Cool.
I ended up with the following:
par(mfrow = c(2, 2))
# Plot 1
plot(rnorm(10),type="l",col="red")
title(main = list(paste("Normal"),
col="black", cex = 1.0))
# Plot 2
plot(rpois(10, 4),type="l",col="blue")
title(main = list(paste("Poison"),
col="black", cex = 1.0))
# Plot 3
Hi,
I'd like to make a pairwise comparison of a data.frame and I'm looking for a
function that will take a list of columns or data.frame and corvert it to
cartesian pairlist. For example for this data.frame (see below), I'd like to
get a list of all possible pairs:
> sound
cs rs ns
7 5 2
Thanks all for your time! I think I got it -- you can use dyn.load()
in R to load in all the libraries inside R.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.o
Dear all,
I know that my question may be so general,
but I would like to know if is there a good book
for model sensitivity analysis (applied to ecology?)
that use R? Is there any package dedicated
to model sensitivity analysis on R?
Cheers
milton
[[alternative HTML version deleted]]
_
Hi readers,
I'm new to the R package and have a question about handling missing data in
R. I have a dataset from a longitudinal study where we are are testing a
series of models, some in which lagged variables are used to predict an
outcome and others in which concurrent variables are used. Due
To further explain my case..
am reproducing one of the examples.from one of contributors' guides..
___
attach(ais)
here<- sex=="f"
plot(pcBfat[here]~ht[here], xlab = Height, ylab = % Body fat)
panel.smooth(ht[here],pcBfat[here])
detach(ais)
__
A condition is in "here",.
On Nov 20, 2009, at 8:03 PM, Peng Yu wrote:
paste(c('a','b'),sep='')
[1] "a" "b"
The above command doesn't concatenate the strings in a single string.
I'm wondering what is the correct way to do so.
Remember that paste is vectorised. That behavior is desired:
> paste('a','b',sep='')
[1] "a
On Fri, 20 Nov 2009, newbyr wrote:
Hi,
I'm looking for a function that will take a list of columns or data.frame
and corvert it to cartesian pairlist. For example for this data.frame (see
below), I'd like to get a list of all possible pairs:
sound
cs rs ns
7 5 2
4 5 4
6 3 1
8 4
Hi,
I'm looking for a function that will take a list of columns or data.frame
and corvert it to cartesian pairlist. For example for this data.frame (see
below), I'd like to get a list of all possible pairs:
> sound
cs rs ns
7 5 2
4 5 4
6 3 1
8 4 1
6 4 2
6 7 1
Dear Rxperts!
I was wondering if it is possible to write a function which can take in
argument of a subset or condition.. Of course, I am aware of the alternate
methods like coplot, par.plot, xyplot etc... I am specifically interested in
using conditions/subsets with "plot"..
A simple fragmented
The labels on the axis overlap. Is there a way to change their font
size smaller?
m=100
n=100
X=replicate(n,rnorm(m))
image(X,axes=F)
axis(side=1,at=seq(from=par()$usr[1],to=par()$usr[2],length=(m+1))[1:m],labels=replicate(m,
'A'),las=2)
__
R-help@r-pr
?paste
Read the help file, esp the collapse parameter. Might help to reread
Intro to R.
On Fri, Nov 20, 2009 at 8:03 PM, Peng Yu wrote:
>> paste(c('a','b'),sep='')
> [1] "a" "b"
>
> The above command doesn't concatenate the strings in a single string.
> I'm wondering what is the correct way to
tmp <- cbind(x=c(1,-.2,.3,.4),
y=c(.5,.6,-.7,.8))
row.names(tmp) <- letters[1:4]
barchart(tmp,
horizontal=FALSE,
stack=TRUE,
auto.key=list(
title="pollutant",
border=TRUE),
xlab="Month",
main="Interesting Plot")
barcha
> paste(c('a','b'),sep='')
[1] "a" "b"
The above command doesn't concatenate the strings in a single string.
I'm wondering what is the correct way to do so.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
See the spTransform function in the rgdal package.
-Don
At 7:05 PM -0500 11/20/09, Jimmy Martina Vasquez wrote:
Hi everybody:
Does anyone know how I can change geodesic coordenates into UTM ones?
