Hi,
Thanks for that.
the way I tried is as follows:
1) Downloaded the r-base package
2) went in that directory where the r-base package was downloaded from
command line
3) entered the command
sudo apt-get install r-base
But got the error, that Couldn't find r-base command.
I don't underst
On Tue, 12 Aug 2008, Jeffrey Horner wrote:
Christophe Dutang1 wrote:
Hi,
I'm currently R porting SF Mersenne Twister algorithm of Matsumoto and
Saito. To get the full power of their code, I want to use their fonction
fill_array32 which need aligned memory. That is to say I need to use the C
On Tue, Aug 12, 2008 at 9:24 PM, Shreyasee Pradhan
<[EMAIL PROTECTED]> wrote:
> Hi,
>
> I am running Ubuntu on my Windows OS through VMware.
> I am trying to install R in Ubuntu, but not getting with those commands,
> which are there on the site.
> Can anyone please tell me how to install it, stepw
stephen sefick wrote:
To update a package on CRAN I just update all of the version
information stuff etc. and then upload it to the ftp site?
Stephen Sefick
Yes, just build the package and submit it to CRAN as before, but with an
increased version number.
Uwe Ligges
_
Please see the footer of this message: we need to know what you did.
Also, SAS may have made some assumptions for you without telling you (for
example used a numerically ill-conditioned covariance matrix), and we
don't know what you did in SAS, either.
On Tue, 12 Aug 2008, Pedro Mardones wrot
On Wed, 2008-07-30 at 16:40 -0700, Deepayan Sarkar wrote:
> Does the rendering improve if you unset the "smooth line art" option
> in Acrobat's settings?
Yes, it does! Thanks.
There still is a problem, though, in that the charts so generated won't
display and print well for users with the default
It's a feature and it's been there forever. (It's even present in
another system not unlike R.)
Suppose you set
y <- matrix(1:3)
and construct
dfr <- data.frame(x=1:3, y)
Then you invoke the constructor function, data.frame, which by default
simplifies things like matrices to single columns,
Hi,
I am running Ubuntu on my Windows OS through VMware.
I am trying to install R in Ubuntu, but not getting with those commands,
which are there on the site.
Can anyone please tell me how to install it, stepwise, with commands to be
used.
As I m new to Ubuntu as well, I am not aware of the comman
First consider using a list:
test <- list()
for (i in 1:10) test[[i]] <- i
If you really want to create variables, then look at "assign"
for (i in 1:10) assign(paste("test.", i, sep=""), i)
On Tue, Aug 12, 2008 at 7:49 PM, Gareth Campbell <[EMAIL PROTECTED]> wrote:
> Hi there,
>
> I know this i
See help(list) and help("[[") ...and 'An Introduction to R'.
/Henrik
On Tue, Aug 12, 2008 at 7:49 PM, Gareth Campbell <[EMAIL PROTECTED]> wrote:
> Hi there,
>
> I know this is probably a really simple question, but without the correct
> keywords, or knowledge of the correct function it is hard to
To simplify:
n <- 2.7e6;
x <- factor(c(rep("A", n/2), rep("B", n/2)));
# Identify 'A':s
t1 <- system.time(res <- which(x == "A"));
# To compare a factor to a string, the factor is in practice
# coerced to a character vector.
t2 <- system.time(res <- which(as.character(x) == "A"));
# Interesting
Dear R-users;
Previously I posted a question about the problem of rank deficiency in
summary.manova. As somebody suggested, I'm attaching a small part of
the data set.
#***
"test" <-
structure(.Data = list(structure(.Data = c(rep(1,3),rep(2,18),re
Christophe Dutang1 wrote:
Hi,
I'm currently R porting SF Mersenne Twister algorithm of Matsumoto and
Saito. To get the full power of their code, I want to use their fonction
fill_array32 which need aligned memory. That is to say I need to use the
C function memalign on windows, posix_memalign
On Tue, 12 Aug 2008, stephen sefick wrote:
I have been reading this thread and I am having a hard interpreting
what these mean. I know that the result is that all of the values
that are zero in a are replaced by NA. Let me try and write it out
is.na(a[a==0] ) <- TRUE
you pull out of a all of
Hi there,
I know this is probably a really simple question, but without the correct
keywords, or knowledge of the correct function it is hard to search for on
the net or within R.
