Hello All,
I am trying to get cluster heatmaps using R from Java in my application.
I got the Rserve using which I am able to make TCP/IP connection to R.
I am trying to send a double[][] array (say 5x8 dimensions) to R and convert
it into matrix using as.matrix() function in R. Is it correct to
Hi, I am a stata user trying to transition to R. Typically I compute
marginal effects plots for (example) probit models by drawing simulated
betas by using the coefficient/standard error estimates after I run a probit
model. I then use these simulated betas to compute first difference
marginal
I created variables automatically like this way
for(i in 1:5){
nam <- paste("a",i,sep="")
assign(nam,1:i)
}
and then, i want to insert a new data into "a2" variable. so, i did next
sentence
paste("a",2,sep="") <- 4
so, i got this error message
Error in get(paste("a", 2, sep =
Lazy and impatient? That's me!
I find it hard to say what my biggest misconceptions were.
Here's one thing:
What I realized very early on:
- many data analysis functions return a bunch of stuff, not all of which
you see when you print() it
what I *failed* to realize:
- The bunch of stuff
Hi,
If I do the following
sprintf("%A",pi)
"0X1.921FB54442D18"
I have this 16 byte character string
hx<-"400921FB54442D18"
This is the exact hex16 representation of PI in
IEEE float that R uses in Intel 32bit(little endian) Windows
SAS uses the same representation. 11 bit exponent and 53 bit
On Fri, Feb 26, 2010 at 1:28 PM, Saeed Abu Nimeh wrote:
> Pat,
> Off the bat, beginners and advanced. In addition, splitting by domain
> would be very helpful -- something along the lines of:
> http://cran.r-project.org/web/views/. But we should be careful, we do
> not want to create 20 other mail
sorry meant community not committee
On 2/26/10 8:36 PM, Saeed Abu Nimeh wrote:
Hi Ivan,
On 2/26/10 6:30 AM, Ivan Calandra wrote:
You are definitely right...
What to do with bad beginner's questions is not a simple issue.
If a "beginner's mailing list" is created, who will answer to such
quest
Hi Ivan,
On 2/26/10 6:30 AM, Ivan Calandra wrote:
You are definitely right...
What to do with bad beginner's questions is not a simple issue.
If a "beginner's mailing list" is created, who will answer to such
questions?
If I subscribe to the beginners mailing list, then I have to expect
novi
Dear Peter,
What data types does your list contain? Have you tried treating the list as
a data frame or matrix?
KeithC.
-Original Message-
From: Heym, Peter-Paul [mailto:ph...@ipb-halle.de]
Sent: Thursday, February 25, 2010 2:11 AM
To: r-help@R-project.org
Subject: [R] how to fast extr
And if your data is in a dataframe (... please include an example of
the results of str() next time...) :
> dfrm <- rd.txt("Column1, Column2, Column3
+ Yes,Yes,Yes
+ Yes,No,Yes
+ No,No,No
+ No,Yes,No
+ Yes,Yes,No", sep=",") #rd.txt is just a wrapper I use for
read.table(textConnection( ), hea
Thanks.
I think i mistake the sampling() with split().
2010/2/26 David Winsemius
>
> On Feb 26, 2010, at 2:40 PM, rusers.sh wrote:
>
> Your method seems to only re-express the data "data.frame(x, g)" using
>> another format.
>>
>
> In all fairness to the first respondent to your question, that
If your data is in a matrix named "orgdata" :
newvar <- apply(orgdata , 1, function(arow, if (all(arow=='Yes'))
'Yes' else 'No'
newdata <- cbind(orgdata, newvar)
finaloutcome <- newdata[ newvar=='Yes',]
The key to this is the apply() function.
I might have missed some parentheses...
There
Barry explained your first puzzle, but let me add some explanation
and examples.
tmpfun <- function( a =3 ) {a}
tmpfun()
[1] 3
tmpfun(a='x')
[1] "x"
Inside the function, the value of the argument is whatever the user
supplied. The default is replaced by what the user supplies. There i
I am new to R, but have been using SAS for years. In this transition period,
I am finding myself pulling my hair out to do some of the simplest things.
