one could also use package distr; e.g.,
library(distr)
x <- 1:10
D <- DiscreteDistribution(x)
## => r, d, p and q functions (also with log-argument)
r(D)(5)
p(D)(4)
d(D)(1)
q(D)(0.3)
Best,
Matthias
roger koenker wrote:
Sure, but it would be more 'fun' to modify ecdf() slightly to produce
an e
On Wed, 7 Jan 2009, Gundala Viswanath wrote:
Dear all,
Does R has any function that measures how much
memory hold by any particular object?
- Gundala Viswanath
Jakarta - Indonesia
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/lis
Dear all,
Does R has any function that measures how much
memory hold by any particular object?
- Gundala Viswanath
Jakarta - Indonesia
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide ht
Dear all,
I'm trying to fit a statistical model to series of measurements.
Unfortunately, my knowledge of statistics is rather limited, so I'm a
bit at loss of what is going on with the model.
First of all, I've prepared a histogram. Then, I've tried to fit a Poisson
model to express the relatio
Hi all,
Is it possible to manipulate the properties of an active graph?
I'm trying to manipulate the plots generated by extRemes into something
suitable for a report, but the only change I can make successfully is add lines
( abline(v=2) ). For example, I'd like to be able to use standard ins
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Charles C. Berry wrote:
> On Wed, 7 Jan 2009, Nathan S. Watson-Haigh wrote:
>
> I'm trying to understand some C code in an R package I'm using. I'm address
> this question here as
> it's matrix algebra...and I'm no pro at that!
>
> the C command rea
On Wed, 7 Jan 2009, Nathan S. Watson-Haigh wrote:
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I'm trying to understand some C code in an R package I'm using. I'm address
this question here as
it's matrix algebra...and I'm no pro at that!
the C command reads:
double alpha = 1.0, beta = 0.0;
On Tue, 6 Jan 2009, Spencer Graves wrote:
Hi, All:
How can I get the list of files contained in a zip file?
"zip.file.extract" will extract a specific 'file' from 'zipname', but
how can I get the names of the files in 'zipname'?
Package Rcompression will I believe allow you to do this
sqldf has some facilities for Date class but has no knowledge of date class.
See example 7b on home page: http://sqldf.googlecode.com
and here is a second example:
> DF <- data.frame(D = as.Date(c("21DEC2006","15DEC2006"), "%d%b%Y"))
> DF
D
1 2006-12-21
2 2006-12-15
> sqldf("select * f
On Wed, Jan 7, 2009 at 11:05 AM, ajay ohri wrote:
>
> FYI..not a R -Help Topic, buy I dont know which list to post discussions like
> this.
> Regards,
> Ajay
>
> -- Forwarded message --
> From: ajay ohri
> Date: Wed, Jan 7, 2009 at 10:46 AM
> Subject: Re: R "Threatens" SAS, Acco
Hi, All:
How can I get the list of files contained in a zip file?
"zip.file.extract" will extract a specific 'file' from 'zipname',
but how can I get the names of the files in 'zipname'?
Thanks,
Spencer
__
R-help@r-project.org
Hi,
I hope to show a heatmap with thre colours, no gradation. How to specify
heatmap.2 to map "green" for values less than -1, "gray" for values between
-1 and 1, and "red" for values greater than 1 ?
Thanks
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__
In this case, how about?
dimnames(mdat) <- NULL
Gundala Viswanath wrote:
Dear all,
I have the following structure of a matrix
str(mdat)
num [1:32268, 1:10] 0 0 0 0 0 0 0 0 0 0 ...
- attr(*, "dimnames")=List of 2
..$ : NULL
..$ : NULL
How can I destroy the attributes such that it simp
on 01/06/2009 09:07 PM jimdare wrote:
> Hi Everyone,
>
> Have created a bar plot of the data below using the following code:
> barplot(TACC,space=0,names.arg=Year). I now want to add a series of
> connected points to represent the catch. I tried to do this using
> line(Catch) or points(Catch), h
Dear all,
I have the following structure of a matrix
> str(mdat)
num [1:32268, 1:10] 0 0 0 0 0 0 0 0 0 0 ...
