I am trying to do a priori ANOVA analysis for a class assignment. The
professor uses SPSS and does not know R. I want to do a simple planned
comparison but have been unable to find a function or specific help. There
is a grouping variable with five levels and a subsequent response variable.
I also
Hello,
I have downloaded "graph" package from
http://www.bioconductor.org/packages/release/bioc/html/graph.html
Is there anyone who can teach me how to install "graph" into R?
Thanks
[[alternative HTML version deleted]]
_
If my survival data includes more than two outcomes, for example death,
disability and censored. Does R have corresponding packages or programes to
run Cox proportional hazard model with multiple failure time data. Millions
of thanks!!
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View this message in context:
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On 18 September 2011 04:58, Felipe Nunes wrote:
> Do you guys know how could I increase the time limit for the iterations in
> censReg? I'm receiving the following message whatever method I use:
> Newton-Raphson maximisation, 150 iterations
> Return code 4: Iteration limit exceeded.
> Log-likeliho
Do you guys know how could I increase the time limit for the iterations in
censReg? I'm receiving the following message whatever method I use:
Newton-Raphson maximisation, 150 iterations
Return code 4: Iteration limit exceeded.
Log-likelihood: -67680.41 on 42 Df
thanks,
*Felipe Nunes*
CAPES/Fulb
Could you repaste your data using dput() so we can see exactly what we are
working with here.
As things stand currently, I can't tell why it doesn't suffice to just
combine the dates and times into POSIX objects and subtract them all from
the first row. For more information on that approach, try ?
Dear Group,
Can you help me solve the problem with calculating Time Post dose using date
time fomat? Here is information for subject 1 and I appreciate your help
for code to generate time post dose from the first dose in each individual.
Thank you in advance.
Regards,
Ayyappa
ID DA
Try playing with match(). Something like
d[match(v,d[,1]),2]
Should work (untested bc I'm writing from my phone though)
Michael Weylandt
On Sep 17, 2011, at 4:33 PM, "Janssen, K.J.M."
wrote:
>
> I am trying to replace values of a vector (consisting of 15 values) by a
> value that is relate
Hi clsnyder,
You forgot the MARGIN argument in you function call. Take a look at ?apply
apply(iris, 2, length)
apply(iris, 2, mean)
HTH,
Jorge
*
*
On Sat, Sep 17, 2011 at 6:42 PM, clsnyder <> wrote:
> Why does one method work, and the other not?
>
> attach(iris)
> head(iris)
>
> mean(Sepal.L
Why does one method work, and the other not?
attach(iris)
head(iris)
mean(Sepal.Length)
[1] 5.84
apply(iris, Sepal.Length, mean)
"Error in if (d2 == 0L) { : missing value where TRUE/FALSE needed"
I seem to get this error frequently with the apply functions but other
"manual" methods work no
I am trying to replace values of a vector (consisting of 15 values) by a value
that is related to a matching value in a dataset (consisting of 17 rows).
Here's an example
The vector:
v <- c(f,a,e,d,m,o,e,f,i,n,e,i,b,a,o)
The dataset's columns consist of the following values
d[,1] <- c(a,b,c,d,e
Dear R users,
Just to clarify. I am not offering to pay someone to do my Dissertation.
These 4-5 commands on Kalman Filter would be only a tiny part of my 10,000
words dissertation. A part that even after trying for a few days, I am still
stuck on. I am offering £50, just to say thanks.
Regards
On Sep 17, 2011, at 5:04 PM, Joshua Wiley wrote:
On Sat, Sep 17, 2011 at 1:43 PM, Joshua Wiley
wrote:
Hi Eran,
You have already gotten some suggestions from Michael, but I think
that Rich is correct to question the rational.
I hope we should question the rationale, and doubt that Rich has
On Sat, Sep 17, 2011 at 1:43 PM, Joshua Wiley wrote:
> Hi Eran,
>
> You have already gotten some suggestions from Michael, but I think
> that Rich is correct to question the rational. Any mechanism you
> choose to replace the missing values will impose its structure on the
> data. Veritate ab abs
Hi Eran,
You have already gotten some suggestions from Michael, but I think
that Rich is correct to question the rational. Any mechanism you
choose to replace the missing values will impose its structure on the
data. Veritate ab absurdo:
## data
x <- sin(seq(1, 17, .1)) + seq(-.5, .5, length.out
Oh I see the problem. Many thanks!
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R-help@r-project.org mailing list
https://stat.ethz.c
Hey,
I hope someone is able to help. I've created a graph using kiteChart (in
the plotrix package) but need to know how to perform some basic text
alterations to the graph. I would like to re-orientate the text on the
y-axis from vertical to horizontal. I understand that the argument normally
On Sat, 17 Sep 2011, R. Michael Weylandt wrote:
How are your time samples missing?
Michael/Eran,
Pardon me for jumping in since I did not read the original message, but I
have a more fundamental question: are the missing time samples meaningful?
For example, a time series of precipitatio
How are your time samples missing?
