Hi,
I have the following problem in simulating samples from a bivariate
exponential distribution with the following construction:
Start with three independent exponential random variables say W1,W2 and W3
with intensity parameters lambda 1, lambda 2 and lambda 3 respectively.
Now I construct a bi
Hello,
I have heard that Chrome OS is Linux based, so I am wondering if there is
anyway to use R on a Google Chromebook using one of your Linux packages. If
not, do you plan on making a version of R that is compatible with
chromebooks or cloud based?
[[alternative HTML version deleted]]
Is there a R package or function that will multiple an arbitrary number of
matrices supplied to it, preferably optimizing the sequence
R_function(matA, matB, matC, matD,)
return matA %*% matB %*% matC %matD %
and optimizing wether it is better to do A(BC) or (AB)C ?
Thanks,
Shi
Nick
try
as.numeric(
strsplit(gsub("[[:alpha:][:punct:][:space:]]{2,}",",",tmpstr),",")[[1]][-1]
)
see ?regexpr for information
HTH
Duncan
Duncan Mackay
Department of Agronomy and Soil Science
University of New England
Armidale NSW 2351
Email: home: mac...@northnet.com.au
At 15:06 16/06
HI,
One way would be:
library(stringr)
tmpstr = "The first number is: 32. Another one is: 32.1.
Here's a number in scientific format, 0.3523e10, and
another, 0.3523e-10, and a negative, -313.1"
pattern<-
"(\\d)+|(\\d+\\.\\d+)|(-\\d+\\.\\d+)|(\\d+.\\d+e\\d+)|(\\d+\\.\\d+e-\\d+)"
str_extract_all
Hi all,
I have been beating my head against this problem for a bit,
but I can't figure it out.
I have a series of strings of variable length, and each will
have one or more numbers, of varying format. E.g., I might
have:
tmpstr = "The first number is: 32. Another one is: 32.1.
Here's a
Hi,
It is better to ?dput() the dummy dataset.
I made up some data for female==0
dat1<- read.table(text="
pbnr dat dep dys sop ago mis age female messpunkt2 messpunkt1 tage
eintrittsjahr
1 10023 1994-02-21 0.75 1.00 0.50 0.50 0.75 35 1 8817 8817 0
1994
2 10023
The r-help list should institute a prize for "Most Obtuse Question
of the Month". This one should be a shoe-in for the June 2013 prize.
cheers,
Rolf Turner
On 16/06/13 12:08, Graham McDannel wrote:
I am attempting to optimize a function I have developed using optim.
I am gettin
On 06/16/2013 04:14 AM, Birdada Simret wrote:
Thank you.
@David: The example is exactly this:
time <- seq(0,72,6)
music <- c(0.05,0.18,0.25,0.31,0.32,0.34,0.35,
0.36,0.37,0.38,0.39,0.40,0.41)
actor <- c(0,1000,2000,3000,4000,5000,6000,7000,8000,9000,1,11000,12000)
par(mar=c(5, 4, 4, 4) + 0.1)
Not unless you read the Posting Guide, stop posting in HTML mail format, and
provide a reproducible example.
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#.
I am attempting to optimize a function I have developed using optim.
I am getting the below error message:
Error in n < 1: 'n' is missing
Could some one provide some additional clarity regarding this message and
what it entails, as well as, how to rectify this issue.
Thanks
[[alternati
On Jun 15, 2013, at 2:38 PM, Fabrice Tourre wrote:
> Dear expert,
>
> How can I make follow codematrix function more faster?
>
> top20.dat <- top20.dat[,7:length(top20.dat[1,])]
> top40.dat <-
> read.table("top40snps.ped",header=F,sep="\t",stringsAsFactors=F)
Did you attach a file with a non-'
table(scltotal$female,scltotal$dys)
Best Regards,
Bhupendrasinh Thakre
Sent from my iPad
On Jun 15, 2013, at 3:58 PM, Sophie Homeyer
wrote:
> Hi,
> i am new to this forum and not sure how it works,
> I am trying to do deskriptive descripe my data in terms of gender:
>
> head(scltotal)
>
>
Dear expert,
How can I make follow codematrix function more faster?
top20.dat <- top20.dat[,7:length(top20.dat[1,])]
top40.dat <-
read.table("top40snps.ped",header=F,sep="\t",stringsAsFactors=F)
row.names(top40.dat) <- top40.dat[,1]
top40.dat <- top40.dat[,7:length(top40.dat[1,])]
codematrix <- f
Hi,
i am new to this forum and not sure how it works,
I am trying to do deskriptive descripe my data in terms of gender:
head(scltotal)
pbnrdat dep dys sop ago mis age female messpunkt2
messpunkt1 tage eintrittsjahr
1 10023 1994-02-21 0.75 1.00 0.50 0.50 0.75 35 1 881
On Jun 15, 2013, at 11:41 AM, jcrosbie wrote:
> There are some CSV file from the link below.
