Hello,
I can see several things that are not right or may go wrong. (Without an
actual dataset, this is just a series of hints.)
1. The read.csv statement. Like read.table, it creates a data.frame,
which defaults to reading strings as factors, coded internally as
integers. Sometimes there ar
Hello,
Try the following.
install.packages("sos") # to install the package
library(sos) # to load the package nto R session
finFn("xlsx")# find it
Have fun.
Hope this helps,
Rui Barradas
Em 16-07-2012 06:17, Karan Anand escreveu:
hi,
i am new to r ,i have a xl
On 15/07/2012 19:57, chester123 wrote:
Hi there and thanks in advance.
Nowadays I am working on the plug-in bandwidth selection with R. Firstly, my
So why use package KernSmooth and not the methods in R itself?
1010 data is the return rate from Yahoo Finance.
Secondly, my code is following:
hi,
i am new to r ,i have a xlsx data with me with 12 sheet in it and
need to convert it to csv first and then need to convert it into time
series ,so if u can pls guide me a little how to do it.
Regards
karan
[[alternative HTML version deleted]]
Hi
I got the following error using as.xts
Error in xts(x, order.by = order.by, frequency = frequency, ...) :
NROW(x) must match length(order.by)
Here is how the data looks like
> d1 <- read.csv(file.path(dataDir,"AppendixA-FishCountsTable-2009.csv"),
as.is=T)
> d1[1:3,]
dive_id date time
Hello,
In my previous email, I used index to subset the data. Then, I looked at your
code. I guess you wanted to try the "subset" function to get the same output.
Try this:
dat1<-read.table(text="
X1 X7 X12 X15 X22 X26 X31 X34 X39 X44 X51
X1 1 2 3 4 5 6 7 8 9 10 11
X7 11 9 7
Hi,
I'm trying to install RSQLite on R 2.14 Ubuntu 12.04 i686. The installation
always gets stalled and ends up not working. I installed libsqlite3-dev but
still no luck. Anyone know how to solve this?
$ R CMD INSTALL RSQLite_0.11.1.tar.gz
* installing to library /home/ubuntu/R/i686-pc-linux-gnu
I have also reinstalled the MuMIn package as suggested at...
http://r.789695.n4.nabble.com/Error-message-number-of-items-to-replace-is-not-a-multiple-of-replacement-length-td3257893.html
...however, this made no difference.
any help is appreciated.
thank you
--
View this message in context:
h
Is it possible to start R-Gui in a windowed state under windows? (I am running
Windows 7 and Vista)
I have the set the property for R icon to "normal window" option, but that has
no effect.
Thanks.
__
R-help@r-project.org mailing list
https://stat.ethz
Extract the date separately from the time initially, and keep it separate. When
you want to process daily data, use that column.
---
Jeff NewmillerThe . . Go Live...
DCN:Basic
Here is an example of using your data to split it into the subsets and
then computing a summary of each subset. You have to remember that
what is returned from 'split' is a 'list' of 'data.frames' that as the
subsets that you want and then use use 'lapply' to process each of the
subsets in the lis
On 2012-07-15 14:37, shyam basnet wrote:
Dear R-Users,
I have a problem on extracting T-Stat and P-Value. I have written R-code below
library("Matching")
data("lalonde")
attach(lalonde)
names(lalonde)
Y<- lalonde$re78
Tr<- lalonde$treat
glm1<-
glm(Tr~age+educ+black+hisp+married+nodegr+re74+r
On 2012-07-15 10:01, Paulo Barata wrote:
Dear Peter,
Thank you. I will try to modify my programming habits.
But it seems there is a flaw in R, when it accepts a reference
to a non-existent variable inside a data frame with the df$var
notation. This should be corrected somehow.
Paulo Barata
Dear R-Users,
I have a problem on extracting T-Stat and P-Value. I have written R-code below
library("Matching")
data("lalonde")
attach(lalonde)
names(lalonde)
Y <- lalonde$re78
Tr <- lalonde$treat
glm1 <-
glm(Tr~age+educ+black+hisp+married+nodegr+re74+re75,family=binomial,data=lalonde)
pscor
Hi,
thanks for your reply but this code just gives me a list but no subsets but
I need subsets because I want to do some calculations with these subsets and
want do make some plots etc. Is there a solution for my problem? I ve posted
an example for the first subset...
http://r.789695.n4.nabble.co
http://r.789695.n4.nabble.com/file/n4636585/Baumdaten_aufbereitet.csv
Baumdaten_aufbereitet.csv
Here you have an overview about my data frame...