If they are recorded as NA, the na.locf() function will fill them with the
previous value (zero-order hold) and with the reversability arguments can
give linear interpolation:
library(xts)
x = c(1:5,NA,6:10)
x = xts(x,Sys.Date()+0:10)
na.locf(x)
(na.locf(x) + n
This one seems to have slipped through the cracks, but I'll take a stab at
it:
I don't think there's an (easy) general solution but there are two direct
ways to get at the idea.
If you are generally only seeking to do things like: x[order(x)] would
sort(x) work for you?
More generally, this can
On 17/09/2011 2:15 PM, Joshua Wiley wrote:
Hi Andrew,
On Sat, Sep 17, 2011 at 12:04 AM, andrewH wrote:
> Dear Folks --
> The anonymous poster ("rmailbox") is perfectly correct. I had forgotten you
> could use names in this way. When referring to rows or columns by name
> rather than by nu
Doesn't seen like an R task, but see pdf2text? (From pdftools, UNIX command
line tools)
---
Jeff Newmiller The . . Go Live...
DCN: Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer (Solar
** I am not a statistician, but...
The default arguments are:
onet.permutation(x, nsim=2000, plotit=TRUE)
you are making nsim=4 (this parameter is not the size of each sample, it
is the number of samples taken)
You are building the distribution for a statistical test through random
sampling, s
Hi Andrew,
On Sat, Sep 17, 2011 at 12:04 AM, andrewH wrote:
> Dear Folks --
> The anonymous poster ("rmailbox") is perfectly correct. I had forgotten you
> could use names in this way. When referring to rows or columns by name
> rather than by number, I usually use either attach() or the $ oper
In an R script I need to extract some figures from many web pages in pdf
format. As an example see
http://www.terna.it/LinkClick.aspx?fileticket=TTQuOPUf%2fs0%3d&tabid=435&mid=3072
from which I would like to extract the "Totale: 1,025,823").
Is there any solution?
Ciao
Vittorio
__
I saw the manual of this function but not sure what to do.
I have a array contain 7 numbers and want to choose 4 to do permutation
test. But using this function with parameters as onet.permutation(scores,4),
it returns 0. Instead, with no parameter, onet.permutation(), it returns
something but eve
Dear all,
in order to estimate transition-specific probabilities in a multi-state
model i applied the 'probtrans()' function from the 'mstate'-package.
Now, i am at loss with the following message (see attached example):
Warning message:
In probtrans(msf.0, predt = 0) :
Negative diagonal elemen
Dear R-help,
I am doing clustering via finite mixture model. I am trying with mixtools.
Please suggest some
packages in R to find clusters via finite mixture model with continuous
variables. And
also I wish to verify model fit and the distributional properties of the
mixture
distributions by
Ms.Karunambigai M
PhD Scholar
Dept. of Biostatistics
NIMHANS
Bangalore
India
- Forwarded Message
From: karuna m
To: R-help@r-project.org
Sent: Thu, 26 May, 2011 10:55:02 AM
Subject: likelihood ratio test
Dear R-help,
Can anybody tell me which R package has Lo-Mendell Rubin LR test
Hi, Agustin,
I also encountered similar problems when cutting trees. However, I think one
himself/ herself has to figure out the components of each cluster. The
labels that are generated by the current packages simply only distinguish
one cluster from another, but do not have more meanings.
Rui
O
On Thu, 15 Sep 2011 22:12:54 +1200, Rolf Turner
wrote:
On 15/09/11 19:24, Torbjørn Ergon wrote:
On Thu, 15 Sep 2011 09:47:35 +1200, Rolf Turner
wrote:
On 15/09/11 07:21, Torbjørn Ergon wrote:
Dear list,
I'm looking for a function to generate (simulate) a random Weibull
point process. Can a
Hello
I would like to use SNOW to parallelise some computations to be made on columns
of a data frame, using different parameter values for each SNOW "worker".
I gather(?) clusterMap() is the appropriate SNOW function to do something like
this. I suspect the problem lies in the fact that I am
On 11-09-17 5:27 AM, andrewH wrote:
Dear Folk--
Suppose I have some objects A, B& C, and a function
getDots<- function(...) {args<- list(...) etc.}
If I do a call to getDots(A, B, C) then the variable args will be assigned
to a list which contains the objects to which A, B& C refer, but whic
On 17-Sep-11 01:20:53, Rolf Turner wrote:
> On 17/09/11 01:19, Michael Friendly wrote:
>
>
>> Trying to interpret associations in complex loglinear models
>> from tables of parameter estimates is like trying to extract
>> sunlight from a cucumber. You have to squeeze very hard, and
>> then are
Dear Folk--
Suppose I have some objects A, B & C, and a function
getDots <- function(...) {args <- list(...) etc.}
If I do a call to getDots(A, B, C) then the variable args will be assigned
to a list which contains the objects to which A, B & C refer, but which will
not (except by happenstance)
Dear Folks --
The anonymous poster ("rmailbox") is perfectly correct. I had forgotten you
could use names in this way. When referring to rows or columns by name
rather than by number, I usually use either attach() or the $ operator,
neither of which works here. If anyone understands why data.df[
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