Hello,
This request looks very similar to:
http://stackoverflow.com/questions/18982662/showing-a-3d-diagram-in-r
http://stackoverflow.com/questions/18913143/non-numeric-argument-error-while-running-fft-on-a-matrix
Regards,
Pascal
2013/9/25 Babak Bastan
> I want to have a 3D diagramm. My Info
I want to have a 3D diagramm. My Information are:
- x:Time - it could be 1:n (integer number)
- Y:Frequency ---it could be 1:n like x
z:the value of z come from a function
*fft_amplitude <- function(x) {sqrt((Re(fft(x)))^2+(Im(fft(x)))^2)}*
**
The input values for this function shoul
It might worth checking out this nice workaround of JJ:
https://github.com/Rapporter/pander/blob/master/R/evals.R#L1135
Best,
Gergely
On 25 September 2013 02:35, Paul Murrell wrote:
> Hi
>
> Attempting to use a display list snapshot (as created by recordPlot())
> between R sessions has always
On Sep 24, 2013, at 3:33 PM, shanxiao wrote:
Hello, all,
Does anyone know any package in r to fit a log linear model with time
varying coefficients in R? I have googled but with no results. Your
help
will be appreciated. J
Perhaps glm (in the default stats package) with an offset of l
Hi,
Yes. It worked. Is 'stringAsFactors=FALSE' the switch to use
when reading data into a frame ? All the values I use are either numbers
or dates or strings. Sometimes while I manipulate the data by filtering,
the values seem to become factors ?
Thanks,
Mohan
From: Jim Lemon
On Sep 24, 2013, at 11:44 AM, steric wrote:
Hello,
I have a large data set that includes many soil parameters (i.e. pH,
calcium
levels, enzyme activity, etc) Does anyone have any input as to the
easiest
way to check a large data set for normality? Is there an R function/
package
that can
Hello,
It is kindly requested to post in plain text. HTML is prohibited.
Your data are stored in "abondance.txt", not in "abondance".
Hope this helps,
Pascal
2013/9/25 Pierre Paradis
> I'm a beginner, trying to do a canonical correspondance analysis with the
> vegan package, but I come up w
Hi
Attempting to use a display list snapshot (as created by recordPlot())
between R sessions has always been strongly discouraged, but as of about
R 3.0.0 it has become impossible (due to internal changes, which was
part of the reason for strongly discouraging this in the first place).
Sorry
Hello, all,
Does anyone know any package in r to fit a log linear model with time
varying coefficients in R? I have googled but with no results. Your help
will be appreciated. J
Shan Xiao
Ph.D. student of Biostatistics,
Department of Biostatistics, IUPUI.
[[alternative HTML
I'm a beginner, trying to do a canonical correspondance analysis with the vegan
package, but I come up with that : > library(vegan) > abondance.txt <-
read.table("C:/Users/abondance.txt",header=T,sep="\t") > abondance <-
cca(abondance[,-c(1,2)]~altitude, data=abondance, nhea) Error in
model.fra
On 09/25/2013 01:56 AM, Sagan Friant wrote:
Thank you! This worked beautifully. Can you help me adapt the code to
do the same thing for a plot of means? The application is not a simple
as I hoped...
plotMeans(rich.small$ALL, rich.small$sample, error.bars="se")
...
Hi Sagan,
Let's see, plotMe
Hello,
?panel.text
?grid.text
Regards,
Pascal
2013/9/24 Jonsson
> Thanks.That worked fine.Is there a way to print a number like 1 inside the
> box plotted?
>
>
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/how-to-add-a-box-to-map-plotted-by-a-levelplot-tp4676815p46768
On 09/24/2013 10:46 PM, mohan.radhakrish...@polarisft.com wrote:
Hi,
Sometimes I get a graph like the attached one. The data type could
have something to do with it. This graph does not use the color and does
not draw
a line. Earlier I used to convert the factors in the data frame to ano
I got bitten badly when a variable I created for the purpose of
recording an old set of names changed when I didn't think I was going
near it.
I'm not sure if this is a desired behaviour, or documented, or warned
about. I read the data.table intro and the FAQ, and also ?setnames.
Ben Bolker crea
On 09/25/2013 03:25 AM, Hermann Norpois wrote:
Hello,
i attached an example with two plotted vectors, respectively. And you might
see that the y and x axis are not the same scale (e.g. the third and the
last plot).
I would prefer them to be the same scale.
