Czerminski, Ryszard astrazeneca.com> writes:
>
> I am looking for an efficient way to find near neighbors...
>
> More specifically...
> I have two sets of points: A & B and I want to find
> points in set B which are closer to set A than some
> cutoff (or n-closest)
>
> I will appreciate very m
ToothGrowth
attach(ToothGrowth)
abline(lm(len ~ does, data = ToothGrowth))
an empty gray graph displayed
continue
plot.new()
the background changes to white colour, still an empty graph
B.R.
satimis
- Original Message
From: Joshua Wiley
To: Stephen Liu
Cc: r-help@r-project.org
Often when things look to small/thin it is because the plot is being created at
too large a size, then shrunk.
How are you creating the graph? How are you transferring it?
Try creating the graph at the exact size that it will be when used in the
powerpoint, then without needing to resize things
On Fri, Nov 19, 2010 at 9:35 PM, Stephen Liu wrote:
> Hi David,
>
>
>> What happens when you follow the directions... i.e. type:
>> plot.new() #???
>
> abline(lm(len ~ dose, data = ToothGrowth))
> plot.new()
>
> The grey background changes to white, still an empty graph
You cannot just use abl
Hi Josh,
plot.new()
the gray background changes to white colour.
If following my steps:-
plot(matrics$resid)
plots a new graph
B.R.
Stephen
- Original Message
From: Joshua Wiley
To: Stephen Liu
Cc: r-help@r-project.org
Sent: Sat, November 20, 2010 12:57:41 PM
Subject: Re: [R] An e
Hi David,
> What happens when you follow the directions... i.e. type:
> plot.new()#???
abline(lm(len ~ dose, data = ToothGrowth))
plot.new()
The grey background changes to white, still an empty graph
If continue on my version:-
abline(matrics)
plot(matrics$resid)
It plots a graph
B.R.
St
On Nov 19, 2010, at 11:14 PM, Stephen Liu wrote:
Hi Josh,
with(ToothGrowth, plot(dose, len))
abline(lm(len ~ dose, data = ToothGrowth))
ToothGrowth
abline(lm(len ~ dose, data = ToothGrowth))
Error in int_abline(a = a, b = b, h = h, v = v, untf = untf, ...) :
plot.new has not been called y
It looks like all the packages you should need are loaded. Does the
call to plot() create a scatter plot correctly? abline() adds a line
to the current plot so that device still needs to be open when you
call abline() (which it should have been if you ran the code from my
first email). If a grap
> this is a simple question, but I wasn't able to figure it out myself.
>
> here is the data frame:
>
> M P Q
> 1 2 3
> 4 5 6
> 7 8 9
>
> M, P, Q each represent a variable
>
> I want to draw 2 random sample from each row separately to create a new
> data frame. how can I do it?
>
> thanks!!
sor
Hi Josh,
> with(ToothGrowth, plot(dose, len))
> abline(lm(len ~ dose, data = ToothGrowth))
ToothGrowth
abline(lm(len ~ dose, data = ToothGrowth))
Error in int_abline(a = a, b = b, h = h, v = v, untf = untf, ...) :
plot.new has not been called yet
ToothGrowth
attach(ToothGrowth)
abline(lm(len
Hi Josh,
> sessionInfo()
R version 2.12.0 (2010-10-15)
Platform: x86_64-pc-mingw32/x64 (64-bit)
locale:
[1] LC_COLLATE=English_United States.1252
[2] LC_CTYPE=English_United States.1252
[3] LC_MONETARY=English_United States.1252
[4] LC_NUMERIC=C
[5] LC_TIME=English_Un
On Nov 19, 2010, at 11:29 PM, Joshua Wiley wrote:
Hi Stephen,
In a session where that code returns an error, can you report the full
results of:
sessionInfo()
capabilities()
?