Thanks in advance for your cooperation,
Jimmy M.
___
I have used Gretl (http://gretl.sourceforge.net/) to apply X-11
(Actually X12-ARIMA) or TRAMO/SEATS to seasonally adjust various
series and then export the results direct from Gretl to R. This
appears to work well.
Best Regards
John
2009/11/20 sdlywjl666 :
> Dear All，
> How to do X-11 seasonal
If there's been an answer to this, I've missed it.
Here's my take.
Antje wrote:
Hi there,
I was wondering if anybody can explain to me why the boxplot ends up
with different results in the following case:
I have some integer data as a vector and I compare the stats of boxplot
with the same
On Nov 20, 2009, at 6:54 PM, Gary wrote:
Hi R Folks,
I need to plot a stacked bar plot with row labels as A,B,C,... and
each bar
divided by x,y, Here is the data:
x y
A 1 .5
B -.2 .6
C .3 -.7
D .4 .8
(for e.g. x,y,... could be air pollutants and A,B,C,... could be
months)
At the m
Hi everybody:
Does anyone know how I can change geodesic coordenates into UTM ones?
Thanks in advance for your cooperation,
Jimmy M.
_
Bing brings you maps, menus, and reviews org
Hi R Folks,
I need to plot a stacked bar plot with row labels as A,B,C,... and each bar
divided by x,y, Here is the data:
x y
A 1 .5
B -.2 .6
C .3 -.7
D .4 .8
(for e.g. x,y,... could be air pollutants and A,B,C,... could be months)
Issue 1) It has negative values.
Issue 2) It contain two c
tsp is supposed to be applied to a ts object. If you are not using ts
objects then that is your problem.
On Fri, Nov 20, 2009 at 6:43 PM, Samik Raychaudhuri wrote:
> Looks like there is a difference between when I use frequency(x) vs. when I
> use frequency(x.ts). If I try to get the tsp attribut
Looks like there is a difference between when I use frequency(x) vs.
when I use frequency(x.ts). If I try to get the tsp attribute of x by
using attr(x, "tsp"), it still shows up as NULL. When I looked at the
code of frequency() function (in stats), it seems to be looking at
attr(x, "tsp"), whi
Thank you! That's exactly what I was looking for.
Very much appreciated!
Karine
On Fri, Nov 20, 2009 at 5:14 PM, Richard M. Heiberger wrote:
>
> install.packages("HH")
>
> library(HH)
>
> ?MMC
>
> Go to the bottom of the page and read the maiz example.
> Read through the example that shows aovl
Not for me.
> x <- 1:100
> x.ts <- ts(x, start = 1, frequency = 4)
> frequency(x.ts)
[1] 4
On Fri, Nov 20, 2009 at 6:21 PM, Samik Raychaudhuri wrote:
> Thanks Gabor. Even after doing as you suggested, when I check the frequency
> of x, it still shows up as 1. I would have expected it to be 4 no
Jason Rupert wrote:
How can I add an overall plot title to these four plots?
I would like to have something that says, "Distribution Comparisons":
title("Distribution Comparisons", outer = TRUE)
But you may have to make room for it with par(oma=...).
-Peter Ehlers
par(mfrow = c(2, 2))
Thanks Gabor. Even after doing as you suggested, when I check the
frequency of x, it still shows up as 1. I would have expected it to be 4
now.
> x.ts <- ts(x, start=1, frequency=4)
> frequency(x)
[1] 1
On 11/20/2009 4:05 PM, Gabor Grothendieck wrote:
The first two components of the tsp vector
On Fri, Nov 20, 2009 at 11:01 PM, wrote:
> I have just updated R version to 2.10 for Windows.
> I cannot find package "fork" which seems to include the exception handling
> functions.
> The list that pops up when I select Install Package does not contain any
> fork package (even spelt
> with cap
image(array,axes=F)
axis(side=1,at=seq(from=par()$usr[1],to=par()$usr[2],length=size),labels=some_labels)
I have the above code to plot a heatmap. But I want to make the labels
on the x-axis vertical. Could somebody let me know how to do it?