An example of this is that I need to generate a new variable based on the
outcome of several existing variables in a data row. In other words,
On Fri, Feb 26, 2010 at 10:56 PM, Shang Gao wrote:
> Dear R users,
>
> A co-worker and I are writing a function to facilitate graph plotting in R.
> The function makes use of a lot of lists in its defaults.
>
> However, we discovered that R does not necessarily preserve the defaults if
> we were
On Feb 26, 2010, at 5:18 PM, Sharpie wrote:
>
>
> Ista Zahn wrote:
>>
>> Hi Tao,
>> Just set the appropriate *.just argument, e.g.:
>>
>> Dat <- data.frame(x1 = rep("this value consists of a long string of
>> text", 5), x2 = rep("this value consists of an even longer string of
>> text", 5))
>>
Hi Ista,
Thanks! I missed that.
...Tao
> From: istaz...@gmail.com
> Date: Fri, 26 Feb 2010 17:48:32 -0500
> Subject: Re: [R] wrap long lines in table using "latex" in Hmisc
> To: shi...@hotmail.com
> CC: r-help@r-project.org
>
> Hi Tao,
> Just set the a
Ista Zahn wrote:
>
> Hi Tao,
> Just set the appropriate *.just argument, e.g.:
>
> Dat <- data.frame(x1 = rep("this value consists of a long string of
> text", 5), x2 = rep("this value consists of an even longer string of
> text", 5))
>
> library(Hmisc)
> latex(Dat, col.just = rep("p{1in}", 2
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of kayj
> Sent: Friday, February 26, 2010 12:02 PM
> To: r-help@r-project.org
> Subject: Re: [R] using grep
>
>
> Hi ,
>
> I have tried
>
> gsub(".*York(\\d+).*", "\\1", grep("Ne
Dear R users,
A co-worker and I are writing a function to facilitate graph plotting in R. The
function makes use of a lot of lists in its defaults.
However, we discovered that R does not necessarily preserve the defaults if we
were to input them in the form of list() when initializing the funct
On Feb 26, 2010, at 12:20 PM, Daniel wrote:
> Hi all,
> anybody get connection with Filemarker 10 for mac?
> How do that?
> I suppose did right, but it is not working.
You need to be sure that you have the current version of R (2.10.1), the
current version of the RODBC package (1.3-0), an ODBC
Hi Tao,
Just set the appropriate *.just argument, e.g.:
Dat <- data.frame(x1 = rep("this value consists of a long string of
text", 5), x2 = rep("this value consists of an even longer string of
text", 5))
library(Hmisc)
latex(Dat, col.just = rep("p{1in}", 2))
You can also set justification for c
On Feb 26, 2010, at 1:04 PM, Yan Zhang wrote:
> I've installed R-2.9.2 (64 bit), unixODBC-2.2.14-p2 (64 bit) and RODBC_1.2-5
> (64 bit) on a 64 bit Redhat Linux server (Red Hat Enterprise Linux Server
> release 5.4 (Tikanga), x86_64) release 2.6.18-164.2.1.el5. I've tested the
> ODBC drive via
On Feb 26, 2010, at 3:02 PM, kayj wrote:
Hi ,
I have tried
gsub(".*York(\\d+).*", "\\1", grep("New York", x, value = TRUE))
and outputs
"P New York722AZ" "K New York20"
Strange:
> x<-c("P Los Angeles44AZ", "P New York722AZ", "K New York20")
>
> gsub(".*York(\\d+).*", "\\1", grep("New Yo
Hi,
I am interested in decomposing an irregularly spaced time series and getting
results similiar to that obtained with the stl command for a regularly spaced
time series. I would like to know if any of the time series packages like zoo
can be used for this. From my search, I was only able to f
What is your R version?
Install the most recent R version (2.10.1).
On Fri, Feb 26, 2010 at 5:02 PM, kayj wrote:
>
> Hi ,
>
> I have tried
>
> gsub(".*York(\\d+).*", "\\1", grep("New York", x, value = TRUE))
>
> and outputs
>
> "P New York722AZ" "K New York20"
> but that is not what i want, I w
Hi ,
I have tried
gsub(".*York(\\d+).*", "\\1", grep("New York", x, value = TRUE))
and outputs
"P New York722AZ" "K New York20"
but that is not what i want, I want the output to be
722,20
--
View this message in context:
http://n4.nabble.com/using-grep-tp1571102p1571251.html
Sent fro
Hello!