A toy example:
a<- c (1,2,3,4,5,6,9,
Use asp=1 in the plot command. E.g.,
par(mar=c(3,1,1,1), fig=c(0,1,.5,1)) ; plot(1:10, 1:10, asp=1)
par(new=TRUE, fig=c(0,.3,0,.5)) ; plot(1:10, 1:10, asp=1)
par(new=TRUE, fig=c(0.3,1,0,.5)) ; plot(1:10, 1:10, asp=1)
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Messag
Hello,
i attached an example with two plotted vectors, respectively. And you might
see that the y and x axis are not the same scale (e.g. the third and the
last plot).
I would prefer them to be the same scale.
A toy example:
a <- c (1,2,3,4,5,6,9,20)
> b <- c (0.2,0.4,0.6,1,0.5,1,1,0.1)
> plot
Hi all,
I am a beginner in R attempting to use TwitteR package to query lists of
Twitter followers for several users. I successfully have set "nx" as an object
assigned with the screenName I want to query but when I use the method
"nx$getFollowerIDs(n=NULL)" it returns a list of users from my o
The rpart and party packages, among others, calculate recursive
partitioning trees
for regression and classification. There are plot methods available for
showing
various features as, well, trees.
But trees can be displayed more compactly as treemaps, eg with the
treemap packge,
giving a re
Check the Jarque-Bera Test for univariate testing
(http://hosho.ees.hokudai.ac.jp/~kubo/Rdoc/library/tseries/html/jarque.bera.test.html)
and Mardia's test for multivariate testing
(http://www.inside-r.org/packages/cran/MVN/docs/mardia.test).
On Sep 24, 2013, at 6:44 PM, steric wrote:
> Hello
Ah... Thanks, Ista. Missed that typo.
-- Bert
On Tue, Sep 24, 2013 at 8:48 AM, Ista Zahn wrote:
> On Tue, Sep 24, 2013 at 11:40 AM, Bert Gunter
> wrote:
> > Time to spend some time with the docs!
> >
> > ?egexp
>
> Just to avoid any confusion: the documentation topic is ?regexp, not ?egexp
>
Hello,
I have a large data set that includes many soil parameters (i.e. pH, calcium
levels, enzyme activity, etc) Does anyone have any input as to the easiest
way to check a large data set for normality? Is there an R function/package
that can do this all at once?
Thank you in advance,
--
Vi
Had yesterday something pretty similar on the 73 installing benchmark:
Error in untar2(tarfile, files, list, exdir, restore_times) :
incomplete block on file
The downloaded source packages are in
‘/private/var/folders/n9/zxfxcd01557dc06bf3c1njy0gn/T/RtmpkwQyuQ/downloaded_packages’
On Sep 24, 2013, at 12:47 AM, Jeff Newmiller wrote:
I have stopped using the Berkeley mirror, and just automatically use
UCLA due to missing packages. However, I feel no compulsion to
extrapolate and say that there is "some sort of corruption going on
at CRAN mirrors" because it is only on
Thank you! This worked beautifully. Can you help me adapt the code to do
the same thing for a plot of means? The application is not a simple as I
hoped...
plotMeans(rich.small$ALL, rich.small$sample, error.bars="se")
On Mon, Sep 23, 2013 at 10:41 PM, Jim Lemon wrote:
> On 09/24/2013 10:05 AM
On Tue, Sep 24, 2013 at 11:40 AM, Bert Gunter wrote:
> Time to spend some time with the docs!
>
> ?egexp
Just to avoid any confusion: the documentation topic is ?regexp, not ?egexp
>
> tells you:
>
> ". (Only ^ - \ ] are special inside character classes.)"
>
> See also inline below.
>
> Cheers,
Is it correct that one does not need to escape special characters such as
"*" (are these
properly called metacharacters) inside []. If so, what is the logic to this?
mytest <- "he*llo"
sub("[*]","",mytest)
sub("\\*","",mytest)
[] is easier to read for me than \\. Is this what people tend to use?
Time to spend some time with the docs!
?egexp
tells you:
". (Only ^ - \ ] are special inside character classes.)"
See also inline below.
