hii everyone
I am new to python programming.And i started implementing a http client
using urllib in which
i was facing a problem with proxy support.i was behind a proxy server and
need to use
proxy of format 10.1.2.21:8080 to connect to internet.when i used this with
proxyhandler
of urllib i got
as to be used in proxies list but my proxy address is
10.1.2.21:9090 and it is squid proxy server.
Regards
venkat
On Wed, Apr 1, 2009 at 4:35 AM, Chris Rebert wrote:
> 2009/3/31 venkat sanaka :
> > hii everyone
> >
> > I am new to python programming.And i started implementing a
Yeah I did i was getting the same error as i got without using http in the
url.
Regards venkat.
On Wed, Apr 1, 2009 at 4:46 AM, Chris Rebert wrote:
> > On Wed, Apr 1, 2009 at 4:35 AM, Chris Rebert wrote:
> >>
> >> 2009/3/31 venkat sanaka :
> >> > hii every
wrote:
> venkat sanaka wrote:
>
>> Yeah I did i was getting the same error as i got without using http in the
>> url.
>>
>>
> In your first message you say you need to use proxy of format
> 10.1.2.21:8080 -- but in your code example you've written and th
Thanks for ur suggestions Terry.These are really helpful for a newbie like
me in python programming.
Regards
Venkat
On Wed, Apr 1, 2009 at 5:59 AM, Terry Reedy wrote:
> venkat sanaka wrote:
>
>> This was the code i executed.
>>
>> >>> proxies={'http
n the
documentation.Thanks a lot for ur replies.
Final code:
>>>import urllib2
>>> opener = urllib2.build_opener()
>>> opener.add_header = [('User-agent', 'Mozilla')]
>>>res=opener.open('http://www.google.com')
>>> print res.read()
On Wed, A
HIi everyone.
i was using python/c api to call a python function from c and I know the
name of the function which i want to call.Is there any way to do that??
This is the method i tried...
for eg:This is the python function i wants to call.
>>>def add(x):
... return x+10
This is my code i