John Kane wrote:
> I don't know the book but I doubt that it is a good way to learn R.
>
> I'd suggest having a look at some of the documentation available on the R
> site. Click on Other (in left column of page) have a look there and then
> select the " contributed documentation" link to get
Stats Wolf gmail.com> writes:
> Postscript, however, does not have to be what I need for two reasons.
> First, it does not accept some special characters from foreign
> languages (exactly like PDF).
You should given an example for that in pdf. I always had the impression
that pdf is the most co
On Thu, May 14, 2009 at 05:09:59PM -0700, ko...@processtrends.com wrote:
> Ajay
>
> I have added a few minor adjustments to your code to make the panel chart you
> want.
> You need to adjust the par(mar) to control space between 1st and 2nd plot.
Thanks! This is a step forward for me. But now:
Hi Charlie,
Thank you so much for suggestions!!
Actually, I used the optimization toolbox in MABLAB before and I even wrote
some numerical optimization programs by myself. As far as I know, some
commercial optimization softwares had already replaced L-BFGS-B by more
advanced algorithms, such as i
Have you looked at the vignette in the deSolve package?
(deS <- vignette('compiledCode')) # opens a "pdf" file
Stangle(deS$file) # writes an R script file to "getwd()"
In spite of the name, this vignette includes an example entirely
in R. By comparing it with
popo UBC wrote:
>
> Hi all!
>
> The objective function I want to minimize contains about 10 to 20
> variables,
> maybe more in the future. I never solved such problems in R, so I had no
> idea about the efficiency of R's optimization functions. I know doing loop
> in R is quite slow, so I am n
Have you considered the following:
solve(qr(A), B)
I have not tried this with a small toy example, and the "qr"
documentation in the Matrix package seems to suggest it. This solves
the optimization problem you mentioned, as noted in
"http://en.wikipedia.org/wiki/Linea
Hi guys
My data is Tasmania txt
There are *N *= 16 samples, consisting of 8 replicate cores (taken from
different areas across the sandflat) from each of 2 natural
'treatments' (either
disturbed "D" or undisturbed "U" by soldier crab burrowing activity. The
abundances of each of *p *= 56 species
Hi all!
The objective function I want to minimize contains about 10 to 20 variables,
maybe more in the future. I never solved such problems in R, so I had no
idea about the efficiency of R's optimization functions. I know doing loop
in R is quite slow, so I am not sure whether this shortage influe
If you need auto(cross)correlations in O(n*log(n)) rather than O(n^2)
you can use an FFT. Here's a good short write-up on using the FFT for
this (numerical recipes chapter):
http://hebb.mit.edu/courses/9.29/2002/readings/c13-2.pdf
Won't get you p values, but is faster than a normal matrix-vector
Bugzilla from n...@jonasstein.de wrote:
>
> Thank you, Baptiste and Charlie.
> I found some examples wich look great on:
> http://www.texample.net/tikz/examples/
>
I'm glad you found Texample! It is an excellent site that shows many
practical, and beautiful, demonstrations of the types of figu
Dear lagreene,
See the second example in
require(MASS)
?fitdistr
HTH,
Jorge
On Thu, May 14, 2009 at 7:15 PM, lagreene wrote:
>
> Hi,
> I was wondering if anyone could tell me how m and s are calculated for a t
> distribution?
>
> I thought m was the sample mean and s the standard deviation-
Ajay Shah wrote:
>
> The pretty picture that I saw at:
>
> http://chartsgraphs.wordpress.com/2009/02/09/r-panel-chart-beats-excel-chart/#more-1096
> inspired me to try something similar. The code that I wrote is:
>
> --snipsnip-
Jean-Louis Abitbol-2 wrote:
>
> Good Day to All,
>
> When sweaving the following:
>
> \begin{table}
> \centering
> <>=
> ftable(ifmtm$type, ifmtm$gender, ifmtm$marche , ifmtm$nfic,
> dnn=c("Type","Gender","Ambulant","Visit"))
> @
> \caption{Four-way cross-tabulation on all data}
> \label{tab:
Tena koe Karsten
Does your dataframe contain multiple values for the same factor combination?
If not, then using expand.grid(), followed by merge() should work.
