int((9.2-9.0)*10) is 1, int((9.21-9.0)*10) is 2, why?

Python 2.5.2 (r252:60911, Feb 21 2008, 13:11:45) [MSC v.1310 32 bit (Intel)] on win32 The following line of code describes an funny question： >>> int((9.2-9.0)*10) 1 >>> int((9.21-9.0)*10) 2 >>> int((9.1-9.0)*10) 0 >>> int((9.11-9.0)*10) 1 >>> int((8.2-8.0)*10) 1 >>> int((8.23-8.0)*10) 2 why? any

Re: int((9.2-9.0)*10) is 1, int((9.21-9.0)*10) is 2, why?

On Sep 5, 9:29 pm, John Machin <[EMAIL PROTECTED]> wrote: > On Sep 5, 11:12 pm, bcm <[EMAIL PROTECTED]> wrote: > > > > > Python 2.5.2 (r252:60911, Feb 21 2008, 13:11:45) [MSC v.1310 32 bit > > (Intel)] on win32 > > The following line of code describes an