On Fri, 26 Jun 2009, David Scott wrote:
Andrew Yee wrote:
A naive question: what happened to the xlsReadWrite package?
http://cran.r-project.org/web/packages/xlsReadWrite/
It says that it was removed from the CRAN repository.
Note that it was archived, not removed entirely. That is done
wi
On Fri, Jun 26, 2009 at 7:21 AM, Michael wrote:
> Let's say I have some automation tasks where I have to fill a table
> field on a webpage, and then submit it to the server, and then obtain
> the returned value (a typical web query), how to do that in R?
>
The RCurl package will let you construct
Let's say I have some automation tasks where I have to fill a table
field on a webpage, and then submit it to the server, and then obtain
the returned value (a typical web query), how to do that in R?
Thanks a lot!
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h
Question: after fitting a gamma function to some data, how do I get
predicted values? I'm a SAS programmer, I new R, and am having
problems getting my brain to function with the concept of "object as
class ...". The following is specifics of what I am doing:
I'm trying to determine the pd
Dear all,
I am not sure what I am doing wrong, but I have some unexplained behaviour when
saving a lattice graph including text to a pdf file. The text seems to move
around. It must have something to do with the way coordinates are set in
devices other than jpg.
Any suggestions would be helpfu
Hi, all,
According to the ADF.test help,""Singf" removes the non-significant lags
at the 10% level of significance until all the selected lags are
significant." However, when I use "singf", it still give me the lags that
are not significant at 10% level.
Anyone knows why?
Thanks.
Harry
Hi all,
This is a really basic question but I can't figure it out.
I am trying to write a piece of code that will use two datasets, z and m..
This code is meant to assign the mean of selected values in dataset m to a new
column z$c in datset z but the rows and columns of the two data sets diffe
Thanks David for reading for me. Anyhow, is there better way to do looping
on xts objects than using apply? Thanks again.
adschai
On Thu, Jun 25, 2009 at 12:39 AM, David Winsemius wrote:
>
> On Jun 24, 2009, at 9:26 PM, R_help Help wrote:
>
> Hi,
>>
>> I do not understand why after I called app
On 25 June 2009 at 17:39, Ivo Shterev wrote:
| Does anyone know how to pass a vector of strings, for example "c("1", "2",
| "3") to a C++ function? Should the input argument to the C++ function be
| vector*?
For the basic mechanics of making R and C/C++ talk, see the 'R Extensions'
manual that c
Hi,
Does anyone know how to pass a vector of strings, for example "c("1", "2", "3")
to a C++ function? Should the input argument to the C++ function be
vector*?
Thanks a lot!
Ivo
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On Jun 25, 2009, at 7:51 PM, Payam Minoofar wrote:
Hello,
Is possible to place a label on a multipanel figure outside the
boundaries of any single one of the existing graphs in a panel?
Specifically, I have a function that creates a panel with quartz()
and then fills it with 6 graphs con
Dear,
Thank you for cheking the mail!
I'm Bo, student in TTU, and had a problem in using r for analyzing microarry
data.
This is what I write in r:
library(limma)
argets <- readTargets(file="targets.txt") *targets.txt is a tab-delimited file
with columns: "SlideNumber", "FileName", "Cy3", "
Hello,
Is possible to place a label on a multipanel figure outside the boundaries of
any single one of the existing graphs in a panel?
Specifically, I have a function that creates a panel with quartz() and then
fills it with 6 graphs consisting of exactly the same plot for 6 different
groups.
Dear List,
I am trying to determine the speed an animal is traveling on each leg of a
track. My data is in longitude and latitude, so I am using the package rgdal
to convert it into a spatial points data frame and transform it to UTM. I
would then like to find the difference between successi
Andrew Yee wrote:
A naive question: what happened to the xlsReadWrite package?
http://cran.r-project.org/web/packages/xlsReadWrite/
It says that it was removed from the CRAN repository. Are there any plans
for it be available again?
Thanks,
Andrew
There was a problem with proprietary code.
On Jun 25, 2009, at 4:47 PM, Frank E Harrell Jr wrote:
Dear Colleagues:
I have used
\SweaveOpts{prefix.string=plot, eps = FALSE, pdf = TRUE}
\SweaveOpts{width=5, height=4}
<>=
plot(...)