If your dataframe is DF, then the following untested code should do it:
fullDF <- expand.grid(factor1=levels(DF$factor1), factor2=lev
tried that does not seem to work, for me ? Always have to specify it fully :
someclass.blah(x)
On Wed, May 13, 2009 at 11:10 PM, Jeff Laake wrote:
> class(x)="someclass"
>
> then blah(x)
>
> will invoke blah.someclass
>
> Just look at all the example code in R. For example summary.glm for
> sum
On Thu, May 14, 2009 at 6:21 PM, Ping-Hsun Hsieh wrote:
> Hi All,
>
> I have a 1000x100 matrix.
> The calculation I would like to do is actually very simple: for each row,
> calculate the frequency of a given pattern. For example, a toy dataset is as
> follows.
>
> Col1 Col2 Col3 Co
Hi,
I was wondering if anyone could tell me how m and s are calculated for a t
distribution?
I thought m was the sample mean and s the standard deviation- but obviously
I'm wrong as this doesn'y give the same answer.
Thank you
--
View this message in context:
http://www.nabble.com/fitdistr-for
Hi there,
I am not getting anywhere near a solution, so here is my question. I
have searched the archives and didn't find a solution, but maybe my
search didn't use the right words. So here it is:
I have a dataframe with the following structure
factor1 factor2 value
In the (rather large) d
On 15/05/2009, at 11:34 AM, myshare wrote:
thanx, I forgot something how then do you check if u have something
like this :
exists("xxx$array")
this does not seem to work !!
Of course not.
I don't think what you want is built in. But you can easily
cobble something together:
!is
thanx, I forgot something how then do you check if u have something like this :
exists("xxx$array")
this does not seem to work !! ;\
On Thu, May 14, 2009 at 11:26 PM, Rolf Turner wrote:
>
> On 15/05/2009, at 11:19 AM, myshare wrote:
>
>> hi guys,
>>
>> How do you check if variable is initialize
On 15/05/2009, at 11:19 AM, myshare wrote:
hi guys,
How do you check if variable is initialized/created, tried :
is.nan(xxx)
is.null(xxx)
is.na(xxx)
exists(xxx)
all of them return :
Error: object "xxx" not found
I need true/false result ?
exists("xxx") # Note the quote marks; requires th
Hi All,
I have a 1000x100 matrix.
The calculation I would like to do is actually very simple: for each row,
calculate the frequency of a given pattern. For example, a toy dataset is as
follows.
Col1Col2Col3Col4
01 02 02 00 => Freq of “02” is 0.5
02
hi guys,
How do you check if variable is initialized/created, tried :
is.nan(xxx)
is.null(xxx)
is.na(xxx)
exists(xxx)
all of them return :
Error: object "xxx" not found
I need true/false result ?
thanx
__
R-help@r-project.org mailing list
https://s
Tom Schenk Jr wrote:
I use RODBC as my conduit from R to SQL. It works well when the tables are
stored on one channel, e.g.,
channel <- odbcConnect("data_base_01", uid="", dsn="")
However, I often need to match tables across multiple databases, e.g.,
"data_base_01" and "data_base_02". H
Gabor,
My f2 was just wrong. It should have been
f2 <- function(x, n=2){ ix<-match(x,x); tix<-tabulate(ix); ix %in%
which(tix>=n) }
which would be roughly the same as your
f1 <- function(x, n=2) ave(x,x,FUN=length)>=n
and flags all elements of x with >= n repetitions.
ave() involves a cal
On 15/05/2009, at 10:04 AM, mau...@alice.it wrote:
I have just installed R2.9.0 on my Windows XP system.
I have followed the same installation procedure I have been using
for over a year. That is installation
from the "exe" file.
"kernel" belongs to package "stats"which is (I think) installe
> -Original Message-
> From: Bert Gunter [mailto:gunter.ber...@gene.com]
> Sent: Thursday, May 14, 2009 2:31 PM
> To: William Dunlap; 'Gabor Grothendieck'; 'christiaan pauw';
> 'jim holtman'
> Cc: r-help@r-project.org
> Subject: RE: [R] Duplicates and duplicated
>
>
> Thanks, Bill. I a
I have just installed R2.9.0 on my Windows XP system.
I have followed the same installation procedure I have been using for over a
year. That is installation
from the "exe" file.