- attr(*, "dimnames")=List of 2
..$ : NULL
..$ : NULL
How can I destroy the attributes such that it simply
gives:
> str(mdat)
num [1:32268, 1:10] 0 0 0 0 0 0 0 0 0 0 ...
- Gundal
Hi Everyone,
Have created a bar plot of the data below using the following code:
barplot(TACC,space=0,names.arg=Year). I now want to add a series of
connected points to represent the catch. I tried to do this using
line(Catch) or points(Catch), however both of these commands result in each
data
I would too.
On Tue, Jan 6, 2009 at 8:17 PM, Ben Bolker wrote:
> Christophe Genolini u-paris10.fr> writes:
>
>>
>> Hi the list,
>>
>> I wrote a tutorial about S4. Is it possible to have a link to it in the
>> page "Contributed Documentation" or "R Documentation" on the CRAN web
>> site ? Who sha
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I'm trying to understand some C code in an R package I'm using. I'm address
this question here as
it's matrix algebra...and I'm no pro at that!
the C command reads:
double alpha = 1.0, beta = 0.0;
dsyrk_("L", "N", nGenes, nGenes, & alpha, mat1, nGen
? `break`
On Tue, Jan 6, 2009 at 7:58 PM, kayj wrote:
> I was wondering if there is anything that breaks a loop in R
>
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
try this:
L3 <- LETTERS[1:3]
x=c(1,1,2,2,3,3,4,4,5,5)
y=1:10
d <- data.frame(cbind(x,y), fac=I(sample(L3, 10, replace=TRUE)))
m.out <- matrix(ncol=10, nrow=10)
m.out[cbind(d$x, d$y)] <- d$fac
On Tue, Jan 6, 2009 at 3:29 AM, wrote:
> Dear Sir or Madam,
>
> I have the following data frame (which
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andrew wrote:
> the SparseM package might be what you are looking for
>
> http://www.econ.uiuc.edu/~roger/research/sparse/SparseM.pdf
>
> On Jan 7, 11:36 am, Søren Højsgaard wrote:
>> You can do
>> mat[lower.tri(mat, diag=F)]
>> Søren
>>
Thanks, al
something like this should do it:
breakFlag <- FALSE
For (k in 1:100)
For ( i in 1:10){
If ( condition ){
breakFlag <- TRUE
break
}
}
if (breakFlag) break
}
On Tue, Jan 6, 2009 at 7:58 PM, kayj wrote:
>
> Hi All,
>
> I was wondering if there
Hi All,
I was wondering if there is anything that breaks a loop in R. For example,
For (k in 1:100)
For ( i in 1:10){
If ( condition ){
Break the inner loop
}
}
}
In the above case, if the program runs the if statement, then I want the
inner loop for (i in 1:10) to stop looping and skip t
First of all, I apologize for misleading you by mentioning irrelevant error
message. Forget about the error message I stated in the first place. I
should have clearly stated in the first place. No error message was shown at
the moment of the problem. Without any warnings and error message shown, m
the SparseM package might be what you are looking for
http://www.econ.uiuc.edu/~roger/research/sparse/SparseM.pdf
On Jan 7, 11:36 am, Søren Højsgaard wrote:
> You can do
> mat[lower.tri(mat, diag=F)]
> Søren
>
>
>
> Fra: r-help-boun...@r-project.org på vegne af N
Daren Tan hotmail.com> writes:
> I have developed some scripts that basically ask for input tab-limited
format files, do some processing,
> and output several pictures or csv. Now I need to have some gui to wrap on
top of the scripts, so that
> end-users can select their input files, adjust s
See also the dist() function documentation.
If you use indexing as described in ?dist
it is straightforward to maintain and
use a vector of the distances.
Steven McKinney
Statistician
Molecular Oncology and Breast Cancer Program
British Columbia Cancer Research Centre
email: smckinney +at+ bccrc
Christophe Genolini u-paris10.fr> writes:
>
> Hi the list,
>
> I wrote a tutorial about S4. Is it possible to have a link to it in the
> page "Contributed Documentation" or "R Documentation" on the CRAN web
> site ? Who shall I contact ?
>
> Christophe
Try c...@r-project.org . Posting to
My goal is to store the DWT coefficients from a number of time series in such a
way to be able to extract subsets satisfying giben conditions.