Josh
On Fri, Nov 19, 2010 at 8:14 PM, Stephen Liu
wrote:
Hi Josh,
with(ToothGrowth, plot(dose, len))
abline
Hi Stephen,
In a session where that code returns an error, can you report the full
results of:
sessionInfo()
capabilities()
?
Josh
On Fri, Nov 19, 2010 at 8:14 PM, Stephen Liu wrote:
> Hi Josh,
>
>
>> with(ToothGrowth, plot(dose, len))
>> abline(lm(len ~ dose, data = ToothGrowth))
>
> ToothGr
On Nov 19, 2010, at 9:40 PM, Emmanuel Levy wrote:
Hello David,
I thought about this at first as well, e.g.,
x1.lim = quantile(x1,prob=c(0.05,0.95))
y2.lim = quantile(y2,prob=c(0.05,0.95))
x1.sub = x1[ x1 > x1.lim[1] & x1 < x1.lim[2] & y2 > y2.lim[1] & y2 <
y2.lim[2]]
y2.sub = y2[ x1 > x1
Hi ALL,
Recently I confronted with a error in using package ProDenICA, when let khttp://finzi.psych.upenn.edu/R/library/ProDenICA/html/ProDenICA.html),
Error in solve.default(V, W) : 'b' must be compatible with 'a'
I have examined the code of function ProDenICA(), but could not find the reason.
Hello Roger,
Thanks for the suggestions.
I finally managed to do it using the output of kde2d - The code is
pasted below. Actually this made me realize that the outcome of kde2d
can be quite influenced by outliers if a boundary box is not given
(try running the code without the boundary box, e.g.
Hi Stephen,
Please try:
with(ToothGrowth, plot(dose, len))
abline(lm(len ~ dose, data = ToothGrowth))
Cheers,
Josh
On Fri, Nov 19, 2010 at 6:44 PM, Stephen Liu wrote:
> Hi folks,
>
> Win7 64bit
> R 1.12.0
>
> I run following command on R:-
>
>> ToothGrowth
>> attach(ToothGrowth)
>> plot(dose
Hi folks,
Win7 64bit
R 1.12.0
I run following command on R:-
> ToothGrowth
> attach(ToothGrowth)
> plot(dose,len)
> matrics=lm(len~dose)
> abline(metrics)
Error in int_abline(a = a, b = b, h = h, v = v, untf = untf, ...) :
plot.new has not been called yet
Only a grey diagram is displayed wi
Hello David,
I thought about this at first as well, e.g.,
x1.lim = quantile(x1,prob=c(0.05,0.95))
y2.lim = quantile(y2,prob=c(0.05,0.95))
x1.sub = x1[ x1 > x1.lim[1] & x1 < x1.lim[2] & y2 > y2.lim[1] & y2 <
y2.lim[2]]
y2.sub = y2[ x1 > x1.lim[1] & x1 < x1.lim[2] & y2 > y2.lim[1] & y2 <
y
Cron still works, but launchd/launchctl seems to be preferred by some
if you're on Mac OS X.
J.
On Fri, Nov 19, 2010 at 7:09 PM, Steve Lianoglou
wrote:
> Hi,
>
> On Fri, Nov 19, 2010 at 10:09 AM, amit jain wrote:
>> Hi All,
>>
>> Can anyone point to any package/resouce to schedule a job in R wh
On Nov 19, 2010, at 8:44 PM, Emmanuel Levy wrote:
Hello,
This sounds like a problem to which many solutions should exist, but I
did not manage to find one.
Basically, given a list of datapoints, I'd like to keep those within
the X% percentile highest density.
That would be equivalent to retai
Maybe you can consider the brownian.motion() function in the animation
package, e.g.
library(animation)
ani.options(interval = 0.05, nmax = 150)
brownian.motion(pch = 21, cex = 5, col = "red", bg = "yellow", main =
"Demonstration of Brownian Motion")
Or here is another (awkward) example of severa
Hello,
This sounds like a problem to which many solutions should exist, but I
did not manage to find one.
