Sorry for my bad description, i don't want get a constructed algorithm without
own work. i only hoped to get some advice how to do this. i don't want to
predict any sort of data, i reference only to newdata which variables are the
same as in the model data. But if factors in the data than i can
Hi,
Can someone tell me how to find the center of cluster points in PCA (PC1 vs
PC2)? Can R find that out? If yes, how it's generated by R? Is the
coordinate of center point equals (mean score of PC1, mean score of PC2)?
Thanks bunch!
Phoebe
[[alternative HTML version deleted]]
___
Thanks milton! It is helpfull!
On Tue, Nov 24, 2009 at 3:27 PM, milton ruser wrote:
> Hi there,
>
> I picked it up from r.colors' grass manual:
>
> http://colorbrewer2.org/
>
> The code bellow cold be usefull for you explore simbols and colors.
>
> x11(900,500)
> par(mfrow=c(1,2))
> x<-runif(20)
Peng Yu wrote:
>
> I'm interested in parsing an html page. I should use XML, right? Could
> you somebody show me some example code? Is there a tutorial for this
> package?
>
Did you try looking through the help pages for the XML package or browsing
the Omegahat website?
Look at:
library(XM
On Nov 24, 2009, at 2:24 PM, Andreas Wittmann wrote:
Dear R-users,
in the follwing thread
http://tolstoy.newcastle.edu.au/R/help/03b/3322.html
the problem how to remove rows for predict that contain levels which
are not in the model.
now i try to do this the other way round and want to r
Hi, I just wanted to check I'm not re-inventing the wheel here.
I'm developing a new algorithm for backfitting (i.e. additive models)
and for computing partial residuals, where partial residuals are still
computed even where there are missing values. Noting additive models
here contain both linear
On Nov 24, 2009, at 5:03 PM, Fang (Betty) Yang wrote:
Dear all,
I am struggling with a small problem. By using aggregate, the empty
subsets
are removed. I need each empty subset to be 0. Any suggestions will be
appreciated.
Code:
edref = aggregate(rep(1,times=dim(eds)[1]),list(eds[,11],
Hi all,
I have a csv file containing words with *UNPRINTABLE ASCII* characters
(described in the following table).
Are there any viable method in eliminating these characters?
I realise that *EXTENDED ASCII* characters (i.e , ¡, ¢, £, ¤ etc) can be
removed or replaced via *"gsub"* or *"gregexpr"
On Nov 24, 2009, at 3:21 PM, David Winsemius wrote:
On Nov 24, 2009, at 1:44 PM, yonosoyelmejor wrote:
I use length(myVector),but when i want to use for example
exp(x.reconstruida[length(myVector)+1:length(myVector)+9]), I need
that
function returns the number of last element,would then:
sorry, that escaped my attention. it was meant to be
y2=10+rand.int+tim+rand.int*tim+e
Daniel
-
cuncta stricte discussurus
-
_
Von: Dennis Murphy [mailto:djmu...@gmail.com]
Gesendet: Tuesday, November 24, 2009 5:00 PM
An: Daniel Mal
According to R help:
princomp() uses eigenvalues of covariance data.
prcomp() uses the SVD method.
yet when I run the (eg., USArrests) data example and compare with my own
"hand-written" versions of PCA I get what looks like the opposite.
Example:
comparing the variances I see:
Using prcomp(USA
What about the melt function in reshape package?
EX:
> x=sample(1:100,20,replace=T)
> x
[1] 48 94 32 96 81 99 10 64 64 94 57 60 16 64 32 76 63 1 64 8
> y=sample(1:100,20,replace=T)
> y
[1] 73 78 82 43 58 85 74 64 73 41 45 38 63 36 44 74 7 88 91 1
> xy=cbind(x,y)
> melt(xy)
X1 X2 val
> I don't really understand what you want and the example solution throws away
> quite a lot of data, so consider this alternative:
>
> data.out2 <- read.table(textConnection("id rater.1 n.1 rater.2 n.2
> rater.3 n.3 rater.4 n.4
> 11 11 0.118 79 NA NA NA NA NA N
i am trying to build an R package and submit to CRAN.
i am using -
package.skeleton(name="xxzz", code_files = "H:\xxzz.R")
to build package xxzz.
---
The code above generates 'xxzz' folder.