>
> I'm having trouble installing the package. Is this the package I have to use
> or is there another one I need to use? If so how do I get this one loaded.
>
>
>
> https://www.enmax.com/Power/Ener
There are some CSV file from the link below.
I'm having trouble installing the package. Is this the package I have to use
or is there another one I need to use? If so how do I get this one loaded.
https://www.enmax.com/Power/Energy+Retailers/Settlement+Reports/Profile+settlement+report.htm
On Jun 15, 2013, at 11:14 AM, Birdada Simret wrote:
> Thank you.
> @David: The example is exactly this:
> time <- seq(0,72,6)
> music <- c(0.05,0.18,0.25,0.31,0.32,0.34,0.35,
> 0.36,0.37,0.38,0.39,0.40,0.41)
> actor <- c(0,1000,2000,3000,4000,5000,6000,7000,8000,9000,1,11000,12000)
> par(mar=
Thank you.
@David: The example is exactly this:
time <- seq(0,72,6)
music <- c(0.05,0.18,0.25,0.31,0.32,0.34,0.35,
0.36,0.37,0.38,0.39,0.40,0.41)
actor <- c(0,1000,2000,3000,4000,5000,6000,7000,8000,9000,1,11000,12000)
par(mar=c(5, 4, 4, 4) + 0.1)
plot(time, music, pch=16, axes=F, ylim=c(0,1),
Hi all,
I'm analysing an e-mail network. I loaded the following information in a
directed igraph:
*Vertex* types: person, e-mail
V(g)[ type == "person" ]
V(g)[ type == "email" ]
*Edge* types: sends, receives
E(g)[ type == "send" ]
E(g)[ type == "receive" ]
So for example:
John --send--> email1
Hi,
May be this helps:
dat1<- read.table(text="
pbnr dat dep dys sop ago mis age female
1 10023 1994-02-21 0.75 1.00 0.50 0.50 0.75 35 1
2 10023 1994-05-25 0.75 1.00 0.50 0.50 0.75 35 1
3 10028 1994-02-01 2.00 1.75 3.00 0.50 1.50 42 1
4 10028 1999-01-15 1.25 0.75 2.25
On 12.06.2013 16:35, Paul Johnson wrote:
I would appreciate ideas about MS Windows install issues. I'm at our stats
summer camp and have been looking at a lot of Windows R installs and there
are some wrinkles about R_LIBS_USER.
On a clean Win7 or Win8 system, with R-3.0.1, we see the user libr
Hi,
You could try this:
#In one of the list element
SampleSummary$ConcLow
# Min. 1st Qu. Median Mean 3rd Qu. Max. NA's
# 0.4200 0.6100 0.7300 0.7373 0.8150 1.6600 1
#additional entry for NA. You may need to check the data and remove the
missing value. Here, I removed t
Hi,
You could use ?twoord.plot() from library(plotrix):
library(plotrix)
dat2<- data.frame(month,music,actor)
dat2$month<- factor(month,labels=c(month.abb,"Pag"))
dat2New<-dat2[order(dat2$month),]
with(dat2New,twoord.plot(month,music,actor,
lylim=c(0,1),rylim=c(0,13000)
On Jun 15, 2013, at 7:46 AM, Ali Arslan Kazmi wrote:
> Greetings,
>
> Apologies if this turns out to be a very silly question, but because I am the
> only person learning/using R at my workplace, I have no choice but to ask
> folks here.
> I have been using Gsub to change some expressions in
On Jun 15, 2013, at 5:18 AM, Birdada Simret wrote:
> Hi dear all, the following code is correct. but I want to use non-numeric
> x-axis, for example
> if I replace time <- seq(0,72,6) by
> month <-
> c("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec","Pag")
>
> Ofcourse
Greetings,
Apologies if this turns out to be a very silly question, but because I am the
only person learning/using R at my workplace, I have no choice but to ask folks
here.
I have been using Gsub to change some expressions in my Corpus object. After
applying the gsub function, say
newCorpus<
confirmed.
On Sat, Jun 15, 2013 at 10:50 AM, Chet Seligman wrote:
> Can anyone confirm that R runs on Widows 8?
