Tks for your advice, let the ++ problem alone, how to write an Unary operator
? Is it permitted in R?
suchas a<-2 , a%+2% will let a be 4 .
I just want to know it , i won't pollute r with it , because i know what is r .
: )
--
PO SU
mail: desolato...@163.com
Majored in Stati
Hello All,
I'm trying to figure out the (automated) way to generate heatmaps from
simple data tables with annotated rows and columns. In the end, I need
these files to be easily viewed in a browser.
The initial data tables are simple; numbers are row-normalized (values are
real numbers varying fr
On 17/10/14 17:29, PO SU wrote:
Dear expeRts,
Now i want to know how to implement an Unary operator like i++ in cpp's
synax form.
e.g. 2++ will let 2 be 3 , a<-2 ,a++ ,will let a be 3
I tried this :
'%++%'<-function(x){
x<<-x+1
}
but it have problem, the biggest one is it seem
Dear expeRts,
Now i want to know how to implement an Unary operator like i++ in cpp's
synax form.
e.g. 2++ will let 2 be 3 , a<-2 ,a++ ,will let a be 3
I tried this :
'%++%'<-function(x){
x<<-x+1
}
but it have problem, the biggest one is it seems the function need two
params lik
Hi Jeremy,
I don't know about references, but this around. See for example:
http://afni.nimh.nih.gov/sscc/gangc/tr.html
the relevant line in cor.test is:
STATISTIC <- c(t = sqrt(df) * r/sqrt(1 - r^2))
You can convert *t*s to *r*s and vice versa.
Best,
Josh
On Fri, Oct 17, 2014 at 10:32 AM
I'm trying to understand how cor.test() is calculating the p-value of
a correlation. It gives a p-value based on t, but every text I've ever
seen gives the calculation based on z.
For example:
> data(cars)
> with(cars[1:10, ], cor.test(speed, dist))
Pearson's product-moment correlation
data: sp
On 17/10/14 09:01, Greg Snow wrote:
I think we have a fortune candidate.
Second the nomination!
cheers,
Rolf
On Thu, Oct 16, 2014 at 12:35 AM, PIKAL Petr wrote:
Hi
It will be even worse with age, try to contact optician :-)
If you want to get better answer you need to provide more info
?rle
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air Quality Modeler INTERNET: cl...@math.utah.edu
Department of Ecology VOICE: (360) 407-6815
PO Box 47600FAX:(360) 407-7534
Olympia, WA 98504-7600
U
I think we have a fortune candidate.
On Thu, Oct 16, 2014 at 12:35 AM, PIKAL Petr wrote:
> Hi
>
> It will be even worse with age, try to contact optician :-)
>
> If you want to get better answer you need to provide more info about your
> file, what you did and how it failed.
>
> Cheers
> Petr
>
> aa <- 1:5
> names(aa) <- c("Eins", "Zwei", "Drei", "Vier", "Fünf")
> aa
Eins Zwei Drei Vier Fünf
12345
> table(aa)
1 2 3 4 5
1 1 1 1 1
You see? It didn't work.
> aa <- c(aa, 1, 2)
> aa
Eins Zwei Drei Vier Fünf
1234512
This is no solution for my cas
On 2014-10-11 15:14 William Dunlap wrote:
> You can use 'factors' to assign labels to small integer values. E.g.,
>> x <- c(1,2,3,4,3)
>> fx <- factor(x, levels=1:5,
>> labels=c("One","Two","Three","Four","Five")) table(fx)
>fx
> One Two Three Four Five
>1 1
On 2014-10-11 14:16 David Winsemius wrote:
> Hmisc...
Tried but has no effect on table() calls.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.ht
If I understand what you¹re trying to do, then I believe this will do the
same as your little loop:
opt.fc <- fc
opt.fc[rmax < 0.1] <- fc1[rmax < 0.1]
(this is an example of vectorization, and it¹s fundamental to how R works
and the power of R)
Then to extend it, use the same method
opt.f
Bart,
Check if the following could help you.
library(xts)
y <- c(rnorm(10,25), rnorm(10,32),rnorm(10,25), rnorm(10,20),
rnorm(10,25)); x <- seq(c(ISOdate(2000,3,20)), by = "hour", length.out =
length(y))
z <- xts( y, order.by=as.POSIXct(x))
limit <- ifelse( lag(z) < 22 | z > 27, 1, 0)
Daniel Me
Hi,
I'm currently facing the problem that I need to write a function where I get a
dataframe back which contains the time (in hours) outside the limits of a
temperature sensor, each month, and for how long exactly.
I wrote a for loop which check:- if a datapoint is outside the limit- if the
prev
I try to run an if-else command line where the else argument should be the
corresponding value of the pmax command.
#
#opt.fc is the optimal forecast
#rmax is the vector of the maximized r squared from pmax-command of 2 data
sets containing r squares
#fc1 are the estimates of
The log files may not have the name of the process ("R"), but only its
process number. A good way to look at the log files in /var/log is to
cause your 'Kill' problem then use 'ls -lstA' or 'ls -lstrA' in
/var/log to see which ones changed recently.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
O
To all:
We have an immediate opening for one PhD statistician in the Analytical
Innovation and Consultation group at Cambridge MA site. This group provides
statistical project support and consultation services to Takeda's discovery,
manufacturing, translational research, phase I clinical trial
Hello,
I would like to draw a circle on top of a pie chart (The plot does not
need to fullfill scientific standards). The circle represents the
relation of a reference-value in comparison to the summed values of the
pie-pieces. To be able to do this I partly followed:
http://rpubs.com/RobinLovelac
Hi, It works! Only one thing we need to note is when we have only one
column name as an output we do not get the results.
> d=c(11:21)
> e=c(51:61)
> data<-data.frame(embed(1:12,2))
> data=cbind(data,d,e)
> data>6
X1 X2 d e
[1,] FALSE FALSE TRUE TRUE
[2,] FALSE FA
This advice works best when you use the lapply function to load your data
frames to begin with. That way your like-structured data frames are grouped
into one list that you can loop through without complicated use of get and
assign.
dtadir <- "mydatadir"
fnames <- list.files( dtadir )
dtalist <
Hi
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Vikash Kumar
> Sent: Thursday, October 16, 2014 7:06 AM
> To: adam.n.jenkin...@gmail.com
> Cc: r-help@r-project.org
> Subject: Re: [R] Retrieving lists of colnames
>
> Hi Adam
On 2014-10-15 15:36, William Dunlap wrote:
Have you looked at recent entries in the system log files in /var/log,
especially /var/log/kern.log?
No such log file exist and other files in the directory do not make
reference to R and any general errors (e.g. internet access).
__
On 2014-10-15 09:13, Sven E. Templer wrote:
did you check the connection in R via for example:
head(readLines("http://cran.r-project.org/web/licenses/GPL-3";))
which should yield:
[1] "GNU GENERAL PUBLIC LICENSE"
[2] " Version 3, 29 June 2007"
[3] ""
[
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