It seems that I have to manually edit the files generated in xxzz folder (to
add tit
i was trying to do a for loop for plotting the histograms , but it doesnt
work properly
> library(lattice)
> columns <- 8:153
> plots <- vector("list", length(columns))
> j <- 0
> for (i in columns)
+ {
+ plots[[ j <- j+1 ]] <- histogram( ~ data[,i] | data[,2],ylab =
"Frequency",
+
On Nov 24, 2009, at 8:33 PM, AC Del Re wrote:
Hi All,
I am wanting to convert a data.frame from a wide format to a long
format
(with >1 variable) and am having difficulties. Any help is
appreciated!
#current wide format
head(data.out2)
id rater.1 n.1 rater.2 n.2 rater.3 n.3
I'm interested in parsing an html page. I should use XML, right? Could
you somebody show me some example code? Is there a tutorial for this
package?
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the post
Hi All,
I am wanting to convert a data.frame from a wide format to a long format
(with >1 variable) and am having difficulties. Any help is appreciated!
#current wide format
> head(data.out2)
id rater.1 n.1 rater.2 n.2 rater.3 n.3 rater.4 n.4
11 11 0.118 79NA NA
Hi,
I have two questions on using the ff package and wonder if anyone who used
ff can share some thoughts.
I need to save a matrix as a memory-mapped file and load it back later. To
save the matrix, I use
mat = matrix(1:20, 4, 5)
matFF = ff(mat, dim=dim(mat), filename="~/a.mat", overwrite=TRUE,
Hi,
Is there any way to access data remotely over the Internet? In
particular, I'm starting a project that will use data from the U.S.
Bureau of Labor Statistics. The Bureau regularly updates various data
series and publishes them as a series of flat files that can be
downloaded via ftp (e.g.
I did not get anything very interesting with that plot but
nonetheless, I suspect that you want to put your oma= parameter a bit
earlier.
On Nov 24, 2009, at 6:14 PM, Roslina Zakaria wrote:
Hi,
I use fCopulae package to draw different graphs of univariate and
bivariate skew t. But the
?unlist
if I understand you correctly.
On 24 Nov 2009, at 5:50PM, Peng Yu wrote:
I have the following list. The second item in the list is a number.
I'm wondering how to write R code to return this information for any
list?
$`1`
integer(0)
$`2`
[1] 123
$`3`
integer(0)
$`4`
integer(0)
$`5
I really appreciate your help. But if there is a big dataset, I need to write
lots of code.
Lisa
David Winsemius wrote:
>
> The solution I offered does exactly that. It also addresses your other
> supplemental request.
>
> --
> David (Dangerfield?)
>
> On Nov 24, 2009, at 5:57 PM, Lisaj
Hi there,
I picked it up from r.colors' grass manual:
http://colorbrewer2.org/
The code bellow cold be usefull for you explore simbols and colors.
x11(900,500)
par(mfrow=c(1,2))
x<-runif(20)
y<-runif(20)
plot(y~x, type="n")
Number.of.symbols<-20
for (i in 1:Number.of.symbols)
{
points(y[i]~x[
Hi All,
I don't know if this has been reported before, but according to Henrique
Dallazuanna's program (below) the number of R packages has exceeded the
3,000 mark. The count today is 3,175. I ran this just a couple of months
ago & the number was still in the high 2,000s, so it must be fairly
r
Hi,
I use fCopulae package to draw different graphs of univariate and bivariate
skew t. But the plots titles overlap. I tried using cex.main, font.main to
adjust the size but they still overlaps. Here is my code:
par(mfrow = c(3, 1))
mu = 0
Omega = 1
alpha1 = 0
alpha2 = 1.5
alpha3 = 2
alpha4
The solution I offered does exactly that. It also addresses your other
supplemental request.
--
David (Dangerfield?)
On Nov 24, 2009, at 5:57 PM, Lisaj wrote:
I have a further question. If there is NA (missing data) in the
original
dataset, just like this:
id var1 var2
1 1
It should be 11 different groups, not 8.
On Tue, Nov 24, 2009 at 3:00 PM, phoebe kong wrote:
> Hi,
>
> I want to draw a plot where the data set has 8 different groups. Could you
> suggest 8 combination of colors and symbols that are distinguishable? If the
> colors are too close, it would be har
Hi,
I want to draw a plot where the data set has 8 different groups. Could you
suggest 8 combination of colors and symbols that are distinguishable? If the
colors are too close, it would be hard to differentiate from the plot.
