Hi,
Given a test matrix, test <- matrix(c(1,2,3,NA,2,3,NA,NA,2), 3,3)
A) How to compute the counts of each column (excluding the NA) i.e., 3, 2, 1
B) How to compute the counts of each column (excluding the NA) that are
greater than the column means ? i.e., 1, 1, 0
I could write a for loop, but
I was able to track down the problem that causes R-Swig to fail in 2.6.
In 2.5, I am able to use the set method against '$' and '$<-' to cause
expressions like r$d to get dispatched to get and set functions. This no
longer seems to work in 2.6, and I was wondering if anyone can give
informatio
Dear R helpers,
I'm trying to write a numerical scheme for a boundary integral method
to solve an electromagnetic problem. This requires the computation of
the distance between points at the surface of an object (a sphere, in
my example). Here is my code,
> require(rgl)
> r<-1
> size<-10
>
I am trying to make an array c(3,8) that contains the averages of what is in
another array c(9,8). I want to average rows 1:3, 4:6, 7:9 and have a loop
replace the generic 1:24 values in my array with the average of the three
rows.
The problem I am having is that R only replaces the last value
Good afternoon,
I've installed R on Suse 10.3 compiling the source files. I opne the program on
shell configuration and i have a problem saving the workspace and *.R or
*.Rdata files. I 've read the manual and written the comand as it says but the
output is:
save.image()
Errore in gzfile(file,
Dear all,
i have recently update R in my computer. To my surprise the menu bar
is written in German language. This is the first time this happen to
me, usually it is English the language used.
I download the last version from several mirrors from different
English and Spanish spoken countries
Hi there,
I am interested in using R for machine learning (supervised classification).
Currently, I have been investigating especially the rpart, tree, and
randomForest package, and have achieved first results.
are there any experiences, how the learned classificators could
be used in e.g. C ?
in
Dear Roland Kaiser,
I think there may different pixel-to-point scaling in different
devices. This scaling seems not only to vary with the device but even
with your physical screen. This is what happens with my current box
(MacBook):
> quartz()
> par("mar")/par("mai")
[1] 6 6 6 6
> par("c
try
tmp<- slot(ex_1.7.selected, 'polygons')
sub.tmp <- slot(tmp[[1]],'Polygons')
[EMAIL PROTECTED]
will get you there.
taka
Jarek Jasiewicz wrote:
> Milton Cezar Ribeiro wrote:
>
>> Dear all,
>>
>> I need to get all points for each polygons and save these points in a
>> data.frame. I tryed
Based on my own experience, the difficulty of installation is mainly
Linux-specific (especially SuSE), should not be a problem on Windows
platform. As computer hardware getting better each day, the resource problem
associated with Java seems to be less and less relevant. My complain about
JGR is th
Many Linux/Unix users (including me) recommend running R in Emacs, using
ESS http://ess.r-project.org/ . You can also run R through Emacs/ESS on
Windows.
Simon.
On Mon, 2008-02-04 at 07:35 +0100, Jarek Jasiewicz wrote:
> Wade Wall wrote:
> > Hi all,
> >
> > I know this question has been asked in
Milton Cezar Ribeiro wrote:
> Dear all,
>
> I need to get all points for each polygons and save these points in a
> data.frame. I tryed to use the slot() function, but I can´t access the
> "coords".
>
> grd <- GridTopology(c(1,1), c(1,1), c(10,10))
> polys <- as.SpatialPolygons.GridTopology(grd
Wade Wall wrote:
> Hi all,
>
> I know this question has been asked in the past, but I am wondering if
> anyone running R on Linux has any guidance as to a text editor that works
> well with R. At the present time I am running R on Windows and using
> TINN-R. For a number of reasons I want to swit
R-helpers:
I have a question regarding the crr function of the cmprsk package for
performing competing risks regression. Specifically, I was wondering
if the standard likelihood ratio test for a categorical covariate
applies. For example:
# Make up a fake
Dear all,
I need to get all points for each polygons and save these points in a
data.frame. I tryed to use the slot() function, but I can´t access the
"coords".
grd <- GridTopology(c(1,1), c(1,1), c(10,10))
polys <- as.SpatialPolygons.GridTopology(grd)
centroids <- coordinates(polys)
x <- cen
Sorry, but the paper is wrong, or at least the language is very loose.