--
View this message in context:
http://r.789695.n4.nabble.com/computing-a-subset-using-a-loop-tp4636564p4636585.html
Sent from the R help mailing lis
Hello,
Try this:
dat1<-read.table(text="
X1 X7 X12 X15 X22 X26 X31 X34 X39 X44 X51
X1 1 2 3 4 5 6 7 8 9 10 11
X7 11 9 7 5 3 1 10 8 6 4 2
X12 3 4 7 8 5 7 2 9 1 3 2
X15 9 9 8 4 7 1 1 3 2 5 3
X22 6 7 7 4 4 2 9 8 8 1 1
X26 3 9 4 8 5 7 6 1
Hi there and thanks in advance.
Nowadays I am working on the plug-in bandwidth selection with R. Firstly, my
1010 data is the return rate from Yahoo Finance.
Secondly, my code is following:
> r=read.table("/Users/user/Desktop/research/a.txt",sep=",",header=TRUE)
> x<-r[8:1010,]
> library(KernSmoot
On Fri, Jul 13, 2012 at 7:55 PM, Chandler Zuo wrote:
> Hi,
>
> Has anyone encountered the problem of rgamma function in C? The following
> simplified program always dies for me, and I wonder if anyone can tell me
> the reason.
>
> #include
> #include
> #include
>
> SEXP generateGamma ()
> {
>
Is this what you want:
> x <- read.table(text = " X1 X7 X12 X15 X22 X26 X31 X34 X39 X44 X51
+ X1 1 2 3 4 5 6 7 8 9 10 11
+ X7 11 9 7 5 3 1 10 8 6 4 2
+ X12 3 4 7 8 5 7 2 9 1 3 2
+ X15 9 9 8 4 7 1 1 3 2 5 3
+ X22 6 7 7 4 4 2 9 8 8 1 1
+ X26 3 9 4 8 5 7 6 1 2 3 8
+ X31 1 2 1 3 1 4 1 5 1 6 1
+ X34 6
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf Of Sandy Adriaenssens
> Sent: Friday, July 13, 2012 3:52 AM
> To: r-help@r-project.org
> Subject: [R] read mignight as 24:00 and not as 0:00
>
> Dear all,
>
> I have dataset which c
Sorry so much for mistakes.
It was an example code and I commited some mistakes typing it. But meaning the
original code is right (I have checked several times) I am not sure about how
to solve the problem of extracting columns and rows using labels from a squared
matrix. I have enclosed a te
try this:
> set.seed(1)
> day= rep(1:30, each=10)
> n= length(day); x= c(1:24)
> time= sample(x, 300, replace= T)
> light= rep(c(20,10,6,0,0,0,0,0,8,20), 30)
> d=data.frame(day,time,light)
>
> # create a dawn/dusk column to mark where it happens
> d$dawn <- c(FALSE, (head(d$light, -1) < 2) & (tail
You're missing a )
You close c() but not subset().
That's the most common cause of incomplete commands: it often works to
just keep typing ) until you get the regular prompt.
Sarah
On Sun, Jul 15, 2012 at 2:47 PM, A J wrote:
>
> Hi there and thanks in advance.
>
> I have a large symmetrical m
For a start, you are missing a quote and a parenthese on the
statement; probably should be: (another quote was also missing)
n<-subset(m, select=c("X1", "X7", "X12","X15", "X22", "X26", "X31",
"X34", "X39", "X44", "X51", "X58"))
Not sure what you want with the rownames; an example would help and
Hi there and thanks in advance.
I have a large symmetrical matrix stored in a text file. After load in R I
would like to extract the same number of columns and rows (symmetrical
submatrix) using their labels.