I have defined the following 11 matrices whose x-axis represent time intervals
and y-axis represent the number of time series:
MS <- 11 d1.mat <-
You can do
mat[lower.tri(mat, diag=F)]
Søren
Fra: r-help-boun...@r-project.org på vegne af Nathan S. Watson-Haigh
Sendt: on 07-01-2009 01:28
Til: r-help@r-project.org
Emne: [R] Memory Efficiency of Symmetric Matrix
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If you want the same network each time, then set the random seed to
the same value:
n<-6
dat <- rbinom(n*(n-1)/2,1,.6)
net<-diag(n)
net[lower.tri(net)] <- dat
net[upper.tri(net)] <- t( net )[upper.tri(net)]
net #the network
library(network)
g<-network(net,directed=FALSE)
set.seed(1)
plot.network(g
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I'm generating a symmetric correlation matrix using a data matrix as input:
mat <- cor(data.mat)
My question is:
Is there a more memory efficient way to store this data? For instance, since:
all(mat == t(mat))
every value is duplicated, and I should b
Nit-picking about syntax does seem needed, mea culpa, I
intended something more like:
Qn <- ecqf(x)
Qn(runif(whatever))
On Jan 6, 2009, at 5:06 PM, roger koenker wrote:
Sure, but it would be more 'fun' to modify ecdf() slightly to produce
an ecqf() function -- essentially rev
Sure, but it would be more 'fun' to modify ecdf() slightly to produce
an ecqf() function -- essentially reversing the arguments to
approxfun()--
and then use
ecqf(runif(whatever))
no nit-picking about efficiency, please.
url:www.econ.uiuc.edu/~rogerRoger Koenker
ema
Thank you. That's exactly what I was looking for.
Antonio, Fabio Di Narzo wrote:
>
> If the ecdf is 'ecdf(x)', do just:
>> sample(x, size=whatever, replace=TRUE)
>
> HTH,
> Antonio.
>
> 2009/1/6 culpritNr1 :
>>
>> Hi All,
>>
>> Does anybody know if there is a simple way to draw numbers from
the empirical distribution gives probability 1/n to each of n observations.
rather than sampling the unit interval, just resample the dataset.
If x is your dataset, and you want an independent sample of size k,
sample(x,size=k,replace=TRUE)
albyn
On Tue, Jan 06, 2009 at 02:39:17PM -0800,
If the ecdf is 'ecdf(x)', do just:
> sample(x, size=whatever, replace=TRUE)
HTH,
Antonio.
2009/1/6 culpritNr1 :
>
> Hi All,
>
> Does anybody know if there is a simple way to draw numbers from an empirical
> distribution?
>
> I know that I can plot the empirical cumulative distribution function th
Hi All,
Does anybody know if there is a simple way to draw numbers from an empirical
distribution?
I know that I can plot the empirical cumulative distribution function this
easy:
plot(ecdf(x))
Now I want to pick a number between 0 and 1 and go back to domain of x.
Sounds simple to me.
Any sug
Hi,
I am using the function plot.network from the network library. However, I
noticed that every time when I use the function I get a different layout (the
network is rotated?). I would like to get the exact same picture every time
when I use the function. Is that possible (maybe set a seed or s
Dear Anthony,
As I said, the sem package won't do multiple-group analysis. I would like at
some point to add multiple-group analysis to the capabilities of the package
but I can't say when I might find time to do that.
Sorry,
John
--
John Fox, Professor
Department of
Hi the list,
I wrote a tutorial about S4. Is it possible to have a link to it in the
page "Contributed Documentation" or "R Documentation" on the CRAN web
site ? Who shall I contact ?
Christophe
__
R-help@r-project.org mailing list
https://stat.eth
Hi John-
Thanks for responding so quickly. Love the package by the way.
I am using R sem to model fMRI data, and I want to compare models
between conditions (i.e., to see if there is a significant difference
between specific path coefficients of two models). I believe this
amounts to what is
Thanks a lot for the suggestions, Jorge and Satoshi Takahama! Both
approaches work well...
