Hello there,
let's suppose I have the following matrix:
mat = [[1,2,3], [3,2,4], [7,8,9], [6,2,9]]
where [.. , .. , ..] are the rows.
I am interested into getting the "row index" of all the matrix rows
where a certain number occurs.
For example for 9 I should get 2 and 3 (starting from 0).
For
Hello there,
I'd like to get the same result of set() but getting an indexable
object.
How to get this in an efficient way?
Example using set
A = [1, 2, 2 ,2 , 3 ,4]
B= set(A)
B = ([1, 2, 3, 4])
B[2]
TypeError: unindexable object
Many thanks, alex
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Hello,
I have this matrix [20*4 - but it could be n*4 , with n~100,000] in
file "EL_list" like this:
1, 1, 2, 3
2, 4, 1, 5
3, 5, 1, 6
4, 7, 5, 6
5, 8, 7, 9
6, 8, 5, 7
7,
Hello,
I am a newby with python. I wrote the following code to extract a text
from a file and write it to another file:
linestring = open(path, 'r').read() #read all the inp file in
linestring
i=linestring.index("*NODE")
i=linestring.index("E",i)
e=linestring.index("*",i+10)
textN = linestring[i+
Hello there :) ,
I am a python newbie and need to run following code for a task in an
external simulation programm called "Abaqus" which makes use of python
to access the mesh (ensamble of nodes with xy coordinates) of a
certain geometrical model.
[IN is the starting input containing the nodes to
Hello guys,
I am just wondering if there is a quick way to improve this algorithm
[N is a structured array which hold info about the nodes n of a finite
element mesh, and n is about 300.000). I need to extract info from N
and put it in to a 3*n matrix NN which I reshape then with numpy. I
think to
On Feb 11, 1:08 pm, Tim Chase wrote:
> Alexzive wrote:
> > I am just wondering if there is a quick way to improve this algorithm
> > [N is a structured array which hold info about the nodes n of a finite
> > element mesh, and n is about 300.000). I need to extract info from N
Hello Pythonguys!
is there a way to improve the performance of the attached code ? it
takes about 5 h on a dual-core (using only one core) when len(V)
~1MIL. V is an array which is supposed to store all the volumes of
tetrahedral elements of a grid whose coord. are stored in NN (accessed
trough th
UN = F[f].fieldOutputs['U'].getSubset(region=TOP).values <---
... EPS_nodes[f] = UN[10].data[Scomp-1]/L3
###
unfortunately I don't have time to learn cython. Using dictionaries
sounds promising.
Thanks!
Alex
On May 26, 8:14 am, Stefan Behnel wrote:
> Alexzive, 25.05.201
sorry it was just bullshit what I wrote about the second bottleneck,
it seemed to hang up but it was just me forgetting to double-enter
during debugging after "for cycle".
On May 26, 1:43 pm, Alexzive wrote:
> thank you all for the tips.
> I 'll try them soon.
>
Hello there,
my Mandriva has the 2.6.4 python pre-installed (in /usr/lib64/
python2.6/)
I need to install numpy 1.4 for python 2.4.3 (I installed it
separately from source on/usr/local/lib/python2.4/ )
but still typing "python" I get:
Python 2.6.4 (r264:75706, Jan 8 2010, 18:59:59)
[GCC 4.4.1] o
thanks guys,
the solution for me was
python2.4 setup.py install --prefix=/usr/local
cheers, AZ
On Jun 14, 11:00 am, Steven D'Aprano wrote:
> On Mon, 14 Jun 2010 01:30:09 -0700, Alexzive wrote:
> > what to change in order to get "python" calling python 2.4.3 instea
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