"kernel" belongs to package "stats"which is (I think) installed by default.
I loaded it but did not use the command:
Dear Duncan,
On Thu, May 14, 2009 at 4:39 PM, Duncan Murdoch wrote:
> On 5/14/2009 3:36 PM, G. Jay Kerns wrote:
>> Question:
>> 1) can you tell me what my original set.seed() value was? (I wouldn't
>> be able to figure it out, but maybe someone can)
>
> The only way I know is to test all 2^32 p
I don't think that that is the conclusion.
All the solutions solve the original problem and the additional
"requirements" may or may not be what is wanted in any
particular case.
The ave solution propagates the NA which seems like
the right thing to do whereas the f2 solution and the
duplicated s
As Hadley said, it's complex in general: the standard approach is to
assemble the arguments into a list and then use do.call -- ?do.call.
Undoubtedly, there are times where this won't do either (at least not
without some further tricks).
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
Hi All,
I am trying to manually extract the scoring equations for a neural
network so that I can score clients on a system that does not have R
(mainframe using COBOL).
Using the example in Modern Applied Statistics with S (MASS), by
Venables and Ripley (VR), pages 246 and 247, I ran the follo
Thanks, Bill. I also had some concerns about how reliable numeric values
converted to character might be, so I'm glad to have an authoritative
criticism. Of course, I was really just being cute with R's versatility.
But Jim Holtman's solution seems like the best way to go, anyway, does it
not?
On Thu, May 14, 2009 at 1:58 PM, Sebastien Bihorel
wrote:
> Dear R-users,
>
> I have got the following problem. I need to create 4x2 arrays of xyplot's on
> several pages. The plots are created within a loop and plotted using the
> print function. It seems that I cannot find the proper grid syntax
Well if your matrix and vector are centered and properly scaled (and there are
no missing values), then the correlations are just a crossproduct and matrix
arithmetic is already fairly fast (assuming you have enough memory).
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain
Dear R-users,
I have got the following problem. I need to create 4x2 arrays of
xyplot's on several pages. The plots are created within a loop and
plotted using the print function. It seems that I cannot find the proper
grid syntax with my viewports, and the more/newpage arguments.
The follow
Also
coef(mylm) where you can deal with coef(mylm) [1], coef(mylm)[2]...
And
plot(y~x, data=mydf)
curve(coef(mylm)[1]+coef(mylm)[2]*x)
could produce interesiting visual results
:-)
milton
On Thu, May 14, 2009 at 2:30 PM, Dieter Wirz wrote:
> Thanks Bert and Luc!
> Sometimes the solutio
The pretty picture that I saw at:
http://chartsgraphs.wordpress.com/2009/02/09/r-panel-chart-beats-excel-chart/#more-1096
inspired me to try something similar. The code that I wrote is:
--snipsnip-
M <- structure(list(date
Alright, i am unsure of the posting rules for these types of questions but i
will be as help ful as possible. My windows based system cant handle a
model i am running so i am trying to install R on our Linux based machine
but i have encountered the following and i dont know linux much but my
intu
Hi,
Is in R any "fast" algorithm for correlation?
What I mean is:
I have very large dataset (microarray) with 55000 rows and 100 columns. I
want to count correlation (p-value and cor.coef) between each row of dataset
and some vector (of course length of this vector is equal to number of
columns of
On 5/14/2009 3:36 PM, G. Jay Kerns wrote:
Dear R-help,
Suppose I write a script that looks something like this:
script.R
set.seed(something)
x <- rnorm(100)
y <- runif(500)
# bunch of other stuff
save.image()
### end of script.R
Now, I give you a copy of my script.R (with the set.see
On Thu, 2009-05-14 at 10:30 -0700, Sunita22 wrote:
> Hello
>
> I have to import 2 txt files into R. 1 file contains the data and the other
> contains the header, column headings, datatypes and labels for the data.
>
This is your first complicating factor.
> I have 2 problems:
>
> 1) my data fi
Dear Grzés,
I am not sure whether I fully understand your question, but try either one
of the following options:
# Data set from Dimitri Liakhovitski's reply
df <- data.frame(kol1=c(2,9,4,3),kol2=c(5,6,6,2),kol3=c(9,6,5,1))
# Option 1
with(df, df[ kol1 != 9 & kol2 != 9 & kol3 != 9, ])
# Option
> I am currently doing some prediction work using the knn script in the
> 'class' package. Does anyone know a way of having R return the IDs (sample
> IDs, or column IDs of the training matrix) of the 'k' samples that are
> chosen by the algorithm as being nearest to a given test sample?
