Hi,
May be this helps:
vec1<- 1:10
library(zoo)
rollmean(vec1,2)
#[1] 1.5 2.5 3.5 4.5 5.5 6.5 7.5 8.5 9.5
vec2<- c(5,8,9,13,20)
diff(vec2)
#[1] 3 1 4 7
A.K.
Hello,
How can I calculate half sum of 2 observ (l(i) + l(i+1))/2 ?
How compute f(i) - f(i+1) ?
please help me.
Thanks, ?cut() could be used in one line.
Categ2<-(!is.na(cut(dat1[,1],breaks=c(7,17+1
identical(Categ,Categ2)
#[1] TRUE
A.K.
- Original Message -
From: Bert Gunter
To: arun
Cc: R help
Sent: Sunday, October 6, 2013 10:18 AM
Subject: Re: [R] Create a categorical variable from n
If t(table(OBJECT)) does not work, does:
u<-as.matrix(table(OBJ))
t(u)
-i.e. use matrix operations?
On Sun, Oct 6, 2013 at 1:47 PM, LAMONT, ANDREA wrote:
>
>
>
>
> From: r-help-bounces@r-project.orgOn Behalf OfBerend Hasselman
> Sent: Sunday, October 0
On 13-10-06 3:15 PM, Rui Barradas wrote:
Hello,
How about
OBJECT <- sample(4, 20, TRUE)
t(t(table(OBJECT)))
Or simply
as.matrix(table(OBJECT))
Hope this helps,
Rui Barradas
Em 06-10-2013 19:22, Bert Gunter escreveu:
Berend et.al:
Yes.
But note that this only works for a 2-d table-- w
On 06-10-2013, at 20:32, Dennis Fisher wrote:
> unsuccessful
>
Please reply to the list and not to me only.
That way others can contribute to solving the problem.
Berend
> Dennis Fisher MD
> P < (The "P Less Than" Company)
> Phone: 1-866-PLessThan (1-866-753-7784)
> Fax: 1-866-PLessThan (1
Hello,
How about
OBJECT <- sample(4, 20, TRUE)
t(t(table(OBJECT)))
Hope this helps,
Rui Barradas
Em 06-10-2013 19:22, Bert Gunter escreveu:
Berend et.al:
Yes.
But note that this only works for a 2-d table-- which the OP indicated
was what he had; in general, one would have to explicitly pe
Berend et.al:
Yes.
But note that this only works for a 2-d table-- which the OP indicated
was what he had; in general, one would have to explicitly permute the
array(table) dimensions, e.g. via aperm() .
Cheers,
Bert
On Sun, Oct 6, 2013 at 10:44 AM, Berend Hasselman wrote:
>
> On 06-10-2013,
On 06-10-2013, at 19:30, Dennis Fisher wrote:
> R 3.0.1
> OS X
>
> Colleagues,
>
> If I execute the command:
> table(OBJECT)
> the output might look like:
> 1 2
> 25 336
>
> I would like it to appear as:
> 1 25
> 2 336
>
> I can accomplish this with:
>
R 3.0.1
OS X
Colleagues,
If I execute the command:
table(OBJECT)
the output might look like:
1 2
25 336
I would like it to appear as:
1 25
2 336
I can accomplish this with:
TABLE <- table(OBJECT)
data.frame(names(TABLE), as.numeric(TA
I think this is unwise. It depends on there being exactly 2 categories
in the desired result and silent coercion from logical to numeric, and
so does not generalize. Sometimes brevity is **not** the soul of wit
(google if necessary).
I would suggest instead that cut specify three intervals and th
On 06.10.2013 01:42, Cleber N.Borges wrote:
I tried to follow the intrusions in
http://cran.r-project.org/doc/manuals/r-patched/R-admin.html#Building-the-bitmap-files
when I type
make bitmapdll (in gnuwin directory)
or make (in gnuwin/bitmap dir)
the libpng and libjpeg seems to compile
but l
On 06.10.2013 03:11, Robert Lynch wrote:
I am trying to fit my data, attached, with the following model
CutOff <- 0
fit.full <- lme(fixed= zGrade ~ Rep + ISE +Yfrm7A +Ufrm7A +Female +White
+HSGPA +MATH +AP_TOTAL +Years +Course +
Course*Rep + Course*ISE +Course*Yfrm7A+Course
No.
Use ?cut instead.
-- Bert
On Sun, Oct 6, 2013 at 6:29 AM, arun wrote:
>
>
>
> Hi,
>
> I created 3 categories. If 1-7 and 18-24 should come under the same category,
> then:
> Categ<- findInterval(dat1$Col1,c(8,18))+1
> Categ[Categ>2]<- 1
> dat1$Categ<- Categ
> tail(dat1)
> # Col1
HI,
Try:
x1 <- (1:100)^2
A.K.
Hi
I am newbie of using R. Please help me create vector x(1^2, 2^2,
3^2,,100^2) in R. Thanks you
I am looking forward to see your reply soon,
Best wish
Andrew,
__
R-help@r-project.org mailing list
https://stat.
Hi,
I created 3 categories. If 1-7 and 18-24 should come under the same category,
then:
Categ<- findInterval(dat1$Col1,c(8,18))+1
Categ[Categ>2]<- 1
dat1$Categ<- Categ
tail(dat1)
# Col1 Col2 Categ
#45 2 -0.5419758 1
#46 21 1.1042719 1
#47 24 -1.0787079 1
#48 18
Hello all,
I have a distribution of numbers with an abundance of zeros
(zero-inflated). I thought about plotting the data in a log-log plot but
then I cannot plot the zeros in such a plot. Also log-log plots are
considered biased and not so robust. I have seen CCDF plots being used
instead of that
Well, first off, you ought to learn to post in plain text as requested in the
Posting Guide. After you have mastered that rather simple task, you might
consider searching with Google for "setting up a cran mirror" which for me
anyway produces this as the first hit:
http://cran.r-project.org/m
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