In article <80b45a8c0910192051nd558023p9b76566464fc3...@mail.gmail.com>,
remkoduur...@gmail.com says...
> I think it is a bug. Apparently plot.POSIXct calls axis.POSIXct for
> both y (correct) and x (incorrect) axes:
Thanks. Reported as bug #14016.
--
Karl Ove Hufthammer
__
Hi,
This is probably going to be one of those, "It depends what you want"
kind of answers, but I'm very curious to see if the group has an opinion
or some general suggestions.
The actual experiment is too complicated for a quick e-mail, but I'll
summarize well enough(hopefully) to get the co
Fulton wrote:
I’m running some logistic regressions and I’ve been trying to include weights
in the equation. However, when I run the model, I get this warning message:
Here’s what it says: Warning message: In eval(expr, envir, enclos) :
non-integer #successes in a binomial glm!
I think it
I’m running some logistic regressions and I’ve been trying to include weights
in the equation. However, when I run the model, I get this warning message:
Here’s what it says: Warning message: In eval(expr, envir, enclos) :
non-integer #successes in a binomial glm!
I think it is because the w
I think it is a bug. Apparently plot.POSIXct calls axis.POSIXct for
both y (correct) and x (incorrect) axes:
set.seed(1)
x=seq(1,1e8,length=100)+round(runif(100)*1e8)
y=as.POSIXct(x,origin="2001-01-01")
plot(y, axes=FALSE)
axis.POSIXct(2, y)
axis.POSIXct(1,y) # is what it does
axis(1, col="red")
Hi Duncan,
Thanks for your response and I'm sorry for the delayed reply - think my spam
filter is to blame.
Your solution did work. Thanks a ton!
Shankar
Duncan Mackay-2 wrote:
>
> Hi Shankar
>
> On a slightly different note - below produces a strip to the left without
> the stacked strip
Thanks Jim - that worked.
Jim Lemon-2 wrote:
>
> On 10/20/2009 01:10 PM, tdm wrote:
>> I have 2 vectors, x and y and have done an xy plot.
>>
>> I want to plot the label (name?) of the vector on the plot rather than
>> the
>> value.
>>
>> text(x,y, labels = x)
>>
>> gives me the value of x.
>>
On 10/20/2009 01:10 PM, tdm wrote:
I have 2 vectors, x and y and have done an xy plot.
I want to plot the label (name?) of the vector on the plot rather than the
value.
text(x,y, labels = x)
gives me the value of x.
text(x,y, labels = labels(x))
gives me something like c("text1","text2"..) p
Hi folks,
I have a one line shell script which looks like this:
R CMD BATCH --no-restore --no-save foo.R
It executes the R program in foo.R and generates
output called foo.Rout.
Is there any way that I can force the output to come
to stdout and stderr (instead of foo.Rout)?
What I really wan
I have 2 vectors, x and y and have done an xy plot.
I want to plot the label (name?) of the vector on the plot rather than the
value.
text(x,y, labels = x)
gives me the value of x.
text(x,y, labels = labels(x))
gives me something like c("text1","text2"..) plotted for each point
text(x,y, la
tmp <- matrix(1:2)
tmp
tmp[,1,drop=FALSE]
See the above example. Is there a way to make 'drop=FALSE' as global
default, so that when I say 'tmp[,1]', R will treat it as
'tmp[,1,drop=FALSE]'?
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mai
Hello!
I am currently using R to deal empirically with copulas. I am using
financial return data to construct copula models that seem appropriate for
my data sets. Is there anyone who has done something similar and who is
interested in talking (or writing...) with me about this topic
(difficultie
On Mon, Oct 19, 2009 at 9:31 AM, Peng Yu wrote:
> On Mon, Oct 19, 2009 at 5:02 AM, Mark Difford
> wrote:
>>
>> Peng Yu wrote:
>>
Some webpage has described prcomp and princomp, but I am still not
quite sure what the major difference between them is.
>>
>> The main difference, which cou
Thanks so much, Chris! I only found Haar transformation from
"filter.select". The manual I found on "wd" doesn't include Haar in the
"family" specification. Essentially I want a code which can return
approximation coefficients and detail coefficients. There might be other
code in "wavethresh" I
The wavethresh package on CRAN has Haar wavelets.