Thanks,
[[alternative HTML version deleted]]
___
I have a further question. If there is NA (missing data) in the original
dataset, just like this:
id var1 var2
1 1 3
2 3 1
3 NA1
4 1 2
5 2 3
how to deal with it? The converted dataset should be this:
id var1.1 var1.2
I have the following list. The second item in the list is a number.
I'm wondering how to write R code to return this information for any
list?
$`1`
integer(0)
$`2`
[1] 123
$`3`
integer(0)
$`4`
integer(0)
$`5`
integer(0)
__
R-help@r-project.org mail
On Nov 24, 2009, at 3:41 PM, djpren wrote:
I am looking for the correct commands to do the following things:
1. I have a binomial logistic regression model and i want to test for
overdispersion.
Under the teach a man to fish precept, ... try:
RSiteSearch("test over dispersion binomial mo
Hi All,
My doub I think is very simple. I hope it is. So you can again help, guide
me.
I´m trying to make a graph (scatter graph) about two variables, imagine I
have a watter.txt file with two variables watter and hardness:
This code extracted from:
http://cran.r-project.org/web/packages/HSAUR/v
See agrep:
agrep("American Services", "Americam Services")
On Tue, Nov 24, 2009 at 7:11 PM, j daniel wrote:
>
> Greetings,
>
> I need to conduct a merge on two databases containing information on
> organizations, but the organization names are often non-identical and there
> is no common unique
If I understand, you can try this:
gsub("\\s+","",x)
On Tue, Nov 24, 2009 at 7:18 PM, Ramyathulasingam
wrote:
>
> Hi there
>
> I am trying to remove the white space and replace it with nothing but didnt
> have any luck with that
>
> x <- and fgh-
>
> i can replace the comma using gsub
> gsub("\
Is this what you want:
> x <- " and fgh-"
> gsub(" +", "", x)
[1] "andfgh-"
On Tue, Nov 24, 2009 at 4:18 PM, Ramyathulasingam
wrote:
>
> Hi there
>
> I am trying to remove the white space and replace it with nothing but didnt
> have any luck with that
>
> x <- and fgh-
>
> i can replace
Dear all, I'm an absolute R-beginner and want to connect to my PostgreSQL DB
(on my local Mac OSX 10.6).
1) I tried to install RPostgreSQL (Package Installer > CRAN (sources)) and
get this log below. There seems to be an issue with libpq, bug I don't have
any clue how to fix this. What can I do?
Hi there
I am trying to remove the white space and replace it with nothing but didnt
have any luck with that
x <- and fgh-
i can replace the comma using gsub
gsub("\\-","",x)
but i cant replace the white space with nothing.
Ramya
--
View this message in context:
http://old.nabble.com/Remov
Greetings,
I need to conduct a merge on two databases containing information on
organizations, but the organization names are often non-identical and there
is no common unique identifier. Does anyone know a good way to calculate a
similarity measure on two names, or even better is there a natura
Dear All,
I am trying to do something very simple but I have not been able to figure it
out.
I am trying to calculate monthly returns (i.e stock returns) from daily prices,
where the first price is on the 14th day of the month and the last price is on
the 13th day of the next month. The return
Hi
I have a data frame which looks like :
hs361224 hs426435 hs903411 hs205893 sPP13_2 hs792300 hs747811
2.5 0.837 -0.7684995 -0.4209555 -0.4996375 1.363161 -0.259850 -0.503650
5 1.8617705 -0.5842845 -0.3615625 -0.9784640 1.862586 2.104920
1.192305
24
.
I am looking for the correct commands to do the following things:
1. I have a binomial logistic regression model and i want to test for
overdispersion.
2. If I do indeed have overdispersion i need to then run a quasi-binomial
model, but I'm not sure of the command.
3. I can get the residuals of t
Hi
Sorry, I forgot to state the version: GNU Emacs 22.3.1
I have been unable to find information on the following problem:
All the text in my *R* window is shown in light red, starting after the
echo "This is mgcv 1.5-6 . For overview type ", the following
`help("mgcv-package")' is already in
Hi
I have been unable to find information on the following problem:
All the text in my *R* window is shown in light red, starting after the
echo "This is mgcv 1.5-6 . For overview type ", the following
`help("mgcv-package")' is already in the light red.