You would
Dear R-help,
Suppose I write a script that looks something like this:
script.R
set.seed(something)
x <- rnorm(100)
y <- runif(500)
# bunch of other stuff
save.image()
### end of script.R
Now, I give you a copy of my script.R (with the set.seed statement
removed, of course) together wit
Hello,I am using xyplot to try and create a conditional plot. Below is a
toy example of the type of data I am working with
slevel <- rep(rep(c(0.5,0.9), each=2, times=2), times=2)
tlevel <- rep(rep(c(0.5,0.9), each=4), times=2)
noutliers <- rep(rep(c(2,4), times=4), times=2)
analysis <- as.fac
Thanks Bert and Luc!
Sometimes the solution is close, but I did not find it
I always tried mylm$Coefficients... Stupid /me.
-didi
BTW: many thanks to all developers of R. IMHO R is one of the most
outstanding free projects!
On Thu, May 14, 2009 at 7:07 PM, Bert Gunter wrote:
>
> -- but it i
The problem is not with the BMA function, but rather that you have made the
common mistake of forgetting that you are smarter than the computer. The
variable Y below is a data frame (not a single numeric vector). Now a smart
person like you sees a single column in the data frame and understand
On May 14, 2009, at 12:16 PM, Lori Simpson wrote:
I am writing a custom function that uses an R-function from the
reshape package: cast. However, my question could be applicable to
any R function.
Normally one writes the arguments directly into a function, e.g.:
result=cast(table1, column1 +
I don't know the book but I doubt that it is a good way to learn R.
I'd suggest having a look at some of the documentation available on the R site.
Click on Other (in left column of page) have a look there and then select the
" contributed documentation" link to get more documentation. Hav
Hello R Group,
Below is the code I submit:
library("BMA")
X <- read.table("C:/Documents and
Settings/Administrator/Desktop/coding.txt",header=TRUE)
Y <- read.table("C:/Documents and
Settings/Administrator/Desktop/1DCS.txt",header=TRUE)
IGout<- iBMA.glm(X, Y, glm.family= gaussian(), ve
On Thu, May 14, 2009 at 12:16 PM, Lori Simpson
wrote:
> I am writing a custom function that uses an R-function from the
> reshape package: cast. However, my question could be applicable to
> any R function.
>
> Normally one writes the arguments directly into a function, e.g.:
>
> result=cast(tabl
I am currently doing some prediction work using the knn script in the
'class' package. Does anyone know a way of having R return the IDs (sample
IDs, or column IDs of the training matrix) of the 'k' samples that are
chosen by the algorithm as being nearest to a given test sample?
I have searched/r
I am writing a custom function that uses an R-function from the
reshape package: cast. However, my question could be applicable to
any R function.
Normally one writes the arguments directly into a function, e.g.:
result=cast(table1, column1 + column2 + column3 ~column4,
mean) (1
The table()-based solution can have problems when there are
very closely spaced floating point numbers in x, as in
x1<-c(1, 1-.Machine$double.eps, 1+2*.Machine$double.eps)[c(1,2,3,2,3)]
It also relies on table(x) turning x into a factor with the default
levels=as.character(sort(x)) and that defa
Hi,
Thanks for the contribution. I tested the code but I got a couple or errors.
I'll try to debug these in the next days.
Maybe there is a simpler approach to what I am trying to do.
I have a bunch of measures and a column with the success of the case (1/0).
I simply want to evaluate my measure
Hello
Yes I have used read.table("file name", sep="\t") for reading the text file
Thank you
On Thu, May 14, 2009 at 11:07 PM, jim holtman wrote:
> What have you tried? Check the Intro manual for hints.
>
> ?read.table probably using sep='\t'
>
> On Thu, May 14, 2009 at 1:30 PM, Sunita22 wr
What have you tried? Check the Intro manual for hints.