I have tried this code in order to extract columns, but R console gives me the
"+" s
I looks like you want to use the 'split' function which would create a
list of dataframes with the various conditions:
result <- split(Baumdaten, list(Baumdaten$transectID,
Baumdaten$Baumart), drop = TRUE)
On Sun, Jul 15, 2012 at 11:31 AM, burton030 wrote:
> Dear all,
>
> I have a data frame wit
Hi,
I guess you can try this:
#You will get the same result here:
df$aaa==2
logical(0)
!df$aaa==2
logical(0)
#But it is different for the variable present in the dataframe
df$a==4
[1] FALSE FALSE FALSE
!df$a==4
[1] TRUE TRUE TRUE
identical(df$aaa==2,!df$aaa==2)
[1] TRUE
identical(df$a==4,!
Dear all,
I have a data frame with different variables and I want to build different
subsets out of this data frame using some conditions and I want to use a
loop because there will be a lot of subsets and this would be saving a lot
of time.
I try to give you an overview about my data fra
Hi Greg,
Thanks for your response. So far I've just been asked to investigate what the
analysis likely would involve. The hope was that there were be some sort of
quick and easy "canned" approach. I don't really think this is the case though.
If I'm asked to do the actual analysis itself, I'll
Holger,
Thanks for providing a reproducible example. However, since your
space key only works sporadically, the below is a little hard to read... ;)
On 2012-07-12 20:26, Holger Taschenberger wrote:
> Hi,
>
> I'm trying to run a permutation test on paired samples.
>
> First I tried the
Try ?match
Adapt it to your need
On Saturday, July 14, 2012 12:55:33 AM UTC+5:30, Silje Nord wrote:
>
> Hi,
>
> Is there a function similar to excel's hlookup in R ?
>
> Thanks,
> Silje
>
> __
> R-help@r-project.org mailing list
> https://stat.ethz
Depending on what options of hlookup you want, 'match' will do exact
matching and 'findInterval' will determine range/interval matching.
What you need to do is follow the posting guide and provide an example
of exactly what you data looks like and what you expect the result to
be.
On Fri, Jul 13,
Paulo Barata-3 wrote
>
> Dr. Dalgaard,
>
> Thank you. You are right, with() is able to catch
> spelling errors in the name of variables inside a data frame.
>
> But couldn't some error or warning be included in R when referring
> to a non-existent variable inside a data frame with the df$var
>
Dear all,
Is anyone aware of an R implementation of LoOF (H.-P. Kriegel, P. Kröger, E.
Schubert, A. Zimek; LoOP: Local Outlier Probabilities; In Proceedings of the
18th ACM Conference on Information and Knowledge Management (CIKM), Hong
Kong, China: 1649–1652, 2009.)? I found http://cran.r-
pro
Hello,
Right, it should be 'varNames' in the apply. I guess I had something
called colNames in my environment. I've just rm(list=ls()) and rerun the
code, corrected. No errors this time.
varNames is the result of expand.grid, therefore does have a dim attribute.
The faulty instruction correc
Hello,
There are obvious bugs in your code, you are testing for light > 2 or
ligth < 2 but this would mean that dusk and dawn are undetermined for
light == 2 and that they happen at light == 1.
Without loops or compound logical conditions:
f <- function(x){
x$dawn <- x$time[ which.m
No idea of how to do what you want but your data set is not working.
I think that you want
x= c(1:24)
day= rep(1:30, each=10)
time= sample(x, 300, replace= T)
light= rep(c(20,10,6,0,0,0,0,0,8,20), 30)
d=data.frame(day,time,light)
n= length(day)
John Kane
Kingston ON Canada
> -Original Mess
> * Sam Steingold [2012-07-13 15:51:46 -0400]:
>
> How do I read/write liblinear models to files?
> E.g., if I train a model using the command line interface, I might want
> to load it into R to look the histogram of the weights.
> Or I might want to train a model in R and then apply it using a co
Dr. Dalgaard,
Thank you. You are right, with() is able to catch
spelling errors in the name of variables inside a data frame.
But couldn't some error or warning be included in R when referring
to a non-existent variable inside a data frame with the df$var
notation, without the use of with()?