How do I increment a dataframe (or similar) name within a loop and assign
data?
A simple example would be:
for(i in
The help page for is.na()
is worth reading repeatedly.
> -Original Message-
> From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED]
> On Behalf Of stephen sefick
> Sent: Tuesday, August 12, 2008 6:53 PM
> To: Charles C. Berry
> Cc: Mike Prager; [EMAIL PROTECTED]
> Subject: Re: [R] ignori
Hmmm... the short answer is that your call to png() is requiring X11 to
generate the plot. Don't know what version you're running, but prior to
R 2.7.0, all png() calls needed access to the X server to create the
plots (on Unix). But with 2.7.0 and later, png() can be called with
type='cairo' t
Emmanuel,
On Tue, Aug 12, 2008 at 4:35 PM, Emmanuel Levy <[EMAIL PROTECTED]> wrote:
> Dear All,
>
> I have a large data frame ( 270 lines and 14 columns), and I would like to
> extract the information in a particular way illustrated below:
>
>
> Given a data frame "df":
>
>> col1=sample(c(0,1)
Hello,
Is this a bug or a feature? I am using R 2.7.1 on Apple OS X.
> y <- matrix(1:3,nrow=3) # y is a single-column matrix
> df <-data.frame(x=1:3,y=y)
> sapply(df,data.class)
x y
"numeric" "numeric"
> df$yy <- y
> sapply(df,data.class)
x yyy
"numeric
I have been reading this thread and I am having a hard interpreting
what these mean. I know that the result is that all of the values
that are zero in a are replaced by NA. Let me try and write it out
is.na(a[a==0] ) <- TRUE
you pull out of a all of the times that are equal to zero then is.na
te
With AutoIt [http://www.autoitscript.com/] you can setup scripts that
send keyboard and mouse events, wait for windows to open and more. It
is quite powerful.
/Henrik
On Tue, Aug 12, 2008 at 4:51 AM, <[EMAIL PROTECTED]> wrote:
> OK thanks, Tolga
>
>
>
> Prof Brian Ripley <[EMAIL PROTECTED]>
> 1
forecast must be quoted:
install.packages("forecast")
and in this case its actually part of the forecasting bundle so we
could also do this:
install.packages("forecasting")
Look at ?install.packages and note the way it works for different values of
the dependencies argument.
On Tue, Aug 12, 20
I initially input the following commands, and got the corresponding errors:
install.packages(forecast)
Error in install.packages(forecast) : object "forecast" not found
> library(forecast)
Error in library(forecast) : there is no package called 'forecast'
I was finally able to get it installed
Dear All,
I have a large data frame ( 270 lines and 14 columns), and I would like to
extract the information in a particular way illustrated below:
Given a data frame "df":
> col1=sample(c(0,1),10, rep=T)
> names = factor(c(rep("A",5),rep("B",5)))
> df = data.frame(names,col1)
> df
names
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of warthog29
> Sent: Tuesday, August 12, 2008 3:40 PM
> To: r-help@r-project.org
> Subject: [R] arima forecast function
>
>
> hi:
>
> I am trying to fit prediction intervals for an arima object.
> My s
hi:
I am trying to fit prediction intervals for an arima object. My search led
me to the link:
http://finzi.psych.upenn.edu/R/library/forecast/html/forecast.Arima.html
which has the function "forecast", as I wanted. However, when I try to run
it in R, I get the message:
Error in plot(forecast(
On Tue, 12 Aug 2008, Mike Prager wrote:
rcoder <[EMAIL PROTECTED]> wrote:
I have a matrix that has a combination of zeros and NAs. When I perform
certain calculations on the matrix, the zeros generate "Inf" values. Is
there a way to either convert the zeros in the matrix to NAs, or only
perfor
2008/8/12 Aiste Aistike <[EMAIL PROTECTED]>:
> Hello,
>
> I have a problem with using read.csv(). I want to read a table from the ONS
> neighborhood statistics website which has an address:
>
> http://www.neighbourhood.statistics.gov.uk/dissemination/LeadTableView.do?a=3&b=5940246&c=Stoke&d=14&e=7&
hi giov
about the dixon test... i just run a simple test with a sample of 40 and I
got:
Error in dixon.test(x) : Sample size must be in range 3-30
So it seems that most of the test in the "outliers" package are designed for
small samples. See also the Rnews article published in May 2006 (vol 6/
Hi
John P. Burkett wrote:
> My aim is to create a figure consisting of three maps: Alaska in the
> upper left corner, the 48 contiguous US states in the center right, and
> Hawaii in the lower left corner. In some ways the figure I'm trying to
> create is analogous to figure 1.5 in Paul Murre
Hi,
I'm currently R porting SF Mersenne Twister algorithm of Matsumoto and
Saito. To get the full power of their code, I want to use their
fonction fill_array32 which need aligned memory. That is to say I need
to use the C function memalign on windows, posix_memalign on linux and
classic
Hey everyone,
I'm part of a team working at NOAA and we have developed a swan script that
analyzes data and generates plots for the forecasters. We are ready to put
the script on the cron and call it a summer but a technical issue has popped
up which has us puzzled.
