this is the code that i have so far:
> data.path <- file.path ("D:/documents/research/5 stations")
> setwd(data.path)
> getwd()
> data <- dir(".")
> num.files <- length(data)
> for(i in 1:num.files) {
+ station.id <- substring(data[i], 1,8)
+ DF <- read.table(data[i], sep=",", blank.lines.sk
So far, I cannot see any mistake, though the sep="" will be more
elegant that sep=",". Are you sure your working directory is
"E:/my_work_directory"? and is there any error msg?
BTW, a reproducible example will help to get better response from the list.
2009/2/18 CJ Rubio :
>
> thanks for your re
Dear List,
I am having problems running stepAIC with a negative binomial regression
model. I am working with data on manta ray abundance, using 20 predictor
variables. Predictors include variables for location (site), time (year, cos
and sin of calendar day, length of day, percent lunar illumi
thanks for your reply.. is there something wrong with the code i have?
because it doesn't write the file in the directory that i am using...
for (i in names(y))
> {write.csv(y[[i]], file=paste(i, ".csv", sep=","))}
thanks again..
ronggui-2 wrote:
>
> If the "file" is a relative path,
If the "file" is a relative path, then it should be in the working
directory. Say, the working directory is E:/my_work_directory (of
course, you can get it by getwd()), and you export a data frame "a" to
csv by:
write.csv(a, file="a.csv"), then the file should be
"E:/my_work_directory/a.csv".
Best
Stavros Macrakis alum.mit.edu> writes:
>
> Some minor improvements and corrections below
>
> # Simple weighted quantile
> #
> # v A vector of sortable observations
> # w A numeric vector of positive weights
> # p The quantile 0<=p<=1
> #
> # Nothing fancy: no interpolation etc.; NA cases not
i have a loop which looks likes this:
> data.info <- rbind(data.info, cbind(station.id, year, date,
> max.discharge))
+ y <- split(data.info, data.info[station.id])
+ for (i in names(y))
{write.csv(y[[i]], file=paste(i, ".csv", sep=","))}
i am wondering, where the file (which i am ab
Hi All,
If you have already finished reading my previous emails regarding
segmentation fault , please have a look at this .I think this may help you
to diagnose the reason for the segmentation fault and help me,because i
don't understand much.
Rather than running the script using the command "
s
Oops !! I had also included just one library in my script i.e RMySQL.So
sorry for the inconvenience:(
--
Thanks
Moumita
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEA
Hi All,
Wanted to add some more information ,regarding my problem.
configuration of teh OS and R:---
Linux 2.6.18-6-686
> R.Version()
$platform
[1] "i486-pc-linux-gnu"
$arch
[1] "i486"
$os
[1] "linux-gnu"
$system
[1] "i486, linux-gnu"
$status
[1] "Patched"
$major
[1] "2"
$minor
[1] "4.0"
$ye
Hi All,
Can anyone help me please?I don't know much about segmentation faults.I
understand what it is,but why my script's throwing the error i don't know.
This is my main function:
*main<-function()*
*{*
*dbName<-"xyz_database"*
*hostName<-"xyz.com"*
*
I am using some functions from package clusterSim to evaluate the best clusters
layout.
Here is the features vector I am using to cluater 12 signals:
> alpha.vec
[1] 0.8540039 0.8558350 0.8006592 0.8066406 0.8322754 0.8991699 0.8212891
[8] 0.8815918 0.9050293 0.9174194 0.8613281 0.8425293
In t
This is my situation:
I have a significant amount of data, and need to send it in pieces to R. I need
R to return certain parameters for further use.
I am sending files from C# (that are being queried from a database) into R.
Currently I am trying to use the R(D)-Com package to figure out how t
Some minor improvements and corrections below
# Simple weighted quantile
#
# v A vector of sortable observations
# w A numeric vector of positive weights
# p The quantile 0<=p<=1
#
# Nothing fancy: no interpolation etc.; NA cases not thought through
wquantile <- function(v,w=rep(1,length(v)),p
"Chinese extend a helping hand to Russians who happen to be in Brazil
about a package written in Germany," which gladdened an American.
