Thank you Jeff for that..
Thanks Tyler.. that worked.. i put the image in inst/extdata and then built
the pkg..and gave the path using system.file().. thanx again
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R-help@r-project.org mailing list
https:/
*Hello All,*
I tried figuring out the problem, I was trying to use laplacedot to predict
the long term, which however would not do a good job.
Then, I tried to do a point by point prediction and building the model
again, everytime. It shows me better results. I tried writing my kernel
function (m
I recently included a .bib file in a package in the directory:
package_name/inst/extdata
I then recall this file using: <- system.file("extdata/bibTest.bib", package =
"metaDAT")
I assume something similar could be helpful here.
> From: jdnew...@dcn.davis.ca.us
> Date: Sun, 9 Dec 2012 22:11
On 10-12-2012, at 00:04, DIMITRIS KARAKOSTIS wrote:
>
> HiThanks for the answer.My actual problem is that I am trying to execute
> rscript through php by using the exec function.I am trying to execute a very
> simple Rscript by using PHP and the exec function.When I run the rscript
> through
http://cran.r-project.org/doc/manuals/r-release/R-exts.html#Data-in-packages
Don't get stuck on your idea that the file is a gif... once you load it into
memory it is an R object.
---
Jeff NewmillerThe
Hi,
What goes wrong when the following error shows up:
> Error in reconcilePropertiesAndPrototype(name, slots, prototype,
> superClasses, :
> No definition was found for superclass “sequencesuperclass” in the
> specification of class “sequences”
Has this something to do with recursive class
My R version: 2.15.1- windows
While creating an R package in windows, i want to include an image (a .gif
image) that will finally be in the package. A function in my package will
call the gif image. Where should i put the images before running "Rcmd
build mypkg" or "Rcmd INSTALL --build mypkg", so
I have a long equation that I need to break in the R documentation of a package
or it trails off the right hand side of the page. Here's the formula:
\deqn{Cov(r_{ist}, r_{iuv})= [.5\rho_{ist}\rho_{iuv}(\rho_{isu}^2 +
\rho_{isv}^2 + \rho_{itu}^2 + \rho_{itv}^2) + \rho_{isu}\rho_{itv}+
\rho_{i
HiThanks for the answer.My actual problem is that I am trying to execute
rscript through php by using the exec function.I am trying to execute a very
simple Rscript by using PHP and the exec function.When I run the rscript
through terminal (mac osx) then I get the output that I want (a plot).Bu
Hi there everyone,
I have the following model (this is naturally a simplified version just for
showing my problem, in case you're wondering this is a translog cost
function with the associated cost share equations):
C ~ á + â1 log X + â2 log Y + ã1 log Z + ã2 log XX
C1 ~ â1 + â2 log YY + ã1 log Z
Your problem seems to be unfamiliarity with this operating-system-specific
feature. You should be reading the OS documentation (e.g. "man fifo" and
learning how to use the feature in general before using it in R. (Hint:
off-topic here.)
Some words to the wise: Make sure you test with two proces
Friends
I need to get R reading from a fifo. I want it to block till there is some
data in the fifo, consume what input it gets there, do some thing with it
then loop back and block again.
Very simple. Yes? No.
The example in the documentation works OK..
zz <- fifo("foo-fifo", "w+")
Yes, I thought it was good, but for a book on graphics the coin problem was
noticeably lacking in clarity.
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#.
Chris Beeley gmail.com> writes:
> Such a strange problem, can't figure it out at all. Using binomial glm
> models, and the step() function, so the call looks like this:
>
> sectionmodel = glm(formula = Target3 ~ S1Q12_NUM.1 + S1Q9_NUM.1 + S1Q5_NUM.1 +
[snip]
> But when I run step() on the res
Dear Professor Carlson
Thank you so much! The $Structure command displays the loadings with the same
style of column heading as the $scores (i.e. [,1] [,2][,3]
[,4][,5] [,6] [,7] [,8] [,9] [,10]
[,11]), and makes me so much more c
On 12/10/2012 05:52 AM, Mark Leeds wrote:
Below has nothing to do with R but people into statistics ( or even those
not into statistics. it's very basic ) might find it interesting. I can't
say anything about the book itself.