Zhen Li wrote:
>
> Dear all,
>
> Using R function "dwt", it seems that I cannot specify the wavelet
> transformation like Haar. What's the R code for wavelet decomposition
> which allows me to specify Haar wavelet transformation? Of course, i
Perhaps you could just call it Det.
On Mon, Oct 19, 2009 at 7:16 PM, David van Leeuwen
wrote:
> Hello,
>
> I am trying to write an R package for doing analysis of speaker
> recognition systems. The big thing in this line of research is a
> DET-plot (detection Error Trade-off, a ROC plot with qno
Hello,
I am trying to write an R package for doing analysis of speaker
recognition systems. The big thing in this line of research is a
DET-plot (detection Error Trade-off, a ROC plot with qnorm() warped
axes). My approach has been to make a class "det" and also a
function "det()" that will pre
You could look into try().
Sarah
On Mon, Oct 19, 2009 at 5:49 PM, Douglas M. Hultstrand
wrote:
> Hello,
>
> I posted this question last week and have not heard anything, I am wondering
> if anyone had ideas for testing a model relationship?
>
> I am working with a real-time hydrologic modeling s
There is a dwt() in package:waveslim, reading the help file:
dwt(x, wf="la8", n.levels=4, boundary="periodic")
wf: Name of the wavelet filter to use in the decomposition. By
default this is set to '"la8"', the Daubechies orthonormal
compactly supported wavelet of length L=8
Hello,
I posted this question last week and have not heard anything, I am
wondering if anyone had ideas for testing a model relationship?
I am working with a real-time hydrologic modeling system, and I am using
R (R batch script on Linux) to create a non-linear relationship
(exponential) bet
Hi,
This is probably going to be one of those, "It depends what you want"
kind of answers, but I'm very curious to see if the group has an opinion
or some general suggestions.
The actual experiment is too complicated for a quick e-mail, but I'll
summarize well enough(hopefully) to get the co
Thanks! I've figured out how to fix it, but how I got here is still a
puzzle. :-) Cheers, Don
On Sat, Oct 17, 2009 at 5:36 PM, Peter Ehlers wrote:
>
> Donald Braman wrote:
>
>> Can someone help me understand this results?
>>
>> levels(as.factor(miset1$facts_convict))
>>>
>> [1] "1" "1" "2"
If you convert your dates to an object d of Date class then
as.numeric(d) will be the number of days since the Epoch. See R News
4/1.
On Mon, Oct 19, 2009 at 2:20 PM, Marlin Keith Cox wrote:
> Hi all and thanks in advance.
>
> I am regressing Time and Weight, and then predicting Weight at
> diff
Here are several ways to find the last character in a string:
> x <- "abc"
> substring(x, nchar(x))
[1] "c"
> sub(".*(.)", "\\1", x)
[1] "c"
> library(gsubfn)
> strapply(x, ".$")[[1]]
[1] "c"
On Mon, Oct 19, 2009 at 3:52 PM, Jason Rupert wrote:
> I am currently being defeated by grep. I am a
Well, regexpr() can do it; the magical incantation is
regexpr(".$",yourstring)
See ?regexpr for details.
However, as your task really doesn't involve MATCHING characters, but
COUNTING characters, it might be simpler to use nchar() and substr():
n <- nchar(yourstring)
lastLetter <- substr(your
here is a simple scriptx texi2dvi("script.tex", pdf=T)would produce of
something like the pdf with the summaries and plots coded inside the
"script.R"Thank you > >[[alternative HTML version deleted]] > > >
rh...@rproject.org mailing list > https://stat.ethz.ch/mailman/listinfo/rhelp >
PLEASE
Thanks for the tip. I actually had to learn a bit of matrix multiplication
and ended up calculating the RMSE this way.
scores_lr <- t(coeffs_alldata) %*% t(df_train)
rmseTrain <- (mean(((scores_lr)- trainY)^2))^0.5
full script and results here if you are interested.
http://ausdm09.freeforums.or
I'm not sure I understand. Why not just take your existing R script
and wrap it in \begin{document} <<>>= ... @ \end{document} and run it
through Sweave?
-Ista
On Mon, Oct 19, 2009 at 2:40 PM, Gabriel Koutilellis wrote:
> Dear list,I have read really a lot the past few days, but I haven't found
I am currently being defeated by grep. I am attempting to determine the value
of the last letter of a character string.