__
R-help@r
--- begin inclusion --
After I simulate Time and Censor data vectors denoting the censoring
time
and status respectively, I can call the following function to fit the
data
into the Cox model (a is a data.frame containing 4 columns X1, X2, Time
and
Censor):
b = coxph (Surv (Time, Censor) ~ X1 + X2,
Jason -
I've found the mult.fig.p function in the cwhmisc package
to be very handy for this sort of thing.
- Phil Spector
Statistical Computing Facility
Department of Stati
I have just updated R version to 2.10 for Windows.
I cannot find package "fork" which seems to include the exception handling
functions.
The list that pops up when I select Install Package does not contain any fork
package (even spelt
with capital letters). Where am I supposed to get it from ?
How can I add an overall plot title to these four plots?
I would like to have something that says, "Distribution Comparisons":
par(mfrow = c(2, 2))
# Plot 1
plot(rnorm(10),type="l",col="red")
title(main = list(paste("Normal"),
col="black", cex = 1.0))
# Plot 2
plot(r
The first two components of the tsp vector are in time units as
mentioned in ?tsp . Thus you would want:
> x <- 1:100
> tsp(x) <- c(1, 25.75, 4)
but normally you don't have to set it explicitly in the first place.
Just use ts:
> x <- 1:100
> x.ts <- ts(x, start = 1, frequency = 4)
> tsp(x.ts)
[1
On Nov 20, 2009, at 5:05 PM, Andrew Barr wrote:
Hi R folks,
I have a massive array (object name "points") in the following form
[,1] [,2]
[1,] 1369 22
[2,] 1370 22
[3,] 1368 23
[4,] 1369 23
[5,] 1370 23
[6,] 1371 23
(10080 rows truncated)
mtx <- matrix(scan(textConnectio
On Fri, 20 Nov 2009, Andrew Barr wrote:
Hi R folks,
I have a massive array (object name "points") in the following form
[,1] [,2]
[1,] 1369 22
[2,] 1370 22
[3,] 1368 23
[4,] 1369 23
[5,] 1370 23
[6,] 1371 23
(10080 rows truncated)
These represent pixel coordinates of inter
?dist
On Friday 20 November 2009, Andrew Barr wrote:
> Hi R folks,
>
> I have a massive array (object name "points") in the following form
>
> [,1] [,2]
> [1,] 1369 22
> [2,] 1370 22
> [3,] 1368 23
> [4,] 1369 23
> [5,] 1370 23
> [6,] 1371 23
> (10080 rows truncated)
>
> Thes
Hello,
I am wondering how I should set up the tsp attribute (available through
attr(x, "tsp")) of a dataset x? Let's assume that x has 100 points, and
I want to set the frequency to 4.
I tried:
> attr(x,"tsp")<-c(1,100,4)
Error in attr(x, "tsp") <- c(1, 100, 4) :
invalid time series parameters
install.packages("HH")
library(HH)
?MMC
Go to the bottom of the page and read the maiz example.
Read through the example that shows aovlist objects don't work
and how to construct the equivalent aov object.
__
R-help@r-project.org mailing list
https
Hi R folks,
I have a massive array (object name "points") in the following form
[,1] [,2]
[1,] 1369 22
[2,] 1370 22
[3,] 1368 23
[4,] 1369 23
[5,] 1370 23
[6,] 1371 23
(10080 rows truncated)
These represent pixel coordinates of interest in a jpeg image. I need
to find the d
Hi everyone,
I'm trying to do a 2-way repeated measures ANOVA with data that looks like
this:
subject block rep day light response
1 1 1oneL1 5.5
2 1 2oneL1 4.5
3 1 1oneL2 4
4 1 2one
Hi Erik,
Interesting blog. I was pleased to see the reference to org-babel, a
language-agnostic alternative to Sweave. Org-babel is a software
masterpiece that anyone using emacs, LaTeX and R should know about,
especially if they also use python, ruby, clojure, etc.
All the best,
Tom
O
Thanks a lot Duncan and David, the remedy was to delete the files .Rhistory
and .RData via the terminal - with "rm . Rhistory" etc. (By default they are
hidden on OS X.) Now R.app opens fine.
best,
Steve
David Winsemius wrote:
>
> Probably best further discussed on R-SIG-Mac list:
>
> https
Hi Michael,
> I'm having trouble figuring out how to format Date variables when used as
> axis labels in graphs.