?read.table probably using sep='\t'
On Thu, May 14, 2009 at 1:30 PM, Sunita22 wrote:
>
> Hello
>
> I have to import 2 txt files into R. 1 file contains the data and the other
> contains the header, column headings, datatypes and labels f
Hello
I have to import 2 txt files into R. 1 file contains the data and the other
contains the header, column headings, datatypes and labels for the data.
I have 2 problems:
1) my data file has mixed type of data e.g. 1 2 3 4 5 3-5 02/04/06 3 4 5 and
so on, the data file is tab separated. when
is there a way to label points in a graph using text(locator(1),"text")
after ggplot() or qplot() ?
> qplot(date, psavert, data = economics, geom = "line",main="jhdjd")->p
> p+opts(text(locator(1),""),new=T)
does not work.
--
View this message in context:
http://www.nabble.com/text%28%29-t
Don't think I have seen this one come across:
> x <- c(1,2,3,2,4,4,6,1)
> duplicated(x) | duplicated(x, fromLast=TRUE)
[1] TRUE TRUE FALSE TRUE TRUE TRUE FALSE TRUE
On Thu, May 14, 2009 at 12:09 PM, Bert Gunter wrote:
> ... or, similar in character to Gabor's solution:
>
> tbl <- table(x)
-- but it is preferable to use the appropriate access functions:
coef(mylm)
?coef
Bert Gunter
Nonclinical Biostatistics
467-7374
## Now, what I believe you're looking for ;
mylm$coefficients ;
Cheers,
--
*Luc Villandré*
/Biostatistician
McGill University Health Center -
Montreal Child
Dieter Wirz wrote:
Dear all -
We perform some measurements with a machine that needs to be
recalibrated. The best calibration we get with polynomial regression.
The data might look like follows:
true_y <- c(1:50)*.8
# the real values
m_y <- c((1:21)*1.1, 21.1, 22.2, 23.3 ,c(25:50)*.9)/0.3-5.
On 5/9/09, John Maindonald wrote:
> The following tinkers with the strip labels, where the
> different panels are for different levelf of a conditioning
> factor.
>
> tau <- (0:5)/2.5; m <- length(tau); n <- 200; SD <- 2
> x0 <- rnorm(n, mean=12.5, sd=SD)
> matdf <- data.frame(
>x = as.ve
Dear all -
We perform some measurements with a machine that needs to be
recalibrated. The best calibration we get with polynomial regression.
The data might look like follows:
> true_y <- c(1:50)*.8
> # the real values
> m_y <- c((1:21)*1.1, 21.1, 22.2, 23.3 ,c(25:50)*.9)/0.3-5.2
> # the measured
On 5/13/09, Liati wrote:
>
> Hi,
> Thank you for your reply.
> This is exactly what I have done.
> However, I would like to get the two plots next to each other (to use as one
> figure).
Look at ?print.trellis and its examples.
-Deepayan
__
R-hel
(Ted Harding) wrote:
>
> This happens also when you use C's fprintf and sprintf (at any rate
> in my gcc):
>
r's printing routines (e.g., print, sprintf, cat, anything else?) seem
to rely on the underlying c sprintf, with no prior r-implemented
rounding. hence they import into r whatever stand
On 14-May-09 15:15:16, James W. MacDonald wrote:
> Wacek Kusnierczyk wrote:
>> (Ted Harding) wrote:
>>> On 14-May-09 12:27:40, Wacek Kusnierczyk wrote:
>>>
... but remember that sprintf introduces excel bugs into r (i.e.,
rounding is not done according to the IEC 60559 standard, see
>
Dear all,
I'm writing my own method to be used in Rpart by defining the list of
functions named init, split and eval. I'm following the example given in the
file 'tests/usersplits.R' in the sources.
By now I'm able to define the split function (and it works correctly in the
tree construction) w
... or, similar in character to Gabor's solution:
tbl <- table(x)
(tbl[as.character(sort(x))]>1)+0
Bert Gunter
Nonclinical Biostatistics
467-7374
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Gabor Grothendieck
Sent: Thursday, M
I am not sure what you are trying to achive. How about:
df<-data.frame(kol1=c(2,9,4,3),kol2=c(5,6,6,2),kol3=c(9,6,5,1))
(df)
new.df<-df[(!(df[[1]] %in% 9)&!(df[[2]] %in% 9)&!(df[[3]] %in% 9)),]
(new.df)
But why would you want to delete all the valid values in all the other
columns if you have you
James W. MacDonald wrote:
> Wacek Kusnierczyk wrote:
>> do they make pompous claims about their software and disregarding claims
>> about others' as well?