Trotsky would be even more proud -- and amazed!! :-)
Regards,
Yihui
--
Yihui Xie
Phone: +86-(0)10-82509086 Fax: +86-(0)10-82509086
Mobile: +86-15810805877
Homep
Dear all,
I have a binned data that looks like this:
> dat
(-1,9] (9,19] (19,29] (29,39] (39,49] (49,59] (59,69] (69,79]
10063374 79 1643443
(79,89] (89,99]
62
I tried to plot a histogram overlayed with curve.
With th
Why I love R [Number 6]:
Chinese extend a helping hand to Russians who happen to be in Brazil
about a package written in Germany. Trotsky would be proud -- and
amazed!
url:www.econ.uiuc.edu/~rogerRoger Koenker
email rkoen...@uiuc.edu Departmen
Hi Uwe,
Thank you for your guidance. I have installed R2WinBUGS and WinBUGS14 under
wine. Using ?bugs for help, it tells me:
useWINE: logical; attempt to use the Wine emulator to run 'WinBUGS',
defaults to 'FALSE' on Windows, and 'TRUE' otherwise. Not available in
S-PLUS.
WINE: character, path
Maybe the suggestions here help:
http://cran.r-project.org/bin/windows/base/rw-FAQ.html#The-Internet-download-functions-fail_002e
On Tue, Feb 17, 2009 at 8:19 PM, Charles Annis, P.E.
wrote:
> Dear R-Helpers:
>
> I'm running R version 2.8.1 on a 1 year old HP Pavilion with a AMD Athelon
> 64 Dual
Gene Leynes wrote:
This is my first help post, hope it works!
Just check out the "sample" function
At the command line type:
?sample
I think it will be pretty clear from the documentation.
Yes, most excellent suggestion and quite helpful!
Thanks,
Esmail
_
This is my first help post, hope it works!
Just check out the "sample" function
At the command line type:
?sample
I think it will be pretty clear from the documentation.
On Tue, Feb 17, 2009 at 9:13 PM, Esmail Bonakdarian wrote:
> (sorry if this is a duplicate-problems with posting at my end)
>
You could 'split' the dataframe and then write out each element: something like
x <- split(data.info, data.info$station.id)
for (i in names(x)) write.csv(x[[i]], file=paste(i, ".csv", sep=""))
On Tue, Feb 17, 2009 at 10:11 PM, CJ Rubio wrote:
>
> it works perfectly thank you for your help...
(sorry if this is a duplicate-problems with posting at my end)
Hello all,
I need some help with a nice R-idiomatic and efficient solution to a
small problem.
Essentially, I am trying to eliminate randomly half of the entries in
a vector that contains index values into some other vectors.
Mo
it works perfectly thank you for your help
what if i want to seperate each stations data and save in a .csv file??
while i'm asking you these i'm also finding some ways to do so..
thank you again.
jholtman wrote:
>
> try using:
>
> data.info <- rbind(data.info, cbind(station.id, y
try using:
data.info <- rbind(data.info, cbind(station.id, year, date, max.discharge))
On Tue, Feb 17, 2009 at 9:26 PM, CJ Rubio wrote:
>
> i have the following constructed and running very well,, thanks to Gabor
> Grothendieck for his help.
>
>>data.info <- c("station.id", "year", "date", "max.
(1) you'll need ImageMagick installed to use the command "convert" to
convert image sequences into GIF animations; see ?movie3d
(2) "viewport" is read only!! see ?open3d carefully
Regards,
Yihui
--
Yihui Xie
Phone: +86-(0)10-82509086 Fax: +86-(0)10-82509086
Mobile: +86-15810805877
Homepage: http:
i have the following constructed and running very well,, thanks to Gabor
Grothendieck for his help.
>data.info <- c("station.id", "year", "date", "max.discharge")
>
> for(i in 1:num.files) {
+ station.id <- substring(data[i], 1,8)
+ DF <- read.table(data[i], sep=",", blank.lines.skip = TRUE)
+ z
Here is what I got for script through your third question:
set.seed(1)
x1 = rbinom(200,1,.5)
x2 = rbinom(200,1,.5)
differ = x1 != x2
differ.indexes = (1:length(x1))[differ == TRUE]
#you were unclear if you want to round up or round down on odd index of
differ.indexes
n = floor( length(d
Check out sum.exact and cumsum.exact in the caTools package.