I have read somewhere (somehow, I can't seem to find it again, it's been a
couple of months) that when analyzing factorial block design, the position
where you put the block factor is important, even more when there are missing
values.
I understand that when using anova.lm, the order is
I've installed R-2.9.2 (64 bit), unixODBC-2.2.14-p2 (64 bit) and RODBC_1.2-5
(64 bit) on a 64 bit Redhat Linux server (Red Hat Enterprise Linux Server
release 5.4 (Tikanga), x86_64) release 2.6.18-164.2.1.el5. I've tested the
ODBC drive via isql and the test was success:
[yzh...@roracletest ~]
Thanks Duncan, that did the trick.
I added a new proxy to the FoxyProxy list, white listing 127.0.0.1 and moved
that to the top of the list.
Help.start() works fine now.
Bill
> -Original Message-
> From: Duncan Murdoch [mailto:murd...@stats.uwo.ca]
> Sent: Friday, February 26, 2010 1:00 P
Ryan Kinzer wrote:
Erik
Thanks for helping. Both of them are factors.
That's the problem, they need to be of class Date. See the R NEWS
article about Date classes in Volume 4/1.
http://cran.r-project.org/doc/Rnews/
I don't see how they could be factors though, since you shouldn't be
Sarah,
Thank you very much, this an easy solution that works very well!
On a more complicated note, is there a way to embed the station name in a
header or footer of the document? It seems there is no way to evaluate a
chunk or an inline \Sexpr{...} in a header or footer?
This would put station I
I'm trying to do data grouping like you said. I will look into data.table
package and I will also consider using a matrix instead of a data frame.
Thank you for your responses.
Thanks,
Rob
On Fri, Feb 26, 2010 at 3:21 PM, Tom Short wrote:
> I'm sorry, Rob, but that code is dense enough and for
I'm sorry, Rob, but that code is dense enough and formatted badly
enough that it's hard to dig through.
You may want to try the data.table package. The development version on
R-forge is pretty fast for grouping operations like this. I'm not sure
if this is what you're really after. It's hard to te
On my computer your two examples seem to execute about the same:
> fedb.ddplyWrapper2Fast <- function(data, pivotColumns, listNameFunctions,
+ ...){
+ lapplyFunctionRecurse <- function(cdata, level=1, ...){
+if(level==1){
+
+
return(lapply(split(seq(nrow(cdata)),cdata[,pivotColu
If you do everything in Windows, Tinn-R is one of the best and also the one I
use. I also tried WinEdt. It's very good, but it is not free. If you want a
cross-platform editor, Emacs+ESS is the one. Like others said, the learning
curve is steep, but worth it.
...Tao
===
I tend to do it the other way around.
Hard-code the station into the ODT file as "thisstation".
Then, in R, do something like this:
allstations <- c("station1", "station2", "station3")
for (i in allstations) {
thisstation <- i
odfWeave("inputfile.odt", paste("output-", i, ".odt", sep=""))
Dear R and odfWeave users,
I am looking for a way to automate generation of many reports using
odfWeave. All reports would use the same input ODT file, the only difference
would be in the name of the dataset which will be analyzed in any particular
report. Right now, the name of the dataset is har
Try this:
foo <- function()
sprintf("The name of this function is %s", gettext(match.call()))
On Fri, Feb 26, 2010 at 5:22 PM, Jacob Wegelin wrote:
>
> Within a function I'd often like to obtain a text string equal to the name
> of the function.
>
> One use for this: To generate a filena
Hi list,
Is there a way to control long-line wrapping in a table using "latex" function
in Hmisc or any other functions? It seems I can't find any examples.
Thank you very much!
...Tao
> This seems to be plain text help, right?
It is.
> Does the html version give the same result?
Interestingly, the html seems to be whole; but it's less convenient to
access from ESS, though.
Do you know what program generates the plain text; and are there any
options that govern where R looks
Within a function I'd often like to obtain a text string equal to the name of
the function.
One use for this: To generate a filename for use in pdf(). This enables me to
keep track of which function generated a particular graphic came.
match.call() puts parentheses at the end of the name. I d
On Feb 26, 2010, at 2:40 PM, rusers.sh wrote:
Your method seems to only re-express the data "data.frame(x, g)" using
another format.