Gang
On Tue, Jan 6, 2009 at 2:12 PM, Satoshi Takahama wrote:
> Perhaps you can convert your matrices to data frames as in:
>
> mapply(t.test,as.data.frame(myData1),as.data.frame(myData2))
> to test by colu
On 1/6/09, Assaf oron wrote:
> Hi all,
>
> I want to create a rather standard overlaid qqnorm plot on a single
> variable, with different subgroups of the same dataset plotted using
> different colors/symbols/etc. (I don't want side-by-side, rather
> different-colored curves on the same graph)
Dear Anthony,
I'm not sure what you mean by a "stacked model comparison." If you mean a
model fit to multiple groups, then the answer is no. If you mean comparison
of nested models, then anova() can be used to get a LR test. See ?anova.sem.
I hope this helps,
John
--
Hi all,
I want to create a rather standard overlaid qqnorm plot on a single
variable, with different subgroups of the same dataset plotted using
different colors/symbols/etc. (I don't want side-by-side, rather
different-colored curves on the same graph)
I managed to do it rather tediously using "
Does anyone know if the sem package in R can implement a stacked model
comparison, for example as in LISREL or AMOS?
Thanks,
Anthony
--
Anthony Steven Dick, Ph.D.
Post-Doctoral Fellow
Human Neuroscience Laboratory
Department of Neurology
The University of Chicago
5841 S. Maryland Ave. MC-2030
Perhaps you can convert your matrices to data frames as in:
mapply(t.test,as.data.frame(myData1),as.data.frame(myData2))
to test by column and
mapply(t.test,as.data.frame(t(myData1)),as.data.frame(t(myData2)))
to test by row?
- Original Message
From: Gang Chen
To: Henrique Dallazuan
Thanks for your help!
I combined the above two to get the following, which seems to work (if
somewhat inelegant):
int.List<-unlist(lapply(lmList, function(x) {coef(x)[1]}),use.names=FALSE)
lmList is my list of lm objects.
-Allen
David Winsemius wrote:
>
>
> On Jan 6, 2009, at 1:50 PM, Al
On Tue, 6 Jan 2009, Sake wrote:
Hi,
I'm heaving difficulties with a dataset containing gene names and positions
of those genes.
Not such a big problem, but each gene has multiple exons so it's hard to say
where de gene starts and where it ends. I want the starting and ending
position of each g
Hello,
I am having trouble with retrieving some data in queries involve with variables
with data type "date". See the enclosed example:
ll<-c("21DEC2006","15DEC2006")
ss<-data.frame(ll)
ss<-transform(ss,ll=as.date(as.character(ll)))
(ss)
ll
1 17156
2 17150
tt<-sqldf("select ll from ss")
(t
On Tue, 06-Jan-2009 at 04:27PM +, Luis Ridao Cruz wrote:
|> R-help,
|>
|> I'm using the "for" control flow to graph plots continuously:
|>
|> par(mfrow=c(3,5), mar=c(0.6,.2,1.2,.2),yaxt="n",xaxt="n")
|> for(j in 1:11)
|> {
|> for(i in 1:15)
|> {
|>
|> species <- spAldur[spAldur$ar ==
On Jan 6, 2009, at 1:50 PM, AllenL wrote:
1. I have a list of lm (linear model) objects. Is it possible to
select,
through subscripts, a particular element (say, the intercept) from
all the
models? I've tried something like this:
?coef
if your list of models is ml, then perhaps somethin
1. I have a list of lm (linear model) objects. Is it possible to select,
through subscripts, a particular element (say, the intercept) from all the
models? I've tried something like this:
List[[1:length(list)]][1]
All members of the list are similar. My goal is to have a list of the
intercepts an
On Tue, 6 Jan 2009, Troels Ring wrote:
Thanks a lot -
windows(record=TRUE) seems to do the job.
If you want to control an already open graphics device you will need
the R-devel version, which has a function msgWindow() to change a lot of
settings, including 'record'.
Sorry not to have fo
Hi Gang,
Perhaps this post might be useful in this case. Please take a special
lookat Gábor
Csárdi's reply.
http://www.nabble.com/apply,-t-test-and-p-values-to20012292.html#a20012292
HTH,
Jorge
On Tue, Jan 6, 2009 at 1:10 PM, Gang Chen wrote:
> Thanks a lot for the quick help!