@
But the figure still has a width of 80% of the text width, the
default set up by Sweave, which issues
On Thu, Jun 25, 2009 at 12:47 PM, Craig P. Pyrame wrote:
> The man page Stavros quotes states that the class attribute of the result is
> taken from 'test', which clearly is not the case:
Actually, the behavior is documented pretty clearly:
The mode of the answer will be coerced from logical
Dear Colleagues:
I have used
\SweaveOpts{prefix.string=plot, eps = FALSE, pdf = TRUE}
\SweaveOpts{width=5, height=4}
<>=
plot(...)
@
But the figure still has a width of 80% of the text width, the default
set up by Sweave, which issues a LateX command in Sweave.sty of
\setkeys{Gin}{.8\textwid
Andrew Yee post.harvard.edu> writes:
> A naive question: what happened to the xlsReadWrite package?
> http://cran.r-project.org/web/packages/xlsReadWrite/
>
> It says that it was removed from the CRAN repository. Are there any plans
> for it be available again?
Presumable removed because it w
http://www.nabble.com/file/p24211204/repeated.csv repeated.csv
Dear all,
I'm currently trying to replicate some Proc Mixed results using lme() and
have a curious result I can't explain.
The dataset is a repeated measures example where patients (each on one of
several treatments) are measured
I have many S-plus project folders that I need to convert to R workspaces.
For the smaller project folders (< 200MB), using "data.dump" with "oldStyle
= T" and "data.restore" (in the foreign package) within R seems to work
fine. However, I have several project folders that are quite large (~ 4GB).
Hello,
I've been trying to calculate home range sizes (for Icelandic geese!) using
minimum convex polygons with the adehabitat package. I've tried to use the R
code shown by demo(homerange) in adehabitat and when that didn't work I've
fiddled around with it but to no avail...Below is the output o
Hi, Dieter Menne,
Thank you for your help. I tried "par(las=1,cex=0.5)", but it changed only
the size of indices on the y axis in the second plot relative to the
default. I really want to increase the height of y axis in order to show all
the indices (x1, x2, ...). In the genetic study, we aften
Hi, Jim,
Thank you for your reply. I just want to increase the height of y axis in
the second plot in order to show all the indices (x1, x2, ...). Can you help
me? Thank you again.
Legen
Jim Lemon-2 wrote:
>
> legen wrote:
>> Hallo, All,
>>
>> I have a question about changing the height or s
Glad if it helps.
check out this page of examples for tikz,
http://www.texample.net/tikz/examples/feature/shadings/
If you do choose this route, you could perhaps read the new wiki page on
importing graphics in a R plot,
http://wiki.r-project.org/rwiki/doku.php?id=tips:graphics-misc:display-ima
A naive question: what happened to the xlsReadWrite package?
http://cran.r-project.org/web/packages/xlsReadWrite/
It says that it was removed from the CRAN repository. Are there any plans
for it be available again?
Thanks,
Andrew
[[alternative HTML version deleted]]
__
Thanks Jorge and Marc,
I drew the line using the function:
segments(x0, y0, x1, y1)
Lesandro
--- Em qui, 25/6/09, Marc Schwartz escreveu:
De: Marc Schwartz
Assunto: Re: [R] How to draw a line in plot when I know the
On Jun 25, 2009, at 1:51 PM, Ted Harding wrote:
On 25-Jun-09 18:38:37, Marc Schwartz wrote:
On Jun 25, 2009, at 1:30 PM, Lesandro wrote:
Hello all,
How to draw a line in plot when I know the start point(x1,y1)
and end point(x2,y2)? I need make this as additional information
in the graph:
plo
I have sent a note to Peter Ruckdeschel who wrote the excellent
SweaveListingUtils package but find myself up against a deadline in
preparing a handout for useR! 2009.
