json_split = {}
value = {"Status": "Submitted", "m_Controller": "Python"}
a = range(31)
del a[0]
for i in a:
json_split[i] = value
keys = json_split.keys()
order = list(keys)
q1 = int(round(len(keys)*0.2))
q2 = int(round(len(keys)*0.3))
q3 = int(round(len(keys)*0.5))
b = [q1,q2,q3]
n=0
threedic
I am trying to add a key value pair of ("Priority":"1") to queue1,
("Priority":"2") to queue2, and ("Priority":"3") to queue3.
When I just add ("Priority":"1") to queue1, it works.
But when I run the above code, ("Priority":"3") is being added to all the
queues.
This looks trivial and I don't
On Tuesday, November 4, 2014 2:37:49 PM UTC-5, Anurag Patibandla wrote:
> I am trying to add a key value pair of ("Priority":"1") to queue1,
> ("Priority":"2") to queue2, and ("Priority":"3") to queue3.
> When I just add (
On Tuesday, October 14, 2014 12:59:27 PM UTC-4, Dave Angel wrote:
> anuragpatiband...@gmail.com Wrote in message:
>
> > I have a dictionary that looks like this:
>
> > {"1":{"Key1":"Value1", "Key2":"Value2", "Key3":"Value3"},
>
> > "2":{"Key1":"Value1", "Key2":"Value2", "Key3":"Value3"},
>
>
On Tuesday, October 14, 2014 5:33:01 PM UTC-4, Skip Montanaro wrote:
> Shuffle the keys, then grab the first 20 for one dictionary, the next 30 for
> the second, and the last 50 for the third.
>
> Skip
Could you please be more specific?
--
https://mail.python.org/mailman/listinfo/python-list
Thanks for the response.
Here is the code that I have tried.
from operator import itemgetter
keys = json.keys()
order = list(keys)
q1 = int(round(len(keys)*0.2))
q2 = int(round(len(keys)*0.3))
q3 = int(round(len(keys)*0.5))
b = [q1,q2,q3]
n=0
for i in b:
queues = order[n:n+i]
n =
'json' has my original larger dict
--
https://mail.python.org/mailman/listinfo/python-list
Thanks Rustom for the advice.
I am new to Python and getting struck at some basic things. How do I assign the
values that I am printing to 3 variables say dict1, dict2, dict3?
When I try to assign them before the print statement like this:
d1, d2, d3 =[(queues[j], json.get(queues[j])) for j in ran
First the values printed by
'[(queues[j], json.get(queues[j])) for j in range(len(queues))] '
is a list, so I tried to convert it into a dict using dict().
And then I tried doing dict[0] but there is an error which says:
'type' object has no attribute '__getitem__'
--
https://mail.python.org/mail
keys = json.keys()
order = list(keys)
q1 = int(round(len(keys)*0.2))
q2 = int(round(len(keys)*0.3))
q3 = int(round(len(keys)*0.5))
b = [q1,q2,q3]
n=0
for i in b:
queues = order[n:n+i]
n = n+i
#print queues
#print [(queues[j], json.get(queues[j])) for j in range(len(queues))
keys = json.keys()
order = list(keys)
q1 = int(round(len(keys)*0.2))
q2 = int(round(len(keys)*0.3))
q3 = int(round(len(keys)*0.5))
b = [q1,q2,q3]
n=0
for i in b:
queues = order[n:n+i]
n = n+i
lists = [(queues[j], json.get(queues[j])) for j in range(len(queues))]
dicts
On Wednesday, October 15, 2014 1:10:41 PM UTC-4, Rustom Mody wrote:
> On Wednesday, October 15, 2014 10:30:49 PM UTC+5:30, Anurag Patibandla wrote:
>
> > keys = json.keys()
>
> > order = list(keys)
>
> > q1 = int(round(len(keys)*0.2))
>
> > q2 = int(roun
Here is my sample dict if that helps:
json = {"1": {"Status": "Submitted", "Startdate": ["01/01/2011"], "Enddate":
["02/02/2012"], "Job_ID": 1, "m_Quantile": "80", "m_Controller": "Python",
"m_Method": "Distributed", "Allocation_3": ["50"], "Allocation_2": ["30"],
"Allocation_1": ["20"], "Note"
On Wednesday, October 15, 2014 1:35:43 PM UTC-4, Rustom Mody wrote:
> On Wednesday, October 15, 2014 10:51:11 PM UTC+5:30, Anurag Patibandla wrote:
>
> > Here is my sample dict if that helps:
>
> >
>
> >
>
> >
>
> > json = {"
On Wednesday, October 15, 2014 1:41:13 PM UTC-4, Dave Angel wrote:
> Anurag Patibandla Wrote in message:
>
> > Thanks for the response.
>
> > Here is the code that I have tried.
>
> >
>
> > from operator import itemgetter
>
> > keys = json.
15 matches
Mail list logo