When we run the script as an
# between (a,b)
a <- 0
b <- 1
x <- rnorm(10)
x
unclass(cut(x, breaks=c(-Inf,a,b,Inf)))==2
-gary
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Shubha Vishwanath Karanth
Sent: Tuesday, August 12, 2008 7:46 AM
To: [EMAIL PROTECTED]
Subject: [R] Between the
rcoder <[EMAIL PROTECTED]> wrote:
> I have a matrix that has a combination of zeros and NAs. When I perform
> certain calculations on the matrix, the zeros generate "Inf" values. Is
> there a way to either convert the zeros in the matrix to NAs, or only
> perform the calculations if not zero (i.e.
It can be done like this with strapply in gsubfn. See home
page at http://gsubfn.googlecode.com . strapply is like
apply except the string to be operated on replaces the
matrix and the regexp replaces the margin number
and the function can be omitted if you are only returning
one item.Its like
Exactly what are you asking? Can you provide an example of the output
you would expect.
On Tue, Aug 12, 2008 at 1:21 AM, Hesen Peng <[EMAIL PROTECTED]> wrote:
> Hi all,
>
> I wonder if there is a way to create a matrix with two (or even more)
> column/row names? Thank you very much.
>
> Have a ni
Hello,
I have a problem with using read.csv(). I want to read a table from the ONS
neighborhood statistics website which has an address:
http://www.neighbourhood.statistics.gov.uk/dissemination/LeadTableView.do?a=3&b=5940246&c=Stoke&d=14&e=7&f=73&g=401878&i=1001x1003x1004x1005&l=145&o=1&m=0&r=1&s
Dear all;
working with a 'fat' data set (700 variables / 50 samples) and trying
to run a manova test on it (I'm aware that it's not the best option
for this kind of data set) I got the error in the summary.manova
function about the rank of the residuals (rank < # variables). Ok. The
thing that I do
Will this do it:
> fileName<-"Agg.20.20.20-all-01"
> sub(".*\\.(\\d+\\.\\d+\\.\\d+).*", "\\1", fileName, perl=TRUE)
[1] "20.20.20"
> sub(".*-([^-]+)-.*", "\\1", fileName, perl=TRUE)
[1] "all"
>
On Tue, Aug 12, 2008 at 4:18 PM, <[EMAIL PROTECTED]> wrote:
> I have a string such as
>
> fileName<-"
You need to store the result of the summary function:
> sfit <- summary(fit)
Then look at the structure of the sfit (or whatever you call it) object
(depending on the fit, it may be different). You can do this with the 'str'
function or the 'TkListView' function in the TeachingDemos package fo
I have a string such as
fileName<-"Agg.20.20.20-all-01".
All I want to do is pull the "20.20.20" and the "all" as strings.
Obviously, they aren't always those values.
The "20.20.20" can be "30.30.30" but it's always after the . which is
next to the second g in Agg and it's always the same len
Try this:
col2rgb("#2C312C")
On Tue, Aug 12, 2008 at 4:22 PM, rostam shahname
<[EMAIL PROTECTED]> wrote:
> Hi,
> I have three matrices, Red, Green and Blue. I would like to produce a matrix
> which is the combined values of Red, Green and Blue matrices.
> I know rgb() does the job, but the value
?C, ?contrasts, ?options (section on contrasts), ?contr.sum
Hope that helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
(801) 408-8111
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Adam Gr
Great, that works. Thank you.