The following is supposed to work:
<<>>=
plot(x, y) # Figure `\ref{myfig}`
@
Where the back tick ` is an escape character
On 25-Jun-09 18:38:37, Marc Schwartz wrote:
> On Jun 25, 2009, at 1:30 PM, Lesandro wrote:
>> Hello all,
>> How to draw a line in plot when I know the start point(x1,y1)
>> and end point(x2,y2)? I need make this as additional information
>> in the graph:
>>
>> plot(wl2[[1]],wl2[[2]])
>>
>> I think
On Jun 25, 2009, at 1:30 PM, Lesandro wrote:
Hello all,
How to draw a line in plot when I know the start point(x1,y1) and
end point(x2,y2)? I need make this as additional information in the
graph:
plot(wl2[[1]],wl2[[2]])
I think that is possible make this with the function abline(), is
Dear Lesandro,
Take a look at
?segments
HTH,
Jorge
On Thu, Jun 25, 2009 at 2:30 PM, Lesandro wrote:
> Hello all,
>
> How to draw a line in plot when I know the start point(x1,y1) and end
> point(x2,y2)? I need make this as additional information in the graph:
>
> plot(wl2[[1]],wl2[[2]])
>
>
Hello all,
How to draw a line in plot when I know the start point(x1,y1) and end
point(x2,y2)? I need make this as additional information in the graph:
plot(wl2[[1]],wl2[[2]])
I think that is possible make this with the function abline(), is possible? I
looked the function lines() too, but don
Alejandra Solis Herrera wrote:
Hi,
I'm trying to fit a binary logistic regression model, and would like to
consider certain characteristics B and C only for people with variable A=1 and
not for those with variable A=0, so I'm trying to do the following:
model<- lrm(formula= y ~ A: (B
Hi,
I'm trying to fit a binary logistic regression model, and would like to
consider certain characteristics B and C only for people with variable A=1 and
not for those with variable A=0, so I'm trying to do the following:
model<- lrm(formula= y ~ A: (B+C) + D + E +...)
I've had no p
On Jun 25, 2009, at 11:38 AM, Rowe, Brian Lee Yung (Portfolio
Analytics) wrote:
Hello useRs:
Does anyone have thoughts on the lifecycle of older releases of R? I
know that currently the 2.8.x and 2.9.x releases seem to be actively
"supported" on the mailing lists, but what about older release
Good to know. I know that other software projects (whether languages,
OSes, applications) tend to keep recent versions in maintenance mode for
a certain period of time prior to "retiring them". I wonder if that
would happen with R, either by design or out of necessity of an
increasing user base.
B
On Thu, Jun 25, 2009 at 9:38 AM, Rowe, Brian Lee Yung (Portfolio
Analytics) wrote:
> Hello useRs:
>
> Does anyone have thoughts on the lifecycle of older releases of R? I
> know that currently the 2.8.x and 2.9.x releases seem to be actively
> "supported" on the mailing lists, but what about older
On Thu, 25 Jun 2009, Rowe, Brian Lee Yung (Portfolio Analytics) wrote:
Does anyone have thoughts on the lifecycle of older releases of R? I
know that currently the 2.8.x and 2.9.x releases seem to be actively
"supported" on the mailing lists, but what about older releases, say
2.4.x? Curious to
Hi,
I was trying to read some help of functions and in all functions I try to see
is giving me this error:
> ?write.table
Erro em
print.help_files_with_topic("C:/ARQUIV~1/R/R-29~1.0/library/utils/chm/write.table")
:
CHM file could not be displayed
Anybody knows what is happening?
Atenciosa
Dear Rolf,
Rolf Turner wrote:
On 25/06/2009, at 12:27 PM, Craig P. Pyrame wrote:
Dear Stavros,
What you discuss below is somewhat scary to me as an R newbie. Is this
just an incident, a bug perhaps, or rather the way things typically go
in R, as your "Welcome to R!" seems to suggest? I ha
There is an archive for all packages for older versions of R, but if
you want up-to-date functionality of packages then you need the
newest versions.
my 2 cents
stephen
On Thu, Jun 25, 2009 at 12:38 PM, Rowe, Brian Lee Yung (Portfolio
Analytics) wrote:
> Hello useRs:
>
> Does anyone have thought
Hi,
How can I obtain the residuals of my long memory model:
x.fd = fracdiff(dif, nar=1, nma=2, M=30)
There is no function as acf() as for arima or garch models...
Many thanks
Ana
[[alternative HTML version deleted]]
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Hello useRs:
Does anyone have thoughts on the lifecycle of older releases of R? I
know that currently the 2.8.x and 2.9.x releases seem to be actively
"supported" on the mailing lists, but what about older releases, say
2.4.x? Curious to hear when people think older versions of R become
obsolete a
Erratum:
> ifelse(TRUE,dd,dd) => 1230786000 (class numeric)
should be
ifelse(TRUE,tt,tt) => 1230786000 (class numeric)
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PLEASE do read the posting guide http://www.
