This is probably causing a problem:
!#/usr/bin/python
It should be "#!", not "!#".
If that doesnt' work, add this line at the top of your script, to check
that the script is begin executed:
print "Content-Type: text/html\n\n"
print "Hello, World!"
If you still get an Internal Server Error put t
>>> import types
>>> type("") is types.ListType
False
>>> type("") is types.StringType
True
>>> type([]) is types.StringType
False
>>> type([]) is types.ListType
True
--
http://mail.python.org/mailman/listinfo/python-list
What am I doing wrong here?
>>> import operator
>>> import itertools
>>> vals = [(1, 11), (2, 12), (3, 13), (4, 14), (5, 15),
... (1, 16), (2, 17), (3, 18), (4, 19), (5, 20)]
>>> for k, g in itertools.groupby(iter(vals), operator.itemgetter(0)):
... print k, [i for i in g]
...
1 [(1, 11)]
An expression like this creates a list of integers:
>>> [0] * 2
[0, 0]
But an expression like this creates list of references to the list
named `foo':
>>> foo = [0, 0]
>>> baz = [foo] * 2
[foo, foo]
So, setting baz[0][0] = 1, is really setting foo[0] = 1. There is only
one instance of foo, but y