An example of my data set is shown below. Regarding the codes, I would like to
identify the value of the last character and then take the appropriate action,
e.g.
If the
In the first instance, questions about contributed packages should be
addressed to the package maintainers rather than to the R-help list.
On 20/10/2009, at 2:06 AM, Javier PB wrote:
Dear users,
I am trying to export polygons from Arcmap into Spatstat to run some
simulations using functions a
Hi everybody,
I used random forest regression to explain the patterns of species
richness and a bunch of climate variables (e.g. Temperature,
precipitation, etc.) All are continuos variables. My results are
really interesting and my model explained 96,7% of the variance.
Now I am trying to take
What package are you using? There are quite a few functions that do
wavelet decomposition. Have you tried an R site search?
Stephen
On Fri, Oct 16, 2009 at 3:43 PM, Zhen Li wrote:
> Dear all,
>
> Using R function "dwt", it seems that I cannot specify the wavelet
> transformation like Haar. Wha
jullian day?
On Mon, Oct 19, 2009 at 1:20 PM, Marlin Keith Cox wrote:
> Hi all and thanks in advance.
>
> I am regressing Time and Weight, and then predicting Weight at
> different Time. The format of the Time data is day/month/year. How
> can I get R to use time series data such as this?
>
> K
Peng,
It's generally useful to know the class of the object you are working
with, and the methods available for that class. This would have led
you to the 'loadings' help page.
> class(pca_result$loadings)
[1] "loadings"
> methods(class='loadings')
[1] print.loadings*
Non-visible functions a
> z <- abind(x[,,1], c(4,5,6),along=0)
z is probably not what you want because you aren't using the drop=FALSE
argument. See the FAQ 7.5
abind, and arrays in general, are rectangular solids. They are not
ragged. For that you need lists. To get something like your request
> x
> , , 1
>
yes, it's in windows, you are so serious, Thanks so much, give me very
good suggestion, i will try it. Thanks again.
Best regards
jun chen
On Mon, Oct 19, 2009 at 5:04 PM, wrote:
> On Mon, 19 Oct 2009, Jun Chen wrote:
>
>> Dear,
>> I would like to deal with microarray data, it can run when i dea
Hi I want to use standalone Rmath.h in C, but I am getting the following
error:
/.../include/R_ext/Boolean.h:29: error: conflicting declaration 'FALSE'
/.../include/Rmath.h:191: error: 'FALSE' has a previous declaration as
'Rboolean FALSE'
/.../include/R_ext/Boolean.h:29: error: conflicting decla
Nigel Harding wrote:
>
> Dear all,
> I am analyzing counts of seabirds made from line transects at sea.
>
> ... is there some easier way to fit
> a quasipoisson distribution?
>
R commander seems to be a relatively easy-to-use front end/GUI for R, to
this statistics and computing novice.
I
(resent as hotmail really cannot format plaintext, but I've just read
Tony Plate's message that what I'd like to do might not be possible)
>
> library(abind) ## array binding
I've looked into using abind() but it seems I might not understand it properly.
I can build my 2 table array and insert a
Unfortunately, I can't read your examples. Can you repost without the
formatting characters which are confusing when rendered in plain text?
One thing to keep in mind is that a R array is a regular object -- e.g., if you have a 2
x 3 x 4 array, then if you want to add a row to a slice, you mus
<4adbca02.8020...@temple.edu>
Content-Type: text/plain; charset="Windows-1252"
Content-Transfer-Encoding: quoted-printable
MIME-Version: 1.0
>=20
> library(abind) ## array binding
I've looked into using abind()=2C but it seems I might not understand it pr=
operly.
I can build my 2 table arra
Hi,
I posted the message below last week, but no answers, so I'm giving it
another attempt in case somebody who would be able to help might have missed
it and it has now dropped off the end of the list of mails.
I am fairly new to R and still trying to figure out how it all works, and I
have run
> sum((x-mean(x))^2)/(n)
[1] 0.4894708
> ((n-1)/n) * var(x)
[1] 0.4894708
hth,
Kingsford
On Mon, Oct 19, 2009 at 9:30 AM, Peng Yu wrote:
> It seems that var() computes sample variance. It is straight forward
> to compute population variance from sample variance. However, I feel
> that it is sti
On 19/10/2009, at 5:26 PM, PerfectTiling wrote:
Hi,
I'd like to
(1) plot a perspective view of a 3D scatterplot, with a fitted
(curved)
surface;
(2) have a "stick" from each point vertically to the surface.
