Hi,
I'm new to CART. I have a data set with a binary reponse (0/1) and several
predictors. I chose 2 continuous predictors to start and used the following
code.
testdata.ltr<-tree(nondev85dev06~dist_rampm_wa + dis_prim_wa,testdata)
The two predictors should be quite explanatory based upon prev
Hi,
Could you please tell me whether there are feature selection algorithms in R or
not such as genetic algorithms? If so, could you please tell me in which
package?
Cheers,
Amy
_
View
Are you really trying to read in binary? You are asking for
characters which would be a null terminated string. If you are trying
to read in binary zeroes, this will not work. What you need to do is
to use 'raw'. Actually you should create a R script to test out the
various conditions you want.
I am using readBin to continuously read characters from the binary file. I'm
trying to figure out how many characters are in the file. What I would like
to do is something like
(while! EOF)
{
charRead <-.Internal(readBin(con,"character",1L,NA,TRUE,swap))
i++
}
I'm not clear on how to determine th
I have 6 or 7 nice constants (for example 1852 meters per nautical mile)
I would like to have available to 4 or 5 functions in an R package. In
C this would just be a header .h file and I would just "include" I am
stuck trying to figure out how to create something like a C header file
for an R p
If you are reading a 'binary' file, then the end of file is when you
read the last byte; the system will tell you. Exactly what are you
trying do to? When you do a read, you typically request the number of
bytes to read and then the system returns the number of bytes read.
But since you did not g
Hello,
I'm new to R and I'm writing a function to read binary tables (the binary
version of read.table essentially). I'm having trouble figuring out how to
determine when I reach end-of-file. Can anybody please help?
thanks!
--
View this message in context:
http://n4.nabble.com/End-of-File-for
On 24-Jan-10 00:27:37, Jim Lemon wrote:
> On 01/24/2010 11:11 AM, anna wrote:
>>
>> Here is the last code that I wrote but it would give me the
>> same problem:
>> I have the matrix mat with n columns mat.1, mat.2 ...mat.n
>>
>> #To be able to use lapply I convert it to a data.frame:
>> mat<- data
http://nseindia.com/content/equities/scripvol/datafiles/01-01-2010-TO-23-01-2010RCOMXN.csv
the url is correct. it is not zipped file.
copy the url in the browser window you will get the
this ..
Symbol,Series,Date, Prev Close,Open Price,High Price,Low Price,Last
Price,Close Price,Average Pr
Regarding your subject, the sqldf package on CRAN allows you to apply
SQL statements directly to R data frames. http://sqldf.googlecode.com
On Sat, Jan 23, 2010 at 5:46 PM, Dimitri Shvorob
wrote:
>
> ... Being an R newbie, I can only think of extracting distinct x values with
> unique, looping o
Hi,
this could be due to how NFS works. Note that there can be up to a 30
second delay before other hosts on the same file system see the
updates that was flushed by one machine. You basically cannot treat
files on an shared NFS file system as if you are working on a single
machine. You have to
On 01/24/2010 11:11 AM, anna wrote:
Here is the last code that I wrote but it would give me the same problem:
I have the matrix mat with n columns mat.1, mat.2 ...mat.n
#To be able to use lapply I convert it to a data.frame:
mat<- data.frame(mat)
lapply(mat, function, argument of function)
It
Yes.
?sqldf
?split
?lapply
But unless you provide commented, minimal, self-contained,
reproducible code, it is hard to say how to proceed to a solution.
On Sat, Jan 23, 2010 at 5:46 PM, Dimitri Shvorob
wrote:
>
> ... Being an R newbie, I can only think of extracting distinct x values with
> uni
On 01/24/2010 03:25 AM, Tal Galili wrote:
Marc,
Following the R FAQ you linked to, I wonder how to ALWAYS have the text and
the plot region fit.
I know that if the text is too long, one can use the par(mar = c(big.number,
4, 4 ,4)) and get the text to fit.