In all fairness to the first respondent to your question, that _was_
what it appeared you were requesting. My other thoughts would be:
> cbind(x[order(g)],
So I have a function that does lapply's for me based on dimension. Currently
only works for length(pivotColumns)=2 because I haven't fixed the rbinds. I
have two versions. One runs WAYYY faster than the other. And I'm not sure
why.
Fast Version:
fedb.ddplyWrapper2Fast <- function(data, pivotColum
My biggest impediment, as a scientist without previous programming
experience, is that the R help is not beginner-friendly. I think it is
probably great for experienced programmers and for the people who helped to
create the software, to help them remember what they did, but I think it is
very di
You can work with factor also:
week <- c('SAT', 'SUN', 'MON', 'FRI')
factor(week, levels = week, labels = 1:4)
On Fri, Feb 26, 2010 at 4:31 PM, Steve Matco wrote:
> Hi everyone,
>
> I am at my wits end with what I believe would be considered simple by a more
> experienced R user. I want to know
Hi, two approaches at least.
a. a nested ifelse statement
b. merging the original data frame with DOW in it with a data frame that
holds the day "MON" to "SUN" and their indicators.
Both approaches illustrated below:
DOW=rep(c("MON","TUE"),100)
#nested ifelse approach
DOW.ind=ifelse(DOW=="MON",
So, I don't understand what you want, you want add the factor to split
result, isn't?
#Example
set.seed(1234)
n <- 3; nn <- 10
g <- factor(round(n * stats::runif(n * nn))) #factor
x <- rnorm(n * nn) + sqrt(as.numeric(g))#value
xg <- split(x, g)
xg
xgD <- split(data.frame(x, g), g)
sapply(x
You could also try a series of simple ifelse statements. I just tried
the following and got it to work, though I am sure there is a faster
way.
t=c("cow", "dog", "chick")
y=c(1,3,4)
mat=cbind(t,y)
mat=as.data.frame(mat)
> mat
t y
1 cow 1
2 dog 3
3 chick 4
mat$g=ifelse(mat$t=="c
Your method seems to only re-express the data "data.frame(x, g)" using
another format. The results are really from the generated data frame. Maybe
be not good.
> table(g)
g
0 1 2 3
7 9 8 6
I hope to randomly split the value 'x' according to the different sample
sizes of different levels, displaye
Try this:
sapply(c('SAT', 'SUN', 'MON', 'FRI'), switch, SAT = 1, SUN = 2, MON =
3, FRI = 4)
On Fri, Feb 26, 2010 at 4:31 PM, Steve Matco wrote:
> Hi everyone,
>
> I am at my wits end with what I believe would be considered simple by a more
> experienced R user. I want to know how to add a vari
You mention ifelse, so for completeness, I will show you a solution that
should work with that. There are other plenty of other possibilities
though, I am sure. The follow is not tested..
Assume 'my.df' is your data.frame, containing a variable "DOW".
my.df$DOW1 <- ifelse(my.df$DOW == "SAT",
Hi everyone,
I am at my wits end with what I believe would be considered simple by a more
experienced R user. I want to know how to add a variable to a dataframe whose
values are conditional on the values of an existing variable. I can't seem to
make an ifelse statement work for my situation. T
Patrick Burns
> * What were your biggest misconceptions or
> stumbling blocks to getting up and running
> with R?
I came into R from SAS, with its powerful data step language and very
simplified data types. Most of my work is data manipulation prior to a
variety of univariate statistical calcu
On 26/02/2010 11:31 AM, Raynor, Bill wrote:
I just upgraded to 2.10.1 on a WinXPSP2 machine. When I type help.start() R
attempts to open a browser session at
http://127.0.0.1:27594/doc/html/index.html using my default browser (Firefox
3.6) and is unable to connect. If I then open the same page
Try this:
split(data.frame(x, g), g)
On Fri, Feb 26, 2010 at 3:55 PM, rusers.sh wrote:
> Hi,
> I am using split function and wonder how to add the factor to the splitted
> results.
> #Example
> n <- 3; nn <- 10
> g <- factor(round(n * stats::runif(n * nn))) #factor
> x <- rnorm(n * nn) + sqrt
It depends on your needs, your budget, and your personal tastes. I program in a
number of languages, so I want a text editor that I can configure easily. I
used CodeWright for years, but it's in limbo now since Borland acquired it and
no longer supports it.