I
On 2012-07-13 01:05, Martin Ivanov wrote:
Dear R users,
I need to add minor axis ticks to my graph. In traditional R this is easily
achievable by simply
adding a second axis with the minor ticks. But how to do that in trellis? I am
already out of ideas.
Any suggestions will be appreciated.
Hello, again.
Inline.
Em 15-07-2012 16:17, Charles Stangor escreveu:
Rui,
Since you are so generous, may I ask you one more question? What is the
deal with the text after the semicolon in the statement below? Is this
an ifelse or something? Why is it needed ?
obrigado.
df1 <- read.table(te
Hi,
I have a dataset which contains several time records for a number of days, plus
a variable (light) that allows to determine night time (lihgt= 0) and daytime
(light> 0). I need to obtain get dusk time and dawn time for each day and place
them in two columns.
This is the starting point (d)
On 2012-07-15 08:41, Paulo Barata wrote:
Dr. Dalgaard,
Thank you. But pre-checking with is.null() or using with()
doesn't solve the problem of catching spelling mistakes
in the name of a variable inside a data frame, when using
the df$var notation often in a program.
Is there some way for R to
Hello,
Thank you, I'm gald it helped. Two notes.
1. I don't believe 1t's a problem with the documentation, though many
times, and R is not an exception, there are books that explain in
simpler terms what the docs alreay explain well. Check out the
"contributed" link in http://cran.r-project.o
On Jul 15, 2012, at 17:41 , Paulo Barata wrote:
>
> Dr. Dalgaard,
>
> Thank you. But pre-checking with is.null() or using with()
> doesn't solve the problem of catching spelling mistakes
> in the name of a variable inside a data frame, when using
> the df$var notation often in a program.
>
>
Dr. Dalgaard,
Thank you. But pre-checking with is.null() or using with()
doesn't solve the problem of catching spelling mistakes
in the name of a variable inside a data frame, when using
the df$var notation often in a program.
Is there some way for R to behave, in relation to a variable
inside
This seems more or less correct to me.
1> sum(df$a==1)
[1] 1
1> sum(df$a==2)
[1] 1
1> sum(df$aaa==2)
[1] 0
There is no df$aaa so the length is 0 which is what I think you are asking.
What am I missing?
John Kane
Kingston ON Canada
> -Original Message-
> From: paulo.bar...@ensp.fiocruz
On Fri, Jul 13, 2012 at 9:25 PM, Silje Nord wrote:
> Is there a function similar to excel's hlookup in R ?
>
Try match(). I think it provides hlookup() functionality.
Liviu
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-he
To the R help list,
When using a data frame, there is no warning or error message
when I refer to a non-existent variable inside the data frame.
Example:
##--
a <- c(1,2,3)
b <- c(11,22,33)
df <- data.frame(a,b)
df
## correct: there is a column in
On Fri, Jul 13, 2012 at 1:41 PM, mdvaan wrote:
> Here's some data (which should give you the error messages):
>
> # read in data
> data <- read.csv("https://dl.dropbox.com/u/13631687/data.csv";, header =
> T, sep = ",")
>
> # first paste all data
> data1 <- paste(data[,1], collapse
Hello,
Why do you need 9 variables in your environment if they are time series
that correspond to the same period? You should use time series functions.
#install.packages('zoo')
library(zoo)
# Make up a dataset
Year <- seq(from=as.Date("1901-01-01"), by="year", length.out=100)
dat <- data.fra
On Jul 14, 2012, at 04:55 , Chandler Zuo wrote:
> Hi,
>
> Has anyone encountered the problem of rgamma function in C? The following
> simplified program always dies for me, and I wonder if anyone can tell me the
> reason.
>
> #include
> #include
> #include
>
> SEXP generateGamma ()
> {
>
Hello,
Try the following.
ib1 <- 1:10
ib2 <- rnorm(10)
hold.list <- objects(pattern="ib")
df <- sapply(hold.list, get)
df
Note that you don't need list(), and that sapply() returns a data.frame
if possible.
Also, 'df' is the name of an R function, use something else like 'df1'.
