Good afternoon!
I have the following data:
a<-data.frame (id_hh=c(1:5), strata=c(1,1,2,2,1),
Nhstrata=c(100,100,200,200,100), Nrmemb=c(2,4,2,5,4))
a$ocmemb1<-c("wk","jl","st","jl","st")
a$ocmemb2<-c("wk","jl","st","wk","wk")
where id_hh is a code of identification for the household (my analys
least=list.
it is late (here)!
On 28/10/2007, Mark Wardle <[EMAIL PROTECTED]> wrote:
> Hi.
>
> Sorry to hear you are having problems. I'm not installing Leopard just
> yet, as I cannot live without a working system running R, PostgreSQL,
> Filemaker, and Adobe applications. At least two on that l
Hi.
Sorry to hear you are having problems. I'm not installing Leopard just
yet, as I cannot live without a working system running R, PostgreSQL,
Filemaker, and Adobe applications. At least two on that least are said
to have problems with Leopard!
If no-one else replies, try the Mac R help list. I
Hi all, I'm looking for a package that will estimate Markov
models and provide transition probabilities. I'm not
speaking of MCMM estimation packages.
Thanks in advance,
David
--
===
David Kaplan, Ph.D.
Professor
Department
Hello all,
I apologize in advance if this is not the correct list to post these sorts
of issues. When attempting to install the latest stable build of R (2.6) or
the most recent nightly build from R.research.att.com, the installer
disables the ability to actually install R or any of the other bundl
toby909 wrote:
>
> Hi All
>
> I can specify whatever inits, it has no effect on the estimation. I am
> replicating a textbook example. The result is completely trash, having
> estimates
> of -58.7 (sd=59.3), where it should be closer to an ml estimate of 0.585
> (SE=0.063).
>
> The two chai
Diane Srivastava zoology.ubc.ca> writes:
> I have a meta-analysis dataset which I would like to analyze as a mixed
> model, where the y-variable is a measure of effect size, the random effect
> is the study from which the effect size was extracted, and the fixed
> effect is a categorical explanato
or, when the package wle is available:
library(wle)
get01mat <- function(digits=3) {
n <- 2^digits
res <- matrix(0,nrow=n,ncol=digits)
for(i in 1:n)
res[i,] <- rev(binary(i-1,dim=digits)$binary)
res
}
On Sat, 27 Oct 2007, Henrique Dallazuanna wrote:
> Hi,
>
> expand.grid(x=c(0,1), y
Thanks a lot.
Henrique Dallazuanna wrote:
>
> Hi,
>
> expand.grid(x=c(0,1), y=c(0,1), z=c(0,1))
>
>
> --
> Henrique Dallazuanna
> Curitiba-Paraná-Brasil
> 25° 25' 40" S 49° 16' 22" O
>
> On 27/10/2007, roger chan <[EMAIL PROTECTED]> wrote:
>>
>>
>> Hi, folks:
>>
>> I need to generate all 0-
library(combinat)
hcube( rep(2,3) ) -1
Here n=3.
Gabor
On Sat, Oct 27, 2007 at 01:08:07PM -0700, roger chan wrote:
>
> Hi, folks:
>
> I need to generate all 0-1 sequences with given length,say,n=3, the ideal
> result would be
> the following matrix:
>
> 0 0 0
> 0 0 1
> 0 1 0
> 0 1 1
> 1 0 0
>
Hi,
expand.grid(x=c(0,1), y=c(0,1), z=c(0,1))
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
On 27/10/2007, roger chan <[EMAIL PROTECTED]> wrote:
>
>
> Hi, folks:
>
> I need to generate all 0-1 sequences with given length,say,n=3, the ideal
> result would be
> the f
Hi, folks:
I need to generate all 0-1 sequences with given length,say,n=3, the ideal
result would be
the following matrix:
0 0 0
0 0 1
0 1 0
0 1 1
1 0 0
1 0 1
1 1 0
1 1 1
Any help would be appreciated.
--
View this message in context:
http://www.nabble.com/How-to-generate-all-permutation-of-
On Sat, 27 Oct 2007, Michael Kubovy wrote:
> Dear R-helpers,
>
> I'm trying to selectively swap labels between two factors, depending
> on an indicator variable i.
>
> Can you point me to a solution, and perhaps how I could have found it?
>
> labels(fact1) is a character vector of r row numbers
Jesse D Lecy wrote:
>
> [snip]
>
> Does anyone know how to make a large graph so that I can print it and
> view the details? I have tried changing the graph size and outputting the
> chart to an image of pdf file, but I keep getting an error:
>
>> jpeg(file="dendrogram.jpeg")
>> par(fin=c
Jonas, if you want the function to load really automatically,
without running source of anything, read
?Startup
Basically you need to create an .Rprofile file (its location depends
on your operating system) containing the R code you want to run
at startup.