The question is:
Is there a way to make
Here is the last code that I wrote but it would give me the same problem:
I have the matrix mat with n columns mat.1, mat.2 ...mat.n
#To be able to use lapply I convert it to a data.frame:
mat <- data.frame(mat)
lapply(mat, function, argument of function)
It works but I still get for all eleme
Dear friends - please give me a hand.
I have a dataset of 40 patients in two groups observed on three
occasions. I only want to plot a line
for each patient in the two groups. I use the ltext function to put the
patient number but fail to make lattice understand the numbers as
unique since ap
... Being an R newbie, I can only think of extracting distinct x values with
unique, looping over them, extracting matching rows from the original data
frame, applying table, and recording the size of table's output alongside
the x value being checked. Is there a more elegant way?
Thank you.
--
Hello everyone, I get for each date a measure for n elements in the form of a
matrix. I am converting it to a ts object using ts(). I want to apply a
function on each column. I started using the apply function ( set to 2) but
what it returns is a matrix with the same columns representing the funct
Hi ff users and Jens,
I am using the ff package and it has been working great. Recently I
noticed an unexpected behavior in the ff package -- when I save an ff
matrix on one machine to an NFS drive and load it on another machine from
the save NFS drive, I got quote a lot of zeros in the matrix.
Christophe,
That's another question for the R-devel mailing list.
A few things however.
Short answer : no it is not possible. I don't think x[i,j] is even
syntactically valid in C or C++.
I'd suggest you to give a go at the .Call interface that lets you
manipulate R objects directly. So in
And once you've renamed the file and started R,
it might be worth a try to see if you can 'attach'
the file.
On 23/01/2010 17:22, Duncan Murdoch wrote:
On 23/01/2010 10:56 AM, Badaoui, Saad wrote:
Dear R help team,
I am trying to open R to continue my analysis but it doesn't want to
open and I
How about?
eval( D( expression( t^3-6*t^2+5*t+30 ), "t" ) )
David Winsemius wrote:
On Jan 22, 2010, at 6:49 PM, Marlin Keith Cox wrote:
I can plot this just fine:
t<-seq(0,4, by=.1)
y<- t^3-6*t^2+5*t+30
plot(t,y ,xlab="t-values", ylab="f(t)", type="l")
This is the first derivative, how I I
On 23/01/2010 10:56 AM, Badaoui, Saad wrote:
Dear R help team,
I am trying to open R to continue my analysis but it doesn't want to open and I get this
message "fatal error unable to restore saved data in .rdata". I don't know what
went wrong ( iam using Windows). Could you please help me on t
Colleagues,
Using R 2.10.1 in OS X (Snow Leopard), I created JPEG documents that
were intended to include italicized text. In the JPEG versions, the
italics appear in bold-face. The identical code (except for the call
to the device) yields italics in PDF. A minimal example is:
PDF vers
Dear R help team,
I am trying to open R to continue my analysis but it doesn't want to open and I
get this message "fatal error unable to restore saved data in .rdata". I don't
know what went wrong ( iam using Windows). Could you please help me on this?
Thanks a lot
Best Regards
Saad
You can guess by looking at class(g). It is a factor. It is NOT
regressing on the mean of g (i.e. 2.5 and 7.5) and you could have
changed g from (0,5] and (5,10] to A and B with the same results.
Read some books or help(lm) to get an idea of what the outputs mean.
Regards, Adai
newbieR
On Jan 23, 2010, at 9:59 AM, Uwe Ligges wrote:
>
>
> On 23.01.2010 16:56, Marc Schwartz wrote:
>> On Jan 23, 2010, at 9:51 AM, Uwe Ligges wrote:
>>
>>>
>>>
>>> On 22.01.2010 21:26, Tal Galili wrote:
Hello dear R help group,
I learned recently that one can change the rot
On 23.01.2010 17:50, Remus Suciu wrote:
Hi.
I'm trying to create an Agresti-Coull confidence interval without using the
binom package.
