All,
I am trying to figure out how to send a image in the body of a email when
Making a Meeting Request.
Below is my current code.
Thanks,
Bruce
# code below is mainly from
http://harunprasad.blogspot.com/2012/01/python-make-meeting-request-appointment.html
#
These do not work:
appt.BodyFormat = olBodyFormat.olFormatHTML
...
appt.BodyFormat = olBodyFormat.olFormatHTML
NameError: name 'olBodyFormat' is not defined
appt.BodyFormat = win32com.client.constants.olFormatHTML
...
appt.BodyFormat = win32com.client.constan
This assignment works:
import win32com.client
oOutlook = win32com.client.Dispatch("Outlook.Application")
appt = oOutlook.CreateItem(0)
appt.BodyFormat = win32com.client.constants.olFormatHTML
But this assignment does not work:
import win32com.client
oOutlook = win32com.client.Dispatc
Is there a way in Python to pass arguments without listing each argument?
For example, my program does the following:
testData (z[0], z[1], z[2], z[3], z[4], z[5], z[6], z[7])
Is there a clever way to pass arguments in a single statement knowing that each
argument is a sequential index from
On Wednesday, August 8, 2012 9:07:04 PM UTC-4, Dave Angel wrote:
> On 08/08/2012 08:41 PM, bruceg113...@gmail.com wrote:
>
> > Is there a way in Python to pass arguments without listing each argument?
>
> > For example, my program does the following:
>
> >
>
> > testData (z[0], z[1], z[2],
My program uses Python 2.6 and Sqlite3 and connects to a network database 100
miles away.
My program reads approx 60 records (4000 bytes) from a Sqlite database in less
than a second.
Each time the user requests data, my program can continuously read 60 records
in less than a second.
However
Uli,
Answers to your questions:
1) There are approx 65 records and each record is 68 bytes in length.
2) Not applicable because number of records is fixed.
3) Takes less than a second to read all 65 records when all is well.
Takes 17 seconds to read all 65 records when all is NOT WELL
4) Perfor
Demian,
I am not a database expert!
I selected sqlite for the following reasons:
1) Ships with Python.
2) Familiar with Python.
3) The Sqlite description at http://www.sqlite.org/whentouse.html appears to
meet my requirements:
Very low volume and concurrency, small datasets, simple to use.
On Monday, August 27, 2012 10:32:47 PM UTC-4, Bryan wrote:
> bruceg113 wrote:
>
> > I selected sqlite for the following reasons:
>
> >
>
> > 1) Ships with Python.
>
> > 2) Familiar with Python.
>
> > 3) The Sqlite description athttp://www.sqlite.org/whentouse.htmlappears to
> > meet my requir
On Tuesday, August 28, 2012 4:27:48 AM UTC-4, Cameron Simpson wrote:
> On 27Aug2012 13:41, bruceg113...@gmail.com wrote:
>
> | When using the database on my C Drive, Sqlite performance is great! (<1S)
>
> | When using the database on a network, Sqlite performance is terrible! (17S)
>
>
>
>
Python Users Group,
I need to archive a MySQL database using a python script.
I found a good example at: https://gist.github.com/3175221
The following line executes however, the archive file is empty.
os.popen("mysqldump -u %s -p%s -h %s -e --opt -c %s | gzip -c > %s.gz" %
(user,p
Is there a simpler way to modify all arguments in a function before using the
arguments?
For example, can the below code, in the modify arguments section be made into a
few statements?
def someComputation (aa, bb, cc, dd, ee, ff, gg, hh):
# modify arguments
# ---
On Friday, November 9, 2012 8:16:12 PM UTC-5, Steven D'Aprano wrote:
> On Fri, 09 Nov 2012 20:05:26 -0500, Roy Smith wrote:
>
>
>
> > In article <18134e77-9b02-4aec-afb0-794ed900d...@googlegroups.com>,
>
> > bruceg113...@gmail.com wrote:
>
> >
>
> >> Is there a simpler way to modify all arg
All,
I never used decorators before. I saw Miki Tebeka's sample code and your
rationale (Aahz) and I like it. For my application problem, decorators seem
like a good solution.