Mark
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Tue 8/12/2008 2:49 PM
To: Altaweel, Mark R.
Cc: [EMAIL PROTECTED]; r-help@r-project.org
Subject: RE: [R] Parsing array data
Hi: you can do
result<-lapply(agg, function(.df) {
Hi: you can do
result<-lapply(agg, function(.df) {
mean(.df$Discharge)
})
this will give you the mean of the Discharge column in the various
dataframes. aggregate s used more when you want to do calculations
on various subset by another variable. if you want to do that, you can.
like say ther
To update a package on CRAN I just update all of the version
information stuff etc. and then upload it to the ftp site?
Stephen Sefick
--
Let's not spend our time and resources thinking about things that are
so little or so large that all they really do for us is puff us up and
make us feel like
Hi,
I have three matrices, Red, Green and Blue. I would like to produce a matrix
which is the combined values of Red, Green and Blue matrices.
I know rgb() does the job, but the values are not between 0-255, they are in
the following format:
"#2C312C"
I would like to have the values between 0-255.
On Tue, 12 Aug 2008, Ben Bolker wrote:
jimineep hotmail.com> writes:
Hi guys,
I want to create variable on the fly: for example
for (i in 1:10) {
cat(paste("VAR",i,sep=""))
}
Will print VAR1, VAR2 etc up to VAR10. However I want to make these into
variables, and then give them a value
Dear Daniel,
Are you really interested on the analyzis of the effect of ML on Grup, our
on the effect of Grup on ML?
I reproduce your sample database, but "changed" some Grup values from 1 to 2
to allow an analysis of variance.
See the example below.
Vale!
miltinho astronaura
Brazil
GBM<-re
when you read it in na.string=0
On Tue, Aug 12, 2008 at 1:43 PM, rcoder <[EMAIL PROTECTED]> wrote:
>
> Hi everyone,
>
> I have a matrix that has a combination of zeros and NAs. When I perform
> certain calculations on the matrix, the zeros generate "Inf" values. Is
> there a way to either convert
Since as long as I can remember, on Windows there is something called
"Alt [Key Numeric] Codes", which allows you to enter many symbols that
are not directly accessible via a single key, cf.
http://en.wikipedia.org/wiki/Alt_codes
For lists of Alt codes, see for instance
http://www.usefulshor
You are trying to do ANOVA on a categorical response.
How can I solve this?
Use a more appropriate model. Did you mean ML to be the response and Grup
the group rather than v.v.? Then try
aov(ML ~ Grup, data = GBM)
On Tue, 12 Aug 2008, Dani Valverde wrote:
Hello,
I am trying to perform
On Tue, 12 Aug 2008, Nazareno Andrade wrote:
Thanks for both answers. I'll look into that.
I understand I can take do a qualitative evaluation of the fits using visual
tests, but a problem I have is that I'd like to quantify in how many out of
hundreds of downloads each model fits better the da
Hi,
Great, that does solve most of my problem.
I loaded the files, and did this: a <-agg[[1]]
meanD=mean(a[['Discharge']]) # returning the mean of the variable discharge for
the first data element in agg
Now, if I wanted to get the mean or just aggregate the variable "Discharge" of
the entire
I'm sure this is an easy thing to do, but I can't seem to get it right. My
first question is: Is there a way to set the intercept of a glm to be an
overall average of the response variable, as opposed to the coefficient
for a particular term.
For example, let's say there are 2 variables (1 an
Hello,
I am trying to perform an ANOVA on a dataframe like this:
ID Grup ML PC
mI Gly Glx
X373.txt 11 0.004685889 0.05994939 0.004589104 0.007144027
0.02042549
X373bis.txt 21 0.004685889 0.0599494 0
See the reference on ?aov, and MASS (the book, see the FAQ).
I think you need to understand the underlying theory first, and that is no
longer (even for my time) part of a statistical education. I learnt it
from Bill Venables who has educated in the 1960s -- so his account in MASS
comes with
XLSolutions Corporation (www.xlsolutions-corp.com) is proud to announce
our*** R/Splus Fundamentals and Programming Techniques***course at 3 USA
locations for September 2008.