Your covariance matrix Szz is not positive definite. It is singular. The
following test that you are doing is neither necessary nor useful:
zz.ev <- eigen(Szz)$values
if(min(zz.ev)[1]<0){
stop("\'Szz\' is not positive definite!\n")
}
You may want to use Moore-Penrose inve
On Wed, Jun 24, 2009 at 9:04 PM, Rolf Turner wrote:
> Do not get your knickers in a twist. R works simply and straightforwardly
> in simple straightforward situations.
Though I find R an incredibly useful tool, alas, it is simply not true
that "R works simply and straightforwardly in simple str
This means that your design matrix or model matrix is rank deficient, i.e it
does not have linearly independent columns. Your predictors are collinear!
Just take your design matrices "covaea" or "covaeb" with 17 predcitors and
compute their rank or try to invert them. You will see the problem.
Rebecca,
I think the problem is that subset is a nume of an R function. If you do
something like
subs <- c(rep(TRUE, 107), FALSE)
fm2 <- lme(distance ~ age + Sex, data = Orthodont, random = ~ 1,
subset=subs)
everything works fine.
Hope this helps,
Andy
__
An
On Jun 25, 2009, at 11:35 AM, Rebecca Sela wrote:
I am trying to estimate models with subsets using the NLME package.
However, I am getting an error in the case below (among others):
subset <- c(rep(TRUE, 107), FALSE)
fm2 <- lme(distance ~ age + Sex, data = Orthodont, random = ~ 1,
subset=
Dear R-help,
I'm very sorry to ask 2 questions in a week. I am using the package
'crr' and it does exactly what I need it to when I use the dataset a.
However, when I use dataset b I get the following error message:
Error in drop(.Call("La_dgesv", a, as.matrix(b), tol, PACKAGE = "base")) :
syst
I am trying to estimate models with subsets using the NLME package. However, I
am getting an error in the case below (among others):
> subset <- c(rep(TRUE, 107), FALSE)
> fm2 <- lme(distance ~ age + Sex, data = Orthodont, random = ~ 1,
> subset=subset)
Error in xj[i] : invalid subscript type 'c
Thanks, Gabor. Works great!
On Thu, Jun 25, 2009 at 10:38 AM, Gabor Grothendieck <
ggrothendi...@gmail.com> wrote:
> Try this (shown for stated problem but generalizes by just adding
> additional arguments):
>
> mapply("[", list(x), ltrs, mnths)
>
>
> On Thu, Jun 25, 2009 at 10:24 AM, Rama Ramak
Hi All...
I¹m trying to build a small demo using gWidgets which permits interactive
scaling and selection among different things to plot. I can get the widgets
for scaling to work just fine. I am using gcheckboxgroup to make the
(possibly multiple) selections. However, I can¹t seem to figure ou
BTW, the XML you show is not legal XML.
For instance, the element
F)>NAF)>
is not a legal XML element name.
Similarly
is not a legal name since it is "2".
And anova:2 means an element with name 2 with (XML) name space prefix
"anova" (which must be declared previously)
As Gabor mentioned
The updated package has been submitted to CRAN and will propagate to
mirrors over the next day or so.
It is maintained on R-Forge at http://r-forge.r-project.org/projects/writexls
, where downloads will be available as well. There is a transient
problem at the moment with R-Forge and the bui
Thanks, David, that works too!
On Thu, Jun 25, 2009 at 10:30 AM, David Winsemius wrote:
>
> On Jun 25, 2009, at 10:24 AM, Rama Ramakrishnan wrote:
>
> Follow-on question: is there a way to do this for higher-dimensional (i.e.
>> more than 2 dimensions) arrays?
>>
>
> The apply method I just pos
Hi Guillaume
Once you have created an XML representation using any of the various
ways to represent XML in R via the XML package (e.g. internal nodes,
lists of lists, hash trees), you can use the saveXML() function:
saveXML(myXML, "fileName.xml")
Personally, I use newXMLNode() and friend
See the StatDataML package.