Gabor
On Sat, Oct 27, 2007 at 08:37:
Dear R-helpers,
I'm trying to selectively swap labels between two factors, depending
on an indicator variable i.
Can you point me to a solution, and perhaps how I could have found it?
labels(fact1) is a character vector of r row numbers
levels(fact1) is a character vector of the n < r unique l
Regarding your first issue:
you could make a package to contain your function (see ?package.skeleton
and the manual "Writing R extensions") - then you could use
library(yourpackagename). Or you could save the definition of your
function(s) in a text file, and use source("textfilename") to load the
Thank you very much for your detailed explanation and two solutions,
Duncan.
Denis
Le 07-10-27 à 12:44, Duncan Murdoch a écrit :
> Chabot Denis wrote:
>> Dear R users,
>>
>> I need to reorder a dataframe using 3 variables for the determine
>> the sorting order.
>>
>> When I create a simple d
Dear useRs,
I have a large dataset (600 to 2000 observations) that I need to cluster with a
hierarchical technique, and then examine so that I can use cutree to extract
various groups. I would like to visualize the results of hclust in a
dendrogram, but this is obviously too much data for the
Chabot Denis wrote:
> Dear R users,
>
> I need to reorder a dataframe using 3 variables for the determine the
> sorting order.
>
> When I create a simple dataframe to test the method, things work as I
> expected:
>
> a1 <- rep(1:10, each=8)
> a2 <- rep(rep(1:2, each=4), 10)
> a3 <- rep(c(1:4),2
On Sat, 27 Oct 2007, kevinchang wrote:
>
> Thanks Chales for pointing out the errors.
> I fixed an errorr and R accepted my "rootFinding" code.
> But the problem right now is that my code will work only if the intialX
> value is close enough to the solution.
> Otherwise, R says there is missing tr
As a newbie to R I have the following question. I would like to compare values
in a time series with values of the same series x observations ago. In gretl
this is simply done like so:
In R, I seem not to get it working. I have tried lag(data,-x) to obtain the
lagged time series which produce
Dear list members,
I have written a function, called say Analysis. I supply an Excel file
name as an argument, it does analysis on this file and returns a pdf
file with specific plots, and a text file with several statistical
models' output (I extract certain values from the output and create my
o
Dear R users,
I need to reorder a dataframe using 3 variables for the determine the
sorting order.
When I create a simple dataframe to test the method, things work as I
expected:
a1 <- rep(1:10, each=8)
a2 <- rep(rep(1:2, each=4), 10)
a3 <- rep(c(1:4),20)
(a <- data.frame(a1, a2, a3))
for e
Hello everyone.
I have got a little question on selecting a proper
bandwidth for kernel regression.
As you all know, for bandwidth selection in a
regression case you can use the averaged squared error
as a criterion for goodness of fit, but for some
problems (e.g. the bandwidth h approaches to ze
Sorry, I meant non-R question.
Sorry for the inconvenience!
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
Thanks Chales for pointing out the errors.
I fixed an errorr and R accepted my "rootFinding" code.
But the problem right now is that my code will work only if the intialX
value is close enough to the solution.
Otherwise, R says there is missing true/false value in the codition test of
while loop.
Many of these points are discussed in
http://www.burns-stat.com/pages/Tutor/R_relative_statpack.pdf
a collaborative effort that I edited. In particular the final quote by
Jonathan Baron addresses point 5:
Another point, which I repeatedly make to students, is that R is
free and will continue to
Hi:
I am a newer in using R for data mining, and find the "e1071" pakage an
excellent tool in doing data mining work!
what frustrated me recently is that when I using the function "svm" and using
the "cross=10" parameters, I got all the "accuracies" of the model greater than
1. Isn't that the
Hello,
I am using Oracle 10.2 and R 2.6 on Windows XP.
I found RODBC working generally OK (with some minor problems) but very slow, so
I am trying to use RJDBC.
While getting things (dbGetQuery) works fine, I have problems with saving:
dbWriteTable(conn, "WAV", save_df, overwrite = F, append = T,
Good afternoon!
As mentioned in the subject, my question regards more the methodological part
that accompanies survey design and the statistical part that is involved.
So, I have the following data:
a<-data.frame (id_hh=c(1:5), strata=c(1,1,2,2,1),
Nhstrata=c(100,100,200,200,100), Nrmemb=c(2,4,
Regarding "financial" data: I have a high frequency (1 minute) measure of
supply/demand and I'd like to know if it has any influence on short term
price changes (also 1 minute).
Question: How do I calculate the correlation between this supply/demand
measure and price changes (correctly)?
Some fa
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