> library(caTools)
Loading required package: bitops
> x <- 1/(12:14)
> sum(x) - cumsum(x)[3]
[1] 2.775558e-17
> sum.exact(x) - cumsum.exact(x)[3]
[1] 0
On Tue, Feb 17, 2009 at 5:12 PM, Stavros Macrakis wrote:
> I recently traced a bug
Dear R-Helpers:
I'm running R version 2.8.1 on a 1 year old HP Pavilion with a AMD Athelon
64 Dual Core Processor 4800+ 2.50GHz chip, Vista Home Premium SP1, and 2 GB
RAM. I can't add packages (even running as Administrator) because I can't
connect to a CRAN mirror.
> chooseCRANmirror()
(After
Hello all,
I need some help with a nice R-idiomatic and efficient solution to a
small problem.
Essentially, I am trying to eliminate randomly half of the entries in
a vector that contains index values into some other vectors.
More details:
I am working with two strings/vectors of 0s and 1s. T
Check out:
https://www.stat.math.ethz.ch/pipermail/r-help/2009-February/187562.html
On Tue, Feb 17, 2009 at 6:45 PM, Oliver Bandel
wrote:
> Hello,
>
>
> I tried to use ylim=c(x,y) in a plot.ts().
>
> This was ignored.
>
> How can I achieve it to create such graphics?
>
>
> Ciao,
> Oliver Bande
On 18/02/2009, at 12:51 PM, Laura Rodriguez Murillo wrote:
Hi dear list,
I wonder if somebody can help me with this. I have a text file with
300 rows and around 30 columns and I need to insert a column that
has the number 1 in every row. This new column should be placed
between columns 6 a
I wonder if an R package would have a function that calculates the following.
Let Y be a normal multivariate function. For example, let Y have 4
dimensions. I want to calculate
P(Y1 < Z1, Y2 < Z2, Y3 > Z3, Y4 > Z4).
There are R functions to do the calculation if all the inequalities
are of the t
On Tue, Feb 17, 2009 at 6:05 PM, Barry Rowlingson
wrote:
> 2009/2/17 Esmail Bonakdarian :
> When I need to use the two together, it's easiest with 'rpy'. This
> lets you call R functions from python, so you can do:
>
> from rpy import r
> r.hist(z)
wow .. that is pretty straight forward, I'll
Hi dear list,
I wonder if somebody can help me with this. I have a text file with
300 rows and around 30 columns and I need to insert a column that
has the number 1 in every row. This new column should be placed
between columns 6 and 7.
As an example: I would want to insert a column (consitin
Hello,
I tried to use ylim=c(x,y) in a plot.ts().
This was ignored.
How can I achieve it to create such graphics?
Ciao,
Oliver Bandel
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting g
I have the following dataframe:
ad <- data.frame(dates, av, sn$SectorName)
colnames(ad) <- c("Date", "Value", "Tag")
which has data (rows 10 to 20, for example) as follows:
DateValue Tag
10 2008-01-16-0.20875Co
Hello!
On Tue, Feb 17, 2009 at 5:58 PM, Warren Young wrote:
>
> Esmail Bonakdarian wrote:
>>
>> I am just wondering if any of you are doing most of your scripting
>> with Python instead of R's programming language and then calling
>> the relevant R functions as needed?
>
> No, but if I wanted to
2009/2/17 Esmail Bonakdarian :
> Hello all,
>
> I am just wondering if any of you are doing most of your scripting
> with Python instead of R's programming language and then calling
> the relevant R functions as needed?
I tend to use R in its native form for data analysis and modelling,
and pytho
Esmail Bonakdarian wrote:
I am just wondering if any of you are doing most of your scripting
with Python instead of R's programming language and then calling
the relevant R functions as needed?
No, but if I wanted to do such a thing, I'd look at Sage:
http://sagemath.org/
It'll give you acc
On Tue, Feb 17, 2009 at 10:00:40AM -0600, Marc Schwartz wrote:
> on 02/17/2009 09:06 AM Hans Ekbrand wrote:
> > Hi r-help!
