
Chel Hee Lee writes:
> This approach may not be fancy as what you are looking for.
As long as it works ans=d it is efficient, it is OK.
>
>> xl <- unlist(x)
The unlist might be a problem as I am working with quite large lists.
>> xl[grep("A", names(xl))]
The grep has one problem, as it would
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