On Dec 20, 2014 11:11 PM, "ce" wrote:
>
>
> Dear all,
>
> I want to create a time series object from 00:00:00 to 23:59:00 without
dates ?
> I can't figure it out with xts ?
>
You can't create an xts object without a date in the index. If the date
doesn't matter, you can just set it to 1970-01-01 (
Dear all,
I want to create a time series object from 00:00:00 to 23:59:00 without dates ?
I can't figure it out with xts ?
ce
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PLEASE do r
Dear varin sacha,
I think that you misunderstand how boot() and boot.ci() work. The boot()
function in the simplest case takes two arguments, for the data and indices
into the data, while boot.ci() takes as its principal argument the object
returned by boot(). All of this seems reasonably clear
On 19/12/2014, 5:48 PM, Ben Marwick wrote:
> I'm looking for the NEWS files for versions of R before 3.0.0, does
> anyone know where they are? I'm interested in getting the names of
> people who have been acknowledged when changes are made to R.
>
> At the bottom of http://cran.r-project.org/src
You are welcome, but you have not yet followed the Posting Guide instructions,
so you may not have prompted someone familiar with your situation to respond
yet.
---
Jeff NewmillerThe . ..
You might find help more tuned to your environment by also participating on the
R-sig-mac mailing list. As always start by reading the archives and posting
guide, as well as using a search engine.
Note that bioconductor has its own website and support forums.
This list is still a good place for
"if weight element is negative set it to zero, else recalculate the weights
again"... this seems like the only way out of this loop is to calculate
negative weights... and since you set them to zero at that point they will all
be zero when you are done. Somehow I doubt that is what you intended
Thank you all for the input. That helps, although I haven’t get the exact
solution..
On Thu, 12/18/14, Chel Hee Lee wrote:
Subject: Re: [R] Add encoded special characters (greek characters) as text to
plot
To: "Jeff Newmiller" , "heyi xiao"
, "he
What about
ifelse(w < 0, 0, w)
See ?ifelse for more information.
Best,
Jorge.-
On Sat, Dec 20, 2014 at 3:26 PM, Esra Ulasan wrote:
> Hello,
>
> I have tried the solve the non-negativity constraint "if else function" in
> R. But I have done something wrong because it still gives the same
> so
Jane,
It's possible, since you are using Mac OS X Lion (10.7.5), you need the R
version for that, which can be found here:
http://cran.r-project.org/bin/macosx/old/R-3.1.1-mavericks.pkg
Cheers!
Tom
On Fri, Dec 19, 2014 at 2:56 PM, Jane Synnergren
wrote:
>
> Hi,
> I get following error when tryi
Hi to everyone,
I am trying to calculate the Bca bootstrap confidence intervals for the Pearson
coefficient.
x=Dataset$math.testy=Dataset$geo.testcor(x,y,method="pearson")[1] 0.6983799
boot.ci(cor, conf=0.95, type=bca)Erreur dans boot.out$t0 : objet de type
'closure' non indiçable
I have tried a
Hello,
I'm producing multiple dotcharts and I want each plotting area (the area
containing the dots only- not the labels) to be the same width. Currently,
the width of the area depends on the length of the labels. I've tried
different margin arguments but they change the parameter of the whole plo
I'm looking for the NEWS files for versions of R before 3.0.0, does
anyone know where they are? I'm interested in getting the names of
people who have been acknowledged when changes are made to R.
At the bottom of http://cran.r-project.org/src/base/NEWS.html it says
"Older news can be found in
Hello,
I have tried the solve the non-negativity constraint "if else function" in R.
But I have done something wrong because it still gives the same solution. I
want that, if weight element is negative set it to zero, else recalculate the
weights again. These are the codes:
for(i in 1:M){ w[,
Hello,
I want to ask about portfolio optimization in R. I have a nonpositive-definite
matrix. I have handled with the singularity. Unfortunately, quadprog etc.
optimization packages fail to solve the optimization problem under the
constraints. Because these packages takes the covariance matrix
Hi,
I get following error when trying to update the affy package to latest
version.
Error: cannot remove prior installation of package Œaffy¹
I think it is because affy requires R 3.1.1 and I have 3.0.2
I try to find a guide how I do to upgrade from 3.0.2 to latest version on
mac, but cannot fin
Thanks. This is what I was referring to:
x <- rep(NA, 3)
is.na(x)
[1] TRUE TRUE TRUE
if (is.na(x)) {print("True")}
[1] "True"
Warning message:
In if (is.na(x)) { :
the condition has length > 1 and only the first element will be used
You are of course right - the warning is generated by if(), n
This may be out of context, but on the face of it, this claim is wrong:
On 20/12/2014, 1:57 PM, Boris Steipe wrote:
"Moreover is.na() behaves differently when evaluated on its own, or as
the condition of an if() statement."
The conditions in an if() statement are not evaluated in special
conditio
Boris et. al:
Indeed, corner cases are a bear, which is why it is incumbent on any
OP to precisely define what they mean by, say, "missing",
"null","empty", etc.
Here is an evil example to illustrate the sorts of nastiness that can occur:
> z <- list(a=NULL, b=list(), c=NA)
> with(z,{
+ c(ident
This can be tricky, because depending on what the missing object is, you can
get either NULL, NA, or an error. Moreover is.na() behaves differently when
evaluated on its own, or as the condition of an if() statement. Here is a
function that may make life easier. The goal is NOT to have to pass e
Hello,
Your list seems to have only 2 elements. You can check this with
length(x)
Or you can try
lapply(x, is.null)
Hope this helps,
Rui Barradas
Em 20-12-2014 15:58, Ragia Ibrahim escreveu:
Hello,
Kindly I have a list of lists as follow
x
[[1]]
[1] 7
[[2]]
[1] 3 4 5
as showen x[[3]] doe
Hi,
On Dec 20, 2014, at 10:58 AM, Ragia Ibrahim wrote:
> Hello,
> Kindly I have a list of lists as follow
> x
> [[1]]
> [1] 7
>
> [[2]]
> [1] 3 4 5
>
> as showen x[[3]] does not have a value and it has NULL, how can I check on
> this
> how to test if x[[3]] is empty.
>
In general you can
Hello,
Kindly I have a list of lists as follow
x
[[1]]
[1] 7
[[2]]
[1] 3 4 5
as showen x[[3]] does not have a value and it has NULL, how can I check on this
how to test if x[[3]] is empty.
thanks in advance
Ragia
[[alternative HTML version dele
You are welcome, I am glad that I was able to help.
Chel Hee Lee, PhD
Biostatistician and Manager
Clinical Research Support Unit
College of Medicine
University of Saskatchewan
On 12/20/2014 03:53 AM, Kristi Glover wrote:
Thank you Prof. Lee for your code. I am sorry that I noticed that I sent
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