(1) R/Splus Fundamentals and Programming Techniques
http://www.xlsolutions-corp.com/Rfund.htm
* San Francisco
I presume that your problem is in quantitative macroeconomics and
that your sample size is limited. Are your variables stationary. If
not you may need to use a VECM or if there is no cointegration work in
first differences.
My choice of variables would in the first instance be determined by
eco
John Poulsen zoo.ufl.edu> writes:
>
> Hello,
>
> I am trying to create a dotplot, and have run into a couple of snags
> with the finishing details. The below code creates the dotplot, but I
> cannot figure out how to: 1) change the color of the CI bars to black,
> not blue, 2) delete the
Hello all,
Does anyone know of any good resources on specifying
anova models in R with aov. I particular, I am
interesting in the details and functioning of the
Error() structure. I could not find anything in the
documentation and help(Error) bounced me into the
aov() help pages.
Thank you.
Br
You can compare non-nested nls fits using the AIC command. Although
that does not give a formal hypothesis test there are rules of thumb for
using the AIC.
On Tue, Aug 12, 2008 at 2:13 AM, Nazareno Andrade
<[EMAIL PROTECTED]> wrote:
> Dear R-helpers,
>
> I am trying to check whether a model of the
Hi everyone,
I have a matrix that has a combination of zeros and NAs. When I perform
certain calculations on the matrix, the zeros generate "Inf" values. Is
there a way to either convert the zeros in the matrix to NAs, or only
perform the calculations if not zero (i.e. like using something simila
Thanks for both answers. I'll look into that.
I understand I can take do a qualitative evaluation of the fits using visual
tests, but a problem I have is that I'd like to quantify in how many out of
hundreds of downloads each model fits better the data. I have some a
hypothesis that there are two
Dear List,
I have had problems inserting some (not all !) figures via odfWeave
(using print(someLatticeFunction)...). The figure was correctly
displayed in a R device window but the resulting ODF document displayed
the correct space for the figure and an empty frame with a "broken
image" icon and
Hi,
I read in csv files with the following code:
res <- vector(mode="list",length=3)
for(i in 1: length(res))
res[[i]]<-read.csv(file=paste("/Users/markaltaweel/Desktop/Output/HydroDataOutput",i,".csv",sep=""),header=T,sep=",")
This allows me to load the data into an array of length 3, with the
Dear List,
I have had problems inserting some (not all !) figures via odfWeave
(using print(someLatticeFunction)...). The figure was correctly
displayed in a R device window but the resulting ODF document displayed
the correct space for the figure and an empty frame with a "broken
image" icon and
On Tue, 12 Aug 2008, Michael R. Head wrote:
On Tue, 2008-08-12 at 14:11 +0100, Prof Brian Ripley wrote:
On Tue, 12 Aug 2008, Michael R. Head wrote:
On Tue, 2008-08-12 at 07:15 -0400, Martin Henry H. Stevens wrote:
Thanks Henrique. We need to use the tilde in formula statements as in,
lm(y ~
Hello,
I am trying to create a dotplot, and have run into a couple of snags
with the finishing details. The below code creates the dotplot, but I
cannot figure out how to: 1) change the color of the CI bars to black,
not blue, 2) delete the horizontal dotplot lines, and 3) arrange the
parame
On Tue, 2008-08-12 at 14:11 +0100, Prof Brian Ripley wrote:
> On Tue, 12 Aug 2008, Michael R. Head wrote:
>
> > On Tue, 2008-08-12 at 07:15 -0400, Martin Henry H. Stevens wrote:
> >> Thanks Henrique. We need to use the tilde in formula statements as in,
> >> lm(y ~ x)
> >>
> >> Any ideas?
> >
> >
To add to Brian's points (which you should heed!) -- you **may** find it
also useful to look at (possibly smoothed) residuals to compare lack of fit
from your alternative models. If any shows up, some subject matter knowledge
might lead you to choose one or the other of your models -- or neither.
(sorry if this arrives multiple times, I sent it from the wrong email
address to the r-help the first time)
Thanks for both answers. I'll look into that.
I understand I can take do a qualitative evaluation of the fits using
visual tests, but a problem I have is that I'd like to quantify in how
ma
SQL has a between operator and via sqldf you can do this using
the built in data frame BOD as an example:
> library(sqldf)
> BOD
Time demand
118.3
22 10.3
33 19.0
44 16.0
55 15.6
67 19.8
> sqldf("select demand between 15 and 17 from BOD")
demand between 15
imicola wrote:
Sorry, this is probably quite an easy question, but I'm new to R and couldn't
find the answer anywhere.