Despite many trials, I keep getting the same problem- see below.
y=334
n=1160
alpha=.05
b=(y+.5*qnorm(1-alpha/2)**2)/(n+qnorm(1-alpha/2)**2)
b
[1] 0.288631
a
On 23.01.2010 01:35, 李道丰 wrote:
Hi,
how to compile with tcl/tk support ? command line options?
thank you:)
There is a manual called "R Installation and Administration" you are
obviously not aware of (probably because you never read the posting
guide of the mailing list). That manual contai
On 23.01.2010 16:56, Marc Schwartz wrote:
On Jan 23, 2010, at 9:51 AM, Uwe Ligges wrote:
On 22.01.2010 21:26, Tal Galili wrote:
Hello dear R help group,
I learned recently that one can change the rotation of labels in the axis,
when using a lattice plot, for example:
library(lattice)
ba
On Jan 23, 2010, at 9:51 AM, Uwe Ligges wrote:
>
>
> On 22.01.2010 21:26, Tal Galili wrote:
>> Hello dear R help group,
>>
>>
>> I learned recently that one can change the rotation of labels in the axis,
>> when using a lattice plot, for example:
>>
>> library(lattice)
>> barchart(yield ~ var
Marc,
Following the R FAQ you linked to, I wonder how to ALWAYS have the text and
the plot region fit.
I know that if the text is too long, one can use the par(mar = c(big.number,
4, 4 ,4)) and get the text to fit.
The question is:
Is there a way to make the plot "know" what "big.number" should be
On 23.01.2010 17:42, Marc Schwartz wrote:
On Jan 23, 2010, at 10:25 AM, Tal Galili wrote:
Marc,
Following the R FAQ you linked to, I wonder how to ALWAYS have the text and the
plot region fit.
I know that if the text is too long, one can use the par(mar = c(big.number, 4,
4 ,4)) and get the
Hi.
I'm trying to create an Agresti-Coull confidence interval without using the
binom package.
Despite many trials, I keep getting the same problem- see below.
> y=334
> n=1160
> alpha=.05
> b=(y+.5*qnorm(1-alpha/2)**2)/(n+qnorm(1-alpha/2)**2)
> b
[1] 0.288631
> ac=b+qnorm(1-alpha/2)*sqrt(b(1-b)/(n
Read the Matrix package documentation
require(Matrix)
help(lu, html=TRUE)
Walmes.
-
..oooO
..
..()... 0ooo... Walmes Zeviani
...\..(.(.)... Master in
On Jan 23, 2010, at 10:25 AM, Tal Galili wrote:
> Marc,
> Following the R FAQ you linked to, I wonder how to ALWAYS have the text and
> the plot region fit.
> I know that if the text is too long, one can use the par(mar = c(big.number,
> 4, 4 ,4)) and get the text to fit.
> The question is:
> Is
Hi the list,
Is there a way to give a matrix to a C function, and then to use it as a
matrix ?
I write a function to print a matrix, but I use it as a vector :
1. void printMatrix(double *mTraj,int *nbCol, int *nbLigne){
2. int i=0,j=0;
3. for(i=0 ; i < *nbLigne ; i++){
4. for(j=0
Uwe and Marc,
You two just made me smile in more then one way - thank you :)
Tal
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www
On 22.01.2010 21:26, Tal Galili wrote:
Hello dear R help group,
I learned recently that one can change the rotation of labels in the axis,
when using a lattice plot, for example:
library(lattice)
barchart(yield ~ variety , data = barley,
groups = year,
ylab = "Barley Yiel
Check out the help page of the lrm function in the rms library. To
show how lrm is used,
the examples simulate data for logistic regression. This may give you
some ideas.
On Wed, Jan 20, 2010 at 10:41 AM, omar kairan wrote:
> Hi,
>
> could someone help me with dilemma on the simulation of logisti
The typical reason for a crash on startup is a corrupted (or version
mismatched) .RData file.
http://cran.r-project.org/bin/macosx/RMacOSX-FAQ.html#R_002eapp-GUI-crashes-on-startup_0021
--
David.