Thanks to all,
Bruce
On Saturday, November 10, 2012 10:35:12 AM UTC-5, Aahz wrote:
> In article ,
>
> Peter Otten
On Thursday, November 15, 2012 11:16:08 PM UTC-5, Ethan Furman wrote:
> Emile van Sebille wrote:
>
>
> >
>
> >> Using a decorator works when named arguments are not used. When named
>
> >> arguments are used, unexpected keyword error is reported. Is there a
>
> >> simple fix?
>
> >
>
> >
Lets say I have the following tuple like string.
(128, 020, 008, 255)
What is the best way to to remove leading zeroes and end up with the following.
(128, 20, 8, 255)-- I do not care about spaces
This is the solution I came up with
s = "(128, 020, 008, 255)"
v = s.replace ("(
On Sunday, May 20, 2018 at 5:01:08 PM UTC-4, Michael F. Stemper wrote:
> On 2018-05-20 14:54, bruceg113...@gmail.com wrote:
> > Lets say I have the following tuple like string.
> >(128, 020, 008, 255)
> >
> > What is the best way to to remove leading zeroes and end up with the
> > following.
On Sunday, May 20, 2018 at 5:32:32 PM UTC-4, Paul wrote:
> >
> >
> > This works for me: mytuplestring.replace("0","")
> >
> > Your regex will also eliminate non-leading zeros.
Your right, what was I thinking?
--
https://mail.python.org/mailman/listinfo/python-list
I am trying to convert a string to a variable.
I got cases 1 & 2 to work, but not cases 3 & 4.
The print statement in cases 3 & 4 reports the following:
builtins.AttributeError: type object 'animal' has no attribute 'tiger'
I am stuck on creating variables that can be accessed as follows
How do I list only the methods I define in a class?
For example:
class Produce():
def __init__ (self):
print (dir (Produce))
def apples(self):
pass
def peaches(self):
pass
def pumpkin (self):
pass
The print (dir(Produce)) statement d
On Thursday, May 31, 2018 at 10:18:53 PM UTC-4, bob gailer wrote:
> On 5/31/2018 3:49 PM, bruceg113...@gmail.com wrote:
> > How do I list only the methods I define in a class?
> Here's a class with some method, defined in various ways:
>
> >>> class x():
> ... a=3
> ... def f():pass
> ..
I have a string that contains 10 million characters.
The string is formatted as:
"001 : some hexadecimal text ... \n
002 : some hexadecimal text ... \n
003 : some hexadecimal text ... \n
...
010 : some hexadecimal text ... \n
011 : some hexadecimal text ... \n"
and I need the
On Saturday, May 16, 2015 at 9:46:17 AM UTC-4, Chris Angelico wrote:
> On Sat, May 16, 2015 at 11:28 PM, wrote:
> > I have a string that contains 10 million characters.
> >
> > The string is formatted as:
> >
> > "001 : some hexadecimal text ... \n
> > 002 : some hexadecimal text ... \n
>
On Saturday, May 16, 2015 at 10:06:31 AM UTC-4, Stefan Ram wrote:
> bruceg113...@gmail.com writes:
> >Your approach using .join is what I was looking for.
>
> I'd appreciate a report of your measurements.
# Original Approach
# -
ss = ss.split("\n")
ss1 = ""
for sdata in ss:
On Saturday, May 16, 2015 at 11:13:45 AM UTC-4, Rustom Mody wrote:
> On Saturday, May 16, 2015 at 8:30:02 PM UTC+5:30, Grant Edwards wrote:
> > On 2015-05-16, bruceg113355 wrote:
> >
> > > I have a string that contains 10 million characters.
> > >
On Saturday, May 16, 2015 at 12:59:19 PM UTC-4, Chris Angelico wrote:
> On Sun, May 17, 2015 at 2:22 AM, wrote:
> > # Original Approach
> > # -
> > ss = ss.split("\n")
> > ss1 = ""
> > for sdata in ss:
> > ss1 = ss1 + (sdata[OFFSET:] + "\n")
> >
> >
> > # Chris's Approach
> >
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