I am a newbie... and the first to admit it... but this has me stuffed:
I have two lists A and B that are both defined as range(1,27) I want
to find the entries that are valid for A = BxB
so here is my code:
A = range(1,27)
B = range(1,27)
for b in B:
if b*b in A:
print b
On Jun 28, 2:48 pm, Mel <[EMAIL PROTECTED]> wrote:
> ToshiBoy wrote:
> > I have two lists A and B that are both defined as range(1,27) I want
> > to find the entries that are valid for A = BxB
> [ ... ]
> > I get, as expected 1,4,9,16,25 printed out being the o
I'm a newbie to Python... well a newbie to programming, really. I know
the basics and try to learn by setting myself simple tasks and goals
just to find out if I can work out a way to code the solutions. Works
for me. However, now I've set my eyes on a more ambitious project:
We sell office machin
Great, I think that's exactly what I'm after. Thank you!
Simon Brunning wrote:
2008/8/3 ToshiBoy <[EMAIL PROTECTED]>:
Currently, I'm using iMacro, an add-on to Firefox, which runs a macro
and enters all the info. It's great, but I would like to try and write
a prog
I'm wondering how to do this the most elegant way: I found this quiz
in some magazine. I've already solved it on paper, but want to write a
python program to solve it. It comes down to being able to represent
range(1,27) through a number of formulas. How do I write a loop that
will loop through thi
Thank you for all your responses. I've tried the permutations road
(thank you to all those of you who have suggested it) and it takes %*&
%^ long :-) As expected. I've solved it a different way, which runs
through the 26 spots by just adding one at a time if available. Still
takes a long time, but
I don't use it often in Vista, but I haven't had any issues. Matter-of-
fact, some things seem nicer in Vista... for instance it resets IDLE
whenever I rerun a module.
Mchizi_Crazy wrote:
> Please help with issue... I heard of compatimbiltity issues and would
> like clarification.
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