I'm using geoR and geoRglm, but can't figure out how to get a border in my
geodata object. Does this need to be defined when I'm importing my data, or
afterwards, and how do I
On Tue, 12 Aug 2008, Bachas wrote:
I have half a solution:
bitmap(file="filename.jpg",type="jpeg"); works to generate a jpeg file.
However, I want my plots to be stored in single jpeg files and I can't get
this to work:
bitmap(file="Rplot%03d.jpg",onefile=FALSE,type="jpeg");
it overwrites my R
jimineep hotmail.com> writes:
>
>
> Hi guys,
>
> I want to create variable on the fly: for example
>
> for (i in 1:10) {
> cat(paste("VAR",i,sep=""))
> }
> Will print VAR1, VAR2 etc up to VAR10. However I want to make these into
> variables, and then give them a value, for example:
>
> v
Hi all,
I got another VAR question here and really appreciate if somebody would help me
out :)
I have five time series, say A,B,C,D,E. My objective is to predict the series A
using the rest, that is, B, C, D and E. A Vector Autoregression Model should
work here. But first of all, I should select
I had the same problem and my conclusion was also that the problem was that
our server was not running an X server.
I also found that bitmap(file="filename.jpg",type="jpeg"); works.. However
I want to store my plots in single jpeg files.. Unfortunately
bitmap(file="Rplot%03d.jpeg",onefile=FALSE,t
> eval(parse(text = "iris[iris$Sepal.Width > 4,]"))
Sepal.Length Sepal.Width Petal.Length Petal.Width Species
16 5.7 4.4 1.5 0.4 setosa
33 5.2 4.1 1.5 0.1 setosa
34 5.5 4.2 1.4 0.2 setosa
>
On Tue, 12 Aug 2008, jimineep wrote:
Hi guys,
I want to create variable on the fly: for example
See
?assign
HTH,
Chuck
for (i in 1:10) {
cat(paste("VAR",i,sep=""))
}
Will print VAR1, VAR2 etc up to VAR10. However I want to make these into
variables, and then give them a val
Jamie Ledingham wrote:
becomes too much to handle by the time the loop reaches 170. Has anyone
had any experience of this problem before? Is it possible to 'wipe' R's
memory at the end of each loop - all results are plotted and saved or
written to text file at the end of each loop so this may b
On Tue, 12 Aug 2008, Shubha Vishwanath Karanth wrote:
ThanksDidn't mean actually using '&', but not bigger than that too...
I usually see something done much better in R-help by a code which I don't know
at all. So, wanted to know if I am missing somewhere in using some codes which
I am n
The code I posted does work if you use it as I explained, not
as you changed it. Executing strings is probably not a very
R-ish thing to do but if that's your aim use eval and parse:
s <- "iris["iris$Sepal.Width > 4,]"
eval(parse(text = s))
On Tue, Aug 12, 2008 at 10:35 AM, Dries Knapen <[EMAIL
You should set environment variables in the environment, not from a
program. See rw-FAQ Q2.15 (and you may be able to set them in Eclipse
before it starts R).
On Tue, 12 Aug 2008, Sergey Goriatchev wrote:
I tried with Sys.setenv() in Eclipse environment in the following manner:
Sys.getenv(
Dries Knapen-2 wrote:
>
> Hi,
>
> Thanks for your reply. However, this didn't work exactly as I needed
> it to since the expression is dynamically built as a character vector
>
> i.e. not executed as
> e <- expression(Sepal.Width > 4)
>
> but as
> e <- expression("Sepal.Width > 4")
>
> in
> vect = c(10:20)
> for (i in 1:10) {
+ assign(paste("VAR",i,sep=""), vect[i])
+ }
> VAR1
[1] 10
> VAR2
[1] 11
2008/8/12 jimineep <[EMAIL PROTECTED]>
>
> Hi guys,
>
> I want to create variable on the fly: for example
>
> for (i in 1:10) {
>cat(paste("VAR",i,sep=""))
> }
> Will print VAR1,
?assign , or consider a named vector/list.
jimineep wrote:
Hi guys,
I want to create variable on the fly: for example
for (i in 1:10) {
cat(paste("VAR",i,sep=""))
}
Will print VAR1, VAR2 etc up to VAR10. However I want to make these into
variables, and then give them a value, for example:
Sorry, this is probably quite an easy question, but I'm new to R and couldn't
find the answer anywhere.