>
> Thanks,
> Chet Seligman
>
> [[alternative HTML version deleted]]
>
> __
> R-help@r-project.org mailing list
> https://stat.ethz.
On Sat, 15 Jun 2013, Chet Seligman wrote:
Can anyone confirm that R runs on Widows 8?
You can : http://lmgtfy.com/?q=site%3Astat.ethz.ch+%22windows+8%22
Thanks,
Chet Seligman
[[alternative HTML version deleted]]
Please read the Posting Guide, and asi it requests post in plain te
Seems unlikely but it runs on Windows 8
John Kane
Kingston ON Canada
> -Original Message-
> From: chet.selig...@gmail.com
> Sent: Sat, 15 Jun 2013 07:50:45 -0700
> To: r-help@r-project.org
> Subject: [R] Widows 8
>
> Can anyone confirm that R runs on Widows 8?
>
> Thanks,
> Chet Seligm
Can anyone confirm that R runs on Widows 8?
Thanks,
Chet Seligman
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/p
On 12.06.2013 15:08, Tim Smith wrote:
Hi,
I was trying to install the GGally package, but was getting errors. Here is
what I get:
install.packages("GGally")
Installing package(s) into ‘/Users/ts2w/Library/R/2.15/library’
(as ‘lib’ is unspecified)
Warning in install.packages :
 pa
Hi dear all, the following code is correct. but I want to use non-numeric
x-axis, for example
if I replace time <- seq(0,72,6) by
month <-
c("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec","Pag")
Ofcourse I use factor(month) instead of time; but I didn't get similar
plo
Hello,
Yes, you can do it like you say. Or you can unsort first and multiply later.
mat5.1 <- sapply(seq_len(ncol(ord)), function(i) mat4[order(ord[,i]), i])
multip<-mat4*2
mat5.2 <- sapply(seq_len(ncol(ord)), function(i) multip[order(ord[,i]), i])
identical(mat5.1*2, mat5.2) #TRUE
Also, it
Hello,
If I understand it correctly, the following should sort all columns of
matrix3 and then unsort the sorted matrix.
ord <- apply(matrix3, 2, order)
# sort matrix3
mat4 <- sapply(seq_len(ncol(ord)), function(i) matrix3[ord[,i], i])
mat4
# unsort mat4
mat5 <- sapply(seq_len(ncol(ord)), f
On 13-06-14 10:52 AM, anferg...@aol.com wrote:
All:
Recently my R session freezes when I try to open a file or save a new script after I have
run existing scripts. The session freezes so that I can no longer click on any windows
within the R session -- including other scripts that are open o
On 13-06-14 7:02 PM, Dan Keshet wrote:
I am using xtable version 1.7-1 built for R 3.0.1 on:
R version 3.0.1 (2013-05-16)
Platform: i686-pc-linux-gnu (32-bit)
Sometimes, not every time, when I load xtable or attempt to load the
help, I get an error such as this "Error: cannot allocate vector of
Hi. Here is an example of sorting matrix columns:
> mat <- matrix(10:1, ncol=2, byrow=TRUE)
> mat
[,1] [,2]
[1,] 109
[2,]87
[3,]65
[4,]43
[5,]21
> apply(mat, 2, function(x) x[order(x)])
[,1] [,2]
[1,]21
[2,]43
[3,]65
[4,]8
I would like to sort matrix3, so that every column in output matrix is
sorted. Also I have to "unsort" it later on.
matrix1<-matrix(rnorm(100,354,78),ncol=10)
matrix2<-matrix(rnorm(100,225,102),ncol=10)
matrix3<-cbind(matrix1,matrix2)
nrCol<-length(matrix3[1,])
class1<-1:10
for(i in 1:nrCol)
{
Dear all
I want to call R repeatedly in batch mode from a bash script that is then
submitted to torque.
My calls to R depend on optional arguments.
When I introduce these arguments as literals, the calls work fine, for instance:
R CMD BATCH --no-save "--args PERIOD='08' YEAR='2008' SC='BAU' "
Hi everyone,
I am new with spatial data analysis in R and I'm not
able to read a shape because of this error message but the shapefile is in my
work directory. Here are my commands; ogrListLayers("border.shp"),
border=readOGR("border.shp","border"). What does it mean?. An
Hi,
Thanks in advance.
I am using R-3.0.1 on Windows XP.
May I request you to assist me for the following please.
I have a data set where each instance has two or more levels. As for example,
level 1 (binary): 0, 1; level 2 (binary): 0, 1 and so on. These levels are
target variables. The
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