for key in dict:
print key[0], key[1], dict[key]
10.08.2012, в 0:11, giuseppe.amatu...@gmail.com написал(а):
> Hi,
> I have a dict() unique
> like this
> {(4, 5): 1, (5, 4): 1, (4, 4): 2, (2, 3): 1, (4, 3): 2}
> and i want to print to a file without the brackets comas and semicolon in
> ord
dict.items() is a list - linear access time whereas with 'for key in dict:'
access time is constant:
http://python.net/~goodger/projects/pycon/2007/idiomatic/handout.html#use-in-where-possible-1
10.08.2012, в 0:35, Tim Chase написал(а):
> On 08/09/12 15:22, Roman Vashkevich wrot
1, Roman Vashkevich wrote:
>> 10.08.2012, в 0:35, Tim Chase написал(а):
>>> On 08/09/12 15:22, Roman Vashkevich wrote:
>>>>> {(4, 5): 1, (5, 4): 1, (4, 4): 2, (2, 3): 1, (4, 3): 2}
>>>>> and i want to print to a file without the brackets comas and se
10.08.2012, в 1:47, Dave Angel написал(а):
> On 08/09/2012 05:34 PM, Roman Vashkevich wrote:
>> Actually, they are different.
>> Put a dict.{iter}items() in an O(k^N) algorithm and make it a hundred
>> thousand entries, and you will feel the difference.
>> Dict uses
10.08.2012, в 13:19, Mok-Kong Shen написал(а):
>
> In an earlier question about lists, I was told about the issue of
> creation of local names in a function. However, I still can't
> understand why the program below outputs:
>
> [999] sss
> [999]
>
> and not two identical lines of output. For b
10.08.2012, в 13:28, Roman Vashkevich написал(а):
> 10.08.2012, в 13:19, Mok-Kong Shen написал(а):
>
>>
>> In an earlier question about lists, I was told about the issue of
>> creation of local names in a function. However, I still can't
>> understand why the
10.08.2012, в 14:12, Mok-Kong Shen написал(а):
> Am 10.08.2012 11:48, schrieb Roman Vashkevich:
>> [snip]
> >The function It takes list by reference and creates a new local
> > str. When it's called with listb and strb arguments, listb is passed
> > by refe
10.08.2012, в 14:12, Mok-Kong Shen написал(а):
> Am 10.08.2012 11:48, schrieb Roman Vashkevich:
>> [snip]
> >The function It takes list by reference and creates a new local
> > str. When it's called with listb and strb arguments, listb is passed
> > by refe