> >
> > Consider the following data-frame:
> >
> >var1 var2 var3
> > 1 314
> > 2 223
> > 3 223
> > 4 44 NA
> > 5 4
Here is one kind of weighted quantile function.
The basic idea is very simple:
wquantile <- function( v, w, p )
{
v <- v[order(v)]
w <- w[order(v)]
v [ which.max( cumsum(w) / sum(w) >= p ) ]
}
With some more error-checking and general clean-up, it looks like this:
# Simple weigh
Hello all,
I am just wondering if any of you are doing most of your scripting
with Python instead of R's programming language and then calling
the relevant R functions as needed?
And if so, what is your experience with this and what sort of
software/library do you use in combination with Python
On 17/02/2009 5:31 PM, phoebe kong wrote:
Hi friends,
I have questions about printing a pretty big size matrix.
As you could see from below, the matrix wasn't showed in R at full size
(11X11), but it was cut partly into three smaller matrices (11X4,11X4,11X3).
I'm wondering if there is a way to
Hi friends,
I have questions about printing a pretty big size matrix.
As you could see from below, the matrix wasn't showed in R at full size
(11X11), but it was cut partly into three smaller matrices (11X4,11X4,11X3).
I'm wondering if there is a way to show the whole matrix with dimension
11X11,
On 17/02/2009 4:42 PM, mwestp...@worldbank.org wrote:
Hello:
I would like to sum every x columns of a dataframe for each row. For instance,
if x is 10, then for dataframe df, this function will sum the first ten elements
together and then the next ten:
sapply(list(colnames(df)[1:10], colnames(
I recently traced a bug of mine to the fact that cumsum(s)[length(s)]
is not always exactly equal to sum(s).
For example,
x<-1/(12:14)
sum(x) - cumsum(x)[3] => 2.8e-17
Floating-point addition is of course not exact, and in particular is
not associative, so there are various possible r
Alex Roy gmail.com> writes:
>
> Dear all ,
> Is there any subset regression (subset selection
> regression) package in R other than "leaps"?
Lars and Lasso are other 'subset selection' methods, see the corresponding
packages 'lars' and 'lasso2' and its description in The Elem
Hello:
I would like to sum every x columns of a dataframe for each row. For instance,
if x is 10, then for dataframe df, this function will sum the first ten elements
together and then the next ten:
sapply(list(colnames(df)[1:10], colnames(df)[11:20]),function(x)apply( df[,x],
1, sum))
If the
Dear R users,
I would like to fit cross classified or multiple membership logistic models
or a 3 level hierarchical logistic model using the Umacs package. Can anyone
advise me on how to proceed or better point me to examples of how its done.
Regards,
--
Luwis Diya,
Leuven Biostatistics and St
Hi Bob - your suggesting worked out great... Many thanks!
Also, thanks everyone for the other suggestions!
Bob McCall wrote:
>
> Look in the package "forecast" for the function "Arima". It will do what
> you want. It's different than arima function in the stats package.
> Bob
>
> Pele wrote
Alex Roy wrote:
>
> Dear all ,
> Is there any subset regression (subset selection
> regression) package in R other than "leaps"?
>
>
RSiteSearch("{subset regression}") doesn't turn up much other than
special-purpose tools for ARMA models etc.. What does leaps not do that y
this is the error message that I was getting
"In sink() ... : no sink to remove"
i got it to work . thanks for the help
David Winsemius wrote:
>
> " did not work."
>
> Might that mean errors? Care to share?
>
> Running that through my wetware R interpreter, I think I am seeing you
Thanks a lot for your help, it worked.
Greg Snow-2 wrote:
>
> The sink() command stops the sinking, so you send the lm output to the
> file, then stop the sinking before printing out the anova result. So the
> simplest thing to try is to put the first sink (with the filename and
> append=T)
url:www.econ.uiuc.edu/~rogerRoger Koenker
emailrkoen...@uiuc.eduDepartment of Economics
vox: 217-333-4558University of Illinois
fax: 217-244-6678Champaign, IL 61820
On Feb 17, 2009, at 1:58 PM, Brigid Mooney wrote:
Than
Thanks for pointing me to the quantreg package as a resource. I was hoping
to ask be able to address one quick follow-up question...