>
> My mistake. I thought your concern was for the quality of the software
> (quality of course being defined by a certain committee of one). Bu
Dear R-list,
another question trying to build consensus cluster ;-)
Using the package "clue" I have found a method of building consensus
clusters the following way from one distance matrix:
clust1 <- c("ward", "single", "complete", "average", "mcquitty",
"median", "centroid")
clust_res <- lapply
Dear list,
I'd like to test the null hypothesis of independence in a 2*2
contingency table in a Bayesian way.
As far as I can see, this can be done by the function ctable in library
LearnBayes. (More precisely, a Bayes factor can be computed.)
Two questions:
1) Is there any other package/func
Wacek Kusnierczyk wrote:
do they make pompous claims about their software and disregarding claims
about others' as well?
My mistake. I thought your concern was for the quality of the software
(quality of course being defined by a certain committee of one). But it
appears this is of a more per
Hi all,
I have a 36x14 matrix of hexadecimal coded colors (see attached file) that
was created with the following code:
cellcol[is.na(cellcol)] <- "#00"
#Aliceblue
cellcol[cellcol < 5] <- "#F0F8FF"
#Skyblue1
cellcol[cellcol >= 5 & cellcol < 20] <- "#87CEFF"
#Blue
cellcol[cellcol >= 20 & cellc
If I want to install RWeka I get an error:
> library("RWeka")
Error occurred during initialization of VM
java.lang.OutOfMemoryError: unable to create new native thread
Could you have any idea to help me?
--
View this message in context:
http://www.nabble.com/I-can%27t-install-RWeka-tp23542141
I have a database like this:
"kol1";"kol2";"kol3" ...
"2";"5";"9"
"9";"6";"6"
"4";"6";"5"...
I looking for a kod in R which let mi aviod in column unnecessary value, for
example number "9".
So, if I have:
Kol1
2
9
4
4...
after loop in R I would like to get my column like this:
Kol1
2
4
4..
Good morning.
I want to estimate a mixture of two Weibull distribution by using the EM
algorithm .
Does it exist an available package to do that ?
Or if not, Is it some avaible EM Algorithm ?
Thanks
Cordially
Abdoul Aziz Junior NDOYE
GREQAM Marseille.
[[alternative HT
James W. MacDonald wrote:
>
>
> Wacek Kusnierczyk wrote:
>> (Ted Harding) wrote:
>>> On 14-May-09 12:27:40, Wacek Kusnierczyk wrote:
>>>
... but remember that sprintf introduces excel bugs into r (i.e.,
rounding is not done according to the IEC 60559 standard, see
?round):
>>
It is not recommended to plot variables on different scales on the same graph.
You can use something like par(mfrow=...) (see ?par) to stack graphs on top of
each other (or next to each other, or both) for easy comparison, but each with
their own scales/axes.
If you have considered all that an
Wacek Kusnierczyk wrote:
(Ted Harding) wrote:
On 14-May-09 12:27:40, Wacek Kusnierczyk wrote:
... but remember that sprintf introduces excel bugs into r (i.e.,
rounding is not done according to the IEC 60559 standard, see ?round):
ns = c(0.05, 0.15)
round(ns, 1)
# 0.0 0.2
(Ted Harding) wrote:
> On 14-May-09 12:27:40, Wacek Kusnierczyk wrote:
>
>>
>> ... but remember that sprintf introduces excel bugs into r (i.e.,
>> rounding is not done according to the IEC 60559 standard, see ?round):
>>
>> ns = c(0.05, 0.15)
>> round(ns, 1)
>> # 0.0 0.2
>> as.
Noting that:
> ave(x, x, FUN = length) > 1
[1] FALSE FALSE FALSE TRUE TRUE FALSE FALSE FALSE FALSE FALSE
try this:
> rbind(x, dup = ave(x, x, FUN = length) > 1)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
x 123445678 9
dup000
Erin Hodgess wrote:
Hi R People:
I have a question about setClass please. I'm working thru "R
Programming for Bioinformatics".