This color annoys me because I need m
On 11/24/2009 10:00 AM, tobiasfa wrote:
Hi!
Trying to make a forecast, and get the following error message:
Error in NextMethod("[<-") : subscript out of bounds
The script is as follows:
Forecast.A<- ts(matrix(NA, nrow=25, ncol = 1,
+ dimnames = list(c(), c("Outcome"))),
+ start = c(2006,
Dear all,
I am struggling with a small problem. By using aggregate, the empty subsets
are removed. I need each empty subset to be 0. Any suggestions will be
appreciated.
Code:
edref = aggregate(rep(1,times=dim(eds)[1]),list(eds[,11], eds[,7],
eds[,27]), sum)
Thanks in advance,
Dear all,
When using contr.sdif (from MASS), is it true that the *Intercept* is the
mean of the response variable *across all levels* of the explanatory
variables included in the model? Somehow, it doesn´t seem to be the
overall mean.
Many thanks for any help!
Christoph
# Below is an example:
Dear R users,
i want to use ANOVA with a small data set, here is an example of the data:
Rich FireDe TimeS Area
8 2 4 C
92.5 7 C
51.9 2 C
7 3 4 C
82.5 0 L
2 4 3 L
9
You might try putting
readline('CR to continue')
between the two sets of plot commands.
-Don
At 8:52 AM -0800 11/24/09, MarcioRibeiro wrote:
Hi Listers,
I am producing some graphics that the commands are in a FUNCTION...
The problem is that I end up viewing just last graphic and in my FUNC
Thank you for your help. But how to change the column names to var1.1,
var1.2, var2.1, and var2.2?
Lisa
Henrique Dallazuanna wrote:
>
> Try this:
>
> cbind(x$id, t(do.call(rbind, lapply(x[-1], sapply, switch, '1' =
> c(1,1), '2' = c(1, 2), '3' = c(2, 2)
>
> On Tue, Nov 24, 2009 at 1:51
Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of David Winsemius
> Sent: Tuesday, November 24, 2009 12:22 PM
> To: yonosoyelmejor
> Cc: r-help@r-project.org
> Subject: Re: [R] Method
>
>
> On Nov 24, 2009, at 1:44 PM, yonosoyelmejor wrote:
>
> what is the reason why the anova() method for coxph objects does not
work when robust standard errors have been requested, e.g.,
A robust variance estimate is normally used in situations where the
model may be mis-specified, e.g., multiple events per subject.
In this case a comparison of partia
> But I do feel compelled to ask: Do you really get meaningful
> information from lm applied to 5 cases? Especially when the predictors
> used may not be the same from subset to subset???
Thanks again for your help David. Your question is a good one. It's a bit
complicated but here's the bas
Hi all,
Windows XP
R 2.10.0
I am trying to generate predictions from a binomial mixed model using glmer.
the models is as follows:
mod.PN <- glmer(PN_out~ as.factor(intr3) + transcode + Yr + (Yr|ID)
family=binomial,data=partset, na.action=na.omit)
where PN_out is a two column binomial variable
Perhaps along these lines:
1st #need to decide what your group width is , so the second number
inside the extraction call will be that number minus 1:
for (x in seq(1:1000, by=6) {
temp <- na,omit( shp[x:(x+5), ] ) # Need the parens in x:(x+5)
lm( formula, data=temp)
}
Or dependi
On Nov 24, 2009, at 3:04 PM, Henrique Dallazuanna wrote:
Try this:
DF[rowSums(DF < 0) == 0,]
ITYM:
> DF <- data.frame(a=1:10, b=c(1:3,-4, 5:10), c=c(-1, 2:10))
>
> DF[rowSums(DF < 0) > 0,]
a b c
1 1 1 -1
4 4 -4 4
--
David
On Tue, Nov 24, 2009 at 5:58 PM, Mark Na wrote:
Dear R
I want to perform linear regression on groups of consecutive rows--say 5 to
10 such--of two matrices. There are many such potential groups because the
matrices have thousands of rows. The matrices are both of the form:
> shp[1:5,16:20]
SL495B SL004C SL005C SL005A SL017A
-2649 1.06 0.56
On Nov 24, 2009, at 1:44 PM, yonosoyelmejor wrote:
I use length(myVector),but when i want to use for example
exp(x.reconstruida[length(myVector)+1:length(myVector)+9]), I need
that
function returns the number of last element,would then:
if the last position of my vector is 1440
exp(x.reco
Thanks Steve, this works very well!