On Jan 22, 2010, at 6:32 PM, Peter Rossi wrote:
Dear R-Help Group:
R will not start on my ima
This also works (giving a matrix so use as.data.frame if you want it
as a data frame):
> tapply(dat.long[,3], dat.long[1:2], c)
year
firm20022003 2004 20052006
0 NA NA 1.000 NA NA
1 0.86456075 -1.06794272 1.185
thank you, dennis. your example was much better than my own, too.
for everyone else's benefit who will be searching for the answers for
this problem on r-help, let me extend this a little. the problem
arises primarily in data sets that are sparse. in my case, the first
(ordered) firm does not
Your url is wrong. is missing ".zip" in the end.
See the code again.
On Sat, Jan 23, 2010 at 6:37 AM, Velappan Periasamy wrote:
> cannot open: HTTP status was '404 Not Found' while running the
> following commands
>
> f <- tempfile()
> download.file("http://nseindia.com/content/equities/scripvo
> Hmm, does it help if you first set
>
> names(attributes(data)$variable.labels) <- names(data)
Yes, it does, many thanks!
I'll take some time later to work out what all these commands mean :^)
--
Fabrice DELENTE
__
R-help@r-project.org mailing lis
Dear friends - I have a dataset of 40 patients in two groups observed on
three occasions. I only want to plot a line
for each patient in the two groups. I use the ltext function to put the
patient number but fail to make lattice understand the numbers as
unique since apparently it starts all o
Fabrice DELENTE wrote:
Hello.
I used Limesurvey to get answers to a survey. Now I need to process the data
collected.
I exported the R syntax file describing the survey structure, the file is a
http://fdelente.free.fr/Surveydata_syntax.R
It contains lines like
attributes(data)$variable.lab
The same link works and dowloads data while copying and pasteing the
link in firebox address box.
the file is there and the server is active.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting gu
Dear RÂ listmates,
I am doing a cross validation with rda.cv to set alpha and delta parameters
in a training set counting on 614 instances. The result of the process in R
is:
     delta
alpha 0 0.333 0.667 1 1.333 1.667 2 2.333 2.667 3
 0   9    9    9
Dear RÂ listmates,
I am doing a cross validation with rda.cv to set alpha and delta parameters
in a training set counting on 614 instances. The result of the process in R
is:
rda.cv(fit = z, x = Tt, y = TtL, nfold = 10)
$nonzero
     delta
alpha 0 0.333 0.667 1 1.33
Hello.
I used Limesurvey to get answers to a survey. Now I need to process the data
collected.
I exported the R syntax file describing the survey structure, the file is a
http://fdelente.free.fr/Surveydata_syntax.R
It contains lines like
attributes(data)$variable.labels[which(names(data)=="V5
and SAS give one a choice of 5 option, and i'm fairly sure that it used
a different default than does R (although one of the 5 corresponds to
the sas default)
see pctldef on
http://www.technion.ac.il/docs/sas/proc/z0146803.htm
my simple brain thinks of thinks of the problem as 'how does one
c
Duncan Murdoch a écrit :
On 22/01/2010 12:52 PM, Christophe Genolini wrote:
Thanks both of you.
>
> > Inf - Inf
> [1] NaN
So isn't the line 9 useless ? If either x[i] or y[i] are NA, then dev
will be NA and !ISNAN(dev) will detect it...
Sothe loop cool be
8.for(i = 0 ; i < taille ; i++)
Interestingly, Hmisc::describe() and summary() seem to be using one Type, and
stats::fivenum() seems to be using another Type.
> fivenum(cbiomass)
[1] 910.0 1039.0 1088.5 1156.5 1415.0
> summary(cbiomass)
Min. 1st Qu. MedianMean 3rd Qu.Max.
9101048108811041139
cannot open: HTTP status was '404 Not Found' while running the
following commands
f <- tempfile()
download.file("http://nseindia.com/content/equities/scripvol/datafiles/01-01-2010-TO-23-01-2010RCOMXN.csv";,
f)
myData <- read.csv(f)
On 1/19/10, Henrique Dallazuanna wrote:
> Try this:
>
> f <- t
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