http://press.princeton.edu/chapters/s8863.pdf
Another brilliant piece
Hello-
Such a strange problem, can't figure it out at all. Using binomial glm
models, and the step() function, so the call looks like this:
sectionmodel = glm(formula = Target3 ~ S1Q12_NUM.1 + S1Q9_NUM.1 + S1Q5_NUM.1 +
S1Q7_NUM.1 + S1Q8_NUM.1 + S1Q6_NUM.1 + S1Q10_NUM.1 + S1Q12_BURG.1 +
S1
On 09-12-2012, at 20:36, DIMITRIS KARAKOSTIS wrote:
>
>
>
> Dear all,
> I have a very simple question. I am trying to find where islocated the
> rscript in mac os x. The r is installed in the applications folderbut I can
> not find the rscript.
Which R do you mean? R.app?
There is also a c
Dear all,
I have a very simple question. I am trying to find where islocated the rscript
in mac os x. The r is installed in the applications folderbut I can not find
the rscript.
Thank you.Dimitris
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_
Dear all,
Sorry for my slow answer, and thanks for all the suggestion.
On 23 Jul 2012, at 22:25, William Dunlap wrote:
> You can use the odd idiom substitute(...()) to get the unevaluated ...
> arguments:
>> f1 <- function(x, ...) substitute(...())
>> f1(1, warning("Hmm"), stop("Oops"), cat("so
Below has nothing to do with R but people into statistics ( or even those
not into statistics. it's very basic ) might find it interesting. I can't
say anything about the book itself.
http://press.princeton.edu/chapters/s8863.pdf
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_
If you are willing to rethink the definition of your special function, the
process can be simplified. The function lmc() log-mean centers a single
grouped numeric vector. Then sapply() can be used to center a batch of them.
> lmc <- function(x, g) unsplit(lapply(split(log(x), g), scale,
scale=FALS
On Dec 9, 2012, at 9:06 AM, 歐詠芝 wrote:
Dear all:
I have simulated ability(500 examinees) and difficulty(40 items).
as:
N <- 500
theta <- rnorm( N )
I <- 40
b <- seq( -2 , 2 , len=I )
p1 <- plogis( outer( theta, b, "-" ) )
I want to simulate 10 responses matrix
through this syntax: respR <- 1
Dear all:
I have simulated ability(500 examinees) and difficulty(40 items).
as:
N <- 500
theta <- rnorm( N )
I <- 40
b <- seq( -2 , 2 , len=I )
p1 <- plogis( outer( theta, b, "-" ) )
I want to simulate 10 responses matrix
through this syntax: respR <- 1 * ( p1 > matrix( runif( N*I ) , nrow=N ,
nc
Hi,
You could also use:
newFunction1<-function(x) {t(t(log(x))-colMeans(log(x)))}
res1<-by(dat1[c("Units","AveragePrice")],dat1["Location"],newFunction1)
res1
#Location: Los Angeles
# Units AveragePrice
#1 0.213682659 0.071790268
#2 -0.005370907 -0.072872965
#3 -0.208311751 0.0010826
by the, just in case anyone is wondering, on macosx 10.8 with Fink
0.34.4 and r-base215 (et al.), the following caused the R package rgl to
build, install, and (seemingly) work:
install.packages("rgl", configure.args='--with-gl-libs=/usr/X11/lib \
--disable-cocoa')
(without --with-gl-lib
bwplot is a trellis function. There is something very basic about the way that
library works that any intro to trellis/lattice should tell you:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-do-lattice_002ftrellis-graphics-not-work_003f
--
For example,> library(orthopolynom)> A<- chebyshev.s.polynomials( 2,
normalized=FALSE)and A is a list of the Chebyshev polynomials with degree 0, 1
and 2. I want to define a function s.t.f(x)=T0(x)+T1(x)+2*T2(x)where T0,T1,T2
are the Chebyshev polynomials with degree 0, 1 and 2, respectively.
O
My macro doesn't work for bwplot. But is working elsewhere.
What changes should i make to fix my macro.
Thanks.
The complete code sample is:
library(gtools)
library(lattice)
pic <- defmacro(fn, plotfunc, expr={png(filename=fn); plotfunc; dev.off()})
# this one fails.
pic("bw.png", {bwplot(Speci
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