It does speak about a 'confidence interval' for a statistic, but that
makes no sense. The author apparently means a confidence interval for
the parameter for which the statistic is an estimate, and nominates the
profile likelih
Yes, this is what I wanted and needed. Thank you all for your replies.
Marcin
On Feb 4, 2008 1:28 AM, Gabor Grothendieck <[EMAIL PROTECTED]> wrote:
> lattice has a type = "smooth" for this:
>
>library(lattice)
>xyplot(dist ~ speed, cars, type = c("smooth", "p"))
>
> Or with a colored line
The motivation for the question comes from Figure 3 of this paper
http://www.ma.hw.ac.uk/~mcneil/ftp/cad.pdf, which shows that a
confidence interval for a statistic is possible. Does there exist a
function in R for such a calculation? If not, how would one go about
doing it in R?
Any pointers wo
lattice has a type = "smooth" for this:
library(lattice)
xyplot(dist ~ speed, cars, type = c("smooth", "p"))
Or with a colored line:
xyplot(dist + dist ~ speed, cars, type = c("p", "smooth"), col =
1:2, distribute.type = TRUE)
In ggplot2 its also a one linear:
library(ggplot2)
q
hits=-2.6 tests�YES_00
X-USF-Spam-Flag: NO
On Sun, 2008-02-03 at 22:26 +0100, Marcin Kozak wrote:
> Thanks a lot, it works.
>
> Any ideas what's going on here?
>
> y<-c(1.75, 1.41, 1.96, 1.03, 2.38, 2.19, 1.81, 1.91, 1.47, 2.25, 1.53,
> 2.79, 2.54, 2.36, 2.65,
> 2.69, 2.58, 3.27, 3.52, 2.93)
> x
Dear Kimmo,
It doesn't appear that anyone has yet mentioned pareto.chart() in the
qcc package; it may serve your purposes. Please note that it does not
require the data frame to be ordered beforehand.
x <- DATA[[2]]
names(x) <- DATA[[1]]
library(qcc)
pareto.chart(x)
Best wishes,
Jay
On Feb
Try this:
plot(x, y)
points(x, predict(fit), pch=16, col="blue")
On 03/02/2008, Marcin Kozak <[EMAIL PROTECTED]> wrote:
> Thanks a lot, it works.
>
> Any ideas what's going on here?
>
> y<-c(1.75, 1.41, 1.96, 1.03, 2.38, 2.19, 1.81, 1.91, 1.47, 2.25, 1.53,
> 2.79, 2.54, 2.36, 2.65,
> 2.69, 2.58,
Thanks a lot, it works.
Any ideas what's going on here?
y<-c(1.75, 1.41, 1.96, 1.03, 2.38, 2.19, 1.81, 1.91, 1.47, 2.25, 1.53,
2.79, 2.54, 2.36, 2.65,
2.69, 2.58, 3.27, 3.52, 2.93)
x<-c(0.59, 0.49, 0.65, 0.41, 0.84, 0.87, 0.69, 0.72, 0.67, 0.93, 0.76,
1.04, 0.87, 0.92, 0.92,
1.04, 0.94, 1.15, 1.1
Try this:
cars.lo <- loess(dist ~ speed, cars)
with(cars, plot(speed, dist))
lines(predict(cars.lo), col="blue")
On 03/02/2008, Marcin Kozak <[EMAIL PROTECTED]> wrote:
> Dear all,
>
> To draw a lowess line on a plot was a piece of cake; to draw a loess
> line, however, seems not that easy. Is t
Dear all,
To draw a lowess line on a plot was a piece of cake; to draw a loess
line, however, seems not that easy. Is the loess plotting implemented
at all in relation to the loess function, or do I have to look in
add-on packages?
Thanks,
Marcin
__
R-
On Fri, 01-Feb-2008 at 03:23PM +0200, Atte Tenkanen wrote:
|> I had a problem:
|>
|> I saved a matrix:
|>
|> > save(Tondistmatrix1, file="/Users/atte/Skriptit/Tondistmatrix1")
|>
|> then I tried to open it with R:
|> > Tondistmatrix1=load("/Users/atte/Skriptit/Tondistmatrix1")
|> > Tondistmatri
On Saturday 02 February 2008, Frank E Harrell Jr wrote:
> Stefan Grosse wrote:
> [...]