> The particular case here is an attempt to re-create Nightingale's coxcomb
> graph with ggplot2,
> where I'd like the months to be labeled as "Mar 1885", "Apr 1885", using a
> date for
Please, ignore this question (see below): I found the way how to do it
Thanks
Leonid
--
Leonid Gibiansky, Ph.D.
President, QuantPharm LLC
web:www.quantpharm.com
e-mail: LGibiansky at quantpharm.com
tel:(301) 767 5566
Leonid Gibiansky wrote:
Dear All
A faster solution using tapply was sent to me via email:
testtapply = function(p){
df = randomdf(p)
system.time({res = tapply(df$x2,df$x1,min);
res = as.Date(res,origin=as.Date('1970-01-01'));
df$mindate = res[as.character(df$x1)]})
}
Thanks Phil!
Tahir
On
Hello,
I wrote a Wordpress blog entry about not only highlighting R syntax, but
embedding R commands within an entry and using Sweave to produce the R output,
all within Emacs. The output of the process is ready to paste Wordpress HTML,
and a few other R blogs have started using it to generat
Quite right, David. I forgot to indicate that MASS needs of course
to be loaded. It's such a useful package that I usually have it
loaded.
Raymond:
When you ask for help with a function in an add-on package
you should indicate that package in your query.
-Peter Ehlers
David Winsemius wrote:
Dear All,
One more nlmeODE question:
I have a differential equation where one of the parameters depends on
time. Values of this parameter at fixed time points are known but need
to be interpolated between these known points. Can it be implemented in
nlmeODE solver?
Thanks
Leonid
--
Hi,
I am about to release the "highlight" package which just does that.
You would basically do :
> highlight( some_file, output = some_other_file_or_connection,
+ renderer = renderer_html() )
If you are in a rush you can grab it from r-forge:
http://r-forge.r-project.org/projects/highli
What is wrong with the "extra step"? Is it taking too much time (you
did not specify that), is it taking too much memory? How many times
are you going to be doing it? If not many, then may be it is OK. You
have to quantify what you are asking for. It may take longer to send
a message to R-Help
On Nov 20, 2009, at 10:52 AM, gcheer3 wrote:
Thank you again, Joh
Based on your code seems I solved the problem.
new code as follows:
cs<-expression(delta[1], delta[2])
plot(sigma, delta1, ylim=range(-0.5, 2), xlab='sigma', ylab='delta',
pch=22,
type='o')
points(sigma, delta2, col='red', a
Hi Anna,
I guess it happened because the range of datas[1:n, 2] differs from the
range of datas[1:n, 3]. A workaround would be either to use the maplot()
function as follows or figuring out their ranges and then plug them in as
the ylim argument in the plot call.
Here is a suggestion using matplo
David and Marc,
thank you very much for your quick and professional help.
Both approaches are doing what I was looking for.
Next time I will try to provide an example that is more clearly.
Regards,
Stefan
University of Bayreuth
__
R-help@r-project.o
Dear all,
I am looking for a R package or R code dealing with multivariate type II
regressions. I know the "lmodel2" and "smatr" packages, but they just allow
to perform bivariate type II regressions.
Ideally, I would use the method described by McArdle (1988) called "standard
minor axis" regres
http://old.nabble.com/file/p26443595/Edragonr.txt Edragonr.txt
HI all,
I have a 72*495 matrix, and the first column is the response, and the
remaining are independences. Final I want to select some independence to fit
y, but there are so many independences, the fit result is not meaning, so
Thank you, David.
thanks for letting me know how to use expression in legend. It works too.
gcheer3 wrote:
>
> a graph question. Thanks a lot in advance.