Basically, given a list of datapoints, I'd like to keep those within
the X% percentile highest density.
That would be equivalent to retain only points within a given line of
a contour plot.
This limitation actually comes from the LaTeX command
\includegraphics{}. It is not impossible to insert animations into
LaTeX, e.g. you can use the LaTeX package 'animate'.
The R package 'animation' has a wrapper saveLatex() which can help you
generate a PDF file containing animations, provided y
On 2010-11-19 22:37, Jinsong Zhao wrote:
Hi there,
When I run the following code, I could get correct objects (with correct
values):
for(i in 1:6) { #-- Create objects 'r.1', 'r.2', ... 'r.6' --
nam <- paste("r",i, sep=".")
assign(nam, 1:i)
# save(nam, file = paste(nam, "RData", sep = "."))
}
Hi
On 20/11/2010 2:10 p.m., Bryan Hanson wrote:
Oh Knowledgeable Ones:
I'm working on a project using grid graphics (for the first time). A toy
example is given below, run it simply with>foobar() I am wondering why the
pink dot and concentric circles are not centered on the 3-color axis syste
Oh Knowledgeable Ones:
I'm working on a project using grid graphics (for the first time). A toy
example is given below, run it simply with >foobar() I am wondering why the
pink dot and concentric circles are not centered on the 3-color axis system.
Further, I feel like the concentric circles don
Hi,
On Fri, Nov 19, 2010 at 10:09 AM, amit jain wrote:
> Hi All,
>
> Can anyone point to any package/resouce to schedule a job in R which runs a
> .R file at a specified time ?
>
> I couldn't find anything useful in R Reference manual or RSiteSearch. I am
> sure its there but i am unable to loc
On 19 November 2010 at 13:13, cameron wrote:
|
| i have a time Series of IBM closing px from 1/1/2000 to today
| I want to graph the time serie by dividing the graph by year and month
| all the monthly graphs with the same year will go to one page. so from
| 1/1/2000 to 11/19/2010. i will have
Hi Cameron,
This is a Sweave FAQ:
http://www.stat.uni-muenchen.de/~leisch/Sweave/FAQ.html#x1-11000A.9
-Ista
On Fri, Nov 19, 2010 at 4:13 PM, cameron wrote:
>
> i have a time Series of IBM closing px from 1/1/2000 to today
> I want to graph the time serie by dividing the graph by year and month
>
On Nov 19, 2010, at 6:10 PM, Thomas Stewart wrote:
You may want to consider using eurodist in matrix form. As in,
ED <- as.matrix(eurodist)
Then you could manipulate the matrix using standard or homemade
functions,
like this one:
max.matrix <- function(A) {
column <- ceiling(which.max(A
You may want to consider using eurodist in matrix form. As in,
ED <- as.matrix(eurodist)
Then you could manipulate the matrix using standard or homemade functions,
like this one:
max.matrix <- function(A) {
column <- ceiling(which.max(A)/nrow(A))
row <- which.max(A) - (column-1)*nrow(A)
A
Hi users
ı cant find and also do nonlinear garnger causality R codes, Is anyone send
me an example??? thanks lots of
--
View this message in context:
http://r.789695.n4.nabble.com/test-for-causality-tp835483p3050981.html
Sent from the R help mailing list archive at Nabble.com.
[[alter
Hi,
I'd like to use a three-dimensional dataset to build a kernel density and
then sample from the distribution.
I already used the npudens function in the np package to estimate the
density and plot it:
fit<-npudens(~x+y+z)
plot(fit)
It takes some time but appears to work well.
Many thanks for your most helpful answers.