I've switched over to SlickEdit. One
Hi,
I am using split function and wonder how to add the factor to the splitted
results.
#Example
n <- 3; nn <- 10
g <- factor(round(n * stats::runif(n * nn))) #factor
x <- rnorm(n * nn) + sqrt(as.numeric(g))#value
xg <- split(x, g)
xg
$`0`
[1] 0.82513702 -0.03911584 2.32955347 0.36745335
On 26/02/2010 1:04 PM, Joris Meys wrote:
Dear all,
I'm trying to understand the S4 way of object-oriented programming, but I
still can't grasp completely what R is doing. I have a class definition for
a class called PM10Meteo, and I set a initializer function. next, I include
a show method and a
Hello,
Ryan Kinzer wrote:
I am trying to understand why R is working in a particular way. I have a
data set with two variables; mark date (markd) and recap date (recapd). I
would like to know the number of days between capture dates. But if I
subtract recap date from mark date I often get the
Hi Frederik,
Not exactly clear how you want them sorted, but one of these two is
probably what you want:
mat <- matrix(100:1, ncol=10)
mat.1 <- apply(mat, 2, sort)
mat.2 <- mat[order(10:1),]
Best,
Ista
On Fri, Feb 26, 2010 at 12:41 PM, frederik vanhaelst
wrote:
> Hello,
>
> i have a 50*100 mat
Try this:
apply(m, 2, sort)
On Fri, Feb 26, 2010 at 2:41 PM, frederik vanhaelst
wrote:
> Hello,
>
> i have a 50*100 matrix, with real numbers. How do i sort each column?
> Now i sort it with a for-loop but this take a lot of time...
>
> Thank you,
>
> Frederik
>
> [[alternative HTML versi
Try this:
gsub(".*York(\\d+).*", "\\1", grep("New York", x, value = TRUE))
On Fri, Feb 26, 2010 at 3:27 PM, kayj wrote:
>
> Hi All,
>
> I have a character vector with naems of cities in the us. I need to extract
> the number that appear after the word "New York", for example,
>
> x<-c("P Los Ang
On 26.02.2010 19:04, Joris Meys wrote:
Dear all,
I'm trying to understand the S4 way of object-oriented programming, but I
still can't grasp completely what R is doing. I have a class definition for
a class called PM10Meteo, and I set a initializer function. next, I include
a show method and a
I am trying to understand why R is working in a particular way. I have a
data set with two variables; mark date (markd) and recap date (recapd). I
would like to know the number of days between capture dates. But if I
subtract recap date from mark date I often get the wrong results.
Example:
The length will remain the same no matter what expression appears in the
subscript. I suggest this:
sum(x == 1)
David Reinke
Senior Transportation Engineer/Economist
Dowling Associates, Inc.
180 Grand Avenue, Suite 250
Oakland, California 94612-3774
510.839.1742 x104 (voice)
510.839.0871 (fax)
Hi all,
anybody get connection with Filemarker 10 for mac?
How do that?
I suppose did right, but it is not working.
--
Daniel Marcelino
Phone: (647) 8910939
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://sta
Hi All,
I have a character vector with naems of cities in the us. I need to extract
the number that appear after the word "New York", for example,
x<-c("P Los Angeles44AZ", "P New York722AZ", "K New York20")
I want the results to be
722, 20
cab I use the grep function, if so how?
I apprecia
Hello,
i have a 50*100 matrix, with real numbers. How do i sort each column?
Now i sort it with a for-loop but this take a lot of time...
Thank you,
Frederik
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://st
I just upgraded to 2.10.1 on a WinXPSP2 machine. When I type help.start() R
attempts to open a browser session at
http://127.0.0.1:27594/doc/html/index.html using my default browser (Firefox
3.6) and is unable to connect. If I then open the same page using IE 8, it
works just fine. How do I fix
Pat,
Off the bat, beginners and advanced. In addition, splitting by domain
would be very helpful -- something along the lines of:
http://cran.r-project.org/web/views/. But we should be careful, we do
not want to create 20 other mailing lists :) We have to group things.
