Hello!
Is there any way that I can get at all the arguments passed to a
function as a map without using keyword arguments?
def foo(a, b, c):
# Can I access all the arguments in a collection somewhere?
I'm mainly curious since I have stumbled on to some cases where it
might have been nice to
On Jan 26, 10:11 am, Chris Rebert wrote:
> On Mon, Jan 26, 2009 at 1:03 AM, brasse wrote:
> > Hello!
>
> > Is there any way that I can get at all the arguments passed to a
> > function as a map without using keyword arguments?
>
> > def foo(a, b, c):
> >
On Jan 26, 10:39 am, Chris Rebert wrote:
> On Mon, Jan 26, 2009 at 1:34 AM, brasse wrote:
> > On Jan 26, 10:11 am, Chris Rebert wrote:
> >> On Mon, Jan 26, 2009 at 1:03 AM, brasse wrote:
> >> > Hello!
>
> >> > Is there any way that I can get at all
Hello!
I am having some trouble building Python 2.6 on AIX. The steps I have
taken are:
export PATH=/usr/bin/:/usr/vacpp/bin/
./configure --with-gcc=xlc_r --with-cxx=xlC_r --disable-ipv6
make
This is the error message I'm seeing:
./Modules/ld_so_aix xlc_r -bI:Modules/python.exp build/
temp.aix-5
the bug tracker.
I would be quite happy if I could build Python on AIX without the
multiprocessing module. Is there some way I can skip some selected
modules when building Python. I tried with ./configure --without-
multiprocessing, but that didn't work.
:.:: mattias
> On Mon, Oct 6,
On Oct 6, 10:16 am, brasse <[EMAIL PROTECTED]> wrote:
> Hello!
>
> I am having some trouble building Python 2.6 on AIX. The steps I have
> taken are:
>
> export PATH=/usr/bin/:/usr/vacpp/bin/
> ./configure --with-gcc=xlc_r --with-cxx=xlC_r --disable-ipv6
> make
>
Hello!
I have been running in to some problems when using
contextlib.nested(). My problem arises when using code similar to
this:
from __future__ import with_statement
from contextlib import nested
class Foo(object):
def __init__(self, tag, fail=False):
print 'ctor', tag
se
On Nov 6, 11:43 am, Robert Lehmann <[EMAIL PROTECTED]> wrote:
> On Thu, 06 Nov 2008 01:02:34 -0800, brasse wrote:
> > Hello!
>
> > I have been running in to some problems when using contextlib.nested().
> > My problem arises when using code similar to this
On Nov 6, 5:45 pm, "Diez B. Roggisch" <[EMAIL PROTECTED]> wrote:
> > If you had a class that wanted to acquire some external resources that
> > must be released at some point, how would you rewrite the code from my
> > example?
>
> If you *can*, use a context. Use __enter__ and __exit__. Try really
On Nov 7, 10:33 am, Peter Otten <[EMAIL PROTECTED]> wrote:
> brasse wrote:
> > with nested(Foo('a'), Foo('b', True)) as (a, b):
> > print a.tag
> > print b.tag
>
> If been watching this thread for a while, and I think that your problems
Hello!
I have been thinking about how write exception safe constructors in
Python. By exception safe I mean a constructor that does not leak
resources when an exception is raised within it. The following is an
example of one possible way to do it:
class Foo(object):
def __init__(self, name, f
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