Greetings,
I designed in JavaScript a small program on my website called 5
queens.
(http://www.cf29.com/design/dame5_eng.php)
The goal is to control all the chess board with five queens that do
not attack each other. I found "manually" many solutions to this
problem (184 until now) and wanted to
On Dec 22, 11:05 pm, Dennis Lee Bieber <[EMAIL PROTECTED]> wrote:
> Only 5? The classic algorithm is 8-queens on a standard 8x8 board,
> as I recall...
This is a different problem. You have to control all the squares with
only 5 queens.
In the 8 queens problem you have to put 8 "safe queen
On Dec 23, 12:39 am, Jervis Liang <[EMAIL PROTECTED]> wrote:
> On Dec 22, 2:36 pm, cf29 <[EMAIL PROTECTED]> wrote:
>
> > The goal is to control all the chess board with five queens that do
> > not attack each other. I found "manually" many solutions to this
On Dec 23, 1:49 am, John Machin <[EMAIL PROTECTED]> wrote:
> > > How did you find 184 solutions? Wolfram says there are 91 distinct
> > > solutions for 5-queens on an 8x8 board with no two queens attacking
> > > each other.
>
> It's *91* distinct solutions to what appears to be *exactly* your
> pro
Sorry again I forgot a part of the function in my previous post:
---
# add nbQueens (5) new queens on safe squares
def newQueens(nbQueens=5):
solution = [] # one solution
for i in range(len(board)): # 64 squares
To make it simple and not have to deal with the 8 queens problem that
is different with the 5 queens one, I'll ask in a different way.
I am not familiar with implementing in Python such terms as "standard
depth-first search of the solution space", "permutation", "recursion",
"'canonical' form", ..
On Dec 23, 2:04 pm, Steven D'Aprano <[EMAIL PROTECTED]
cybersource.com.au> wrote:
> def combinations(seq, n):
> if n == 0:
> yield []
> else:
> for i in xrange(len(seq)):
> for cc in combinations(seq[i+1:], n-1):
> yield [seq[i]]+cc
>
> >>> for c
Which website would you recommend for a great documentation about
Python?
I am looking for a list of methods and properties of all the Python
elements with syntax examples.
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I installed Python 2.5 on my Mac (OS X Tiger). When running scripts
with the TextWrangler Run command it is using the system installed
version of Python (2.3). If I run the scripts with the Apple Terminal
it uses the new version (2.5).
Is there any way to ask TextWrangler to use the new version of
Thank you Jean, I could fix this problem. Creating the symbolic link
wasn't really obvious though.
They also say about the documentation:
*Extract the documentation files, and place them in some suitable
location, e.g.
~/Library/Python-Docs
*Edit your "environment.plist" file, and create an enviro
Greetings,
On Mac OS 10.5.6, I updated Python to version 3.0.1.
When I want to run a py file, I get an error:
xxx:~ xxx$ cd '/Users/xxx/Documents/programmingPractice/' && '/usr/
local/bin/python' '/Users/xxx/Documents/programmingPractice/
python_file.py' && echo Exit status: $? && exit 1
-bash: /
nt to run py file either with Python
Launcher.app or directly from BBEdit (the text editor i use). I get
the "cannot execute binary file" error.
In /usr/local/bin/ the python symbolic link is connected to Python v3
Charly http://cf29.com/
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ly I was using the open menu of Python Launcher to open my
files. And now it works fine.
Usually I use to run python scripts from BBEdit itself and this is now
working as expected.
What a great place to find answers! Thanks again.
Charly
http://cf29.com/
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