Hard to say. Read the Posting Guide for useful suggestions on getting help,
including providing the output of sessionInfo() and avoiding HTML formatted
emails because what you see is not what we see.
I suggest you delete the ggplot2 subdirectory in your win-library directory and
try the
instal
Hi,
Try this:
GetPropPlot<- function (PrePropData, direction, SSThreshold, cell, stim) {
if (direction== ">") {
PropData<-ddply(PrePropData,.(SUBJECT, STIM, CELL, SIGNAL, DAY),
here(summarise),
PROP=FindGreaterThanProportion(SIMSCORE, SSThreshold))
}
PlotSubs
Hi,
This is a resend of a previous message reproduced below but with sample data to
run.
Thanks.
George Chen
Hi There,
I am having trouble carrying through an object listed in the outer function
into the inner function of a nested pair.
sample data below -
library(plyr)
SUBJE
Hi There,
I am having trouble carrying through an object listed in the outer function
into the inner function of a nested pair.
This is my code:
FindGreaterThanProportion<- function (y, SSThreshold) {
DenomCells<-length(y)
NumerCells<-subset(y,y>SSThreshold)
PropCells<-length(NumerCel
I don't think na.rm is a valid at parameter for the subset function. I would
normally use the is.na function to logically test for NA values. I also don't
know where your VALID_EMAIL variable is coming from.
a <- subset(mydf, !is.na(EMAIL_ADDRESS))
The na.strings argument to read.csv and friend
I have a dataset "mydf" with a field EMAIL_ADDRESS. When importing, I
specified:
mydf <- read.csv(file = extract, header = TRUE, stringsAsFactors = FALSE,
na.strings=c("NA",""))
I've also tried setting na.strings= c("NA","","") but I don't know if
it's appropriate to put there.
I'm running
a <-
On 01/22/2014 10:03 PM, katerina stavrianaki wrote:
Hello,
My name is Katerina, i am new to R and i am working with the ETAS package.
My goal is to fit the spatiotemporal etas model to an aftershock sequence (
atach file example.csv).I have installed the packages: spatstat, SAPP and ETAS.
By re
... and I should have added (more complexity!) that the formula method
of xyplot parses the formula and passes down what's on the left hand
side of "~" to the "y" argument of the panel function.
And if all else fails, read the docs! -- in this case for ?xyplot --
where it explicitly says:
"... A
On Jan 22, 2014, at 3:02 PM, Bert Gunter wrote:
> Well, if the professor wrote that, it wouldn't have run for him
> either!
Fortune? Or just a great line?
Don McKenzie
Research Ecologist
Pacific Wildland Fire Science Lab
US Forest Service
Affiliate Professor
School of Environmental and For
Well, if the professor wrote that, it wouldn't have run for him
either! You need to take better notes.
What's going on: You need to distinguish between formal and actual arguments.
?panel.xyplot
tells you that the formal arguments for this function are x,**y** ,...
(emphasis added) and NOT x,**z*
Hello everyone,
I'm very green on R, I'm following a Coursera course about it when I
hit a problem when I rewrote the same code the professor use in the
lecture.
I'm running Win 7 x64, R 3.0.2 x64 and the last version of Rstudio IDE
I put up this script:
library(lattice)
x <- rnorm (100)
z <-
1. When using a package from CRAN, you usually want to copy the package
author on the question. (In this case, me.)
2. The corrgram function is basically a wrapper around the pairs()
function. What you want to do doesn't seem to be possible based on this
discussion:
https://stat.ethz.ch/piperma
Any insight on issues leading to the following error modes would be
appreciated.
#Version_1 CALL
alphaDivOTU <- ggplot(data=alphaDivOTU_pt1to5, aes(y = Num.OTUs,x =
Patient,fill = Timepoint)) +
geom_bar(position = position_dodge) +
theme(text = element_text(family = 'Helvetica-Narrow',
Hello world,
I have a database with time series of concentration of nutrients for
several lakes. I wanted *one* corrgram for each
nutrient in all lakes (correlation of a single nutrient content of all
lakes in different years). The single corrgram works pretty well,
but I cannot create a page
Hi Dear helper,
I installed Rx643.0.2 on my windows 7 Enterprise computer, and I installed all
the packages as well. However, when I tried to use ggplot2 package with the
commend library("ggplot2",
lib.loc="C:/Users/JXD043/Documents/R/win-library/3.0"), I got the following
error message:" Err
Dear all,
I am preparing a graph in which values derived from 2 variable are
displayed using the stripchart function.
I have applied the factor function to separate the 2 variables in two
groups, although I noticed that the graph works anyway even without the
factorisation of the variables.
However
Hallo,
Trust, that my request is one that can be posted under this mailing list
Would like to install
lossDev, Version in the Repository 3.0.0-4
and I did it under CRAN(sources).
get as response
"versuche URL 'http://cran.at.r-project.org/src/contrib/lossDev_3.0.0-4.tar.gz'
"Content type 'ap
Dear R-helpers...
I've be trying to run a variance analysis to compare means between various
lines in various treatments.
I have 10 genotypes (GEN), tested in 2 environments (ENV) and in each
environment there are 3 repetitions (REP). Several traits were recoded (yield,
flowering, plant height.