Tony Lancaster
On 18 November 2010 20:28, David Winsemius wrote:
>
> On Nov 18, 2010, at 1:23 PM, Henrique Dallazuanna wrote:
>
> Try this also:
>>
>> x$x - ave(x$x, x$f)
>>
>
> Could also use scale for only its centering capacities:
>
> unlist(
> t
i have a time Series of IBM closing px from 1/1/2000 to today
I want to graph the time serie by dividing the graph by year and month
all the monthly graphs with the same year will go to one page. so from
1/1/2000 to 11/19/2010. i will have
11 pages, and each page will have 12 graphs (jan to dec)
Rescinded. Problem solved. I discovered that TukeyHSD doesn't like
numeric factors; changing the "level" to a factor solved my problem.
SR
Steven H. Ranney
steven.ran...@montana.edu
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/lis
All -
I think I'm being dense, but for the life of me, I can't figure out
why I get error message with the code below.
I have data that looks like
param level perc.surv asin.tran
DO 3 0.6864407 0.9764544
DO 3 0.125 0.3613671
DO 3 0.8738739 1.2077299
DO 4 0.4615385 0.7468986
D
see
http://onlinelibrary.wiley.com/doi/10./j.1467-9892.2010.00684.x/abstract
kjetil
On Fri, Nov 19, 2010 at 6:02 PM, wrote:
> hello,
>
> I try to model traffic accidents with the following model:
>
> glm.nb(y~j+w+m+sf+b+ft,data=fr[]). the problem is that there exist
> autocorrelation in th
Yes. This is what I want to do. Thanks!
I've tried to paste function but I didn't know how to use
appropriately in this case.
Have a nice weekend.
On Fri, Nov 19, 2010 at 3:05 PM, Jorge Ivan Velez
wrote:
> Perhaps this?
> paste('graph', 1:10, '.png', sep = "")
> Please give us more context/deta
Perhaps this?
paste('graph', 1:10, '.png', sep = "")
Please give us more context/details on what you are trying to do. I
will undoubtedly help us to help you. In this case, the posting guide is
your friend.
HTH,
Jorge
On Fri, Nov 19, 2010 at 3:57 PM, Soyeon Kim <> wrote:
> Dear All,
>
> I wa
hello,
I try to model traffic accidents with the following model:
glm.nb(y~j+w+m+sf+b+ft,data=fr[]). the problem is that there exist
autocorrelation in the data. one possibility is to model traffic
accidents with inar(1)-models. has anyone an idea how to change this
model in order to abta
On Fri, Nov 19, 2010 at 10:34:26AM -0800, wangwallace wrote:
>
> this is a simple question, but I wasn't able to figure it out myself.
>
> here is the data frame:
>
> M P Q
> 1 2 3
> 4 5 6
> 7 8 9
>
> M, P, Q each represent a variable
>
> I want to draw 2 random sample from each row separatel
Dear All,
I want to print out "graph1.png" "graph2.png" "graph3.png" ... How
can I print it out?
Thank you,
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/po
I will appreciate a lot if you do not mind add a new option like
'useFormat'. I suggested format() because I'm "allergic" to too many
options.
I must say it is not hard to define the formatting, but it is just
tedious to do it for every single number because by default we have
too many digits espe
I'm trying to configure Version 2.12.0 or R to do memory profiling.
I've reconfigured the code:
% ./compile --enable-memory-profiling=YES
and verified that it's configured correctly by examining the output. I then
rebuild R:
% make
Then I fire up R and run a script, using Rprof with the memor
This is very strange. (Debian squeeze, R 2.12.0 compiled from source)
I did some moderately large computation (including svd of a 560x50 matrix),
running a few minutes, and R memory increasing to about 900MB on this
2 GB ram laptop. I had done Rprof(memory.profiling=TRUE) first.
Then doing summary
Some remarks:
Why are you using assignments to indicate the return values of functions?
This is R idiom:
> f<-function(u){
> f<-0
> for (j in 1:4){
>f<-f+coeff[j]*(zeta(j)(u))
> }
> f
> }
>
If you only want the inner product of 2 vector, "outer" probably is an overkill.
g <- function(u){
Harlan and Tal have had problems. I had lots too. I spent hours getting it
to work. Terrible process to go through but RGoogleDocs is so useful that
the time was worth it - I think!