> > alternatively you could use the hardy (next ubuntu version) repository
> > either via synaptic or the package (for the 0.4.9 package):
> >
> > http://packages.ubuntu.com/hardy/math/rkward
>
> The hardy releas
On 2/3/08, K. Elo <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I have a small problem when using barchart. I have the following data:
>
>letters a
> 6f 18
> 1a 15
> 10 j 12
> 9i 12
> 4d 9
> 5e 6
>
> The data is from a survey and summaries the alternative
I successfully chrooted R running Rserve with an unprivileged user,
and thought I'd publish the process.
Attached is a jailkit.ini for use with jailkit;* and a chroot/setuid
wrapper, chwrap.c.
To set up the chroot in, for instance, /var/R; perform:
mkdir -v /var/R
jk_init -v -c jailkit.ini
I believe that glmm.admb relies on the proprietary software ADMB. If
so, your question is inappropriate for this list which is for
discussion and assistance regarding the open source and freely
available software R.
There are ways of fitting a generalized linear mixed model in R, in
particular th
Perhaps,
letters <- c("f","a", "j","i","d","e")
a <- c(18,15,12,12,9,6)
df <- data.frame(letters, a)
library(lattice)
barchart(reorder(df$letters, df$a) ~ df$a)
-Lauri
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
P
On Feb 1, 2008 7:30 AM, Falco tinnunculus <[EMAIL PROTECTED]> wrote:
> Dear all,
> Is it possible with two random effects in lme()?
> lmefit1<- lme(Handling ~ Mass + factor(Prey)+ Mass*factor(Prey), random = ~
> 1 |Place+Age)
I assume that Place and Age are not nested. If so, it's possible to
Hi,
I have a small problem when using barchart. I have the following data:
letters a
6f 18
1a 15
10 j 12
9i 12
4d 9
5e 6
The data is from a survey and summaries the alternatives selected in one
question. The idea is to have a bar chart illustr
Dear R users,
I have a linear model of the kind
outcome ~ treatment + covariate
where 'treatment' is a factor with three levels ("0", "1", and "2"),
and the covariate is continuous. Treatments "1" and "2" both have
regression coefficients significantly different from 0 when using
treatment contr
Hello List,
I saw the example in "Writing R Extensions" where a convolve function
is implemented in C, which is makes the whole business of calling C
from R easy to understand.
Is there a similar example of how to call Fortran 90 from R somewhere?
Thanks,
Max
__
Dear all,
I have a set of shapefiles which contents are polygons.
I would like to know if is there a way of I obtain the links between the
polygons, something like a "polygon spanning tree". For point patterns I can
use de spatstat package, but I need to do it for polygons.
Below I send a sampl
Megh Dal <[EMAIL PROTECTED]> [Sun, Feb 03, 2008 at 12:17:00PM CET]:
> Can anyone here please tell me whether is it possible to
> produce a chart displayed in http://www.datawolf.blogspot.com/
> in R for visualizing multivariate time series? If possible how?
Assuming you mean
http://bp0.blogger.
Hi all,
Can anyone here please tell me whether is it possible to produce a chart
displayed in http://www.datawolf.blogspot.com/ in R for visualizing
multivariate time series? If possible how?
Regards,
-
[[alternative HTML version deleted]]
__
Thanks Thierry
It works perfect now.
Regards,
TL
On Fri, Feb 1, 2008 at 11:28 PM, ONKELINX, Thierry
<[EMAIL PROTECTED]> wrote:
> Tribo
>
> That function was added during the latest update. So you should update
> to this version (0.5.7). You can update packages with update.packages()
>
>
> Th
(little correction below)
> Dear list,
>
> This is off-topic, but perhaps there is an expert out there who can help
> me in
> a bootstrapping test.
>
> I have two samples A, B from, say, a normal distribution. A third sample R
> is the vector of pairwise minima of the same random variables:
>
>
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