The latter helps one visualize where a point lies in 3D, relative
to the
su
Dear list,I have read really a lot the past few days, but I haven't found a
matching solution for my problem.I have R 2.9.2 on Windows XP and MikTex 2.8
installed.What I want to do is to automate the sweave file generation.I thought
I could use the R2Sweave, RweaveLatex, and Sweave in a combinat
You misunderstood my comment; perhaps I was too cryptic.
I intended you to look up help(loadings) where the
argument "cutoff" is pretty clearly indicated to default
to 0.1.
-Peter Ehlers
Peng Yu wrote:
On Mon, Oct 19, 2009 at 1:58 AM, Peter Ehlers wrote:
Peng Yu wrote:
Please see below that
Hi all and thanks in advance.
I am regressing Time and Weight, and then predicting Weight at
different Time. The format of the Time data is day/month/year. How
can I get R to use time series data such as this?
Keith
--
M. Keith Cox, Ph.D.
Alaska NOAA Fisheries, National Marine Fisheries Servi
Weber, Sam wrote:
Hi,
I was hoping to get some advice on how to derive estimates of slopes from four
parameter logistic models fit with SSfpl.
I fit the model using:
model<-nls(temp~SSfpl(time,a,b,c,d))
summary(model)
I am interested in the values of the lower and upper asymptotes (paramet
Amazing.
Thanks a lot
milton
On Mon, Oct 19, 2009 at 12:55 PM, Henrique Dallazuanna wrote:
> Milton,
>
> Try this:
>
> myDF[grep("k", names(myDF))] <- sapply(myDF[grep("k", names(myDF))],
> function(idx)myDF$namesp[idx])
>
>
> On Mon, Oct 19, 2009 at 2:03 PM, milton ruser
> wrote:
> > Dear R-g
Hey Ashta,
Simply typo, it's splines... library(splines).
Cheers...
-
Simon Bonner
Post-Doctoral Fellow
Department of Statistics, UBC
www.simon.bonners.ca
On Mon, 2009-10-19 at 12:59 -0400, Ashta wrote:
> Hi All,
>
> I am using R version 2.9.2 (2009-08-24) window version
> and I wanted to
Gabriel Margarido wrote:
Hello, everyone.
I have the following problem with TclTk: I create some windows and want to
change their position with geometry manage (sometimes they will be centered,
sometimes not).
If the toplevel is created and its dimensions are gathered via 'tkwinfo', I
get (usual
Hi All,
I am using R version 2.9.2 (2009-08-24) window version
and I wanted to use the
> library(spline)
Error in library(spline) : there is no package called 'spline'
I tried to install packages as well and it is not there either.
Am I missing something there. Where can I get this library?
Th
Milton,
Try this:
myDF[grep("k", names(myDF))] <- sapply(myDF[grep("k", names(myDF))],
function(idx)myDF$namesp[idx])
On Mon, Oct 19, 2009 at 2:03 PM, milton ruser wrote:
> Dear R-gurus,
>
> Just supose I have a dara.frame that looks like
>
> myDF<-read.table(stdin(),head=T,sep=",")
> codID,na
Hello, everyone.
I have the following problem with TclTk: I create some windows and want to
change their position with geometry manage (sometimes they will be centered,
sometimes not).
If the toplevel is created and its dimensions are gathered via 'tkwinfo', I
get (usually) correct values. However
Hi,
I wouldn't combine the year and country codes in the first place, and
certainly not as a numeric value. Do you have the raw data with
country and year listed separately? From the output you listed it
looks like you indeed have a single value (2e+07) for yearctry. You
can check with
unique(e$ye
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Ian Willems
> Sent: Monday, October 19, 2009 6:50 AM
> To: 'r-help@r-project.org'
> Subject: [R] how to get rid of 2 for-loops and optimize runtime
>
> Short: get rid of the loo
Dear R-gurus,
Just supose I have a dara.frame that looks like
myDF<-read.table(stdin(),head=T,sep=",")
codID,namesp,k1,k2,k3,k4
1,spA,2,5,6,3
2,spB,4,5,4,6
3,spC,2,1,5,6
4,spC,5,4,3,2
5,spD,1,2,3,4
6,spE,2,4,3,1
I need to update the columns k1-k4 with the namesp, but
considering the math between
Dear R users
I have the following problem when calling optim() to minimize a function
"f.obj" (= outer loop) that calls another function "f.con" (a contraction
mapping, = inner loop). It seems to me that it is a numerical problem that I
currently fail to take into account when coding.
