You seem confused. You are programming in R, and asking questions about bash on
an R mailing list. You seem to need to learn the difference between environment
variables and bash variables and how processes acquire and transfer environment
variables, which is really an operating system concept a
Dear R users;
I am MSc student and I want to write my own function, but it cant be
completed. please help me for solve it. here is my code:
pah1$P = (pah1$Fluoranthene/pah1$Pyrene)
T = function(x){
for (i in 1:length(pah1$P))
if (i >= 1)
print("Combustion")
if (i < 1)
print("Petroleum")
}
T(pah1$P
Dear R users;
I have a question about surface plot that show me spatial variability of
parameter. I have a data frame with 6 variables and X and Y for coordinate
system.
X Y pH
..... ...
so I want to create a surface plot for my data.
please help me.
many thanks.
Hello,
It is difficult searching for previous posts about this since the keywords are
short and ambiguous, so I hope this is not a duplicate question.
I can easily declare an array on the command line.
$ names=(X Y)
$ echo ${names[0]}
X
I am unable to do the same from within R.
> system("name
Hello,
I'm using the prefmod package, with pattPC fit, and I'm having some trouble
interpreting the results.
I am giving two different species of animal a choice between two of three
different patterns, V, H, and 45. I have run a number of paired tests with
different combinations of the above,
I'm an undergrad who is new to MCMCpack and I haven't been able to find an
answer to my problem online yet: I'm attempting to run MCMClogit with a
Cauchy proper prior but I'm getting the warning "Cannot calculate marginal
likelihood with improper prior" (my purposes require the marginal likelihood
Dear list,
I am working with R to download numerous html source code from which the
data extracted will be further processed.
The problem is the Chinese character in the html source code are all
garbled and I can't really find a way to convert them to something readable.
This problem persists on ub
Hi,
This link may help:
http://stackoverflow.com/questions/14476961/why-do-i-get-position-dodge-requires-constant-width-even-though-widths-are-con
A.K.
- Original Message -
From: David Arnold
To: r-help@r-project.org
Cc:
Sent: Sunday, July 28, 2013 5:41 PM
Subject: [R] ggplot position
Hi,
library(ggplot2,plyr)
qplot(carat,depth,data=diamonds,
geom="boxplot",
group=round_any(carat,0.1,floor),
xlim=c(0,3))
Typing:
warnings()
Gives me:
Warning messages:
1: position_dodge requires constant width: output may be incorrect
How should the above code be adjusted t
Hi,
?max
?min
max(mydates)
#[1] "2007-06-22"
min(mydates)
#[1] "2004-02-13"
max(mydates)-min(mydates)
Time difference of 1225 days
max(as.numeric(mydates))-min(as.numeric(mydates))
#[1] 1225
A.K.
- Original Message -
From: Peter Maclean
To: "r-help@r-project.org"
Cc:
Sent: Sunday,
On Jul 28, 2013, at 12:20 PM, Peter Maclean wrote:
> #This my look trivial but has been killing my time
> #I want to extract most current and old date from mydates #variable that has
> more than 10,000 observation.
> #Get days
> # use as.Date( ) to convert strings to dates
> mydates <- as.Date
If I read this correctly:
mydates <- as.Date(c("2007-06-22", "2007-05-21", "2004-04-13",
"2004-03-11","2004-02-13"))
xx <- min(mydates)
yy <- max(mydates)
yy-xx
John Kane
Kingston ON Canada
> -Original Message-
> From: pmaclean2...@yahoo.com
> Sent: Sun, 28 Jul 2013 12:20:30 -0700 (
#This my look trivial but has been killing my time
#I want to extract most current and old date from mydates #variable that has
more than 10,000 observation.
#Get days
# use as.Date( ) to convert strings to dates
mydates <- as.Date(c("2007-06-22", "2007-05-21", "2004-04-13",
"2004-03-11","2004-
Inline.
On Sun, Jul 28, 2013 at 10:38 AM, Rui Barradas wrote:
> Hello,
>
> You should Cc the list, the odds of getting more and better answers is
> greater.
> I don't believe what you want is statistically sound, why more than one
> bandwidth? Anyway, if density() doesn't do what you need, you ca
Hello,
You should Cc the list, the odds of getting more and better answers is
greater.
I don't believe what you want is statistically sound, why more than one
bandwidth? Anyway, if density() doesn't do what you need, you can try to
look for similar functions in other packages. Try the followin
Hi all,
Tnx for all the replies:
Mike Colvin provided a simple answer in one step.
Bats.cast <- dcast(data = Bats.melt, formula = Species ~ Location, fill =0)
tnx all for the reminder of potential issues of willy nilly replacing
missing data with zeros.
In this case the 0 [zero value] for NAs
Hi all,
I am using reshape2 to reformat a data frame and all is great using:
Bats.melt <- melt(data = Bats)
Bats.cast <- dcast(data = Bats.melt, formula = Species ~ Location)
dput(Bats.cast,'C:/=Bat data working/Nica_new/Bats_niche.robj')
write.csv(Bat.cast,'C:/=Bat data working/Nica_new/test_
The mechanics of replacing missing values are very easy in R
> tmp <- data.frame(a=1:4,b=c(5,6,NA,8))
> tmp
a b
1 1 5
2 2 6
3 3 NA
4 4 8
> tmp[is.na(tmp)] <- 0
> tmp
a b
1 1 5
2 2 6
3 3 0
4 4 8
>
But pay attention to Bert's warning. This is most likely the wrong
statistical way to respon
Inline.
--Bert
On Sun, Jul 28, 2013 at 6:19 AM, Neotropical bat risk assessments
wrote:
> Hi all,
>
> I am using reshape2 to reformat a data frame and all is great using:
>
> Bats.melt <- melt(data = Bats)
>
> Bats.cast <- dcast(data = Bats.melt, formula = Species ~ Location)
>
> dput(Bats.cast,
Hi all,
I am using reshape2 to reformat a data frame and all is great using:
Bats.melt <- melt(data = Bats)
Bats.cast <- dcast(data = Bats.melt, formula = Species ~ Location)
dput(Bats.cast,'C:/=Bat data working/Nica_new/Bats_niche.robj')
write.csv(Bat.cast,'C:/=Bat data working/Nica_new/test_
Thanks very much Ben for your extremely helpful response.
I have loads of data so this worked fine.
cheers,
Stan
On Saturday, July 27, 2013, Ben Bolker wrote:
> Stanislav Aggerwal gmail.com> writes:
>
> >
> > I have searched the r-help archive and saw only one
> > unanswered post related
> > to
Hello,
Try function ?density, argument bw, in package stats.
Hope this helps,
Rui Barradas
Em 28-07-2013 04:18, Ms khulood aljehani escreveu:
HelloI want to know how can
implement variable bandwidths for kernel
density estimation in R.
What the packages that
I need to use? And what the
On Jul 27, 2013, at 00:00 , Miller Ruiz wrote:
> Hello
>
> I'm trying to run the script below for making a boxcox transformation of
> some variables contained on an excel file, but i can't get it. I ever have
> the same message :
> error : $ operator is invalid for atomic vectors
>
> One of th
HelloI want to know how can
implement variable bandwidths for kernel
density estimation in R.
What the packages that
I need to use? And what the command?
Thank You Khulood H.
[[alternative HTML version deleted]]
Dear Arun,,
Thank you. its perfect! wow! thank you very much..and David, thank you for
you too.. its such a help. I am so sorry it must've been confusing at the
beginning..
really, I dont know how to thank you..
well do you mind if I ask you how can you be so expert? what kind a book or
training
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