Mark
On Tue, Nov 24, 2009 at 2:07 PM, Steve Lianoglou <
mailinglist.honey...@gmail.com> wrote:
> Hi,
>
> On Nov 24, 2009, at 2:58 PM, Mark Na wrote:
>
> > Dear R-helpers,
> >
> > I have a dataframe that should not contain any negative values, but it
> does.
It implies that the random intercept is perfectly collinear with the random
slope, as you suggested. I attach an example.
The data generating process of y1 has a random intercept, but no random
slope. When you fit a model with random intercept and random slope, the
correlation between the two is
Erik and others,
Many thanks for your assistance. Erik correctly points out that the
as.dist() coercion requires a different format than I was using. The
correct format for input to as.dist() is a square matrix, not a lower
triangle matrix. Once I had that in order, everything went much better.
I
If the last position of your vector is 1440, what do you expect to get
from 1440 + 1???
And you certainly need some parentheses in there if you expect to get a range of
values from your vector.
Perhaps you need some subtraction?
And no, we still can't tell exactly what you want. If this doesn't
a
On 11/24/2009 1:13 PM, novocaine wrote:
Hi,
I can't seem to figure out how to tell R to stop expanding an object. I
would like to use the literal name rather than the expanded value.
The issue occurs in a function I've been writing. The problematic part looks
like this:
# "fund" is a matr
Hi,
On Nov 24, 2009, at 2:58 PM, Mark Na wrote:
> Dear R-helpers,
>
> I have a dataframe that should not contain any negative values, but it does.
> I wish to print the rows from my dataframe that contain a negative value in
> any column. I've tried this:
>
>> dataframe[dataframe<0,]
>
> but i
Try this:
DF[rowSums(DF < 0) == 0,]
On Tue, Nov 24, 2009 at 5:58 PM, Mark Na wrote:
> Dear R-helpers,
>
> I have a dataframe that should not contain any negative values, but it does.
> I wish to print the rows from my dataframe that contain a negative value in
> any column. I've tried this:
>
>>
Dear R-helpers,
I have a dataframe that should not contain any negative values, but it does.
I wish to print the rows from my dataframe that contain a negative value in
any column. I've tried this:
> dataframe[dataframe<0,]
but it just returns a row of NAs.
I would very much appreciate any help
I use length(myVector),but when i want to use for example
exp(x.reconstruida[length(myVector)+1:length(myVector)+9]), I need that
function returns the number of last element,would then:
if the last position of my vector is 1440
exp(x.reconstruida[1440+1:1440+9]
This is what I need, I hope havin
Sure,but my problem is that the script is run from the console
windows,therefore I believe that the cat or readline doesn´t work...
JorisMeys wrote:
>
> I can't reproduce the error you have. With me, it runs all fine. In
> fact, readline apparently flushes automatically, as I didn't have to
> us
Hi,
I can't seem to figure out how to tell R to stop expanding an object. I
would like to use the literal name rather than the expanded value.
The issue occurs in a function I've been writing. The problematic part looks
like this:
# "fund" is a matrix of open, high, low, close, and volume pr
Hi!
Trying to make a forecast, and get the following error message:
Error in NextMethod("[<-") : subscript out of bounds
The script is as follows:
> Forecast.A <- ts(matrix(NA, nrow=25, ncol = 1,
+ dimnames = list(c(), c("Outcome"))),
+ start = c(2006, 10), frequency = 12)
> for (i in 1:25) {
Perhaps something like:
as.numeric(chron(times.=c('01:23:21','11:12:13')))
[1] 0.05788194 0.46681713
-Don
At 7:02 AM -0800 11/24/09, RanjanV wrote:
Hello Everyone
I am new to R
I would like to know how to deal with Time Variable. If I have a column of
containing Time data in the format of
In my experience, it is generally due to something like this example:
as.numeric(c('1','b','2'))
[1] 1 NA 2
Warning message:
NAs introduced by coercion
There may be other operations that generate that error, I can't say
for sure. But the above example illustrates what I look for when I
Dear R-users,
in the follwing thread
http://tolstoy.newcastle.edu.au/R/help/03b/3322.html
the problem how to remove rows for predict that contain levels which are
not in the model.
now i try to do this the other way round and want to remove columns
(variables) in the model which will be lat
2009/11/24 Kevin Wright :
> If had done a little searching before posting, you surely would have found
> this link
> https://stat.ethz.ch/pipermail/r-help/2008-July/169149.html
> which describes how to create .xls files that are customized any way that
> you desire.