Calling
Hi Ista
You got that correct, yearctry is a composite created as yearctry =
year*1+country, so that say for example USA with country code 1 and year
2000 will be 201, for year 2005, it will be 2005001, the years are
listed from 2000 to 2008, for many countries, for UK say it will be 244
It seems that var() computes sample variance. It is straight forward
to compute population variance from sample variance. However, I feel
that it is still convenient to have a function that can compute
population variance. Is there a population variance function available
in R?
$ Rscript var.R
> s
Or even
> install.packages(Hmisc)
> library(Hmisc)
then use spss.get
Actually spss.get uses read.spss from foreign package but with common
default options.
Caveman
On Mon, Oct 19, 2009 at 3:18 PM, Jorge Ivan Velez
wrote:
> Hi Suman,
> See the read.spss function in the foreign package, e.g.:
>
Søren Højsgaard wrote:
> In the 'doBy' package there is an esticon() function for calculating linear
> contrasts for various model types. I have defined an S3-method
> 'esticon.mer()' for 'mer' objects from the lme4 package. Building the package
> and invoking the method gives:
>
>> esticon(fm1
On Mon, 19 Oct 2009, Jun Chen wrote:
Dear,
I would like to deal with microarray data, it can run when i deal with
little data. However, the amount number of SNP data are 45181, amount
numbers of animal are 3081,it can not be allocated 1000Mb memory when
i importing them to R
Procedure sentence
Krystyna Golabek wrote:
>
>
> Using AIC for model selection I find my minimal model is
> FOLLOW~MOVERSTATUS+DISTANCE however it appears DISTANCE is not significant
> at 95% confidence, see output quoted below.
> However, removing DISTANCE gives a higher AIC=433.5, therefore I will keep
> it in
Hi,
?loadings
print (pca_result$loadings,cutoff=0)
unclass(pca_result$loadings)
--
Andris Jankevics
AIO
Groningen Bioinformatics Centre
Groningen Biomolecular Sciences and Biotechnology Institute
University of Groningen
Kerklaan 30, Haren, 9751 NN, The Netherlands
On Mon, Oct 19, 2009 at 4:34
On Mon, Oct 19, 2009 at 1:58 AM, Peter Ehlers wrote:
>
> Peng Yu wrote:
>>
>> Please see below that [3,1] of loadings is not printed. I am wondering
>> what the problem is?
>
> Not trying ?loadings, perhaps??
'loadings' gives me the same thing.
> pca_result$loadings
Loadings:
Comp.1 Comp.2
On Mon, Oct 19, 2009 at 5:02 AM, Mark Difford wrote:
>
> Peng Yu wrote:
>
>>> Some webpage has described prcomp and princomp, but I am still not
>>> quite sure what the major difference between them is.
>
> The main difference, which could be extracted from the information given in
> the help file
In article
,
b.rowling...@lancaster.ac.uk says...
> If you can't get to the command line where you started R, then you
> can send the process the 'STOP' and 'CONT' signals using the 'kill'
> command. You need to get the process ID (see "man ps" for this) and
> then use "kill -STOP 12345" and "kil
Hi,
I was hoping to get some advice on how to derive estimates of slopes from four
parameter logistic models fit with SSfpl.
I fit the model using:
model<-nls(temp~SSfpl(time,a,b,c,d))
summary(model)
I am interested in the values of the lower and upper asymptotes (parameters a
and b), but als
Hi Ian,
first of all, take a look at the functions sapply, mapply, lapply,
tapply, ... : they are the more efficient way of implementing loops.