On Thu, Jun 25, 2009 at 10:54 AM, guillaume Le
Ray wrote:
> Hello everybody,
>
> I have programed a function to translate the R object structure into a XML
> data structure but I haven't found a function in the XML package to export
> this data in an XML file!
>
> my da
I get this error while computing partial correlation.
*Error in solve.default(Szz) :
system is computationally singular: reciprocal condition number =
4.90109e-18*
Why is it?Can anyone give me some idea ,how do i get rid it it?
This is the function i use for calculating partial correlation.
Hello everybody,
I have programed a function to translate the R object structure into a XML
data structure but I haven't found a function in the XML package to export
this data in an XML file!
my data look like that:
Assessor:codec
33.98159
28
6.510894
F)> 1.725149e-22F)>
Try this (shown for stated problem but generalizes by just adding
additional arguments):
mapply("[", list(x), ltrs, mnths)
On Thu, Jun 25, 2009 at 10:24 AM, Rama Ramakrishnan wrote:
> Follow-on question: is there a way to do this for higher-dimensional (i.e.
> more than 2 dimensions) arrays?
>
>
Hello,
Is there a way to access function's slots from inside the function? I
want to make functions slot dependent without recurring to generic
function mechanism.
Probably this goes a bit against R philosophy, but otherwise I don't
really see the use of extending functions in R.
Would
On Jun 25, 2009, at 10:24 AM, Rama Ramakrishnan wrote:
Follow-on question: is there a way to do this for higher-dimensional
(i.e.
more than 2 dimensions) arrays?
The apply method I just posted generalizes to higher dimensional arrays.
--
DW
On Thu, Jun 25, 2009 at 10:17 AM, Rama Ramakr
On 6/25/2009 7:20 AM, John Sorkin wrote:
R 2.8
Windows XP
Excel 2003
I am trying to read an Excel spread sheet. I have looked at the RODBC help
pages and am having trouble setting up code that will work. My code and the
results are pasted below:
jo<-odbcConnectExcel("i:\\all\\sorkinjohn\\st
On Jun 25, 2009, at 10:02 AM, Rama Ramakrishnan wrote:
Dear R-Users,
I need to lookup values from a 2-d table using the row names and
column
names as indices. I was wondering if there's a way to do this
without an
explicit loop.
Example:
#x is the 2-d table that holds the values
x <- mat
Follow-on question: is there a way to do this for higher-dimensional (i.e.
more than 2 dimensions) arrays?
On Thu, Jun 25, 2009 at 10:17 AM, Rama Ramakrishnan wrote:
> That works!! Very nice way to do it! Thank you, Henrique!
> Rama Ramakrishnan
>
>
> On Thu, Jun 25, 2009 at 10:11 AM, Henrique D
Dear all,
I'm training an SVM with default settings on a matrix csr (SparseM
package). I realized that if I train
the SVM with the (hopefully) equivalent matrix (Matrix package)
representation, the returned models and predictions
sometimes differ. I expected both representations of the same dat
Try this:
y$values <- diag(x[y$ltrs, y$mnths])
On Thu, Jun 25, 2009 at 11:02 AM, Rama Ramakrishnan wrote:
> Dear R-Users,
> I need to lookup values from a 2-d table using the row names and column
> names as indices. I was wondering if there's a way to do this without an
> explicit loop.
>
> Exam
That works!! Very nice way to do it! Thank you, Henrique!
Rama Ramakrishnan
On Thu, Jun 25, 2009 at 10:11 AM, Henrique Dallazuanna wrote:
> Try this:
>
> y$values <- diag(x[y$ltrs, y$mnths])
>
> On Thu, Jun 25, 2009 at 11:02 AM, Rama Ramakrishnan wrote:
>
>> Dear R-Users,
>> I need to lookup valu
Resending after fixing a mistake in the earlier email ... sorry for the
confusion.
**
Dear R-Users,
I need to lookup values from a 2-d table using the row names and column
names as indices. I was wondering if there's a way to do this without an
explicit loop.
Example:
#x is the 2-d table that
Dear R-Users,
I need to lookup values from a 2-d table using the row names and column
names as indices. I was wondering if there's a way to do this without an
explicit loop.