On 22 Jan 2014, at 15:51 , William Dunlap wrote:
>> sapply(X, function(m){nlevels(factor(m$latitudes))})
>
> I think that length(unique(x)) is a more direct and easier to remember
> way of determining the number of unique values in the vector x,
> rather than nlevels(factor(x)).
However, it ma
I hereby announce the availability of the Fourth edition of my document
«Introduction à la programmation en R» (in French) in the contributed
documentation section of CRAN. The document is now accompanied by a set of
short videos on more challenging topics like creation and indexing of arrays,
that is awesome, thank you Jim!
2014/1/22 jim holtman :
> try:
>
> table(dataframe$religion[!duplicated(dataframe$name)])
>
>
> Jim Holtman
> Data Munger Guru
>
> What is the problem that you are trying to solve?
> Tell me what you want to do, not how you want to do it.
>
>
> On Wed, Jan 22, 2014
try:
table(dataframe$religion[!duplicated(dataframe$name)])
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
On Wed, Jan 22, 2014 at 11:04 AM, Simone Gabbriellini
wrote:
> Dear List,
>
> I have a data.frame
Dear List,
I have a data.frame like this:
name religion neighbor religion.neighbor
pippo a minnie a
pluto a mickey a
paperino b donald a
paperino b minnie b
when I table(dataframe$religion) my data.frame, I get
a b
2 2
of course, "paperino" is cited twice but should be counted once. Is
there an
> sapply(X, function(m){nlevels(factor(m$latitudes))})
I think that length(unique(x)) is a more direct and easier to remember
way of determining the number of unique values in the vector x,
rather than nlevels(factor(x)).
Bill Dunlap
TIBCO Software
wdunlap tibco.com
> -Original Message-
Hello,
My name is Katerina, i am new to R and i am working with the ETAS package.
My goal is to fit the spatiotemporal etas model to an aftershock sequence (
atach file example.csv).I have installed the packages: spatstat, SAPP and ETAS.
By reading the ETAS package manual i saw the data must be i
Here is the change to create a Sunday in a week if it does not exist.
I took out the Sunday (2009-11-01) for testing and you will notice
that week 201129 did not have a Sunday, so it has NaN as the result.
> x <- read.table(text = " Date nrec
+
+ 1 2011-07-17 667
+
+ 2 2011-07-18 266
+
+ 3
Hello Jim,
Thanks for this. I will study it. One thing, you wrote "# process each
week, substituting the mean if Sunday exists". Even if Sunday's data does
not exist, I need an entry for Sunday if Friday or Saturday (or both)
exist. I don't yet understand what you wrote so I am not sure if that is
Here's one way of doing it. Does not use "complicated" IFs; just
splits the data and works on it.
> x <- read.table(text = " Date nrec
+
+ 1 2011-07-17 667
+
+ 2 2011-07-18 266
+
+ 3 2009-10-29 29
+
+ 4 2009-10-30 211
+
+ 5 2009-10-31 237
+
+ 6 2009-11-01 898", header = TRUE, as.is =
Dear all,
I have written a simulation in R that has a significant running time
(probably 60-80 hours). While I can run the code on my laptop, it tends to
slow things down to a significant extent and it leads to a very high CPU
temperature overall.
Is there an easy and convenient way to run R remo
Hi John,
A server it means a computer that has an operating system, where you can
run R. For example, a Linux OS can be run in a computer connected to
your Local Area Network at home. There you can install R and you can
communicate with it via batch mode or interactive. The simplest is you
be
Hello. I am trying to work out some complicated if() logic.
I thought of using which() and if() but cannot get it.
I have a dataframe that looks like this:
head(deleteFridayTest)
Date nrec
1 2011-07-17 667
2 2011-07-18 266
3 2009-10-29 29
4 2009-10-30 211
5 2009-10-31 237
6 2
Thanks Jim.. once again your rock
On Wednesday, January 22, 2014 9:51 AM, Jim Lemon wrote:
On 01/22/2014 07:37 PM, Alaios wrote:
> Hi there,
> I would like to be able to draw a density plot or a box plot where the median
> and the median and the mean would be visible.
>
> If I decide a de
Hi
First of all without posting some of your data it is really difficult to
understand what you really want. Just select only a small part for 2 your data
frames and post an output from dput.
e.g.
dput(data3[1:10, 1:7])
dput(data4[1:10, 1:7])
Most probably resulting timestamp is in POSIXlt mo
Hi
That is great!
Thanks
On Mon, Jan 20, 2014 at 12:10 PM, Jim Lemon wrote:
> On 01/20/2014 11:44 AM, Bill wrote:
>
>> I am trying to read a csv file with a date-time field. There are many rows
>> with the same date but different times. I first want to clear the times so
>> that rows from the s
On 01/22/2014 07:37 PM, Alaios wrote:
Hi there,
I would like to be able to draw a density plot or a box plot where the median
and the median and the mean would be visible.
If I decide a density plot I need to put two big marks one for the median and
one for the mean, which I do not know how I
Hi there,
I would like to be able to draw a density plot or a box plot where the median
and the median and the mean would be visible.
If I decide a density plot I need to put two big marks one for the median and
one for the mean, which I do not know how I can achieve to put marks in a
density p
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