I get slightly different variants between using the rq funciton with formula
= mydata ~ 1 as I would if I ran the same data using the quantile function.
Example:
The sink() command stops the sinking, so you send the lm output to the file,
then stop the sinking before printing out the anova result. So the simplest
thing to try is to put the first sink (with the filename and append=T) before
you start the loop, remove all calls to sink within the loop, th
It should be in the datasets package that is automatically loaded with R (at
least my copy), try ?state and you should see the help for it and others.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
From: Alina Sheyman [mailto:ali
Thanks for the clarification.
I actually had MASS open to that page while
I was composing my reply but forgot to mention
it (trying to do too many things at once) ...
Ben Bolker
Prof Brian Ripley wrote:
> On Tue, 17 Feb 2009, Ben Bolker wrote:
>
>> Jessica L Hite/hitejl/O/VCU vcu.edu> writ
" did not work."
Might that mean errors? Care to share?
Running that through my wetware R interpreter, I think I am seeing you
ask for creation of models with variable outcomes from a the first 100
columns of "data". And then you are specifying a formula that includes
a weird mixture o
On Tue, 17 Feb 2009, Ben Bolker wrote:
Jessica L Hite/hitejl/O/VCU vcu.edu> writes:
I am attempting to run a glm with a binomial model to analyze proportion
data.
I have been following Crawley's book closely and am wondering if there is
an accepted standard for how much is too much overdisper
Hi guys,
I have a tricky problem that I'd appreciate your help with.
I have two categorical variables, say varA and varB and an associated
frequency Freq for combinations of the levels of varA and varB. This was
created with a table() call.
I'd now like to make panel plots of the frequency. I can
Thanks very much, exactly what I need.
Oliver
On Feb 16, 10:36 pm, Marc Schwartz wrote:
> on 02/16/2009 07:51 PM Oliver wrote:
>
>
>
> > hi,
>
> > I am a R beginner. One thing I notice is that when do graphing is,
>
> > if I want to draw two figures in a row such as this:
>
> > par(mfrow(1, 2))
Hi All,
I am trying to run several linear regressions and print out the summay and
the anova reslts on the top of
each other for each model. Below is a sample progarm that did not work. is
it possible to print the
anova below the summary of lm in one file?
thanks for your help
#
Hi,
I am getting an error compiling the R-devel on a suse architecture
64-bit architecture. The cp attribute is sending 'trusted.lov'
and an error. This is a sample of the output:
> make[3]: Entering directory
>`/lustre/people/schaffer/R-devel/src/library/base'
>building package 'base'
>make[4]
Thanks Greg,
do you know where i can find the sate.center dataset that you mention?
On Tue, Feb 17, 2009 at 12:28 PM, Greg Snow wrote:
> You need to give the symbols function the locations where you want the
> centers of the circles to be. Some datesets with map information also have
> center
Jessica L Hite/hitejl/O/VCU vcu.edu> writes:
> I am attempting to run a glm with a binomial model to analyze proportion
> data.
> I have been following Crawley's book closely and am wondering if there is
> an accepted standard for how much is too much overdispersion? (e.g. change
> in AIC has an
You need to give the symbols function the locations where you want the centers
of the circles to be. Some datesets with map information also have centers of
the states that you can use, for the USA, there is the state.center dataset
that may work for you, or the maptools package function get.Pc
I do know that Harrell's Quantile function in the Hmisc package will
allow quantile estimates from models. Whether it is general enough to
extend to time series, I have no experience and cannot say.
--
David Winsemius
On Feb 17, 2009, at 11:57 AM, Brigid Mooney wrote:
Hi All,
I am lookin
> Hello list,
>
> I am sorry for the previous half post. I accidentily hit send. Thanks
> again in advance for any help.
>
> I have many (approx 20) files that I have merged. Each data set contains
> rows for individuals and data in 2 - 5 columns (depending upon which data
> set). The individua
It is a issue specific to 0.8-32 and some files (most likely those
with some (not all) Windows codepages declared).
We are trying to collect together some examples, and will update
foreign accordingly later in the week.