>
> mapply() s
Folks:
I am getting duplicate messages on posts. Please correct my details if I'm
wrong, but I believe it's because folks are posting to **both** the
addresses, r-help@r-project.org and r-h...@stat.math.eth.ch . I believe the
first is just an alias for the second, and that's why the suplicate po
Thanks a lot for the quick help!
mapply() seems promising. However, mapply(t.test, myData1, myData2)
would not work, so how can I specify the margin in mapply() which
function t.test() will be applied over? For example, I specify the 2nd
dimension (column) in apply(myData1, 2, t.test) to run one-s
Bellow, you can see the R data.
But this stucks even in first line (read.table..).
I dont know how to calculate this and write the result into a new table.
Edwin
data <- read.table("test.data")
data <- subset(data, (data$Zusatz!="60") & (data$Zusatz!="0"))
list(EndpointKeepAliveTim
I think that you can use mapply for this.
On Tue, Jan 6, 2009 at 3:24 PM, Gang Chen wrote:
> I can run one-sample t-test on an array, for example a matrix myData1,
> with the following
>
> apply(myData1, 2, t.test)
>
> Is there a similar fashion using apply() or something else to run
> 2-sample
I can run one-sample t-test on an array, for example a matrix myData1,
with the following
apply(myData1, 2, t.test)
Is there a similar fashion using apply() or something else to run
2-sample t-test with datasets from two groups, myData1 and myData2,
without looping?
TIA,
Gang
__
Increase the memory as much as you can, read in the data, (however long it
takes) then aggregate the data into smaller chunks, selecting only the bits
you want.
Remove the big original data set from memory (using rm()) and keep (or save
the smaller aggregated data using wite.table())
If this
For the mean, min, max and standard deviance (deviation I suppose) you
don't need to store all data in the memory, you can calculate them
incrementally. Read the file line by line (if it is a text file).
G.
On Tue, Jan 6, 2009 at 6:10 PM, Edwin Sendjaja wrote:
> Hi Ben,
>
> Using colClasses doen
The sqldf R package can import a file into an sqlite database and
extract a portion of it. You basically need two statements:
one to specify the name and format of the file and one to specify what
you want to extract. See home page at:
http://sqldf.googlecode.com
On Tue, Jan 6, 2009 at 12:10 PM,
Hi Ben,
Using colClasses doensnt improve the performace much.
With the data, I will calculate the mean, min, max, and standard deviance.
I have also failed to import the data in a Mysql Database. I dont have much
knowledge in Mysql.
Edwin
> Edwin Sendjaja web.de> writes:
> > Hi Simon,
> >
Just in case anyone is still interested, here are some
comparisons of the time it says to compute grouped medians
via sapply(split(x,group),median) and gm(x,group), which
uses the trick used by rle() to find the first and last
entries in each group.
Which method is fastest depends on the nature of
Hi Simons,
Is SAS more powerfull than R?
Well, I think I cannot afford to buy SAS.
actually, my computer isn't really slow. I think 4GB RAM is big enough for
personal PC. I am just wondering, why R running so slow with these specs to
handling 3 GB data set. What if the data set were 1 TB?mm
I have two specific questions regarding the output of lda function in MASS.
#Question1:
#=
n: sample size, p: number of variables
Some articles in the literature say that LDA is singular
for p > n-1. However, my experimentation with lda (default arguments) for
two class problems shows c
Thanks a lot -
windows(record=TRUE) seems to do the job.
Sorry not to have found it.
Troels
jim holtman skrev:
?windows
On Tue, Jan 6, 2009 at 10:44 AM, Troels Ring wrote:
Hi, I'm using windows xp and R 2.8.0 - I wonder what is the command to put
in a script that has the same effect as whe
Hi all,
I'm trying to draw a contour plot
with rounded (smoothed) contour lines instead of sharp angles;
when the grid consists of only a few points
in x- and y- axis, the resulting contour
is in facts rather ugly since very sharp angles may appear.
I did not find any way to do it,
by using eith
Another thing to try is placing Sweave.sty in the same directory
as your .Rnw file and experiment with and without
\usepackage{Sweave}
in your .Rnw file.
On Tue, Jan 6, 2009 at 11:39 AM, Duncan Murdoch wrote:
> Your example works for me. I'd guess there's a problem with the way you
> handled S
?windows
On Tue, Jan 6, 2009 at 10:44 AM, Troels Ring wrote:
> Hi, I'm using windows xp and R 2.8.0 - I wonder what is the command to put
> in a script that has the same effect as when in a plot you choose menu
> "History" and "Recording".