Actually, I was wondering if there is such a thing as an updateClass,
in order to change a "contains" option, please?
that is, if I had
setClass("dog",
representat
mau...@alice.it wrote:
I am trying to use the "kernel" function. To understand how it works I tried out some of the examples.
None of them works as shown in the following:
kernel("daniell", 50) #
Error in kernel("daniell", 50) : unused argument(s) (50)
which works for me. Have you
I have genetic data, and I would like to do an dissimilariry table of the
factorial analysis.
What package should I use and the command line?
Lassana TOURE
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
https:
Stefan Grosse wrote:
> Debbie Zhang schrieb:
>
>> Now, I am trying to obtain the sample variance (S^2) of the 1000 samples
>> that I have generated before.
>>
>> I am wondering what command I should use in order to get the sample variance
>> for all the 1000 samples.
>>
>>
>>
>> What I am ca
threshold wrote:
Hi, do you have any suggestions how to make 3D scatterplot, BUT under linux.
Worth mentioning is the fact that 'scatterplot3d' does not load under Ubuntu
8.10.
Why not? It is in pure R code, hence it is just as OS dependent as R itself.
Uwe Ligges
Do you know any alternat
Hi,
I am using rpart for my decision stump. I am trying to extract the learned
stump from the output of rpart.
For example:
cntrl <- rpart.control(maxdepth = 1, minsplit = learn-1,
maxsurrogate = 0, usesurrogate=0, maxcompete = 1,
cp = 0,
Axel Leroix wrote:
>
>
> Then I perform an lm regression using the following code:
> reg1 <-lm(data$prod~data$pri+data$cli)
> summary(reg1)
>
Use
reg1 <-lm(prod~pri+cli, data=data)
instead. It is not necessary to call the data frame you read your stuff into
"data", any more useful name,
Graves, Gregory wrote:
Thanks. But ... Still don't get it.
Referring explicitly to the monthname column which had many entries
across many years did not work. So taking your clue I created a new
variable list of names of month
month.name<-list(c("Jan", "Feb", "Mar", "Apr", "May", "Jun", "Ju
On 14-May-09 12:27:40, Wacek Kusnierczyk wrote:
> jim holtman wrote:
>> Depending on what you want to do, use 'sprintf':
>>
>>> x <- 1.23456789
>>> x
>> [1] 1.234568
>>
>>> as.character(x)
>> [1] "1.23456789"
>>
>>> sprintf("%.1f %.3f %.5f", x,x,x)
>> [1] "1.2 1.235 1.23457"
>>
> ... b
lehe wrote:
>
> I am using latex.table to write my results into a latex table. If my
> results is like a matrix except that some column has strings and others
> have numbers. Is it possible to feed my results into latex.table?
>
Such a matrix-like structure is called a dataframe. See latex in
Thanks. But ... Still don't get it.
Referring explicitly to the monthname column which had many entries
across many years did not work. So taking your clue I created a new
variable list of names of month
month.name<-list(c("Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul",
"Aug", "Sep", "Oct", "N
Since you got the most suitable way to get x, why can't you get the
variances in the same way? Just like:
v = vector()
for (i in 1:length(x)) v[i] = var(x[[i]])
BTW, it is much better to use lapply, like this:
lapply(x, var)
On Thu, May 14, 2009 at 8:26 PM, Debbie Zhang wrote:
>
> Thanks f
Another way of making functions visible to examples is to list the
package name as "Depends" in the package "DESCRIPTION" file.
Alternatively, if you precede use in "\examples" with
"library(packageName)", you should also list it as "Suggests" in
"DESCRIPTION".
Hope this helps.
Sp
-Original Message-
From: Uwe Ligges [mailto:lig...@statistik.tu-dortmund.de]
Sent: Thursday, May 14, 2009 4:44 AM
To: Nair, Murlidharan T
Cc: r-help@r-project.org
Subject: Re: [R] scatterplot3d
Nair, Murlidharan T wrote:
> Does anyone have any suggestion on this? I tried par(new="T")
Debbie Zhang schrieb:
> Now, I am trying to obtain the sample variance (S^2) of the 1000 samples that
> I have generated before.
>
> I am wondering what command I should use in order to get the sample variance
> for all the 1000 samples.
>
>
>
> What I am capable of doing now is just typing in
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