Hi !
This is maybe a silly question, but...
is there a "easy way" to make eval() convert all floating numbers to Decimal
objects and return a Decimal?
for example:
eval('1.0001+0.111') --> convert each number to a Decimal object,
perform the sum and obtain a Decimal object as a result
On Tuesday 29 March 2005 03:04, Raymond Hettinger wrote:
> from decimal import Decimal
> import re
>
> number = re.compile(r"((\b|(?=\W))(\d+(\.\d*)?|\.\d+)([eE][+-]?\d{1,3})?)")
> deciexpr = lambda s: number.sub(r"Decimal('\1')", s)
>
> for s in ('1.0001+0.111',
> '+21.3e-5*85-.1234/81.