> Best wishes
> Troels
>
> --
>
> Troels Ring - -
> Depar
One other suggestion: use the SweavePDFMikTex function from patchDVI
(available on http://r-forge.r-project.org/projects/sweavesearch) to
handle both the Sweave call, and the pdflatex call.
Duncan Murdoch
__
R-help@r-project.org mailing list
https:/
Hi,
I am not very knowledgeable about this kind of stuff but my guess is that if
you have a fairly slow computer and massive data sets there isnt alot you
can do except get a better computer, buy more RAM or use something like SAS
instead?
Hopefully someone else will chip in Edwin, best of l
Terry Therneau schrieb:
> Apologies -- you are being more subtle than I thought. Nevertheless, I think
> that the censoring language isn't quite right.
>
> You are thinking of a hierarchical model:
>
> z ~ N(Xb, sigma), where Xb is the linear predictor, whatever covariates
> you
> thin
Your example works for me. I'd guess there's a problem with the way you
handled Sweave.sty, but I don't really know what it would be. Can't you
tell MikTex to use the Sweave file from its original location, using
-include_directory?
Duncan Murdoch
On 1/6/2009 10:48 AM, Mr Derik wrote:
Than
On Tue, Jan 06, 2009 at 07:21:48AM -0800, Sake wrote:
> I'm heaving difficulties with a dataset containing gene names and positions
> of those genes.
> Not such a big problem, but each gene has multiple exons so it's hard to say
> where de gene starts and where it ends. I want the starting and endi
> I'm heaving difficulties with a dataset containing gene names and
positions
> of those genes.
> Not such a big problem, but each gene has multiple exons so it's hard to
say
> where de gene starts and where it ends. I want the starting and ending
> position of each gene in my dataset.
> Attached
R-help,
I'm using the "for" control flow to graph plots continuously:
par(mfrow=c(3,5), mar=c(0.6,.2,1.2,.2),yaxt="n",xaxt="n")
for(j in 1:11)
{
for(i in 1:15)
{
species <- spAldur[spAldur$ar == 1993+i & spAldur$aldur == j,]
plot(spec...@coords[,1], spec...@coords[,2], xlim=c(-10,-3.5),
Hi,
I am currently using solve.QP from the quadprog package to solve some
quadratic optimization problems of the form:
min[ -d'b + (1/2) b'Db ] under constraints A'b >= b_0
solve.QP appears to use an implementation of the Goldfarb and Idnani
algorithm. I now have a problem of this form where the
Dear Jason,
Have a look at scale_y_continuous() and scale_fill_discrete(). This might work
(untested as your example is not reproducible with a (dummy) dataset).
qplot(Age, data = recerts_combined_values, binwidth = 5, fill =
combined_values$Test.Type, main="Combined Age Histogram") +
scale_x_
Thanks for replying.
I'm working on a windows XP sp3 PC.
I am trying to run the test file provided by R at the moment:
% -*- mode: noweb; noweb-default-code-mode: R-mode; -*-
\documentclass[a4paper]{article}
\title{A Test File}
Hi, I'm using windows xp and R 2.8.0 - I wonder what is the command to
put in a script that has the same effect as when in a plot you choose
menu "History" and "Recording".
Best wishes
Troels
--
Troels Ring - -
Department of nephrology - -
Aalborg Hospital 9100 Aalborg, Denmark - -
+45 99326
Dear Sarah,
Thank you a lot,
It does exactly what I need.
By the way, I tried doing what Prof. Ripley suggested I just was not able to
get it right - I am pretty new to this after all.
Thank again,
Herwig
Sarah Goslee wrote:
>
> You didn't do what Prof. Ripley suggested - adding a ... argumen
Hi,
I'm heaving difficulties with a dataset containing gene names and positions
of those genes.
Not such a big problem, but each gene has multiple exons so it's hard to say
where de gene starts and where it ends. I want the starting and ending
position of each gene in my dataset.