Manually convert to html, then
On Nov 24, 2009, at 12:53 PM, Adaikalavan wrote:
Not very elegant but this does the trick:
df <- cbind( var1=c(1,3,2,1,2), var2=c(3,1,1,2,3) )
df <- data.frame(id=1:5, df)
data.frame(id=df$id,
var1.1 = (df$var1<3) + 2*(df$var1==3), # 1 for < 3; 2
for 3
var1.2 = (d
Try this;
with(x, data.frame(Case = rep(Case, (Endyear - Startyear) + 1),
Year = unlist(mapply(seq, Startyear, Endyear
On Tue, Nov 24, 2009 at 4:14 PM, Joseph Magagnoli wrote:
> Hi all,
> I have a dataframe that has one observation per case.
> for example:
>
> Case
There are multiple ways, some are OS specific (and I don't see where you told
us that).
Some things to try:
par(ask=TRUE)
# or
pdf('tempfile.pdf')
yourfunctionhere()
dev.off()
# or
par(mfrow=c(2,2))
# or
Windows(record=TRUE)
# or
Look at the help for the function creating the plots, som
Hi all,
I have a dataframe that has one observation per case.
for example:
CaseStartyear Endyear
A 1979 1989
B 1950 1955
I would like to create a dataframe in which each case has
multiple observations corresponding to the start and end
www.rseek.org is great for finding functions/packages that perform
specific tests.
Sarah
On Tue, Nov 24, 2009 at 1:09 PM, Silvano wrote:
> Hi,
>
> how can I make tests like Dunnett and Duncan using R?
>
> Thanks,
>
--
Sarah Goslee
http://www.functionaldiversity.org
__
Hi,
how can I make tests like Dunnett and Duncan using R?
Thanks,
--
Silvano Cesar da Costa
Departamento de Estatística
Universidade Estadual de Londrina
Fone: 3371-4346
__
R-help@r-project.org mailing list
https:/
Not very elegant but this does the trick:
df <- cbind( var1=c(1,3,2,1,2), var2=c(3,1,1,2,3) )
out <- df
out[ which(df==1, arr.ind=T) ] <- "1&1"
out[ which(df==2, arr.ind=T) ] <- "1&2"
out[ which(df==3, arr.ind=T) ] <- "2&2"
outlist <- apply(out, 2, strsplit, split="&")
do.call( "cbind.data.fram
On Nov 24, 2009, at 11:52 AM, MarcioRibeiro wrote:
Hi Listers,
I am producing some graphics that the commands are in a FUNCTION...
The problem is that I end up viewing just last graphic and in my
FUNCTION
there are 4 graphics with the PAR command function... Like those
below...
How do I v
Try this:
cbind(x$id, t(do.call(rbind, lapply(x[-1], sapply, switch, '1' =
c(1,1), '2' = c(1, 2), '3' = c(2, 2)
On Tue, Nov 24, 2009 at 1:51 PM, Lisaj wrote:
>
> Hello, R users,
>
> I have a dataset that looks like this:
>
> id var1 var2
> 1 1 3
> 2 3 1
> 3 2
Tom Backer Johnsen wrote:
As a general observation, few, if any, statistical packages, generate
tables in the format what you might think you need or want. R is not an
exception. Then it is better to transfer the table to a spreadsheet,
shift things around, add headers, etc.. The R2HTML libr
Doesn't the APA package in LaTeX help in this situation?
--Chris Ryan
Original message
>Date: Tue, 24 Nov 2009 18:24:52 +0100
>From: Tom Backer Johnsen
>Subject: Re: [R] From R to LaTeX to pdf?