My problems were overcome when
1. I used the latest zip file by Duncan Temple Lang see below
2. I inserted an
Hi wangwallace,
Here are two ways of doing it. Could you please be more specific?
# data set
X <- matrix(1:9, ncol = 3, byrow = TRUE)
colnames(X) <- c('M', 'P', 'Q')
X
# option 1 -- two samples per row
replicate(2, {
out <- t(apply(X, 1, sample))
colnames(out) <- colnames(X)
list(out)
})
#
Does ?constrOptim look as though it will handle your needs?
--
Jonathan P. Daily
Technician - USGS Leetown Science Center
11649 Leetown Road
Kearneysville WV, 25430
(304) 724-4480
"Is the room still a room when its empty? Does the room,
the thing itself have pur
Hi,
I am a beginner of R. There is a question about constraint minimization. A
function, y=f(x1,x2,x3x12), needs to be minimized. There are 3
requirements for the minimization:
(1) x2+x3+...+x12=1.5 (x1 is excluded);
(2) x1=x3=x4;
(3) x1, x3 and x5 are in the range of -1~0, respectively. T
On 19/11/2010 1:09 PM, newbster wrote:
I would like to plot multiple random walks onto the same graph. My p
variable dictates how may random walks there will be.
par(mfrow=c(1,1))
p<- 100
N<- 1000
S0<- 10
mu<- 0.03
sigma<- 0.2
nu<- mu-sigma^2/2
x<- matrix(rep(0,(N+1)*p),nrow=(N+1))
y<- matrix(
this is a simple question, but I wasn't able to figure it out myself.
here is the data frame:
M P Q
1 2 3
4 5 6
7 8 9
M, P, Q each represent a variable
I want to draw 2 random sample from each row separately to create a new data
frame. how can I do it?
thanks!!
--
View this message in conte
I would like to plot multiple random walks onto the same graph. My p
variable dictates how may random walks there will be.
par(mfrow=c(1,1))
p <- 100
N <- 1000
S0 <- 10
mu <- 0.03
sigma <- 0.2
nu <- mu-sigma^2/2
x <- matrix(rep(0,(N+1)*p),nrow=(N+1))
y <- matrix(rep(0,(N+1)*p),nrow=(N+1))
t<-
Hello:
I have a problem when I tried to color the USA map with different colors.
The following is my data (I only used the second column of data):
alaska,1, 2
Hawaii, 0, 0
USA,5, 5
And here is my code:
library("latticeExtra")
library("mapproj")
state<-read.table
Also
spDists
spDistsN1 Euclidean or Great Circle distance between points
In the sp package.
(and in my personal opinion, the sp package would be a good place to start,
since its part of a group of packages I view as Rs core packages for working
with spatial data)
-Don
On 11/19/10 5:
On Nov 19, 2010, at 12:50 PM, David Winsemius wrote:
On Nov 19, 2010, at 12:32 PM, Shi, Tao wrote:
Hi list,
I was trying to use "predict.coxph" to calculate martingale
residuals on a test
data, however, as pointed out before
What about resid(fit) ? It's my reading of Therneau & Gramsc
Hi David,
Thank you for the quick reply!
resid(fit) only gives the residuals on the training data not on test data.
...Tao
- Original Message
> From: David Winsemius
> To: "Shi, Tao"
> Cc: r-help@r-project.org; dieter.me...@menne-biomed.de; r_ting...@hotmail.com
> Sent: Fri, No
I second Harlan's call.
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English)
--
Dear all,
I don't like the current behaviour, but that change could break a lot of
existing documents. Since you can easily wrap your Sexpr arguments in a call to
whatever formatting function you want, why force all of those users to change
their documents?
I'm someone who would change a whole l
Immanuel -
I don't believe you can associate a color with a TclVar,
but you can use tkconfigure to change the color of a label.