Second, could you elaborate a bit further on the data set : the amount
of the month ago, is that one value from another row, or the sum of
all values in
joris meys wrote:
2 problems :
test seems to be a data frame or list with one variable. So you have
to specify :
as.numeric(test$classcol)
But this will make the internal factor levels the real values, not the
numbers you specified. What you need, is
as.numeric(as.character(test$classcol))
w
Short: get rid of the loops I use and optimize runtime
Dear all,
I want to calculate for each row the amount of the month ago. I use a matrix
with 2100 rows and 22 colums (which is still a very small matrix. nrows of
other matrixes can easily be more then 10)
Table before
Year month quart
2 problems :
test seems to be a data frame or list with one variable. So you have
to specify :
as.numeric(test$classcol)
But this will make the internal factor levels the real values, not the
numbers you specified. What you need, is
as.numeric(as.character(test$classcol))
Cheers
Joris
On Mon, O
Hi,
If any one has time I need some help understanding the P-values given in the
lmer output.
Using AIC for model selection I find my minimal model is
FOLLOW~MOVERSTATUS+DISTANCE however it appears DISTANCE is not significant at
95% confidence, see output quoted below.
However, removing DIST
Hello,
I figure this is quite a simple problem really, but since I'm quite
new to R I need to ask:
If I have a data frame:
str(test) :
$ classcol: Factor w/ 3 levels "1","2","3"
How do I convert the entries in this column to numbers. I.e., I want
to be abl to do simple calculations like test[1,
On Mon, Oct 19, 2009 at 3:21 PM, Barry Rowlingson
wrote:
> On Mon, Oct 19, 2009 at 2:01 PM, Karl Ove Hufthammer wrote:
>
>> If you start the application using the command line, just press
>> 'Ctrl + Z' to pause/suspend it. Then type 'fg' when you want to
>> resume it.
>
> If you can't get to the
This is kind of a general question about methodology more than anything. But I
was looking for fome advice. I have fit a time-series model and feel pretty
confident that I have taken this model (exponential smoothing) as far as it
will go. In other words looking at the data and the fitted curves
On 10/18/2009 11:26 PM, tdm wrote:
> I have build a model but want to then manipulate the coefficients in some
> way.
>
> I can extract the coefficients and do the changes I need, but how do I then
> put these new coefficients back in the model so I can use the predict
> function?
>
> my_model <
On 10/19/09, Prof Brian Ripley wrote:
> It is a 'List of 1', so you want tmp[[1]] which you can access as a data
> frame. As the help file says
>
Thank you. I forgot how to access elements of lists.
Regards
Liviu
__
R-help@r-project.org mailing list
ht
Hi
Up! I finally get it work. For the record:
1. problem - spaces in path definition
2. problem - customised Rprofile.site which throws error when trying to
load some packages
After starting with all customised values disabled R CMD INSTALL
worked as charm.
Thank you very much, it is
On Mon, Oct 19, 2009 at 2:01 PM, Karl Ove Hufthammer wrote:
> If you start the application using the command line, just press
> 'Ctrl + Z' to pause/suspend it. Then type 'fg' when you want to
> resume it.
If you can't get to the command line where you started R, then you
can send the process th
On Mon, Oct 19, 2009 at 3:01 PM, Karl Ove Hufthammer wrote:
> In article @mail.gmail.com>, r.m.k...@gmail.com says...
>> I am not - I am using Linux.
>>
>> Just for interests sake: how can I pause a task in Linux?
>
> If you start the application using the command line, just press
> 'Ctrl + Z' to
In the 'doBy' package there is an esticon() function for calculating linear
contrasts for various model types. I have defined an S3-method 'esticon.mer()'
for 'mer' objects from the lme4 package. Building the package and invoking the
method gives:
> esticon(fm1, c(1,1))
Confidence interval ( WA
HI,
Please keep r-help copied on the reply -- hopefully someone will pick
up this thread and help us out.
On Mon, Oct 19, 2009 at 2:17 AM, saurav pathak wrote:
> Dear Ista
> Thanks for answering, the previous question was a primer to what I wanted, I
> did just what you said with "yearctry " belo
Hi Suman,
See the read.spss function in the foreign package, e.g.:
# install.packages(foreign)
require(foreign)
?read.spss
HTH,
Jorge
On Mon, Oct 19, 2009 at 8:06 AM, Suman Kundu <> wrote:
> Hello,
>
> In R, How to read SPSS file and access the data item?
>
> Thank you.