This will help splitting the
Sharpie wrote:
Dwayne Blind wrote:
Dear all,
Do you use a text editor ? What would you recommend for Windows users ?
What
about Tinn-R ?
Thank you very much,
Dwayne
Learning a text editor is a significant and very valuable investment of your
time. In order to maximize the return from thi
On 26/02/2010 12:55 PM, Allen L wrote:
Dear R forum,
I've looked many places for this and figure there must be an easy way to
implement.
I want to set the working directory in my script to the place where the R
code is located.
Something like:
>setwd(directory where this script is found).
If
Khazaei -
I think
mapply(function(x,ind)x * a / (b + ind),c(NA,w),c(NA,1:length(w)))
does what you want, but since you didn't include a reproducible
example, I can't tell for sure.
- Phil Spector
Statistical Com
Dear all,
I'm trying to understand the S4 way of object-oriented programming, but I
still can't grasp completely what R is doing. I have a class definition for
a class called PM10Meteo, and I set a initializer function. next, I include
a show method and a print method as shown below.
setClass( Cl
Dear R forum,
I've looked many places for this and figure there must be an easy way to
implement.
I want to set the working directory in my script to the place where the R
code is located.
Something like:
>setwd(directory where this script is found).
Thanks!
-Allen
--
View this message in con
> "UweL" == Uwe Ligges
> on Fri, 26 Feb 2010 17:24:43 +0100 writes:
UweL> On 26.02.2010 17:04, linda garcia wrote:
>> Dear all,
>> I am using biclust package for biclustering. I wanted to
>> know how can I extract my clusters from the object?
>>
>>
>> lib
Sharpie wrote:
>
> For example, I spend an equal amount of time working on Windows, OS X and
> Linux. There are a ton of great Windows-only editors out there, but they
> aren't a good option for me because I only use windows 1/3 of the time I'm
> at a computer.
>
> Some good editors I know of
Dwayne Blind wrote:
>
> Dear all,
>
> Do you use a text editor ? What would you recommend for Windows users ?
> What
> about Tinn-R ?
>
> Thank you very much,
> Dwayne
>
>
Learning a text editor is a significant and very valuable investment of your
time. In order to maximize the return fro
Dear Patrick (and all)
I'm now working with R a couple of years, before working mostly in Matlab
Lazy & impatient is both true for me :-)
* What were your biggest misconceptions or
stumbling blocks to getting up and running
with R?
> * What documents helped you the most in this
> initial phas
I also agree, Emacs without question. The learning curve is a bit steep
but once you know it you can use it
for just about anything, but cleaning the kitchen sink!
Gérald Jean
Conseiller senior en statistiques,
VP Planification et Développement des Marchés,
Desjardins Groupe d'Assurances Générale
On Fri, Feb 26, 2010 at 11:57 AM, Matt Asher wrote:
> Hi,
>
> This:
>
> agents <- list(agent(1), agent(2))
>
> worked perfectly. Thanks Uwe!
>
> I'm not fully sure what you mean by this:
>
> "
> Anyway, I hope you know that lexical scoping will yield in the
> environments attached to all those fun
As has been said before: Emacs! It's not as scary as it used to be.
For Windows I recommend
http://vgoulet.act.ulaval.ca/en/ressources/emacs/
-Ista
On Fri, Feb 26, 2010 at 11:10 AM, Dwayne Blind wrote:
> Dear all,
>
> Do you use a text editor ? What would you recommend for Windows users ? What
>
Hi,
This:
agents <- list(agent(1), agent(2))
worked perfectly. Thanks Uwe!
I'm not fully sure what you mean by this:
"
Anyway, I hope you know that lexical scoping will yield in the
environments attached to all those functions they have been generated in
and you know about possible consequenc
How about taking the unusual step of reading 'An Introduction to R',
where, if you peruse the table of contents, you will quickly be led
to Chapter 8: Probability Distributions.
-Peter Ehlers
On 2010-02-26 7:23, Антон Морковин wrote:
Dear all,
how to calculate values of t-distribut
My apologies, I misread your formula. Here is a clearer example anyways:
w <- 1:10
N <- length(w)
a <- 1
b <- 1
k <- 1:(N-1)
w[k+1] <- w[k]*(a/(b+k))
w
[1] 1.000 0.500 0.667 0.750 0.800 0.833 0.8571429
[8] 0.875 0.889 0.900
Best,
Josh
On Fri, Feb 26, 2010
Cassiano wrote:
I think I have 'libgfortran'.