Does this little program help?
library(tcltk)
base = tktoplevel()
lab = tklabel(base,text='correct',foreground='green')
tkpack(lab)
red = function(...)tkconfigure(lab
Just to get the message through that some already tried, e.g. on
Windows 7 with R (Rterm) you get:
> cat("\u2591","\u2592","\u2593")
¦ ¦ ¦>
>
See it didn't even cut'n'paste the same visual symbols as I see in
Rterm but I guess you cannot see that. Make sense? No? Point is,
expect issues if yo
On Nov 19, 2010, at 12:32 PM, Shi, Tao wrote:
Hi list,
I was trying to use "predict.coxph" to calculate martingale
residuals on a test
data, however, as pointed out before
What about resid(fit) ? It's my reading of Therneau & Gramsch [and of
help(coxph.object) ] that they consider thos
Hi Giovanni,
Thanks a lot for your input. I will explore using 'nlme' and 'lme4'. I had read
your paper early on and was hoping, for reasons outlined in your paper
regarding the differences in approaches and jargon between statisticians and
econometricians ..., I could do what I needed with the
Hi list,
I was trying to use "predict.coxph" to calculate martingale residuals on a test
data, however, as pointed out before
http://tolstoy.newcastle.edu.au/R/e4/help/08/06/13508.html
predict(mycox1, newdata, type="expected") is not implemented yet. Dieter
suggested to use 'cph' and 'predict
On Nov 19, 2010, at 11:45 AM, Jeff Newmiller wrote:
The glyphs displayed depend on the "terminal" you are using, which
may be operating-system dependent. Beware of assuming that other
people will see the same things you do in their consoles.
On a Mac this:
> cat("\u2591","\u2592","\u259
many thanks - that's perfect, excluding records on a rep-by-rep basis is what
I was just hoping for but I probably didn't explain myself that well!
James
--
View this message in context:
http://r.789695.n4.nabble.com/predict-an-rpart-model-how-to-ignore-missing-levels-in-a-factor-tp3049218p3050
The glyphs displayed depend on the "terminal" you are using, which may be
operating-system dependent. Beware of assuming that other people will see the
same things you do in their consoles.
"Mark Heckmann" wrote:
>just found it out.
>to get an overview:
>
>for (i in 2590:3000)
> cat(eval
just found it out.
to get an overview:
for (i in 2590:3000)
cat(eval(parse(text=paste("\"\\u", i, "\"", sep=""
Thanks,
Mark
Am 19.11.2010 um 17:24 schrieb Henrique Dallazuanna:
> In the plot window:
>
> plot(1, main = "\u2591\u2592\u2593")
>
>
> On Fri, Nov 19, 2010 at 2:02 PM, Mark
is it also possible on the console?
that is what i am actually interested in?
Thanks in advance!
Mark
Am 19.11.2010 um 17:24 schrieb Henrique Dallazuanna:
> In the plot window:
>
> plot(1, main = "\u2591\u2592\u2593")
>
>
> On Fri, Nov 19, 2010 at 2:02 PM, Mark Heckmann
> wrote:
> Hi,
>
> can
Hello all,
using package tcltk this is my problem:
I want to set a colour of a tclVar().
I have a tklabel (fixed in position) which should display two variables
occasionally.
If a constraint is fulfilled, the tklabel should display
correct<-tclVar('correct') in green, otherwise it should di
http://hudson-ci.org/
give hudson a try. It's incredibly easy to set up, and handles job
dependencies and notifications for job failures.
Its suggested use case is for automated software builds, but it fits
the role of scheduled jobs (and interjob dependencies) very well.
-Whit
On Fri, Nov 19
In the plot window:
plot(1, main = "\u2591\u2592\u2593")
On Fri, Nov 19, 2010 at 2:02 PM, Mark Heckmann wrote:
> Hi,
>
> can the R console print all extended ASCII characters?