> Regards,
> Suman Kun
On 10/19/2009 8:06 AM, Suman Kundu wrote:
> Hello,
>
> In R, How to read SPSS file and access the data item?
RSiteSearch('SPSS', restrict='function')
> Thank you.
> Regards,
> Suman Kundu
>
> [[alternative HTML version deleted]]
>
>
Dear users,
I am trying to export polygons from Arcmap into Spatstat to run some
simulations using functions available in Spatstat package.
One particular area to be exported is formed by a number of polygons
defining the external boundaries of the area (as a groups of islands) and a
number of p
Thank you all who replied to my post. That cleared things up very well
Anjan
On Sun, Oct 18, 2009 at 11:10 PM, ANJAN PURKAYASTHA <
anjan.purkayas...@gmail.com> wrote:
> Hi,
> newbie question. I have a data-frame with 3 named columns: Name, Obs1,
> Obs2.
> The Name column members are made of alpha
On 10/19/2009 5:28 AM, Cheryl Squair wrote:
I would like to wrap a y-axis label onto two lines. My label is an expression
containing both text and math symbols. I have looked at plotmath,
strsplit(), strwrap(), deparse(), do.call(), substitute() and bquote().
Based on previous posts, I can get pl
In article , r.m.k...@gmail.com says...
> I am not - I am using Linux.
>
> Just for interests sake: how can I pause a task in Linux?
If you start the application using the command line, just press
'Ctrl + Z' to pause/suspend it. Then type 'fg' when you want to
resume it.
--
Karl Ove Hufthammer
It is a 'List of 1', so you want tmp[[1]] which you can access as a
data frame. As the help file says
For a fit with a single stratum the result will be a list of
ANOVA tables, one for each response (even if there is only one
response): the tables are of class '"anova"' inheritin
On Mon, Oct 19, 2009 at 2:40 PM, Anders Carlsson
wrote:
>
> Peter Dalgaard wrote:
>>
>> Anders Carlsson wrote:
>>
>>>
>>> Hello,
>>> I’m currently running a script that takes several days to complete, and
>>> have therefore chosen to start two instances of R, each doing half the
>>> work (since I
Hello,
In R, How to read SPSS file and access the data item?
Thank you.
Regards,
Suman Kundu
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the po
Dear,
I would like to deal with microarray data, it can run when i deal with
little data. However, the amount number of SNP data are 45181, amount
numbers of animal are 3081,it can not be allocated 1000Mb memory when
i importing them to R
Procedure sentence show:
m<-matrix(scan("D:/SNPdata.txt"),
Rene wrote:
> Dear all,
>
> I am stuck at applying loop function for creating separated plots.
>
> I have coding like below:
>
> dataset.table <-
>
table(data.frame(var1=c(1,2,3,1,2,3,1),colour=c("a","b","c","c","a","b","b")
> ))
> kk = function(f)
> {
> ls=as.charac
We are happy to inform you that abstract submission and registration for
`useR! 2010' is now available online from
http://www.R-project.org/useR-2010/
This meeting of the R user community will take place at the Gaithersburg,
Maryland, USA campus of the National Institute of Standards and Te
Dear R users,
the tmvtnorm package, the package for the truncated multivariate normal
distribution, has been updated on CRAN.
The major changes in version 0.8 are:
* Reimplemented the Gibbs' sampler for random number generation in Fortran for
performance reasons. This compiled code is now even
I would like to wrap a y-axis label onto two lines. My label is an expression
containing both text and math symbols. I have looked at plotmath,
strsplit(), strwrap(), deparse(), do.call(), substitute() and bquote().
Based on previous posts, I can get plain text to wrap. However, when I try
these m
Peter Dalgaard wrote:
Anders Carlsson wrote:
Hello,
I’m currently running a script that takes several days to complete, and
have therefore chosen to start two instances of R, each doing half the
work (since I have a two-processor machine). The problem is that this
renders my computer worthle
Dear all
How do I access individual elements of a "summary.aov" object?
> data(iris)
> AnovaModel.1 <- aov(Sepal.Length ~ Species, data=iris)
> tmp <- summary(AnovaModel.1)
> tmp
Df Sum Sq Mean Sq F value Pr(>F)
Species 2 63.231.6 119 <2e-16 ***
Residuals 147 39.0
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