>
> I made two scatterplots on one graph (sigma vs. delta1, sigma vs. delta2)
> (20 observations of delta1, delta2 and corresponding sigma)
Thank you again, Joh
Based on your code seems I solved the problem.
new code as follows:
cs<-expression(delta[1], delta[2])
plot(sigma, delta1, ylim=range(-0.5, 2), xlab='sigma', ylab='delta', pch=22,
type='o')
points(sigma, delta2, col='red', axes=FALSE, type='o')
legend("topleft", cs,pch
On Nov 20, 2009, at 1:56 PM, anna_l wrote:
Hello, I am trying to plot a graphic with many lines with the
following
command:
plot(datas[1:n,1],datas[1:n,2],type="l",main="SP500 Prices and Moving
Averages",xlab="Date",ylab="Prices",col="black")
lines(datas[1:n,1],datas[1:n,3],type="l",col="g
On Nov 20, 2009, at 1:47 PM, Peter Ehlers wrote:
Raymond Wong wrote:
This is probably simple, but I have a hard time finding the
solution. Any help greatly appreciated.
I would like to use the results of
fitdistr(z,densfun=dweibull,start=list(scale=1,shape=1)) for
further processing. H
Hello, I am trying to plot a graphic with many lines with the following
command:
plot(datas[1:n,1],datas[1:n,2],type="l",main="SP500 Prices and Moving
Averages",xlab="Date",ylab="Prices",col="black")
lines(datas[1:n,1],datas[1:n,3],type="l",col="green",lty="solid")
But I just see the first curve
Thanks a bunch, Baptiste,
Your lapply call works like a charm. BTW, it works also if a, b, and c
are expressions :D
Sebastien
baptiste auguie wrote:
Hi,
You can try this, though I hope to learn of a better way to do it,
a = c(quote(alpha),quote(beta),quote(gamma))
b = lapply(1:3, function(
Raymond Wong wrote:
This is probably simple, but I have a hard time finding the solution. Any help
greatly appreciated.
I would like to use the results of fitdistr(z,densfun=dweibull,start=list(scale=1,shape=1)) for further processing. How do I assign the values of scale and shape to b and
On Nov 20, 2009, at 1:01 PM, Peng Yu wrote:
On Sat, Nov 21, 2009 at 11:55 AM, Steve Lianoglou
wrote:
read.delim gives me a data.frame. Is there a function that can
return
the result in a matrix rather than data.frame?
m <- as.matrix(read.delim(..))
I knew this approach. But this takes a
take a look at geshi. b
On Nov 20, 2009, at 4:26 PM, Tal Galili wrote:
My question if in the Subject, but if to extend: I am specifically
curious
about WordPress blogs. But any solution will give me a lead.
Thanks,
Tal
--
Contact me: tal.gal...@gm
This is probably simple, but I have a hard time finding the solution. Any help
greatly appreciated.
I would like to use the results of
fitdistr(z,densfun=dweibull,start=list(scale=1,shape=1)) for further
processing. How do I assign the values of scale and shape to b and a without
manually en
I can't think of anything that is already built in.
But you can always:
read.as.matrix <- function(...) as.matrix(read.delim(...))
and now you get one step only ;-)
b
On Nov 20, 2009, at 4:01 PM, Peng Yu wrote:
On Sat, Nov 21, 2009 at 11:55 AM, Steve Lianoglou
wrote:
read.delim gives me a
My question if in the Subject, but if to extend: I am specifically curious
about WordPress blogs. But any solution will give me a lead.
Thanks,
Tal
--
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostati
On Nov 20, 2009, at 11:07 AM, RWilliam wrote:
In reply to suggestion by David W., setting an offset parameter
doesn't seem
to work as R is not recognizing the "X2" part of coxph(
Surv(Time,Censor)~X1, offset=log(4.3*X2), data= a ). Also, here's some
sample data:
The problem, arising as
Hi,
Im having mayor issues with predict from the nnet package.
Im training a neural network for forecasting. I trained the network with
info from 1995 to 2009 and I want to forecast month by month 2010.(the
network forecasts one month at a time).
Since I have to do iterative forecasting
Dear all.
I am using the akima function to produce 3d contour plots using interp based
on irregular data.
using the eg in the akima manual
library("akima")
data(akima)
plot(y ~ x, data = akima, main = "akima example data")
with(akima, text(x, y, formatC(z,dig=2), adj = -0.1))
## linear interpola
On Sat, Nov 21, 2009 at 11:55 AM, Steve Lianoglou
wrote:
>> read.delim gives me a data.frame. Is there a function that can return
>> the result in a matrix rather than data.frame?
>
> m <- as.matrix(read.delim(..))