Cheers,
Bert
On Tue, Sep 24, 2013 at 8:30 AM, Juliet Hannah wrote:
> Is it correct that one does not need to escape special characters such as
> "*" (are
On 24-09-2013, at 16:51, arun wrote:
> Hi,
> Try:
> ME<- matrix(NA,dim(geno[1]),dim(geno)[2])
> indx0<- geno==0 & !is.na(geno)
> ME[indx0]<- Mx[indx0]+My[indx0]
> indx1<- geno==1 & !is.na(geno)
> ME[indx1]<- apply(cbind(Mx[indx1],My[indx1]),1,max)
>
I would do this to avoid the apply
ME[indx1
Hi,
Try:
ME<- matrix(NA,dim(geno[1]),dim(geno)[2])
indx0<- geno==0 & !is.na(geno)
ME[indx0]<- Mx[indx0]+My[indx0]
indx1<- geno==1 & !is.na(geno)
ME[indx1]<- apply(cbind(Mx[indx1],My[indx1]),1,max)
ME
A.K.
- Original Message -
From: JiangZhengyu
To: "r-help@r-project.org"
Cc:
Sent:
Hi,
Try:
set.seed(49)
qcd<- matrix(sample(1:20,124*69,replace=TRUE),ncol=69)
set.seed(345)
listt<- matrix(sample(1:80,124*5,replace=TRUE),ncol=5)
lst1<-list(c(15,2),c(56,54),c(15,62),c(4,14))
names(lst1)<- 2:5
S<- do.call(cbind,lapply(names(lst1),function(i)
{ww<-listt[,as.numeric(i),drop=FAL
You might be more successful if:
1. Post in plain text, not HTML, as the posting guide asks;
2. Don't post at all. Instead read the included tutorial, An Introduction
to R, or one of the many on the web that you might prefer. Nothing wrong
with being a newbie; but (imo, of course) there **is** so
Dear useRs,
although we have just (around a month ago) founded the Budapest Users of R
Network, I am more than happy to announce that 75 members already joined
and we are very close to take part in the first official meeting.
We will meet at the ELTE University, Budapest, Hungary at 18:00 (CET)
t
Dear R experts,
I have 3 matrices - "Mx", "My" and "geno" that have the same exact dimensions
(attached). I want to calculate a expression matrix (ME) of the same dimension
as well. It is a little complicated.
To calculate and for a specific cell in ME, e.g. ME[2,2],
if value of
Hi Anna
Have a look a ylab in my script - you will need to modify the label I was
going from memory on the exact label argument name . I think it is text =
"Np" or whatever you want.
The strip arguments are controlled by useOuterStrip see ?useOuterStrip
So you will need to modify as a custom sc
Try:
plot(as.numeric(data$Var1),data$Freq,ylim=c(0,700),col="green",type="o",ylab="",xlab="",las=2,lwd=2.5,xaxt="n")
A.K.
- Original Message -
From: "mohan.radhakrish...@polarisft.com"
To: r-help@r-project.org
Cc:
Sent: Tuesday, September 24, 2013 8:46 AM
Subject: [R] Graph is withou
Hi,
Sometimes I get a graph like the attached one. The data type could
have something to do with it. This graph does not use the color and does
not draw
a line. Earlier I used to convert the factors in the data frame to another
data type and drew the correct graphs.
Any idea why this ha
We would like to announce the following statistics course:
Beginner's Guide to MCMC, GAM and GAMM
When: 10-14 March 2014
Where: Elche, Alicante, Spain
For details, see: http://www.highstat.com/statscourse.htm
Course flyer: http://www.highstat.com/Courses/Flyer2014_3ElcheV2.pdf
Kind regards,
On 23.09.2013 13:48, Rhymes wrote:
I have a problem with comparing dates. i tried it like "datesub =
subset(data, 2012-11-19 < data$date)", but this doesn't work and i don't
know why.
Errr, in R:
2012-11-19 == 1982
You probably want to convert it to a Date object or Posix.. object, but
sin
On 24.09.2013 10:07, Michel wrote:
I sent this message :
Hello everyone,
R beginner, I am confronted with the need to use
Rmpf.
It helps to provide a sensible subject line and not to misspell package
names:Rmpfr.
In
On 13-09-24 6:19 AM, Babak Bastan wrote:
I do the folloowing in order to get 3D Plot:
y<-1:(point/2)
x<-20:30
z<-r[1:(point/2)]
persp(x,y,z,theta = 135, phi = 30, col = "green3", scale = FALSE,
ltheta = -120, shade = 0.75,
border = 1)
y:
[1] 1 2 3 4 5
x:
[1] 20 21 22 23 24 25
z:
[1
Hi,
I have a problem with running a script in parallel with the foreach function
for computing linear models at every voxel of a set of 3D images. When I run
it using %do%, it runs fine and I get the correct output but when I run it
with %dopar% then my main output is not correct. The problem insi
Thanks.That worked fine.Is there a way to print a number like 1 inside the
box plotted?