Hope this
Hi Peter,
I copied the data from your email and run it again.
dat1<-read.table(text="
2.5 3.6 7.1 7.9
100 3 4 2 3
200 3.1 4 3 3
300 2.2 3.3 2 4
",sep="",header=TRUE)
dat1
X2.5 X3.6 X7.1 X7.9
100 3.0 4.0 2 3
200 3.1 4.0 3 3
300 2.
- Forwarded Message -
From: arun
To: "Akkara, Antony (GE Energy, Non-GE)"
Cc: R help
Sent: Friday, July 13, 2012 10:05 AM
Subject: Re: [R] Column create and Update using function
Hi,
I thought you want to check all the columns at once using "apply" or similar
functions.
dat1[!(da
Hi,
You could use either one of these methods:
#Method 1:
#dat1 : data
list1<-split(dat1,dat1$group)
dat2<-data.frame(list1)
dat2<-data.frame(list1[[5]][1],list1[[4]][1],list1[[3]][1],list1[[2]][1],list1[[1]][1])
colnames(dat2)<-c(rev(levels(dat1$group)))
head(dat2)
Group 1 Group 2 Group 3 G
Hi,
Try this:
dat1<-read.table(text="
ABC XYZ PQR
2 4 3
5 4 8
7 1 3
",sep="",header=TRUE)
newdat<-apply(dat1,2,function(x) ifelse(x<6 & x>3,"","RC"))
colnames(newdat)<-paste(colnames(newdat)
Hi Antony,
There is still some confusion as to what you actually want as result.
For example, your statement
->"In this i need to check each particular column values are between Max and
Min value.
If the coulmn value not coming between Max and Min, then i need to create
another coulmn"
This i
# I've read that rollapply, and its wrapper apply.rolling()
# from PerformanceAnalytics package, do not work with multivariate
# time series neither their output can be a multivariate time series.
# Then I was wondering if any other function like those exists, or
# if I need to write my own functi
# Thank you, Michael: it works fine!
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__
R-help@r-project.org mailin
Simplify your model. Does your TandemRepeat have a lot of levels? Or is
your sample size very small?
Alain
Dear all,
I am
fitting a hurdle model in the following way:
HNB <-
hurdle(chro ~ as.factor(TandemRepeat)| as.factor(TandemRepeat), data
=data_negbin_fin,
dist = "negbin")
But the std.
er
On Jul 14, 2012, at 19:58 , Schaber, Jörg wrote:
> Dear Peter,
>
> thanks for your clarifications. Sample size is around 200 in each group.
> Would that justify your approach?
It's certainly better than 10...
I did a small check on the IgM data from the ISwR package (298 obs.) and found
som
What does Excel's HLOOKUP do?
On Saturday, July 14, 2012, Silje Nord wrote:
> Hi,
>
> Is there a function similar to excel's hlookup in R ?
>
> Thanks,
> Silje
>
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
>
Hello,
I am trying to reproduce a code example from
http://www.babelgraph.org/wp/?p=358 babelgraph when compiling the function
to call the C++ code I get the following error:
Error in compileCode(f, code, language = language, verbose = verbose) :
Compilation ERROR, function(s)/method(s) not
Thanks for your suggestions!
The Siegel Tukey test and the permutation test sound promising, indeed.
I applied the wilcoxon test already, but understood that it mainly tests
differences in the medians (location), even though being sensitive to all kinds
of differences between distributions, sim
Here's some data (which should give you the error messages):
# read in data
data <- read.csv("https://dl.dropbox.com/u/13631687/data.csv";, header =
T, sep = ",")
# first paste all data
data1 <- paste(data[,1], collapse = "|")
# second paste subsets of the data
da
Dear all,
I have dataset which contains date and time in the format
"yearmonthdayhour". I can read in these data correctly as follows:
mydata <- read.csv("pm10_corine_gridcel_hourly_2011.csv", header = TRUE)
mydata$date <- as.POSIXct(strptime(mydata$date, format = "%Y%m%d%H",
tz="UTC"))
However,
Dear Peter,
thanks for your clarifications. Sample size is around 200 in each group. Would
that justify your approach?
I found a couple of more tests for scale on continous variables, ie.
Mood Test
Ansari-Bradley Test (that one is also implemented in R)
Klotz Test
Conover Test
Would one of tho
Hi,
Is there a function similar to excel's hlookup in R ?