> I am especially interested in characters 176-178 from
> http://www.asciitable.com/
> bottom table.
> As far as I kn
Hi
r-help-boun...@r-project.org napsal dne 19.11.2010 16:58:01:
> PtitBleu
>
> Hello Petr,
>
> Your solution works well with my example.
> But with the function I want to use (which calls another functions), I
still
> have errors.
> I have to work on it again (but only on monday).
>
> Again
Hi
r-help-boun...@r-project.org napsal dne 19.11.2010 16:34:04:
Without going too deeply to your code, try to check na.locf function from
zoo package.
I would split your data to list according to study and subject, use
na.locf with respect to your miising value types
> x<-c(NA, 1:5)
> y<-rev(
On Nov 19, 2010, at 10:09 AM, amit jain wrote:
Hi All,
Can anyone point to any package/resouce to schedule a job in R which
runs a .R file at a specified time ?
That wouldn't be an R function but rather a system function, wouldn't
it?
I couldn't find anything useful in R Reference ma
Hi,
can the R console print all extended ASCII characters?
I am especially interested in characters 176-178 from
http://www.asciitable.com/
bottom table.
As far as I know the character mapping in R is somewhat different
(octal).
So as I am not familiar with these things I am not sure if it
On Nov 19, 2010, at 10:38 AM, Marc Schwartz wrote:
What's wrong with:
options(prompt = paste(format(Sys.time(), "%a %b %d %X %Y %Z"),
">"))
Fri Nov 19 09:30:53 2010 CST>
Fri Nov 19 09:30:53 2010 CST>
Fri Nov 19 09:30:53 2010 CST>
That one doesn't get updated with every prompt.
Duncan Mur
Hello Petr,
Your solution works well with my example.
But with the function I want to use (which calls another functions), I still
have errors.
I have to work on it again (but only on monday).
Again thank you,
Ptit Bleu.
PS : I have access to all the functions but I don't want to modify all of
On 19/11/2010 10:38 AM, Dieter Menne wrote:
Duncan Murdoch-2 wrote:
>
> On 19/11/2010 10:12 AM, Yihui Xie wrote:
>> Maybe this should go to R-devel as a wishlist:
>> val<- format(eval(parse(text=cmd), envir=.GlobalEnv))
>>
> I don't like the current behaviour, but that change co
I want to use something like printCoefmat() in a print.summary method to
print a more nicely formatted version
of the result from a summary method, but where the estimates may be
cross-classified by one or more factors.
However, printCoefmat() assumes that the labels for the parameters are
the
On Nov 19, 2010, at 10:23 AM, Barry Rowlingson wrote:
Someone on stackoverflow.com was wondering how to display the current
time in the R prompt. I could have swore there was a mechanism for
hooking a function into R such that it is was called before the ">"
prompt was given, but no amount of s
Hi
r-help-boun...@r-project.org napsal dne 19.11.2010 15:41:08:
>
> Hello,
>
> I would like to replace a for loop with lapply in order to speed up the
> treatment of my data (I've read lapply can help to do it).
Not exactly. For loop if correctly written can be as quick as lapply. See
P.Burns
On Fri, Nov 19, 2010 at 3:36 PM, Duncan Murdoch
wrote:
> Barry was probably remembering SweaveHook.
The key is the "taskCallbackManager". Does exactly what it says on
the tin. Doesn't come up with any of my search strings!
Hopefully now this is in R-help it'll come up when people search for
Duncan Murdoch-2 wrote:
>
> On 19/11/2010 10:12 AM, Yihui Xie wrote:
>> Maybe this should go to R-devel as a wishlist:
>> val<- format(eval(parse(text=cmd), envir=.GlobalEnv))
>>
> I don't like the current behaviour, but that change could break a lot of
> existing documents.