Example:
#x is the 2-d table that holds the values
x <- matrix(rnorm(26*12),nrow=26)
rownames(x) <- letters
colnames(x) <
Try this:
DF <- data.frame(tt = ISOdate(2009, 1:12, 1), x = 1:12, y = 1:12)
st <- as.POSIXct("2009-05-01 00:00:00")
en <- as.POSIXct("2009-07-01 23:59:59")
DF[DF$tt > st & DF$tt < en, ]
If the data in DF is numeric you would probably be better off
using a zoo series than a data.frame in which cas
Look at the anova.mean function in the HH package.
It does what you are asking, although limited to one-way ANOVA.
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Hi,
I have a big dataframe with a POSIXct column and I'd like to extract a
subset contained in a given time interval, from Date 1 to Date 2.
Paulo E. Cardoso
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Your request for a more general approach is precisely the reason that
Hadley Wickham wrote the plyr package. He describes a split-apply-
combine strategy for a variety of data structures and tools to
implement those strategies here:
http://had.co.nz/plyr/plyr-intro-090510.pdf
The argument t
On Thu, Jun 25, 2009 at 2:55 PM, Gabor Grothendieck wrote:
> It works for me. Try a more recent version of R.
Good to see that it is fixed in 2.9.1. I am using the latest release and am
going to wait till 2.9.1 is released.
Thanks,
Rainer
>
> > a <- c("PR", "NC", "A2", "BS")
> > b <- c(1,
Have a look at ddply from the plyr package, http://had.co.nz/plyr.
It's made for exactly this type of operation.
Hadley
On Wed, Jun 24, 2009 at 10:34 PM, Stephan Lindner wrote:
> Dear all,
>
>
> I have a code where I subset a data frame to match entries within
> levels of an factor (actually, the
It works for me. Try a more recent version of R.
> a <- c("PR", "NC", "A2", "BS")
> b <- c(1, 0.5, 0.25, 0.125, 0.0625, 0.03125)
>
> class(expand.grid(a, b, stringsAsFactors=FALSE)[[1]])
[1] "character"
> class(expand.grid(a, b, stringsAsFactors=TRUE)[[1]])
[1] "factor"
> R.version.string
[1] "R
Zeljko Vrba wrote:
>
> On Wed, Jun 10, 2009 at 08:21:06AM +0200, Poizot Emmanuel wrote:
>> Error in fun(...) :
>>GDAL Error 1: libgrass_I.so: Ne peut ouvrir le fichier d'objet
>> partagé: Aucun fichier ou dossier de ce type (sorry for the french :) )
>>
>
> It would have been far more
On 6/25/2009 5:44 AM, Anne Skoeries wrote:
> Hello,
>
> how can I get a variable driven summary of one column of my data.frame?
>
> Usually I would do
>> summary(data$columnname) to get a summary of column named "columnname"
> of my data.frame named "data".
>
> In my case the columnname is not s
...
> Occasionally, (about 1 in every 100 simulations) I get the following warning:
> Error in coxph(Surv(start, end, censorind) ~ binary + uniform :
> X matrix deemed to be singular; variable 2
It is not uncommon for the X matrix in a Cox model to be close enough to
singular that the p
On Thu, Jun 25, 2009 at 1:38 PM, Henrique Dallazuanna wrote:
> I also not find this in the source code, but you can rewrite the function
> with this:
>
That's true - but this should be fixed in the package itself. I have just
converted the factor to characters.
Cheers
Rainer
>
> expand.grid <
Dear Oscar,
Try this:
# Some data
set.seed(123)
a <- matrix(rnorm(100*200), ncol = 200)
b <- matrix(rnorm(100*200), ncol = 200)
# Auxiliar function to extract the coefficient
# after fitting models without intercept
mycoef <- function(x, y) coefficients( lm(y ~ x - 1) )
# Results
res <- sapply(1
Very good points :-)
> - colClasses() in R.utils is similar, except for the particular codes and
> classes supported, to expandClasses() here.