>To: Erik Iverson
>Cc: "r-help@r-project.org" , Joel Fürstenberg-Hägg
>
>
>I am sure y
Back in March Soren Vogel asked exactly the same thing:
Here is the solution that was offered then. (He offered a dataset as
requested in the Posting Guide.) ... with only a minor adjustment:
g <- rep.int(c("A", "B", "C", "D"), 125)
t <- rnorm(5000)
a <- sample(t, 500, replace=TRUE)
b <- sam
Hi Michael,
Looking at the help for beanplot(), note that the 'log' option defaults to
'auto' which means the function will automatically log-transform data like
yours. This also implies that the mean it shows is the geometric mean, not the
arithmetic mean. As you note, the transformation do
Gérald Jean wrote:
> Hello,
>
> I use:
>
> R version 2.9.2 (2009-08-24)
> Copyright (C) 2009 The R Foundation for Statistical Computing
> ISBN 3-900051-07-0
>
> on Ubuntu 9.10, I usually run R from ESS (5.4 on current Unbuntu) from
> Emacs-22.2.1. But I also tried the following from the console
I am sure you are right. I myself have not looked at the LaTeX function
in Hmisc, that really sounds interesting, and thank you. On the other
hand I had the impression (which may be wrong) that the original
question was posed by someone with not too much experience. If that is
the case the s
Hello Everyone
I am new to R
I would like to know how to deal with Time Variable. If I have a column of
containing Time data in the format of hh:mm:ss such as 00:56:45, 01:24:36,
01:41:25, and so on..
I could find averages for this column using the Chron package. But now I
need to plot a gr
Hi Listers,
I am producing some graphics that the commands are in a FUNCTION...
The problem is that I end up viewing just last graphic and in my FUNCTION
there are 4 graphics with the PAR command function... Like those below...
How do I view/get the other 3 graphics? Any help?
Thanks in advance...
Hello, R users,
I have a dataset that looks like this:
id var1 var2
1 1 3
2 3 1
3 2 1
4 1 2
5 2 3
I want to split one column to two columns with 1 = 1 and 1, 2 = 1 and 2, 3 =
2 and 2:
id var1.1 var1.2 var2.1 va
On Thu, Oct 15, 2009 at 4:11 AM, Fearghas MacGregor
wrote:
> I'd recommend "The Elements of Statistical Learning" by Hastie, Tibshirani,
> and Friedman. There's a lot of good information on clustering, as well as a
> wealth of info on many other apsects of classification, machine learning,
> etc.
Hello,
I use:
R version 2.9.2 (2009-08-24)
Copyright (C) 2009 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
on Ubuntu 9.10, I usually run R from ESS (5.4 on current Unbuntu) from
Emacs-22.2.1. But I also tried the following from the console and it
gave the same results.
I have
You should really learn at least basic SAS yourself. Don't abandon R, but if
you use R only because it is the only program you know, then you are making an
uninformed decision. If you learn SAS and still prefer R (I do) then it is an
informed decision and much better. And your teachers are no
-Original Message-
From: Henrique Dallazuanna [mailto:www...@gmail.com]
Sent: Tue 24/11/2009 16:10
To: Foadi, James (Imperial Coll.,RAL,DIA)
Cc: r-help@r-project.org
Subject: Re: [R] convex hull for cluster analysis
Try this:
plot(Y)
polygon(Y[chull(Y),])
Yes! Lovely!
Thanks.
J
D
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Karl Ove Hufthammer
> Sent: Tuesday, November 24, 2009 1:11 AM
> To: r-h...@stat.math.ethz.ch
> Subject: Re: [R] Loess Fit
>
> On Mon, 23 Nov 2009 14:03:11 -0700 Greg Snow
> wr
Try this:
plot(Y)
polygon(Y[chull(Y),])
On Tue, Nov 24, 2009 at 1:58 PM, wrote:
> Dear R gurus and users,
> I seem to have problem finding the right tool for plotting convex hulls over
> 2D plots, after a cluster analysis. In fact I would like to draw a convex hull
> in 2D for a generic group
Thx Chris, extending the margins worked like a charm. It would be nice
though if the plot function would take the length of the labels into
account as well, but I guess I'm just being too much of a spoiled kid
here ;-)
Cheers
Joris
On Thu, Nov 19, 2009 at 6:46 AM, Chris Campbell wrote:
> On Mon,
If had done a little searching before posting, you surely would have found
this link
https://stat.ethz.ch/pipermail/r-help/2008-July/169149.html
which describes how to create .xls files that are customized any way that
you desire.
Kevin Wright
On Mon, Nov 23, 2009 at 7:02 AM, koj wrote:
>
> De
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