I knew this approach. But this takes an extra step. Is there a command
that read a
Hi,
You can try this, though I hope to learn of a better way to do it,
a = c(quote(alpha),quote(beta),quote(gamma))
b = lapply(1:3, function(x) as.character(x))
c = c(quote('-10'^th),
quote('-20'^th),
quote('-30'^th))
testplot <- function(a,b,c) {
text <-
lapply(seq_along(a), function(i
read.delim gives me a data.frame. Is there a function that can return
the result in a matrix rather than data.frame?
m <- as.matrix(read.delim(..))
-steve
--
Steve Lianoglou
Graduate Student: Computational Systems Biology
| Memorial Sloan-Kettering Cancer Center
| Weill Medical College o
read.delim gives me a data.frame. Is there a function that can return
the result in a matrix rather than data.frame?
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.o
Dear All,
I am new to this list, and also to population modeling with R (nlmeODE).
Could someone send me a simple example how to do posthoc-type estimate
(for example, for the Theoph.nlme model in PKPDmodels library):
I have a PK model, and I have a new subject. How to estimate individual
par
with(p,plot(x,y,pch=20,col=1+as.integer(value)))
--
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air Quality Modeler INTERNET: cl...@math.utah.edu
Department of Ecology VOICE: (360) 407-6815
PO Box 47600FAX:(
On Fri, 20 Nov 2009, Sam Thomas wrote:
When plotting Binary Trees (ctree) from the party package, is there a
way to adjust the font sizes of the leaves?
Currently, this is not implemented in "party". In interactive usage it is
not easy to change the fontsize. If you're printing to PDF, you co
I have a file with 3 cols as:
xyvalue
110.5000
121.8333
134.
210.7500
220.7500
234
310.7500
321.4167
335.1667
I read them in using
p <- read.table("data.txt", header=TRUE)
My questoin: how to draw a image to show
When plotting Binary Trees (ctree) from the party package, is there a
way to adjust the font sizes of the leaves?
require(party)
irisct <- ctree(Species ~ ., data = iris)
plot(irisct)
I want to adjust the font sizes for "Node 2", "Node 5", etc. I'd also
like to be able to adjust the fo
Dear R-users,
I am developing a plotting function, which receives expressions and
character/numerical vectors as part of the many input arguments and
which tries to concatenate them before displaying the result to the
plot. I currently cannot find a way to make this concatenation works. I
hav
On 20/11/2009 7:11 AM, Antje wrote:
Hey there,
I'm running R 2.10 on Windows XP (Professional) and I was wondering
where the HTML help window disappeared?
With earlier versions everything was fine. Now I get only this
old-fashioned text windows without any links when I type
?some_function
Can
In reply to suggestion by David W., setting an offset parameter doesn't seem
to work as R is not recognizing the "X2" part of coxph(
Surv(Time,Censor)~X1, offset=log(4.3*X2), data= a ). Also, here's some
sample data:
X1 X2 TimeCensor
1 1 0.40619454 77.00666
Probably best further discussed on R-SIG-Mac list:
https://stat.ethz.ch/mailman/listinfo/r-sig-mac
... since that is where the tricks of convincing MacOSX to display
system files is discussed and a semi-regular basis:
https://stat.ethz.ch/pipermail/r-sig-mac/2009-November/006768.html
https:
plot(sigma, delta1, ylim=range(-0.5, 2), xlab='sigma', ylab='delta',pch=22,
type='o')
points(sigma, delta2, col='red', axes=FALSE, pch=1,type='o')
legend("topleft",c(expression(Delta*1),expression(delta*2)),fill=TRUE,col=c("black","red"),pch=c(1,22))
See:
>?plotmath
Still, gimme a easily runnabl
See:
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/40714.html
There are many packages which have this functionality as well and a
search (??, RSiteSearch, rseek.org) will find them.
The links box on the http://gsubfn.googlecode.com page has links to
regular expression pages on the web.
On Fri,
On 20/11/2009 10:38 AM, Stropharia wrote:
Thanks Duncan,
I managed to get R to start through the terminal this way. Still no luck
getting the R.app to start. Is it possible to directly access (and then
trash or modify) the .RData and .RProfile files? I assume they would be
recreated if I could t
On Fri, 20 Nov 2009, Barry Rowlingson wrote:
On Fri, Nov 20, 2009 at 1:25 PM, wrote:
In general, is it possible to run R scripts through cron jobs ?