On Tue, 17 Feb 2009, Harry Haupt wrote:
Hi,
after updating to foreign
Hello list,
Thanks in advance for any help.
I have many (approx 20) files that I have merged. For example
d1<-read.csv("AlleleReport.csv")
d2<-read.csv("AlleleReport.csv")
m1 <- merge(d1, d2, by = c("IND", intersect(colnames(d1), colnames(d2))),
all = TRUE)
m2 <- merge(m1, d3, by = c("IND",
Two places that have worked examples leap to mind:
--- Sarkar's online accompaniment to his book:
http://lmdvr.r-forge.r-project.org/figures/figures.html
Thumbing through the hard copy I see Figure 6.5 might of interest.
--- Addicted to R's graphics gallery:
http://addictedtor.free.fr/graphiques
Hi All,
I am looking at applications of percentiles to time sequenced data. I had
just been using the quantile function to get percentiles over various
periods, but am more interested in if there is an accepted (and/or
R-implemented) method to apply weighting to the data so as to weigh recent
dat
Paul Heinrich Dietrich wrote:
Hi all,
I've managed to get JAGS working on my Ubuntu Hardy Linux with a 32-bit
computer and AMD processors using R 2.8.1. JAGS is great. I've read that
JAGS is the fastest, but that hasn't been my experience. At any rate, I
have more experience with WinBUGS und
see auto.arima in the forecast package.
On Tue, Feb 17, 2009 at 10:20 AM, emj83 wrote:
>
> is there some sort of R function which can advise me of the best ARIMA(p,q,r)
> model to use based on the Schwarz criterion e.g for e.g p=0-5, q =0, r=0-5
> or for example p+r< 5???
>
> or is this something
I'm trying to create a fairly basic map using R. What i want to get is the
map of the country with circles representing a count of students in each
state.
What I've done so far is as following -
map("state")
symbols(data1$count,circles=log(data1$count)*3,fg=col,bg=col,add=T,inches=F)
this gives
Hoi Bart,
I think you're right that ALS should be applicable to this problem.
Unfortunately in writing I see that there is a bug when the spectra are
NOT constrained to nonnegative values (the package has been used to my
knowledge only in fitting multiway mass spectra thus far, where this
constrai
Hi Dylan, Chuck,
Mark Difford wrote:
>> Coming to your question [?] about how to generate the kind of contrasts
>> that Patrick wanted
>> using contrast.Design. Well, it is not that straightforward, though I may
>> have missed
>> something in the documentation to the function. In the past I hav
Hi Bernhard,
I'm wondering what you will expect to get in "dividing" two proportional
survival curves from a fitted cox model.
Anyway, you can provide a newdata object to the survfit function
containing any combination of cofactors you are interested in and then
use summary, eg:
fit <- coxph(
Hi all,
I've managed to get JAGS working on my Ubuntu Hardy Linux with a 32-bit
computer and AMD processors using R 2.8.1. JAGS is great. I've read that
JAGS is the fastest, but that hasn't been my experience. At any rate, I
have more experience with WinBUGS under Windows and would like a versi
is there some sort of R function which can advise me of the best ARIMA(p,q,r)
model to use based on the Schwarz criterion e.g for e.g p=0-5, q =0, r=0-5
or for example p+r< 5???
or is this something I will have to write my own code for?
Thanks Emma
--
View this message in context:
http://www.n
On 2/17/2009 10:55 AM, mau...@alice.it wrote:
A couple of weeks ago I asked how it is possible to run an R script (not a
function) passing some parameters.
Someone suggested the function "commandArgs()".
I read the on-line help and found no clarifying example. Therefore I do not
know how to use
Peter Dalgaard wrote:
>
> Yes, something in the logic appears to have gotten garbled.
>
> It's in this part of read,spss:
>
> if (is.character(reencode)) {
> cp <- reencode
> reencode <- TRUE
> }
> else if (codepage <= 500 || codepage >= 2000) {
> attr(rval,
Try this:
A <- 1
B <- 2
C <- 3
source("myfile.R")
Now the code in myfile can access A, B and C.
On Tue, Feb 17, 2009 at 10:55 AM, wrote:
> A couple of weeks ago I asked how it is possible to run an R script (not a
> function) passing some parameters.
