On 07/12/2020 16:48, Bischoop wrote:
I worked on my wee script that replaces a letters: https://bpa.st/OYBQ .
I would like to have some suggestions about the code from more
experienced programmers, the code does work and do its job but perhaps
could work in a better way.
Thanks
Sure!
First o
On 12/7/2020 8:33 PM, Pablo Galindo Salgado wrote:
It's starting to get very cold (at least on the Northern hemisphere) so we
have been carefully packaging a total of three new Python releases to keep
you warm these days!
Python 3.9.1 is the first maintenance release of Python 3.9, and also the
PyDev 8.1.0 Release Highlights
-
*Interactive Console*
- The selection for which console to open may be saved. (*#PyDev-1112*)
- When the *current editor* option is selected, the related
interpreter is no longer asked. (*#PyDev-1112*)
-
*Debugger* (updated to pydevd 2
Yes. Import os, and use os.system( ) to call your Fortran (or C) executable.
If the executable saves results in a file or files, Python can read them in an
format a nice overall report. In html or xml, if you like.
Using Python as glue, the execution time will be exactly what it was for you
On Mon, 7 Dec 2020 at 20:38, Tito SanĂ² wrote:
> Is it possible to get better performance in Python?
Have you installed BLAS for Scipy? What OS do you have?
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Am 07.12.20 um 17:59 schrieb Tito SanĂ²:
Regarding the solution of linear algebraic equations I noticed a big
difference in the computation
time in Python compared to the old fortran language.
I have compared both the linelg and lapack.dgesv-lapack.zgesv modules with
the fortan: dgelg and f04adf
Would this be a reasonably correct way to annotate a property with a
type hint?
>>> class Foo:
... bar: int
... @property
... def bar(self):
... return 1
...
>>> foo = Foo()
>>> import typing
>>> typing.get_type_hints(foo)
{'bar': }
I could also decorate the property method r
Hi!
I am looking at some code, that I found somewhere in the internet, to
compute DCT for each 8x8 block in an gray (2D) image (512x512).
This is the code:
def dct2(a):
return
scipy.fft.dct(scipy.fft.dct(a,axis=0,norm='ortho'),axis=1,norm='ortho')
imsize=im.shape
dct=np.zeros(imsize)
# Do