Yes, the only problem might be if you use anything that needs a
graphics window. In the old days you needed an X11 display to create
png graph
try this:
> x <- ' middle of the string '
> sub("^[[:space:]]*(.*?)[[:space:]]*$", "\\1", x, perl=TRUE)
[1] "middle of the string"
On Fri, Nov 20, 2009 at 10:51 AM, Bos, Roger wrote:
> I have a character string and I would like to remove the leading and
> tailing white spaces. The ex
> "DS" == David Scott
> on Sat, 21 Nov 2009 02:29:38 +1300 writes:
DS> This is a reply to my own question. I thought I had found an answer but
DS> it seems not so (some analysis follows below). Maybe Martin Maechler or
DS> Robin Hankin or Duncan Murdoch may have some ide
I have a character string and I would like to remove the leading and
tailing white spaces. The example for 'sub' shows how to remove the
trailing white spaces, but I still can't figure out how to remove both
trailing and leading white spaces because I can't find any documentation
for what "+$" mea
On Nov 20, 2009, at 10:23 AM, gcheer3 wrote:
Thanks for your reply. It is very helpful. I am sorry I didn't make
my
queston clearer.
I have two concerns about this graph.
One thing is denote 'sigma' and 'delta' as greek letters, usually I
use
'expression'. But I don't know how to use 'e
Joh, thank you very much. sorry for confusing you. I didn't make my question
clear. I tried your code it looks much better than my original one. Just I
prefer I can write the greek letter delta1 and delta 2 instead of words
'delta1' and 'delta2'. Also, it will be nice if there is a square symbol
Thanks Duncan,
I managed to get R to start through the terminal this way. Still no luck
getting the R.app to start. Is it possible to directly access (and then
trash or modify) the .RData and .RProfile files? I assume they would be
recreated if I could then open the R.app. Having searched for the
On Nov 20, 2009, at 9:21 AM, Marc Schwartz wrote:
On Nov 20, 2009, at 8:04 AM, David Winsemius wrote:
On Nov 20, 2009, at 6:26 AM, Stefan Strohmeier wrote:
Dear R users,
I have a time series of precipitation data. The time series
comprises ~ 20 years and it is supposed to be constant (o
ylim = c(0, max(log10(D10$Part.P)))
Make sure you remove any 0s or NAs before computing the max though.
--sundar
On Fri, Nov 20, 2009 at 6:12 AM, helene frigstad
wrote:
>
> Hi,
>
> is there any way to set the ylim range from zero to whatever is the max
> value in that dataset? I am plotting man
Thanks for your reply. It is very helpful. I am sorry I didn't make my
queston clearer.
I have two concerns about this graph.
One thing is denote 'sigma' and 'delta' as greek letters, usually I use
'expression'. But I don't know how to use 'expression' in the 'legend'
The other thing is, the gra
Hi,
is there any way to set the ylim range from zero to whatever is the max
value in that dataset? I am plotting many similar plots to the one below,
and would like to avoid having to find the max value each time.
plot (D10$Part.P ~ D10$Klorofyll,pch=16,log = "xy", xlab = ("Chla"), ylab =
("PO
Hi,
is there any way to set the ylim range from zero to whatever is the max
value in that dataset? I am plotting many similar plots to the one below,
and would like to avoid having to find the max value each time.
plot (D10$Part.P ~ D10$Klorofyll,pch=16,log = "xy", xlab = ("Chla"), ylab =
("PO
On Fri, Nov 20, 2009 at 1:25 PM, wrote:
> In general, is it possible to run R scripts through cron jobs ?
Yes, the only problem might be if you use anything that needs a
graphics window. In the old days you needed an X11 display to create
png graphics with the png() function, but not any more.
On 20 November 2009 at 14:25, mau...@alice.it wrote:
| In general, is it possible to run R scripts through cron jobs ?
| Is it possible to make the script detect the system interrupt, save its
current status and then exit so that next time it is rescheduled it can pick up
from where it left ?
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