I'm using geoR and geoRglm, but can't figure out how to get a border in my
geodata object. Does this need to be defined when I'm importing my data, or
afterwards, and how do I go about doing t
On 12 Aug 2008, at 17:00, Gabor Grothendieck wrote:
Executing strings is probably not a very
R-ish thing to do
I know - but as far as I can see there was no other way around in
this case...
but if that's your aim use eval and parse:
s <- "iris["iris$Sepal.Width > 4,]"
eval(parse(text = s
I have half a solution:
bitmap(file="filename.jpg",type="jpeg"); works to generate a jpeg file.
However, I want my plots to be stored in single jpeg files and I can't get
this to work:
bitmap(file="Rplot%03d.jpg",onefile=FALSE,type="jpeg");
it overwrites my Rplot001.jpg file.
Any one additional
thanks petr,
i try it out and get back to you in case of problems.
cheers,
lukas
Von: Petr PIKAL [mailto:[EMAIL PROTECTED]
Gesendet: Di 12.08.2008 13:18
An: Indermaur Lukas
Cc: [EMAIL PROTECTED]
Betreff: Odp: [R] biplot_group_colours_and_point_symbols
Hi
[EMAI
I tried with Sys.setenv() in Eclipse environment in the following manner:
> Sys.getenv("LANGUAGE")
LANGUAGE
""
> Sys.setenv(LANGUAGE="en")
> Sys.getenv("LANGUAGE")
LANGUAGE
"en"
Once I've done this at the beginning of the session, warnings are in English.
When I exit Eclipse and then re
Hi guys,
I want to create variable on the fly: for example
for (i in 1:10) {
cat(paste("VAR",i,sep=""))
}
Will print VAR1, VAR2 etc up to VAR10. However I want to make these into
variables, and then give them a value, for example:
vect = c(10:20)
for (i in 1:10) {
cat(paste("VAR",i,sep
Hi all,
A two part quick question regarding gls
1) I'd like to pass a formula to gnls from a gam(mgcv package). Is there
a quick way to do this? I tried using
>gnls(gam$call$formula, data=df, correlation=AC1) but it keeps
outputting a message to the effect that I need x ~ y etc as the formula
I have the same problem. I am using R on our bioinformatics server. From what
I have read jpeg() needs to use a widows graphics device like X11 to be able
to generate a jpeg file.
I am also very curious to see if anyone knows a solution, now I need to use
pdf() of ps() which is more time consuming
Running R version 2.6.1 under Gentoo Linux and using the fPortfolio
package, I am having trouble specifying a sector constraint. One of the
constraints to be imposed is that assets 1 and 2 together account for no
more than 13.63% of the portfolio. My attempt at coding that
constraint, "maxsumW
Hello R users,
I would like to use an integer and a date as attributes in sqlQuery,
and these arguments
are defined in my function.
I guess this is clearer comparing to my first post.
Here is my function:
GetReturn<-function(code,date)
{
db<-"C:/Test.mdb"
channel<-odbcConnectAccess(db)
ssql<
Andreas Tille <[EMAIL PROTECTED]> wrote:
> what is the trick to get larger fonts for Graphs to make a good
> slide for presentations?
Generally I use something like
cex = 2
in the plot function, as well as
lwd = 3
--
Mike Prager, NOAA, Beaufort, NC
* Opinions expressed are personal and not
Most internationalized programs (including R) respond to the LANGUAGE
environent variable: have you tried setting it to "en"?
We would need to know your OS to help more (it looks like it might be
Windows or possibly Mac OS: the terms used are not right for either).
On Tue, 12 Aug 2008, Sergey
Hi,
Thanks for your reply. However, this didn't work exactly as I needed
it to since the expression is dynamically built as a character vector
i.e. not executed as
e <- expression(Sepal.Width > 4)
but as
e <- expression("Sepal.Width > 4")
in which case subset() throws an error (must evaluat
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