Attached is the
Hi,
I have developed some scripts that basically ask for input tab-limited format
files, do some processing, and output several pictures or csv. Now I need to
have some gui to wrap on top of the scripts, so that end-users can select their
input files, adjust some parameters for processing, a
Great advice. I did a quick read and came up with the following:
qplot(Age, data = recerts_combined_values, binwidth = 5,
fill = combined_values$Test.Type,
ylab="Counts", xlab="Age, months",
main="Combined Age Histogram",
legend.name = "Type of Tests")
U
Edwin Sendjaja web.de> writes:
>
> Hi Simon,
>
> My RAM is only 3.2 GB (actually it should be 4 GB, but my Motherboard doesnt
> support it.
>
> R use almost of all my RAM and half of my swap. I think memory.limit will not
> solve my problem. It seems that I need RAM.
>
> Unfortunately, I
You didn't do what Prof. Ripley suggested - adding a ... argument.
Here's a crude version of what you want; I'm sure there's a more elegant
solution for passing the needed data to the panel function.
panel.cor <- function(x, y, digits=2, prefix="", splitvar, col.cor, ...)
{
usr <- par("usr");
Hi Simon,
My RAM is only 3.2 GB (actually it should be 4 GB, but my Motherboard doesnt
support it.
R use almost of all my RAM and half of my swap. I think memory.limit will not
solve my problem. It seems that I need RAM.
Unfortunately, I can't buy more RAM.
Why R is slow reading big data se
Magnus zulutime.net> writes:
>
> I have a simulation program that generates a data frame for each run. I
> aggregate the data.frames into a list (df.list). The structure of all data
> frames is the same, only the values are different.
>
> I then want to aggregate the various runs. Currently
On 1/6/2009 6:44 AM, Mr Derik wrote:
Hello
I have been setting up my computer to run Sweave. I have got the whole thing
working on example files, except that my MikTex returns an "Undefined
Control Sequence" error for \Sexpr and my output file contains verbatim code
sequences at the apropriate p
Yup, it was a typo. But I always try capital if lower case doesnt work,
Sorry.
- Original Message -
From: "David Winsemius"
To: "Simon Pickett"
Cc: "Edwin Sendjaja" ;
Sent: Tuesday, January 06, 2009 12:40 PM
Subject: Re: [R] Large Dataset
When I do it on a Mac installation I ge
Try this:
unname(dat)
On Tue, Jan 6, 2009 at 6:14 AM, Gundala Viswanath wrote:
> Dear all,
>
> I have the following matrix.
>
> > dat
> A A A A A A A A A A
>[1,] 0 0 0 0 0 0 0 0 0 0
>[2,] 0 0 0 0 0 0 0 0 0 1
>[3,] 0 0 0 0 0 0 0 0 0 2
>
> How can I change it into:
> [,
Only a couple of weeks ago I had to deal with this.
adjust the memory limit as follows, although you might not want 4000, that
is quite high
memory.limit(size = 4000)
Simon.
- Original Message -
From: "Edwin Sendjaja"
To: "Simon Pickett"
Cc:
Sent: Tuesday, January 06, 2009 1
I have a simulation program that generates a data frame for each run. I
aggregate the data.frames into a list (df.list). The structure of all data
frames is the same, only the values are different.
I then want to aggregate the various runs. Currently I use the following
method (for three runs
Dear Gundala,
Try this:
# Original matrix
set.seed(123)
X=matrix(rnorm(100),ncol=10)
colnames(X)<-paste('X',1:10,sep="")
X
# No headers
colnames(X)<-NULL
X
HTH,
Jorge
On Tue, Jan 6, 2009 at 3:14 AM, Gundala Viswanath wrote:
> Dear all,
>
> I have the following matrix.
>
> > dat
> A A
Hi guys,
Have done something like this:---
#Looping through each set of elements of the correlation
cross product combinations and collecting datatsets for those elements
for(corr_combs_counter in 1:1)
{
rowval_corr_combs<-corr_c
Hello
I have been setting up my computer to run Sweave. I have got the whole thing
working on example files, except that my MikTex returns an "Undefined
Control Sequence" error for \Sexpr and my output file contains verbatim code
sequences at the apropriate point in the text rather than the R out
Valentina Kraus wrote:
> Unfortunately, I need add=T because there are many other things in the graph.
>
> I could swear that it worked 2 years ago.
It can't have worked. Axis settings are fixed before you start adding
things. Presumably you used xlim, xaxs et al. on one of the previous
commands
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