In fact I saw colClasses() once and got the idea from it, but when I needed the
functionallity I did not remember where had I seen it and rewrote it. N
legen wrote:
Hallo, All,
I have a question about changing the height or scale of the y axis. When I
use following two R codes, I can get two plots. Please look at the y axes,
the number of indices (x1, x2, …) on the y axis in the first plot is smaller
than that in the second plot, and hence the
Try the function sqlFetch to import the data in the spreadsheet.
jo<-odbcConnectExcel("i:\\all\\sorkinjohn\\stats\\silvermannatalie\\NEMOcomb
ined06-24-09.xls",readOnly = TRUE)
mo<-sqlFetch(jo,'Your Sheet Name or Number',colnames=F,rownames=F)
mo
Hope it helps.
-
Dear List,
I'm searching for a way (package, function or something) providing
the http PUT, GET POST ... methods in R. httpRequest and RCurl
seems to have a lack of the PUT method.
Regards
Thomas
|| Thomas Bock c/o Physikalisch-Technische Bundesanstalt
|| Abbestr. 2-12, D-10587 Berlin, Germany
Dear John,
Try this:
require(RODBC)
spreadsheet <- "Sheet1" # please change this to your needs
channel <-
odbcConnectExcel("i:\\all\\sorkinjohn\\stats\\silvermannatalie\\NEMOcombined06-24-09.xls")
mydata <- sqlFetch(channel, spreadsheet)
odbcClose(channel)
# attach(mydata)
mydata
HTH,
Jorge
O
That's quite nice. Three comments:
- colClasses() in R.utils is similar, except for the particular
codes and classes supported, to expandClasses() here.
- not sure if this is important but if as() were the last
possibility tried rather than the first then in most
cases (in fact all cases handle
I also not find this in the source code, but you can rewrite the function
with this:
expand.grid <-
function (..., KEEP.OUT.ATTRS = TRUE, stringsAsFactors = FALSE)
{
nargs <- length(args <- list(...))
if (!nargs)
return(as.data.frame(list()))
if (nargs == 1L && is.list(a1 <- ar
One thing you might consider when working with large dataframes is that
instead of partitioning the dataframe into smaller ones, create a list of
indices and use that to access the subset. Works especially well when using
'lapply' to cromp through many segments of a data frame:
> y
suid mon
Try:
data[,variable]
On Thu, Jun 25, 2009 at 6:44 AM, Anne Skoeries wrote:
> Hello,
>
> how can I get a variable driven summary of one column of my data.frame?
>
> Usually I would do
> > summary(data$columnname) to get a summary of column named "columnname" of
> my data.frame named "data".
>
> I
Another options is:
head(lapply(a, tail, 2), 2)
On Wed, Jun 24, 2009 at 8:42 PM, Ivo Shterev wrote:
>
> Hello,
>
> I have a question about list indexing. Lets say we have a list of 3 lists,
> each containing 3 different type elements:
>
> > a=replicate(3, list(list(c(1,1,1), diag(3), c(2,2,2)))
Hi
I have the feeling, that the argument stringsAsFactors has no impact in the
function expand.grid:
a <- c("PR", "NC", "A2", "BS")
b <- c(1, 0.5, 0.25, 0.125, 0.0625, 0.03125)
class(expand.grid(css, fscs, stringsAsFactors=FALSE)[[1]])
[1] "factor"
class(expand.grid(css, fscs, stringsAsFactors=T
Hello,
how can I get a variable driven summary of one column of my data.frame?
Usually I would do
> summary(data$columnname) to get a summary of column named
"columnname" of my data.frame named "data".
In my case the columnname is not static but can be set dynamically.
So I save the chosen c
R 2.8
Windows XP
Excel 2003
I am trying to read an Excel spread sheet. I have looked at the RODBC help
pages and am having trouble setting up code that will work. My code and the
results are pasted below:
> jo<-odbcConnectExcel("i:\\all\\sorkinjohn\\stats\\silvermannatalie\\NEMOcombined06-24-0
Hi,
Could I please be removed from the email list!
Thank you,
Sophie
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PLEASE do read the posting guide http://www.R-project
Dear,
I am using wavelet function from library(dplR), I would like to have a
normalised spectrum as an output (power relative to white noise).
I was wondering if anyone can help me with that.
Thank you.
irina
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On 25-Jun-09 10:15:30, Sebastian Stegmann wrote:
> Dear R-community,
> I'm struggling with a paper that reports only fragmented results
> of a 2by2by3 experimental design. However, Means and SDs for all
> cells are given.
>
> Does anyone know a package/function that helps computing an ANOVA
> with
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