After that I digit 'dpkg -l | grep libgfortran' in terminal, I got this
message:
ii libgfortran2 4.2.4-5ubuntu1
Runtime library for GNU Fortran applications
ii libgfortran2-dbg
Cassiano wrote:
I think I have 'libgfortran'.
After that I digit 'dpkg -l | grep libgfortran' in terminal, I got this
message:
ii libgfortran2 4.2.4-5ubuntu1
Runtime library for GNU Fortran applications
ii libgfortran2-dbg
On 26.02.2010 17:04, linda garcia wrote:
Dear all,
I am using biclust package for biclustering. I wanted to
know how can I extract my clusters from the object?
library(biclust)
test<- matrix(rnorm(5000), 100, 50)
test[11:20,11:20]<- rnorm(100, 3, 0.1)
loma<- binarize(test,
Thomas Adams wrote:
Paul,
I think your point "you need [to] spend at least a few hours a week on
it" is key. Since I am not doing statistics daily, more in fits &
starts as my latest project -may- require, my approach has been more
task oriented. A less-than-ideal approach. So, I think your s
There is a list here:
http://www.sciviews.org/_rgui/projects/Editors.html
On Fri, Feb 26, 2010 at 11:10 AM, Dwayne Blind wrote:
> Dear all,
>
> Do you use a text editor ? What would you recommend for Windows users ? What
> about Tinn-R ?
>
> Thank you very much,
> Dwayne
>
> [[alternative
A general facility for this is Reduce:
f <- function(w, k, a = 2, b = 1) w*a / (b+k)
c(7, Reduce(f, 2:9, 7, accumulate = TRUE))
the result of which is:
c(7, Reduce(f, 2:9, 7, accumulate = TRUE))
[1] 7.00 7.00 4.67 2.33 0.93
0.31 0.09 0.022
I'm trying to implement the two-sample Wald-Wolfowitz runs test. Daniel
(1990) suggests a method to deal with ties across samples. His suggestion
is to prepare ordered arrangements, one resulting in the fewest number of
runs, and one resulting in the largest number of runs. Then take the mean
of
On Fri, Feb 26, 2010 at 6:14 AM, Sebastien Bihorel
wrote:
> Thanks Deepayan,
>
> This confirms what I thought I should do... One follow-up question about
> your suggested code: is it possible to create a lattice graph object myplot
> and modify the layout just for panel 7 and 8, rather than creati
Thank you both for your replies; both are very useful. The larger issue at hand
is that the data will actually be huge, thus the end result will be a very
large, sparse data frame.
So, I decided to put all three possible solutions to a timing test and see what
they yield. I simulated 15000 poss
On 26.02.2010 16:33, Matt Asher wrote:
Hi folks,
I am having trouble accessing sub-functions when the main function is
stored in an array. For example, the following test code works fine:
fcns = c(abs, sqrt)
fcns[[1]](-2)
fcns[[2]](2)
However, when I try to access sub-functions declared with
Dwayne Blind wrote:
Dear all,
Do you use a text editor ? What would you recommend for Windows users ? What
about Tinn-R ?
Dwayne,
Perhaps you have seen http://www.sciviews.org/_rgui/ , it has
information on several possibilities. It would be hard to pull me away
from using Emacs with ESS
On 26.02.2010 05:22, Yi Du wrote:
Hi there,
I use plot(type="o") to draw the line. And I need put some legend to this
line. But how can I let the legend to display the line type in the graph
generated from type="o"? I can only find the lty in the legend. But I tried
several times and still fa
But if x has any missing values:
> x <- c(1, 1, 1, NA, NA, 2, 1, NA)
>
> sum( x == 1)
[1] NA
>
> sum(x==1, na.rm=TRUE)
[1] 4
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Henrique Dallazuanna
Sent: Friday, February 26, 2010
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of
> khaz...@ceremade.dauphine.fr
> Sent: Friday, February 26, 2010 7:23 AM
> To: r-help@r-project.org
> Subject: [R] question to make a vector without loop
>
> Hello all,
>
> I
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