> Someone suggested the function "commandA
I seriously doubt that a survfit object could only contain that
information. I suspect that you are erroneously thinking that what
print.survfit offers is the entire story.
What does str(survfit(, data=) ) show you?
> data(aml)
> aml.mdl <- survfit(Surv(time, status) ~ x, data=aml)
# this is
Hi,
is it possible to wrap a text using Hershey fonts? "\n" does not work!
Thanks in advance,
Martina
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-g
Prof Ripley:
Many thanks - it did indeed say it cannot find fGarch after I tried your
advice - but a completely clean re-install did the trick.
John
On Tue, Feb 17, 2009 at 1:09 AM, Prof Brian Ripley wrote:
> Start R with --vanilla, or rename youe saved workspace (.RData).
> Then
>
> library(fG
on 02/17/2009 09:06 AM Hans Ekbrand wrote:
> Hi r-help!
>
> Consider the following data-frame:
>
>var1 var2 var3
> 1 314
> 2 223
> 3 223
> 4 44 NA
> 5 435
> 6 223
> 7 343
>
> How can I get R to convert
A couple of weeks ago I asked how it is possible to run an R script (not a
function) passing some parameters.
Someone suggested the function "commandArgs()".
I read the on-line help and found no clarifying example. Therefore I do not
know how to use it appropriately.
I noticed this function retur
Harry Haupt wrote:
> Hi,
> after updating to foreign version 0.8-32, I experienced the following error
> when I tried to load a SPSS file:
>
> Fehler in inherits(x, "factor") : objekt "cp" nicht gefunden
> Zusätzlich: Warning message:
> In read.spss("***l.sav", use.value.labels = TRUE, to.data.fra
Hi,
See ?survfit.object
if fit is the object you get using survfit,
fit$surv will give you the survival probability.
Best,
arthur
Bernhard Reinhardt wrote:
Hi!
I came across R just a few days ago since I was looking for a toolbox
for cox-regression.
I´ve read
"Cox Proportional-Hazards Reg
Hi!
I came across R just a few days ago since I was looking for a toolbox
for cox-regression.
I´ve read
"Cox Proportional-Hazards Regression for Survival Data
Appendix to An R and S-PLUS Companion to Applied Regression" from John Fox.
As described therein plotting survival-functions works wel
Ok,
I feel properly ashamed. I suppose my "real" data is a little bit different
than my toy data (although i don't know how) because i did try the merge
function as simple as merge(t1, t2) and did not work. Maybe a reset of my
session will solve my problems and more coffee my confusion.
Ag
This is on the Mac FAQ:
http://cran.cnr.berkeley.edu/bin/macosx/RMacOSX-FAQ.html#How-can-R-for-Mac-OS-X-be-uninstalled_003f
HTH,
--sundar
On Tue, Feb 17, 2009 at 7:17 AM, ANJAN PURKAYASTHA
wrote:
> I need to uninstall R 2.7.1 from my Mac. What is the best way to uninstall
> it? Simply delete t
Hi Monica,
merge(t1, t2) works on your example. So why don't you use merge?
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature
and Forest
Cel biometrie, methodolo
I need to uninstall R 2.7.1 from my Mac. What is the best way to uninstall
it? Simply delete the R icon in the Applications folder?
Or is it more involved?
TIA,
Anjan
--
=
anjan purkayastha, phd
bioinformatics analyst
whitehead institute for biomedical research
nine ca
Hi,
after updating to foreign version 0.8-32, I experienced the following error
when I tried to load a SPSS file:
Fehler in inherits(x, "factor") : objekt "cp" nicht gefunden
Zusätzlich: Warning message:
In read.spss("***l.sav", use.value.labels = TRUE, to.data.frame = TRUE) :
***.sav: File-ind
Try merge(t1, t2)
On Tue, Feb 17, 2009 at 9:33 AM, Monica Pisica wrote:
>
> Hello list,
>
> I am wondering if a joining "one-to-many" can be done a little bit easier. I
> tried merge function but I was not able to do it, so I end up using for and
> if.
>
> Suppose you have a table with locatio
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