>
On Nov 19, 2010, at 9:36 AM, Duncan Murdoch wrote:
> On 19/11/2010 10:31 AM, Marc Schwartz wrote:
>> On Nov 19, 2010, at 9:23 AM, Barry Rowlingson wrote:
>>
>> > Someone on stackoverflow.com was wondering how to display the current
>> > time in the R prompt. I could have swore there was a mech
On 19/11/2010 10:31 AM, Marc Schwartz wrote:
On Nov 19, 2010, at 9:23 AM, Barry Rowlingson wrote:
> Someone on stackoverflow.com was wondering how to display the current
> time in the R prompt. I could have swore there was a mechanism for
> hooking a function into R such that it is was called
Hello, using r-2.12.0 on a Toshiba laptop with Win7
I am trying to install JGR, iut installs OK but when loading, complains about
rJava
so I did:
> install.packages("rJava")
Installing package(s) into ‘I:\R\cran’
(as ‘lib’ is unspecified)
trying URL
'http://www.stats.ox.ac.uk/pub/RWin/bin/window
Hello all,
I have a big data.frame multiple studies, subjects and timepoints per
subject, i.e.
STUDY[,1] SUBJECT[,2] .. WT[,16] HT[,17] TEMP[,18] BSA[,19]
1 150 170 37
1.90
1 1NA
On Nov 19, 2010, at 9:23 AM, Barry Rowlingson wrote:
> Someone on stackoverflow.com was wondering how to display the current
> time in the R prompt. I could have swore there was a mechanism for
> hooking a function into R such that it is was called before the ">"
> prompt was given, but no amount
On 19/11/2010 10:12 AM, Yihui Xie wrote:
Maybe this should go to R-devel as a wishlist:
Can we change as.character() to format() in this line in
src/library/utils/R/Sweave.R?
val<- as.character(eval(parse(text=cmd), envir=.GlobalEnv))
i.e.
val<- format(eval(parse(tex
## i have one question anouth this package..
library(datasets)
eurodist
## if i type this i get max distance between european cities
> max(eurodist)
[1] 4532
## but i would like get something like this: 4532 Gilbratar - Anthens
## and another one..
## if a live in barcelona and i would like trav
On Nov 19, 2010, at 10:00 AM, PtitBleu wrote:
Thanks for your answer but do you have a solution using the function ?
I need to you use the data frame with a function (not the one given).
I do not think lapply is the *apply you want. since it will
individually access the columns and you app
Someone on stackoverflow.com was wondering how to display the current
time in the R prompt. I could have swore there was a mechanism for
hooking a function into R such that it is was called before the ">"
prompt was given, but no amount of searching in R's docs, R's source,
or RSiteSearch can find
On 19/11/2010 9:59 AM, Santosh Srinivas wrote:
Hello group,
I have a data frame called test.df with a bunch of columns.
When I do a print(test.df), I want the numbers to appear a pre-defined
setting.
I believe this can be achieved by sprintf but this needs to be done
individually for the data
Maybe this should go to R-devel as a wishlist:
Can we change as.character() to format() in this line in
src/library/utils/R/Sweave.R?
val <- as.character(eval(parse(text=cmd), envir=.GlobalEnv))
i.e.
val <- format(eval(parse(text=cmd), envir=.GlobalEnv))
I guess this wo
Hi All,
Can anyone point to any package/resouce to schedule a job in R which runs a .R
file at a specified time ?
I couldn't find anything useful in R Reference manual or RSiteSearch. I am sure
its there but i am unable to locate.
Thanks for your help.
Puneet
_
Any new thoughts on this? I really want to get this working again! Is there
someone else that can help or somewhere else I should be asking?
Thanks!
-Harlan
On Wed, Nov 17, 2010 at 10:16 AM, Harlan Harris wrote:
> Following up again. I found on the forums for the Google Apps API this
> threa
Thanks for your answer but do you have a solution using the function ?
I need to you use the data frame with a function (not the one given).
Thanks in advance again.
Ptit Bleu.
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