Thanks,
Silje
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented
Dear All,
I've used mice package for my latent class analysis and binary logistic
regression
I've imputed five data sets and with long format I've added new variable
that shows latent class membership.
And then in addition to other variables, I'll use binary logistic
regression and try to pool t
On 12-07-14 7:54 PM, 水静流深 wrote:
my system :debian
in console:
nano /home/tiger/R-2.15.1/etc/Rprofile.site
here is my content:
.First<- function(){
cat("\nWelcome at", date(), "\n")
}
#
.Last<- function(){
cat("\nGoodbye at ", date(), "\n")
}
when i save it ,reopen my R ,
why there is
Dear all,
I am searching for a way to compute a test comparable to Chuang et al.
("Causality in Quantiles and Dynamic Stock
Return-Volume Relations"). The aim of this test is to check wheter the
coefficient of a quantile regression granger-causes Y in a quantile range. I
have nearly computed every
G'day R (power) users,
I have a many vectors, called:
ib1
ib2
ib3
...
ib100
and I would like them in one data frame (df) such that:
> df
ib1 ib2 ib3 ib4 . ib100
x x xxx
x x xxx
x x xxx
I have attempted:
ho
I have a read a lot about the benefits of vectorization in R. I have a
program that takes "almost forever" to run. A good way to see if I have
learned something ... My problem can be summarized like this : I have a
nonlinear function of several variables that I want to optimize over one
letting the
Hi,
I would like to use xyplot to create a figure. Unfortunately, I cannot find
documentation in xyplot to specify alternating the x-axis tick labels with
the x-axis tick marks. I can do this with the regular R plot function as
follows.
#A small version of my data looks like this
data<-data.fram
We are using GAM in mgcv (Wood), relatively new users, and wonder if anyone
can advise us on a problem we are encountering as we analyze many short time
series datasets. For each dataset, we have four models, each with intercept,
predictor x (trend), z (treatment), and int (interaction between x an
Hi, R-help,
I have a group of data from RNA-seq want to be analyzed by Fisher's
exact test in R. I want to compare the significant difference of about
30, individuals in two different samples, and I have no idea how to use
R, so could you please give me some suggestions or the scripts for
Dear all,
Please I am working on PCR and PLSR with pls package and my issue is the
command to extract components. Please help with a solution.
Thanks.
[[alternative HTML version deleted]]
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Hello, I'm new to R with a (probably elementary) question.
Suppose I have a dataset called /A/ with /n/ locations, and each location
contains within it 3 time series of different variables (all of 100 years
length); each time series is of a weather variable (for each location there
is a temperatur
I'm looking for a single book that provides a deep, yet readable
introduction to applied data analysis for general readers.
I'm looking for coverage on things like understanding randomness, "natural
experiments", confounding, causality and correlation, data cleaning and
transforms, lagging, residu
Hi,
I don't really understand how ROCR works. Here's another example with a
randomforest model: I have the training dataset(bank_training) and testing
dataset(bank_testing) and I ran a randomForest as below:
bankrf<-randomForest(y~., bank_training, mtry=4, ntree=2,
keep.forest=TRUE,im
OK, I need help!!
I've been searching, but I don't understand the logic of some this
dataframe addressing syntax.
What is this type of code called?
test [["v3"]] [is.na(test[["v2"]])] <-10 #choose column v3 where column v2
is == 4 and replace with 10
and where is it documented?
The code belo
my system :debian
in console:
nano /home/tiger/R-2.15.1/etc/Rprofile.site
here is my content:
.First <- function(){
cat("\nWelcome at", date(), "\n")
}
#
.Last <- function(){
cat("\nGoodbye at ", date(), "\n")
}
when i save it ,reopen my R ,
why there is no
Welcome at Sun Jul 15 07:53:
Hi,
Has anyone encountered the problem of rgamma function in C? The
following simplified program always dies for me, and I wonder if anyone
can tell me the reason.
#include
#include
#include
SEXP generateGamma ()
{
srand(time(NULL));
return (rgamma(5000,1));
}
Has anyone encounte
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