--
View this message in context:
http://r.789695.n4.nabble.com/how-to-add-a-box-to-map-plotted-by-a-levelplot-tp4676815p4676825.html
Sent from the R help mailing list archive at Nabble.com.
That worked fine, thanks. But only worked when the values are positive but
when I added negative values, the box was wrong. May be the order I lat and
long should be different?any ideas
--
View this message in context:
http://r.789695.n4.nabble.com/how-to-add-a-box-to-map-plotted-by-a-levelplot
I do the folloowing in order to get 3D Plot:
y<-1:(point/2)
x<-20:30
z<-r[1:(point/2)]
persp(x,y,z,theta = 135, phi = 30, col = "green3", scale = FALSE,
ltheta = -120, shade = 0.75,
border = 1)
y:
[1] 1 2 3 4 5
x:
[1] 20 21 22 23 24 25
z:
[1] 4811.003.5930256.9686664.9
Hi,
I prefer to build my packages on Linux!
I changed the object trPaths as below,
After R CMD build TinnRcom on Linux and did the installation
on Windows from the source code: It worked very well!
I thank all who contributed to the solution and apologize for my lack
of knowledge in this area.
> "M" == Michel
> on Fri, 20 Sep 2013 17:56:58 +0200 writes:
> Hello everyone, R beginner, I am confronted with the need
> to use Rmpf.
why ?
> In my first scripts I made use of
> X=read.table(file.choose(), header=FALSE, sep=",",dec=".")
> X=as.matrix(X)
well
Dear R-useRs,
I'm looking for an R-function for censored linear regression. I have the
following data
x1 <- rnorm(100)
x2 <- rnorm(100)
y <- x1 + 2*x2 + rnorm(100,0,0.5)
stat <- rep(1,100)
stat[50:100] <- 0
data <- data.frame(y,x1,x2,stat)
y is the dependent variable, x1 and x2 are the indepe
Hi Anna
I have never used doubleYScale and I am not sure what you want but try this
You need to do this first if columns not correct saves doing later - I
forgot to mention it for Week but as you have given the order for the
factors do it as well
SummPdata[,1] <- as.numeric(SummPdata[,1])
SummNd
At 02:26 23/09/2013, peake wrote:
Thanks for the advice. Like I said, I am still pretty new to R, and stats
in general. I tried wading through the search results on google, but I
didn't really find anything that I could understand. I am working with
percentages as my dependent variable, and I am
Hello,
One way is:
> levelplot(r, col.regions=myPal) +
> layer(sp.polygons(wrld_simpl, lwd=0.5)) +
> layer(panel.rect(2,45,8,51))
Regards,
Pascal
2013/9/24 Jonsson
> conne2 <- file("C:\\ome1440s.bin","rb")
> bioms<- readBin(conne2, integer(), size=1, n=1440*720, signed=F)
>
conne2 <- file("C:\\ome1440s.bin","rb")
bioms<- readBin(conne2, integer(), size=1, n=1440*720, signed=F)
library(raster)
library(rasterVis)
data(wrld_simpl)
library(maptools) ## needed for wrld_simpl
r <- raster(nrow=720, ncol=1440)
r[] <- bio
respectd sir,
i am working on regional frequency analysis of flood flow data and want to use
packages lmomRFA, lmom, imomco,etc andby using these i want to find RMSE ,
errorbounds and absolute biase but could not make it clear to use, please help
regards
atta muhammad asif
assistant professor
at
I sent this message :
Hello everyone,
R beginner, I am confronted with the need to use
Rmpf.
In my first scripts I made use of
X=read.table(file.choose(), header=FALSE,
sep=",",dec=".")
Hi David,
Thank you for your interest and advice regarding this analysis.
I went to double check that the subset process worked properly with the
select=c(-time,-status) and I can confirm that it did.
Best,
Erel
-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net]
Se
On 24/09/2013 03:51, Jose Claudio Faria wrote:
I think I found the main problem!
I am developing the package under Linux and after R CMD build,
manually compressing the folder TinnRcom inside of the folder
TinnRcom.RCheck and installing in Windows.
And how on earth did you expect the helpers h
On 23/09/2013 22:43, MacQueen, Don wrote:
The very first response, from Jeff Newmiller, included a link
http://efele.net/maps/tz/world/
which says it has offers a shapefile of timezones of the world.
An outline of a solution, then it to
download the shapefile
load it into R
input y
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